classical mechanics i m.sc(maths). to find the curve joining two points along which a particle...
TRANSCRIPT
![Page 1: Classical Mechanics I M.Sc(Maths). To find the curve joining two points along which a particle sliding from rest under gravity travels from higher point](https://reader036.vdocuments.mx/reader036/viewer/2022072016/56649ef35503460f94c04fd4/html5/thumbnails/1.jpg)
Classical MechanicsI M.Sc(Maths)
![Page 2: Classical Mechanics I M.Sc(Maths). To find the curve joining two points along which a particle sliding from rest under gravity travels from higher point](https://reader036.vdocuments.mx/reader036/viewer/2022072016/56649ef35503460f94c04fd4/html5/thumbnails/2.jpg)
To find the curve joining two points along which a particle sliding from rest under gravity travels
from higher point to lower point in the least timeLet v be the velocity of particle when it is at p(x,y). the time taken by the particle to slide
through a small distance ds along the curve = ds/vTotal time taken by the particle to slide from point A to point B is t12 = ∫ds/v
Now the total energy at A=(K.E)+(P.E)T.E=TA+VA=0+0=0
Total energy at A= ½ mv2+(-mgy) , m is the mass and v is velocity
![Page 3: Classical Mechanics I M.Sc(Maths). To find the curve joining two points along which a particle sliding from rest under gravity travels from higher point](https://reader036.vdocuments.mx/reader036/viewer/2022072016/56649ef35503460f94c04fd4/html5/thumbnails/3.jpg)
By conservation theorem, ½ mv2-mgy=0v2=2gyt12= =
= =
For t1 to be minimum we have
-------(2)
![Page 4: Classical Mechanics I M.Sc(Maths). To find the curve joining two points along which a particle sliding from rest under gravity travels from higher point](https://reader036.vdocuments.mx/reader036/viewer/2022072016/56649ef35503460f94c04fd4/html5/thumbnails/4.jpg)
=
=
=
=
![Page 5: Classical Mechanics I M.Sc(Maths). To find the curve joining two points along which a particle sliding from rest under gravity travels from higher point](https://reader036.vdocuments.mx/reader036/viewer/2022072016/56649ef35503460f94c04fd4/html5/thumbnails/5.jpg)
-----(3)
Now f does not involve x explicitly.
c ,where c is constant
Substituting values and solving the equations we get y(1+z2)=1/c2=b(say)
y+yz2=by2=b-y/y
![Page 6: Classical Mechanics I M.Sc(Maths). To find the curve joining two points along which a particle sliding from rest under gravity travels from higher point](https://reader036.vdocuments.mx/reader036/viewer/2022072016/56649ef35503460f94c04fd4/html5/thumbnails/6.jpg)
Put y = bsin2φ and solving we get b-y=bcos2φSubstituting in the above integral and solving we get
b
But sin2 φ=1-cos2φ.hence substituting we get b[φ- ½ (sin2 φ)]=x+c1
When x=0,y=0 we get c1=0.so x = b[φ- ½ (sin2 φ)]
![Page 7: Classical Mechanics I M.Sc(Maths). To find the curve joining two points along which a particle sliding from rest under gravity travels from higher point](https://reader036.vdocuments.mx/reader036/viewer/2022072016/56649ef35503460f94c04fd4/html5/thumbnails/7.jpg)
Also y=bsin2φ= b/2(1-cos2 φ).
Let b/2 =a and 2φ=θ. Then the above equation becomes a(θ-sin θ)=x and a(1-cos θ)=y which is the parametric equation of cycloid.