class: sz3 jee-main model date: 12-07-2020 time: 3hrs wtm-06 … · 2020-07-12 ·...
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Class: SZ3 JEE-MAIN MODEL Date: 12-07-2020
Time: 3hrs WTM-06 Max. Marks: 300
IMPORTANT INSTRUCTIONS
PHYSICS
Section Question Type +Ve
Marks - Ve
Marks No.of
Qs Total marks
Sec – I(Q.N : 1 – 20) Questions with Single Answer Type 4 -1 20 80
Sec – II(Q.N : 21 – 25) Questions with Numerical Answer Type
(+/ - Decimal Numbers) 4 0 5 20
Total 25 100
CHEMISTRY
Section Question Type +Ve
Marks - Ve
Marks No.of
Qs Total marks
Sec – I(Q.N : 26 – 45) Questions with Single Answer Type 4 -1 20 80
Sec – II(Q.N : 46 – 50) Questions with Numerical Answer Type
(+/ - Decimal Numbers) 4 0 5 20
Total 25 100
MATHEMATICS Section Question Type
+Ve Marks
- Ve Marks
No.of Qs
Total marks
Sec – I(Q.N : 51 – 70) Questions with Single Answer Type 4 -1 20 80
Sec – II(Q.N : 71 – 75) Questions with Numerical Answer Type
(+/ - Decimal Numbers) 4 0 5 20
Total 25 100
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–:SZ3 Jee-Main Exam Syllabus (12-07-20):–
TOPICS
PHYSICS
PRESENT WEEK 50%:
Multiplication of Vectors by a Scalar, Scalar Product, Vector
Product, Worksheet Practice
PREVIOUS WEEK 50%:
Resolution of Vectors, Direction Cosines, Lami's Theorem,
Applications, Worksheet Practice.
TOPICS
CHEMISTRY
PRESENT WEEK 50%:
Crystal lattice of NaCl, CsCl, unit cell, coordination number, limiting
radius ratio, Properties of ionic compounds, Covalent bond,
formation Lewis dot structures, types, Co - valency, formal charge,
Resonance, characteristics of resonance, Properties of covalent
compounds.
PREVIOUS WEEK 50%:
Filling of orbitals in atoms, Aufbau Principle, Pauli’s exclusion
Principle and Hund’s rule of maximum multiplicity. Electronic
Configuration up to 30, Magnetic moments, Chemical bonding:
Introduction, electronic theory of valency, octet rule Ionic bond,
formation, factors favourable for the formation of ionic bond,
electro valency, Crystal lattice energy, born Haber cycle, Fajans
rules
TOPICS
MATHS
PRESENT WEEK 50%:
Transformations: Standard Formulae of Trigonometric
Transformations, Conditional Identities, Related Problems.
PREVIOUS WEEK 50%:
Important Standard Results On Multiple And Sub Multiple Angles,
Problems On Standard Results, Problems Related C±S<0 AND
C±S>0. Miscellaneous Problems.
SZ3 _JEE-MAIN_WTM-06_QP_Dt.12-07-2020
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SECTION-I(1-20)
(Single Answer Type)
This section contains 20 multiple choice questions. Each question has 4 options
(1), (2), (3) and (4) for its answer, out of which ONLY ONE option can be correct. Marking scheme: +4 for correct answer, 0 if not attempted and -1 in all other cases.
01. If a and b are two vectors such that 4a = , 1/2b = and
. 1a b = − , find the angle between a and b
1) 120º 2) 60º 3) 90º 4) 30º
02. Cross product of vectors obeys
1) commutative law 2) associative law
3) distributive law 4) all the above
03. Find a unit vector perpendicular to each one of the vectors
ˆ ˆ ˆ4 3a i j k= − + and ˆ ˆ ˆ3 2b i j k= + −
1) ˆ ˆ ˆ5 13 11
215
i j k− + + 2)
ˆ ˆ ˆ5 13 11
310
i j k− + +
3) ˆ ˆ ˆ5 13 11
315
i j k− + + 4) 0
04. Distributive law is obeyed by
1) scalar product 2) vector product
3) both 1 and 2 are correct 4) both 1 and 2 are incorrect
05. Let ,a b and c be three vectors such that 0.a b c+ + = If
3, 4 5,a b and c= = = the value of . . .a b b c c a+ + is
1) 20 2) – 25 3) 30 4) 15
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06. For a vector a is three dimensional space, the value of the
expression 2 2 2
i a j a k a + + is
1) a2 2) 3a2 3) 2a2 4) 0
07. The angle between ( ) ( )A B and B A is ( in radian )
1) 2
2) 3)
4
4) zero
08. If 2 3 6A i j k= + + and 3 6 2B i j k= − + then vector perpendicular to
both A and B has magnitude K times that of 6 2 3i j k+ − . Then K is
1) 1 2) 3 3) 7 4) 9
09. If 2 3 2 3A i j and B j k= + = + the component of B along A is
1) 6 2) 1
6 3)
6
13 4)
6
13
10. If ,A Band C are coplanar vectors, then
1) ( ). 0A B C = 2) ( ). 0A B C =
3) ( ). . 0A B C = 4) all the above are true
11. The angle between the vectors ( )i j k+ + and ( )i j k− − is
1) 1 8sin
3
− 2) 1 2cos
3
−
3) 1 8cos
3
− 4) 1 8sin
9
−
12. A Vector P points vertically downwards and another vector Q
points towards north then. The vector P Q points towards.
1) East 2) West
3) South 4) Vertically up
13. A 10 kg body is suspended by a rope is pulled by means of a
horizontal force to make 060 by rope to vertical. The horizontal
force is
1) 10kgwt 2) 30kgwt
3) 10 3kgwt 4) 30 3kgwt
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14. If ' 'P is in equilibrium then 1
2
T
T is
1) 3 2) 2 3) 1
3 4)
1
2
15. If ' 'O is at equilibrium then the value of the tension 1T and 2T are,
(20N is acting vertically downwards at O).
1) 20N, 30N 2) 20 3 ,20N N
3) 20 3 ,20 3N N 4) 10 ,30N N
16. A force 10N is resolved into the perpendicular components. If the
first component makes. 030 with the force, the magnitudes of the
components are
1) 5N, 5N 2) 5 2 ,5N N
3) 5 3 ,5N N 4) 10 ,10 3N N
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17. If ˆ ˆ ˆ2 3 4A i j k= − + , its components in YZ- plane and ZX- plane are
respectively
1) 13 and 5 2) 5 and 2 5
3) 2 5 and 13 4) 13 and 29
18. A car weighting 100 kg is on a slope that makes an angle 030 with
the horizontal. The component of car’s weight parallel to the slope
is ( )210g ms−=
1) 500N 2) 1000N 3) 15000N 4) 20000N
19. A man walks towards east with certain velocity. A car is travelling
along a road which is 30º west of north. While a bus is travelling in
another road which is 60º south of west. Find the angle between
velocity vector of man and car
1) 60º 2) 120º 3) 90º 4) 30º
20. A bird moves in such a way that it has a displacement of 12 m
towards east, 5 m towards north and 9 m vertically upwards. Find
the magnitude of its displacement
1) 5 2m 2) 5 10m 3) 5 5m 4) 5 m
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SECTION-II(21-25)
(Numerical Value Answer Type)
This section contains 5 questions. The answer to each question is a Numerical
values comprising of positive or negative decimal numbers (place value
ranging from Thousands Place to Hundredths Place). Eg: 1234.56, 123.45, -123.45, -1234.56, -0.12, 0.12 etc. Marking scheme: +4 for correct answer, 0 in all other cases.
21. If vectors P, Q and R have magnitudes 5, 12 and 13 units and
P Q R+ = , then the angle between Q and R is 1 4
cos13
N−
. Then
the value of N is
22. If 2A i j k= + − , 2 3B i j k= + + and 6 2 6C i j k= − − , then the
angle between ( )A B+ and C will be 018N , then the value N is
23. If 1a and 2a are two non collinear unit vectors and if 1 2 3a a+ =
, then the value of ( ) ( )1 2 1 2. 2a a a a− − is p/2. Then the value of p
is
24. The components of a vector along the x and y directions are (n+1)
and 1 respectively. If the coordinate system is rotated by an angle
60º then the components changes to n and 3. Then the value of
n is
25. A bird moves with velocity 120ms− in a direction making an angle
of 60º with the eastern line and 60º with vertical upward. The
velocity vector in rectangular form is + +ˆ ˆ ˆ10 10 2i j Nk . Then the
value of N is
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SECTION-I(26-45)
(Single Answer Type)
This section contains 20 multiple choice questions. Each question has 4 options (1), (2), (3) and (4) for its answer, out of which ONLY ONE option can be
correct. Marking scheme: +4 for correct answer, 0 if not attempted and -1 in all other cases.
26. In which of the following compounds resonance does not occurs
1) 2H O 2)
2SiO 3) 3SO 4) Both (1) and (2)
27. Resonance in molecules influences
1) Bond length 2) Bond strength
3) Bond polarity 4) All of these
28. The more stable lewis dot structure for CO molecule is
1) 2) 3) 4)
29. Covalent compounds are generally soluble in
1) Polar solvents 2) Non-polar solvents
3) Concentrated acids 4) All solvents
30. Which of the following lewis dot structure is not correct for nitrite
ion?
1) 2) 3) 4)
31. Covalency of Aluminium in ( )2
2 5AlCl H O
+
are respectively
1) 3 2) 6 3) 4 4) All
32. In 2N O molecule, shown by lewis dot structure
31 2 ..
: :..
N N O − the
formal charges of first, second and third atoms in sequence are
1) 1,0, 1+ − 2) 0, 1, 1+ − 3) 1,0, 1− + 4) 0, 1, 1− +
33. Maximum number of covalent bonds by which two atoms can be
bonded to each other
1) four 2) two
3) three 4) no fixed number
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34. Which one of the following molecules contains both ionic and
covalent bonds?
1) 2 2CH Cl 2)
2 4K SO 3) 2BeCl 4)
2SO
35. Coordination number of NaCl is
1) 6 2) 8 3) 4 4) 2
36. If Pauli’s exclusion principle is not known, the electronic
arrangement of Lithium atom is
1) 2 11 2s s 2) 1 21 2s s 3) 31s 4) 2 1 11 2 2s s p
37. 2 3,Mg Al+ + have identical_____________
1) Configuration 2) Atoms
3) Ions 4) Molecules
38. The pair of ions having same electronic configuration is __________
1) 3 3,Cr Fe+ + 2) 3 2,Fe Mn+ +
3) 3 3,Fe Co+ + 4) 3 3,Sc Cr+ +
39. Ionic compounds do not exhibit space isomerism because
1) They are solids
2) The ionic bond is non directional
3) They are electrolytes
4) They contain ions
40. Stability of ionic compounds is influenced by
1) Electronegativity 2) Lattice energy
3) Sublimation energy 4) Electron affinity
41. Among ,NaF RbF and CsF more ionic and strongly ionic are
1) ,RbF CsF 2) ,NaF NaF
3) ,CsF NaF 4) ,CsF CsF
42. How many unit cells are present in a cube shaped ideal crystal of
NaCl of mass 1 g? (Atomic masses : Na = 23, Cl = 35.5)
1) 211.7 10 unit cell 2) 212.57 10 unit cell
3) 215.14 10 unit cell 4) 211.28 10 unit cell
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43. AB is an ionic solid. The ionic radii of A+ and B− are respectively cr
and ar . Lattice energy of AB is proportional to
1) c
a
r
r 2) ( )c ar r+ 3) a
c
r
r 4)
1
c ar r+
44. Which of the following reaction involves the Liberation of energy?
1) ( ) ( )s gNa Na+⎯⎯→ 2) ( ) ( )2 2
g gCl Cl⎯⎯→
3) ( ) ( ) ( )g g sNa Cl NaCl+ −+ ⎯⎯→ 4) ( ) ( ) ( )s g g
NaCl Na Cl+ −⎯⎯→ +
45. The cation with high polarising power is
1) 2Mg + 2) 1K + 3) 1Cu+ 4) 3Al +
SECTION-II(46-50)
(Numerical Value Answer Type)
This section contains 5 questions. The answer to each question is a Numerical
values comprising of positive or negative decimal numbers (place value ranging from Thousands Place to Hundredths Place). Eg: 1234.56, 123.45, -
123.45, -1234.56, -0.12, 0.12 etc. Marking scheme: +4 for correct answer, 0 in all other cases.
46. How many electrons are delocalised in Pyridine?
47. A compound of vanadium possesses of magnetic moment of
1.73BM. The oxidation state of Vanadium in this compound is
48. Magnetic moment of xM + is 24 .BM The number of unpaired
electrons in xM + is
49. How many of the following compounds violate octet rule?
I) 5BrF II) 6SF III) 7IF
IV) 4XeOF V)
2ClF VI) 4PCl+
50. Total number (sum) of valence electrons present in 2
3CO −
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SECTION-I (51-70)
(Single Answer Type)
This section contains 20 multiple choice questions. Each question has 4 options (1), (2), (3) and (4) for its answer, out of which ONLY ONE option can be
correct. Marking scheme: +4 for correct answer, 0 if not attempted and -1 in all other cases.
51. sin47 sin25 sin61 sin11− + − =
1) cos7 2) sin7 3) 2cos7 4) 2sin7
52. sin 70 cos 40
cos70 sin 40
+
+ =
1) 3 2) 3 3) 1
3 4)
1
2
53. If sin sin ,cos cosa b+ = + = , then ( )sin + =
1) ab 2) a b+ 3) 2 2
2ab
a b− 4)
2 2
2ab
a b+
54. If cos cos ,sin sina b+ = + = and 2 − = , then cos3
cos
=
1) 2 2 2a b+ − 2)
2 2 3a b+ − 3) 2 23 a b− − 4)
2 2
4
a b+
55. In ABC , sin 2 sin 2 sin 2
cos cos cos 1
A B C
A B C
+ +
+ + − =
1) 4cos cos cos2 2 2
A B C 2) 4sin sin sin
2 2 2
A B C
3) 8cos cos cos2 2 2
A B C 4) 1 4sin sin sin
2 2 2
A B C+
56. If ( )1
sin sin 25
B A B= + , then ( )tan
tan
A B
A
+ is equal to
1) 5
3 2)
2
3 3)
3
2 4)
3
5
57. If A B C+ = , then 2 2 2cos cos cos 2cos cos cosA B C A B C+ + − =
1) 1 2) 2 3) 0 4) 3
58. 2 2sin 14 cos 16 sin14 cos16 + − =
1) 1
4 2)
3
4 3)
1
2 4)
3
2
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59. If ( ) ( )cos 60 ,cos ,cos 60− + are in H.P., then cos =
1) 2
3 2)
2
3 3)
3
2 4)
3
2
60. 2 2sin 8 sin 7
sin8 cos8 sin 7 cos7
−
− =
1) 1
2 3+ 2)
1
2 3− 3)
1
3 2− 4) 2 3+
61. If 90 180 , then 1 cos 2 1 cos 2
1 cos 2 1 cos 2
+ + −
+ − − =
1) tan4
+
2) tan
4
−
3) cot 4) tan
62. If
2
2
tan 194
cosec cos cot 4 sec2 2
tan 14
− − = +
− +
, then =
1) 2) 2 3) 22
− 4) 4
63. The value of 2
2
1 tan 15
1 tan 15
−
+ is equal to
1) 1 2) 3 3) 3
2 4) 2
64. If tan , tan2 2
are the roots of
28 26 15 0x x− + = then ( )cos + =
1) 627
725 2)
547
715 3)
547
715
− 4)
627
725
−
65. If 1
2cos 20xx
+ = then the value of 3
3
1x
x+ =
1) 1
4 2)
1
2 3) 1 4)
1
8
66. If 1 cos
tansin
BA
B
−= , then tan2 tanA B− =
1) 0 2) 1 3) 1
2 4)
1
4
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67. If 2 tan tan2 2
= , then
3 5cos
5 3cos
+
+ =
1) cos 2) sin 3) tan 4) cot
68. If 1
tan7
= , is acute, then cos2 is equal to
1) 12
25 2)
24
25 3)
48
25 4)
24
25−
69. If sec cos 1− = , then 2tan
2
=
1) 5 2+ 2) 5 2− 3) 2 5− 4) 0
70. If ( )sin a+ = and ( )sin b+ = , then ( ) ( )cos2 4 cosab− − − =
1) 2 21 a b− − 2)
2 21 2 2a b− −
3) 2 22 a b+ − 4)
2 22 a b− −
SECTION-II(71-75)
(Numerical Value Answer Type)
This section contains 5 questions. The answer to each question is a Numerical
values comprising of positive or negative decimal numbers (place value ranging from Thousands Place to Hundredths Place). Eg: 1234.56, 123.45, -
123.45, -1234.56, -0.12, 0.12 etc. Marking scheme: +4 for correct answer, 0 in all other cases.
71. 2 2 2 2 2 2sin 12 sin 21 sin 39 sin 48 sin 9 sin 18+ + + − − is equal to ______
72. If ( ) ( )2 2 2cos cos sin sin .sin
2k
− − + − =
, then
2 24k + is equal to
73. If 2 4 8 14 1
cos cos cos cos15 15 15 15 k
= , then k is equal to ______
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74. If 2 2 cos 1 674a a x− + = and tan 7
2
x =
, then the integral value of a is
_____
75. If 1 2 3 4 5 6
14cos36 cot 7
2n n n n n n
+ = + + + + + then the value of
6
1
i
i
n=
is equal to
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