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Classroom/Office Address-C-225, Ganesh Marg, C-Block, Mahesh Nagar (200 Meter from Riddhi Siddhi Tiraha), Gopal Pura Mode (between Gandhi Nagar Railway Station and Durga Pura Railway Station), Jaipur, Rajasthan, 9660807149, 7014320833, 8078607812
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Previous Years Exam Papers of Rajasthan State
(CIVIL ENGINEERING)
CHAPTER-WISE, DETAILED & ERROR FREE SOLUTIONS
For
B. CHAND PUBLICATION
RAJASTHAN JUNIOR ENGINEER
EXAMINATION 2020
PWD, PHED, WRD, RSAMB, DLB, Panchayati Raj and others
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B. Chand Publication
Engineers Pride- Most advanced and Honest Institute for UPSC IAS, UPSC IES,GATE,GATE,SSC-JE, RRB-JE, State(AEn/JEn),PSUs etc.-By IITian (B.Tech/ IIT Guwahati),Ex. Assistant Commandant, IES(Indian Railways)-B.CHAND, Class Room/Office Address-C-225, Ganesh Marg, C-Block, Mahesh Nagar (200 Meter from Riddhi Siddhi Tiraha), Gopal Pura Mode (between Gandhi Nagar Railway Station and Durga Pura Railway Station), Jaipur, Rajasthan, 9660807149, 7014320833, 8078607812, [email protected] , www.engineerspride.org , www.engineeringpride.com -
1st Edition: March 2020
2nd Edition: April 2020
MRP: 500/- Only
Disclaimer - all care has been taken while designing this book but still there might be some
error and for more clarity students may refer to video solutions of this book available on
Engineers Pride website and App.
RAJASTHAN JUNIOR ENGINEER EXAMINATION 2020
Copyright © 2020, by B. CHAND Publication. All rights are reserved. No part of this publication may be
reproduced, stored in or introduced into a retrieval system, or transmitted in any form or by any
means (electronic, mechanical, photo-copying, recording or otherwise), without the prior written
permission of the above-mentioned publisher of this book
mailto:[email protected]://www.engineerspride.org/http://www.engineeringpride.com/
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Content (Paper-wise)
S.No. Name of Examination (Chronological Order) No. of MCQs
1.0 ACF 2011 200
2.0 Lecturer 2011 100
3.0 VP-ITI 2012 100
4.0 RPSC-AE 2013 100
5.0 WRD-JE(Degree) 2013 80+40
6.0 WRD-JE(Diploma) 2013 80+40
7.0 GWD-AE 2014 100
8.0 Lecturer 2014 100
9.0 WRD-JE(Degree) 2016 80+40
10.0 WRD-JE(Degree) 2016/TSP 80+40
11.0 WRD-JE(Diploma)2016 80+40
12.0 WRD-JE(Diploma)2016/TSP 80+40
13.0 PHED-JE(Degree) 2016 60+40
14.0 PHED-JE(Diploma) 2016 60+40
15.0 RPSC-AE 2018 100
Total 1720
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Index | Subject-wise
S. No. Subject Page No.
1. Strength of Materials (SOM) 5
2. Theory of Structures (TOS) 35
3. Building Materials & Concrete Technology 45
4. Construction Technology 80
5. Reinforced Cement Concrete & Prestresses Concrete (RCC &
PSC)
87
6. Design of Steel Structures (DSS) 112
7. Project Management (PM) 128
8. Tendering System (TS) 134
9. Geotechnical Engineering (GT) 136
10. Environmental Engineering (EE) 172
11. Fluid Mechanics (FM) 197
12. Hydraulic Machines (HM) 219
13. Open Channel Flow (OCF) 222
14. Survey Technology (ST) 225
15. Highway Engineering (HE) 252
16. Hydrology (HDD) 267
17. Irrigation Engineering (IRR) 279
18. Geology 292
19. Bridges 294
20. CAD 303
21. Rajasthan History, Art and Culture 310
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Classroom/Office Address-C-225, Ganesh Marg, C-Block, Mahesh Nagar (200 Meter from Riddhi Siddhi Tiraha), Gopal Pura Mode (between Gandhi Nagar Railway Station and Durga Pura Railway Station), Jaipur, Rajasthan, 9660807149, 7014320833, 8078607812
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22. Rajasthan Geography 322
23. Rajasthan Economy 340
24. Rajasthan Polity 460
25. Other minor topics of Rajasthan GK 380
26. India GK 385
27. Current Affairs 396
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aka Mechanics of Solids (MOS) or Solid Mechanics
S. NO. CHAPTER Page No.
1 CH 01 Simple stress, simple strain,
properties or materials and Elastic
Constants
7
2 SFD and BMD
3 CG and MOI
4 Deflection
5 Transformation of Stresses
6 Bending Stress
7 Shear Stress
8 Torsion
9 Springs
10 Columns
11 Pressure vessels
12 Combined stress
Strength of Materials (SOM)
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CH 01 Simple stress, simple strain,
properties or materials and Elastic
Constants
1. If a material has identical elastic properties in all directions it is said to be....
(1) Homogenous
(2) Isotropic
(3) Elastic
(4) Orthotropic
ACF-(Rajasthan)-2011, Lecturer
Rajasthan l Diploma l collage-2011 &
PHED-JE 2016 (Diploma)
Sol. (2) A property of a material is the response of a material to external stimuli.
Consider any point inside the bulk of a material. At that point, we apply a stimulus (or a load) in a direction. We get a certain response and that is what we call property of the material in that direction.
However, if we apply similar stimuli at all possible directions at that one point and get different results every time, we call that material anisotropic.
Now, if we get similar results by applying similar stimuli in all possible directions at that point, we call the material Isotropic. It is an idealized concept and no such material exists.
If we get similar results by applying similar stimuli in only 3 mutually perpendicular directions at that point alone, we call the material orthotropic.
It is important to mention that we decide anisotropy/isotropy at a certain point inside the bulk of the material only. At some other point, same stimuli may produce different results.
So, a material can be orthotropic at some point, anisotropic at another & isotropic at other. It is not a bulk concept.
But this phenomenon will make our calculations almost impossible. So, we employ the concept of homogeneity while studying our systems. A material is called homogeneous if it exhibits similar results (properties) in a single direction only but at every point throughout the bulk of the material.
The material easiest to analyse is the one which is both isotropic & homogeneous because its each and every point behaves similarly to external stimuli from all directions. On the other hand, anisotropic material calculations require advanced matrix calculations and Finite Element analysis-based software like Ansys, Abacus etc.
2. If a composite bar of steel and copper is heated, the copper bar will be under.......
(1) Tension
(2) Compression
(3) Shear
(4) Torsion
ACF-(Rajasthan)-2011 & Lecturer Rajasthan l Diploma l collage-2011
Sol. (2) A composite bar may be defined as a bar made up of two or more materials joined together in such a manner that both
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are extended or contracted as a single unit.
Since coefficient of thermal expansion of copper is more than that of steel hence copper bar will expend more but as both the bars are connected rigidly with each other so their final length will be same. This results compression in copper bar and tension in steel bar.
Thermal expansion is the tendency of matter to change its shape, area, and volume in response to a change in temperature.
Material
Fractional expansion
per degree C x10^-6
Fractional expansion
per degree F x10^-6
Glass, ordinary
9 5
Glass, Pyrex 4 2.2
Quartz, fused
0.59 0.33
Aluminium 24 13
Brass 19 11
Copper 17 9.4
Iron 12 6.7
Steel 13 7.2
Platinum 9 5
Tungsten 4.3 2.4
Gold 14 7.8
Silver 18 10
3. Poisson's ratio is involving.......
(1) Elastic Modulli
(2) Stresses
(3) Strains
(4) None of these
ACF-(Rajasthan)-2011
Sol. (3) Poisson's ratio is given by
Lateral strain
Longitudinal strain
= −
Hence, strains are involved in
Poisson's ratio
4. The necessary condition for equilibrium of body is
(1) ∑H =0
(2) ∑V =0
(3) ∑M =0
(4) All of the above
ACF-(Rajasthan)-2011
Sol. (4)
2D
3D
https://en.wikipedia.org/wiki/Shapehttps://en.wikipedia.org/wiki/Areahttps://en.wikipedia.org/wiki/Volume
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5. Every material obeys the Hook’s law within its
(1) Elastic limit
(2) Plastic limit
(3) Limit of proportionality
(4) None of the above
ACF-(Rajasthan)-2011, Lecturer Rajasthan l Diploma l collage-2011 & Lecturer l Rajasthan l Diploma l collage-2014
Sol. (3)
Every material obeys the Hooke's Law
within limit of proportionality.
Up to limit of proportionality, axial stress is
propositional to longitudinal strain
according to Hooke's law.
Mathematically,
σ ∝ Longitudinal
σ= E Longitudinal
where, E= Young's modulus
6. For an isotropic, homogeneous and elastic material obeying Hooke's law, number of independent elastic constant is
(1) 2 (2) 3
(3) 9 (4) 1
Lecturer l Rajasthan l Diploma l collage-2011
Sol. (1) For an isotropic, homogeneous and
elastic material obeying Hooke's law, the
Number of elastic constants is 2.
Number of independent elastic constants
in case of orthotropic material are 9.
Number of independent constants for in
anisotropic material are 21.
7. The property by virtue of which a material deformed under the load is enabling to return to its original dimension when load is removed.
(1) Plasticity (2) Ductility
(3) Elasticity (4) Malleability
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Lecturer l Rajasthan l Diploma l collage-2011 and VP-ITI-(Rajasthan)-2012
Sol. (3) The property by virtue of which a
material deformed under the load is
enabling to return to its original dimension
when load is removed is called Elasticity.
Malleability is the ability of materials to deform easily under compressive stress. This can be often characterized as materials ability to form thin sheets by hammering or rolling.
On the other hand, Ductility is the ability of materials to deform easily under tensile stress. This can be often characterized as materials ability to be drawn into wires. It is also used to describe the extent to which the material can be plastically deformed.
In case you do not know the difference between compressive and tensile stress, compressive stress is generated by the force acting towards the centre, while the tensile stress is generated by the force acting away from the material. In layman's term, compressive force makes the material smaller and the tensile force stretches the material.
8. Modulus of rigidity is defined as the ratio of
(1) Longitudinal stress to longitudinal strain
(2) shear stress to shear strain
(3) Stress to strain
(4) Stress to volumetric strain
RPSC-AEN-2013
Sol. (2) According Hooke's low, shear stress
is proportional to shear strain up to
proportional limit.
mathematically,
shear stress (𝜏) ∝ shear strain (𝛾)
G =
G=
where, G = Modulus of rigidity or shear
modulus.
Note: Line equation,
y=mx
where, m= slope of the line
Similarly, G =
G= slope of shear stress– shear strain curve
up to propositional limit.
9. The relation between modulus of elasticity E, bulk modulus K, Poisson's ratio 1/m is.
(1)E = 3K (1 - 2/m)
(2)E = 2K (1 - 3/m)
(3)K = 3E (1 - 2/m)
(4)K = 2E (1 - 3/m)
RPSC-AEN-2013
Sol. (1) Take 𝝁 =𝟏
𝒎
• The relationship between Young’s modulus (E), rigidity modulus (G) and Poisson’s ratio (µ) is expressed as:
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• The relationship between Young’s modulus (E), bulk modulus (K) and Poisson’s ratio (µ) is expressed as:
• Young’s modulus can be expressed in terms of bulk modulus (K) and rigidity modulus (G) as:
• Poisson’s ratio can be expressed in terms of bulk modulus (K) and rigidity modulus (G) as:
10. The maximum value of Poisson's ratio for an elastic material is
(1) 0.25 (2) 0.5
(3) 0.75 (4) 0.1
Lecturer l Rajasthan l Diploma l collage-2014
Sol. (2) Typical Poisson's Ratios for some common materials are indicated below.
Material Poisson's Ratio
- μ -
Upper limit 0.5
Aluminium 0.334
Aluminium, 6061-T6 0.35
Material Poisson's Ratio
- μ -
Aluminium, 2024-T4 0.32
Beryllium Copper 0.285
Brass, 70-30 0.331
Brass, cast 0.357
Bronze 0.34
Clay 0.41
Concrete 0.1 - 0.2
Copper 0.355
Cork 0
Glass, Soda 0.22
Glass, Float 0.2 - 0.27
Granite 0.2 - 0.3
Ice 0.33
Inconel 0.27 - 0.38
Iron, Cast - gray 0.211
Iron, Cast 0.22 - 0.30
Iron, Ductile 0.26 - 0.31
Iron, Malleable 0.271
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Material Poisson's Ratio
- μ -
Lead 0.431
Limestone 0.2 - 0.3
Magnesium 0.35
Magnesium Alloy 0.281
Marble 0.2 - 0.3
Molybdenum 0.307
Monel metal 0.315
Nickel Silver 0.322
Nickel Steel 0.291
Polystyrene 0.34
Phosphor Bronze 0.359
Rubber 0.48 - ~0.5
Sand 0.29
Sandy loam 0.31
Sandy clay 0.37
Stainless Steel 18-8 0.305
Steel, cast 0.265
Steel, Cold-rolled 0.287
Material Poisson's Ratio
- μ -
Steel, high carbon 0.295
Steel, mild 0.303
Titanium (99.0 Ti) 0.32
Wrought iron 0.278
Z-nickel 0.36
Zinc 0.331
Note
I. In general, range of poisson’s ratio is
-1 to 0.5 but for most of the civil
engineering materials this range is 0.0
to 0.5
II. Polymer foam has got value of
poisson’s ratio as -1
11. A metal bar of length 100 mm is inserted between two rigid supports and its temperature is increased by 100 C. If the coefficient of thermal expansion is 8 x 10-6 per 0C and the young's modulus is 1.5 x 105 MPa, the stress in the bar is
(1) Zero (2) 12 MPa
(3) 24 MPa (4)2400 MPa
Lecturer l Rajasthan l Diploma l collage-2014
Sol. (2) Given: Length (𝑙) = 100 mm
t (change in temperature) = 10°C
∝ = 8 × 10-6 per °C
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E = 1.5 × 105 MPa
we know that,
stress in the bar (𝜎) = ∝ tE
= 8 ×10-6 × 10 × 1.5 × 105
= 12 MPa
Note that strain in this bar will be
zero as it is inserted between rigid
supports.
12. The stress below which a material does not fractures under large number of reversals of stress is called: -
(1) Creep
(2) Ultimate strength
(3) Endurance limit
(4) Residual stress
[RPSC-AEN-GWD-2014]
Sol. (3)
The stress below which a material
does not fractures under large
number of reversals of stress is called
endurance limit. Endurance limit is
also known as Fatigue limit.
Creep is a property by virtue of
which a material undergoes
additional deformation (over and
above elastic deformation) with
passes of time under sustained
loading within elastic limit.
13. The greatest amount of strain energy per unit volume that a material can absorb up to its elastic limit is: -
(1) Toughness Index
(2) Proof resilience
(3) Resilience
(4) Potential energy
VP-ITI-(Rajasthan)-2012
Sol. (*)
I. Strain energy absorbed by the
material up to elastic limit is called
resilience.
II. Strain energy absorbed per unit
volume by the material up to elastic
limit is called modulus of
resilience.
III. Maximum strain energy that can be
absorbed by the spring up to the
elastic limit without creating a
permanent distortion is called
proof resilience.
Note that for this question no answer is
correct but still proof resilience (2) can
be marked as nearest correct
Stress
Endurance
limit For ferrous metals
Number of cycles of loading which
cause fatigue failure
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14. The value of Poisson's ration of the materials lie between: -
(1) 1 and 2 (2) 0 and 1/2
(3) 0 and 1 (4) 2 and 3
VP-ITI-(Rajasthan)-2012
Sol. (2)
For more information kindly refer to the solution of Q.10
15. Simple stress means
(1) Direct tensile stress
(2) Direct compressive stress
(3) Shear stress
(4) Only one type of stress
Lecturer l Rajasthan l Diploma l collage-2014
Sol. (4) Simple stress means only one type
of stress. Note that for this question all
options are correct but option (4) is best.
16. The relationship between modulus
of elasticity (E) and Bulk Modulus (K)
and Poisson’s ratio m is
(1) E=3k(1-2m) (2) E=3k(1+2m)
(3) E=3k(1-m) (4) E=3k(1+m)
PHED-JE 2016 (Diploma)
Sol. (1) E=3k(1-2m), for more information
refer the solution of Q.9 and don’t get
confused with the notation of poission’s
ratio.
17. A rubber bar of length 1.5m and
200mm diameter is stretched along
its length by 20mm with a force of 15
kN. As a result, its diameter is
reduced by 2mm. The poisons' ratio
of the bar material will be:
(1) 5 (2) 1
(3) 0.75 (4) 0.5
WRD-JE-DIPLOMA-TSP-2016
Sol. (3)
Poison’s ratio,laterral strain
longitudinal strain = −
( )2 / 20020 /1500
−= −
0.75 =
18. A structure is subjected to different
sets of loads, and then sum of
deflections under each set of loads
acting separately is equal to total
deflection of the structure due to
different sets loads provided loads
are within:
(1) Elastic limits including buckling
(2) Proportional limits without
buckling
(3) Elastic limit
(4) Limit State
WRD-JE-DIPLOMA-TSP-2016
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Sol. (2) The statement given in this
question is talking about principle of
superposition. This principle is applicable
when Hooke’s law is valid, and
deformations are very small. Hooke’s law is
valid within proportional limit hence
answer is (2)
19. The phenomenon of decreased
resistance of material due to
reversal of stress is called-
(1) Creep (2) Fatigue
(3) Resilience (4) Plasticity
AE-RAJASTHAN-2018
Sol. (2) In materials science, fatigue is the
weakening of a material caused by cyclic
loading(reversal of stress) that results in
progressive and localized structural
damage and the growth of cracks.
20. What shall be the ratio of modulus
of elasticity to shear modulus of a
material having poison's ratio of 0.5
(1) 3 (2) 1.5
(3) 1 (4) 0.5
WRD-JE-DIPLOMA-2016
Sol. (1)
G=𝐸
2(1+𝜇)
𝐸
𝐺= 2(1 + 𝜇)
= 2(1 + .5)
= 3
https://en.wikipedia.org/wiki/Materials_science