circular motion- sl- m

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  • 8/18/2019 Circular Motion- SL- M

    1/4

    1. (a) (i) from satellite towards centre of Earth;

    (ii) tangent to circle at satellite in correct direction;

    (no labels, [1 max] ) 2

     

    (b) direction of motion is changing / force acts on satellite;

    and changing direction means changing velocity / any further detail; 2

     

    (c) work done is product of force and distance moved in direction of force;

    force is always normal to direction of motion;

    hence no work done;

    (accept argument based on changes in E k  and E  p) 3

    [7]

     

    2. [1]

     

    3. (a)  Look for an answer on the following lines!

    the direction of the car is changing;

    hence the velocity of the car is changing;

    or 

    since the direction of the car is changing;

    a force must be acting on it, hence it is accelerating; 2 ma"

     

    (b) (i) arrow pointing vertically downwards; #

    (ii) weight;

     Do not penalize the candidate if they state “gravity”.

    normal reaction; 2

    Do not penalize the candidate if they state “push of thetrack on the marble”.

     

    (iii) loss in PE = 0.05 $ #% $ (%!& ' %!3);

    gain in *E 2#

    mv 2;

    to give v  = 3.0 m s '#

    ;or 

    use of  v = gh2

     to give v  = 4.0 m s '#

     at point B;

    and ten use of v 2  ' u

    2 = 2gh !it v  = 4.0 m s

     '# and h = 0.35 m;

    to get u = 3.0 m s '#

    ; 3 ma"

    Do not penalize the candidate if g = 9.8 m s –

     is used.

      1

  • 8/18/2019 Circular Motion- SL- M

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    (iv) recogni#e tat resultant force = r 

    mv2

    ;

    = #+!%

    )%!,%!%(   ×

     = 2.$ %;

    % = r 

    mv 2

      ' mg ;= 2.$ ' %! 2!# -; .

    [12]

     

    4. &[1]

     

    5. (a)

    e l e c t r o nc h a r g e e

     p r o t o nc h a r g e e

    /

    0

    1 ' 2

    (i) correct ';

    (ii) correct ;

     

    (*) F  = k   2

    2

     !

    e

     or  F  =2

    2

    .  !

    e

    oπε  ;

     Accept if answer is seen in c!.

      " 

  • 8/18/2019 Circular Motion- SL- M

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    (c) F  = k    !

    mv

     !

    e  2

    2

    2

    =;

    to give #  =2

    2

    mv

    ke

    ;

    correct su*stitution #  =#223#

    3&2

    #%)2!2(#%#!,

    #%)3!#(#%,

    ×××

    ×××

     to give #  = 5.2 $ #% '##

     m; 3

     

    (d)  Answers will $e open%ended $ut essentially look for a description of either emission or a$sorption spectra eg !en elements in teir gaseous pase (state) are e"cited te+ emit ligt ,discarge tu*es emit ligt;!ic as a series of !ell defined !avelengts;te !avelengts are caracteristic of te element;te e"istence of tese caracteristic !avelengts support te idea of atomic energ+ levels; 3 ma"

    [9]

     

    6. (a) for circular motion- force reuired to!ards centre of circle , centripetal force;tis provided as a result of e"tension of te spring; 2

    Do not give credit where candidate implies that the spring is pulled outwards $y a force.

     

    (*) force produced *+ spring = .5 $ #& 2+ -;

    use of F  = r 

    mv2

    ;

    2/ = 23!%

    )%+!%(   2v×

    ;

    v  = .// m s '#

    ; 4[6]

     

    7. (a) (i) spacing of te dots is increasing , &'(() ;

    (ii) tree furter dots;spacing increases *+ t!o suares *et!een an+ t!o dots; 2

    (iii) distance = 3/.$ m;

     

    (*) (i) travels (2.2 $ . ) &!& between drops;

    speed    

       =

    &%!%

    &!&

    m s '#

    ; 2

      *

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    (ii) in eac 0.10s speed increases *+ &%!%

    )..!%(   ×

     = 2.0 m s '#

    ;

    acceleration =   

       =

    &%!%

    %!2

    2.5 m s '2

    ; 2

    or 

    in (2 $ %!&%) seconds, distance traveled is 3!2 m;

    a =22 )!#(

    2!32)(2   ×=

     s

     = 2.5 m s '2

    ; Allow a different choice of appropriate time interval to givecorrect answer.

    [8]

      +