chemistry 11 final examination review -...
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Chemistry 11 Final Examination Review - Answers
Part A - True or False. Indicate whether each of the following statements is true or false. Correct the false statements.
T 1. Dalton's atomic theory includes a statement that says atoms of the same element are identical. F 2. Dalton's theory states that atoms have variable masses.
Dalton’s atomic theory states that atoms of the same element have the same mass and that atoms of different elements have different masses.
F 3. J.J. Thomson is credited with the discovery of protons. J.J. Thomson is credited with the discovery of electrons.
F 4. The mass of an electron is equal to the mass of a proton. The mass of an electron is less than the mass of a proton. T 5. The mass of a proton is approximately equal to the mass of a neutron. T 6. The atomic number represents the number of protons in a nucleus. T 7. The proton has a mass of approximately 1 u. F 8. The difference in mass of isotopes of the same element is due to the different number of protons in the nucleus.
The difference in mass of isotopes of the same element is due to the different number of neutrons in the nucleus.
T 9. The isotope carbon-12 is used as the relative mass standard for the atomic mass scale. F 10. The mass of the most common isotope of each element is listed on the periodic table.
The average mass of the naturally occurring isotopes of each element is listed on the periodic table.
Part B - Multiple Choice
D 1. A(n) __ is used to represent a compound. a) symbol b) equation c) subscript d) formula A 2. ___ atoms or groups of atoms are called ions. a) charged b) diatomic c) neutral d) monatomic A 3. For the formula of a compound to be correct, the algebraic addition of the charges on the atoms or ions in the compound must add up to __. a) zero b) one c) two d) four D 4. Potassium bromide is an example of a(n) __ compound. a) molecular b) organic c) polyatomic d) ionic B 5. The only common polyatomic ion that has a positive charge is the __ ion. a) phosphate b) ammonium c) sulfate d) nitrate A 6. In the formula H2SO4, the number 4 would be called a(n) __. a) subscript b) oxidation number c) coefficient d) charge B 7. Which subatomic particle contributes the least to the mass of an atom? a) nucleon b) electron c) proton d) neutron
Chemistry 11 – Final Examination Review – Answers – Page 1 of 27
D 8. In the free, or uncombined, state the number of protons in the nucleus of an element must equal the __.
a) mass number c) mass number - atomic number b) number of neutrons in the nucleus d) number of electrons present
C 9. Which of the following ideas of the Bohr model is not retained in the modern theory of atomic structure?
a) Electrons can absorb or emit energy only in whole numbers of photons. b) Atoms have a central positively charged nucleus. c) Electrons move around the nucleus as planets orbit the sun. d) Most of the volume of an atom is empty space.
B 10. Which of the following orbitals is spherical in shape? a) 3p b) 2s c) 4d d) 5f B 11. The third energy level of an atom may have __ electrons. a) 2 b) 18 c) 8 d) 32 C 12. How many sublevels are possible at the fourth energy level? a) 2 b) 3 c) 4 d) 18 A 13. Lustrous, malleable, ductile elements that are good conductors of electricity and heat are classified as __.
a) metals b) nonmetals c) metalloids d) noble gases C 14. The electron configuration of a certain element ends with 3p5. Which of the following
describes its position in the periodic table? a) period 5, group 13 b) period 3, group 15 c) period 3, group 17 d) period 5, group 15 B 15. Which of the following is an example of a metalloid?
a) iodine b) boron c) bromine d) indium B 16. The periodicity of the elements is basically a function of their __. a) nuclear stability b) atomic numbers c) mass numbers d) none of these D 17. An element with seven electrons in the outer level would be a __.
a) metal b) metalloid c) noble gas d) nonmetal A 18. As the atomic number in a period increases, the degree of nonmetallic character __.
a) increases c) increases then decreases b) decreases d) remains the same
B 19. Elements in a group have similar chemical properties because of their similar __. a) nuclear configurations c) mass numbers
b) outer electron configurations d) names D 20. The period number in the periodic table designates the __ for the row.
a) total nuclear charge c) maximum number of outer electrons b) maximum number of nucleons d) highest energy level
B 21. The radii of the atoms become smaller from sodium to chlorine across period 3. This is primarily a result of __.
a) the shielding effect c) the increased number of electrons b) increased nuclear charge d) decreased metallic character
D 22. Which of the following would correctly characterize a nonmetal? a) low first ionization energy, low electron affinity b) high first ionization energy, low electron affinity c) low first ionization energy, high electron affinity d) high first ionization energy, high electron affinity
Chemistry 11 – Final Examination Review – Answers – Page 2 of 27
D 23. Compared to the stability of the original atom, the stability of its ion that resembles a noble gas configuration would be __.
a) identical b) sometimes less c) less d) greater B 24. Which of the following does NOT affect the ionization energy of an electron?
a) the distance of the electron from the nucleus c) the number of energy levels in the atom b) the number of neutrons in the nucleus d) the charge on the nucleus
A 25. For each subsequent electron removed from an atom the ionization energy required __. a) increases b) decreases c) remains the same d) no pattern
C 26. The formation of bonds between atoms depends on __. a) the electron configurations of the atoms involved b) the attraction the atoms have for electrons
c) both of the preceding factors d) neither of the preceding factors
D 27. The particle that results when two or more atoms form covalent bonds is a __. a) single charged atom b) molecule c) polyatomic ion d) b or c
A 28. Compounds that have low melting points, are brittle, and do not conduct electricity are probably __. a) covalent c) ionic b) metallic d) compounds of polyatomic ions
A 29. The most active __ have the highest electronegativities. a) nonmetals b) metalloids c) metals d) noble gases D 30. __ compounds have high melting points, conduct electricity in the molten phase, and tend to be
soluble in water. a) hydrogen b) metallic c) covalent d) ionic A 31. The element in the following group that has the lowest electronegativity is __. a) potassium b) arsenic c) bromine d) chromium D 32. If there are only two electron pairs in the outer energy level of an atom in a molecule, they will be
found __. a) at 90º to one another c) at 120º to one another b) on the same side of the nucleus d) on opposite side of the nucleus
B 33. The __ molecule has two bonding pairs and two unshared pairs of electrons. a) CH4 b) H2O c) NH3 d) HF
D 34. A certain atom contains 34 protons, 34 electrons, and 45 neutrons. This atom has a mass number of __. a) 34 b) 45 c) 68 d) 79
C 35. An example of a compound is a) oxygen b) mercury c) salt d) diamond
A 36. Carbon is classed as an element rather than as a compound because it a) cannot be chemically decomposed into two or more substances b) has been known for many centuries
c) is formed when wood is heated out of contact with air d) combines with oxygen to form a gas
A 37. The positively charged particles in the nucleus of an atom are called a) protons b) neutrons c) electrons d) ions
C 38. The charged particles that are found outside the nucleus of an atom are called a) protons b) ions c) electrons d) mesons
Chemistry 11 – Final Examination Review – Answers – Page 3 of 27
D 39. A nonmetallic atom generally becomes a negative ion by a) losing protons b) losing electrons c) gaining protons d) gaining electrons
A 40. Which of the following subatomic particles has the smallest mass? a) electron b) neutron c) proton d) nucleus A 41. The nuclear atom was first postulated by a) Rutherford b) Bohr c) Dalton d) Thompson B 42. Which of the following symbols represents an atom that contains the largest number of neutrons?
a) 235 92U b) 239
92U c) 239 93Np d) 239
94Pu
C 43. The nuclide symbol 16 8O represents an oxygen atom with a) a mass of 8 u c) a mass of 16 u b) an atomic number of 16 d) 16 neutrons
C 44. If Z represents the atomic number of an element and A represents the mass number, then the number of neutrons in one atom is
a) A b) A + Z c) A - Z d) Z - A D 45. Which of the following statements about the elemental species 24
11X and 2512Z is correct?
a) They are isotopes of the same element. b) They are nonmetals. c) They are members of the same chemical family. d) They have the same number of neutrons per atom.
B 46. An element X has a mass number of 32 and an atomic number of 16. The most common ion of element X is represented by a) X+ b) X2- c) X- d) X2+
Part C - Short Answer 1. What is the maximum number of electrons that may occupy one orbital? two 2. The Lewis electron dot diagram is used to represent only which electrons in the atom? Valence electrons 3. What is the diagonal rule used to predict? The order in which orbitals are filled 4. How many sublevels are possible at the third energy level? three 5. How many orbitals are there in the f sublevel? seven 6. What is the maximum number of electrons that can occupy a d sublevel? ten 7. Which sublevel may contain a maximum of three pairs of electrons? ‘p’ sublevel
Chemistry 11 – Final Examination Review – Answers – Page 4 of 27
8. What must be true about the spins of two electrons occupying the same orbital? They must have opposite spin 9. Write the electron configuration for each of the following elements:
a) lithium 1s22s1
b) radium 1s22s22p63s23p64s23d104p65s24d105p66s24f145d106p67s2
c) sodium 1s22s22p63s1
d) mercury 1s22s22p63s23p64s23d104p65s24d105p66s24f145d10
10. Draw the energy level diagram for each of the following elements: a) tin
6s ↑ ↑ 5p ↑↓ ↑↓ ↑↓ ↑↓ ↑↓
↑↓ 4d 5s ↑↓ ↑↓ ↑↓ 4p ↑↓ ↑↓ ↑↓ ↑↓ ↑↓
↑↓ 3d 4s ↑↓ ↑↓ ↑↓
↑↓ 3p 3s ↑↓ ↑↓ ↑↓
↑↓ 2p 2s
↑↓ 1s
Chemistry 11 – Final Examination Review – Answers – Page 5 of 27
10. Draw the energy level diagram for each of the following elements: b) krypton
5s ↑↓ ↑↓ ↑↓ 4p ↑↓ ↑↓ ↑↓ ↑↓ ↑↓
↑↓ 3d 4s ↑↓ ↑↓ ↑↓
↑↓ 3p 3s ↑↓ ↑↓ ↑↓
↑↓ 2p 2s
↑↓ 1s
c) gold
6p ↑↓ ↑↓ ↑↓ ↑↓ ↑ 5d ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ ↑↓
↑↓ 4f 6s ↑↓ ↑↓ ↑↓ 5p ↑↓ ↑↓ ↑↓ ↑↓ ↑↓
↑↓ 4d 5s ↑↓ ↑↓ ↑↓ 4p ↑↓ ↑↓ ↑↓ ↑↓ ↑↓
↑↓ 3d 4s ↑↓ ↑↓ ↑↓
↑↓ 3p 3s ↑↓ ↑↓ ↑↓
↑↓ 2p 2s
↑↓ 1s
Chemistry 11 – Final Examination Review – Answers – Page 6 of 27
10. Draw the energy level diagram for each of the following elements: d) potassium
↑ 3d 4s ↑↓ ↑↓ ↑↓
↑↓ 3p 3s ↑↓ ↑↓ ↑↓
↑↓ 2p 2s
↑↓ 1s
11. Write the energy level population for each of the following elements: a) calcium 2, 8, 8, 2 b) sulfur 2. 8. 6 c) scandium 2, 8, 9, 2 d) tungsten 2, 8, 18, 32, 12, 2 12. Element X has the following configuration: 1s22s22p63s22p64s23d104p65s1
a) What period is this element located in? five
b) What group is this element in? one (alkali metals)
c) Identify the element. Rubidium (Rb)
d) Is the element a metal, nonmetal, or metalloid? Metal 13. List five properties of metals and five properties of nonmetals.
Metals - good conductors of heat and electricity - lustre - malleable and ductile - high densities - high boiling points and melting points - resist stretching and twisting - solids at room temperature
Nonmetals - no lustre - poor conductors - may be solid, liquid or gas - low densities - low melting and boiling points
Chemistry 11 – Final Examination Review – Answers – Page 7 of 27
14. In a group, do the radii of atoms increase or decrease as the atomic number increases? Explain why.
In a group, the radii increases as the atomic number increases because electrons are being added at higher energy levels which are located further from the nucleus producing a larger atom.
15. Does the radii of atoms within a period increase or decrease as the atomic number increases? Explain why.
The radii of atoms in a period decrease as the atomic number increases. As you go across (left to right) a period the electrons are being added to the same energy level while more protons are added to the nucleus. The attractive force is greater and the electrons are pulled closer to the nucleus producing a smaller atom.
16. In each of the following pairs of atoms, pick the one that is larger. a) Mg, Na b) K, Ca c) Al, B d) Br, Cl e) F, N f) Ne, Ar 17. In a group, will the ionization energy tend to increase or decrease with increasing atomic number?
Explain why. In a group the ionization energy decreases as the atomic number increases. As you go down a group the size of the atom increases causing the electrons to be located further away from the nucleus. The attraction between the nucleus (+) and electrons (-) which decreases as the distance between them increases, which makes it easier to remove an electron.
18. In a period, will the ionization energy tend to increase or decrease with increasing atomic number? Explain why. In a period the ionization energy increases as the atomic number increases. As you go across a period (left to right) the size of the atom decreases, the electrons are located closer to the nucleus with a greater attraction between the electrons and the nucleus. Because the attraction is greater, more energy is required to remove an electron.
19. Do metals or nonmetals generally have lower ionization energies? Metals generally have lower ionization energies than nonmetals. 20. Carbon has a first ionization energy of 1086.5 kJ/mol. Predict whether the first ionization energies of the
following elements will be more or less than that of carbon. a) helium higher ionization energy b) lithium lower ionization energy c) fluorine higher ionization energy d) silicon lower ionization energy
Chemistry 11 – Final Examination Review – Answers – Page 8 of 27
21. As the distance between the nucleus and the outer electrons of an atom increases, will the ionization energy increase or decrease? As the distance between the outer electrons and the nucleus increases, the attractive force decreases which causes the ionization energy to decrease.
22. As the positive charge on an ion increases, will the ionization energy increase or decrease? As the positive charge on the ion increases the electrons are held more tightly and the ionization energy increases.
23. How are substances that are gases or soft solids at room temperature classified?
Substances that are gases or soft solids at room temperature are classified as covalent compounds.
24. Would an element with two outer electrons be a metal or a nonmetal?
An element with two outer electrons would be a metal. 25. What Russian scientist designed the first periodic table?
Mendeleev designed the first periodic table. 26. Which group of elements has eight outer electrons?
The noble gases have eight outer electrons. 27. For the transition elements, as the atomic number increases, to which sublevel are the electrons
being added? For the transition metals, the electrons are being added to the “d” sublevel.
28. According to the octet rule, how many pairs of outer electrons do the most stable atoms have?
According to the octet rule, the most stable atoms have four pairs of outer electrons.
29. In the lanthanide series, as the atomic number increases, to which sublevel are electrons being
added? In the lanthanide series, electrons are being added to the “f” sublevel.
30. Which atom in each of the following pairs would have the lower first ionization energy? a) N, O b) Te, Se c) C, Ge d) Br, I e) I, Sb f) Al, N
Chemistry 11 – Final Examination Review – Answers – Page 9 of 27
31. In a group, will the electron affinity tend to increase or decrease with increasing atomic number? Explain why. In a group, electron affinity decreases as atomic number increases. As you go down the group, the size of the atom increases, electrons are added further from the nucleus where the attraction is less, therefore less energy is released when an electron is added to the atom, and electron affinity is smaller.
32. In a period, will the electron affinity tend to increase or decrease with increasing atomic number?
Explain why. In a period, the electron affinity increases as the atomic number increases. As you go across (left to right) the size of the atom decreases and the electrons are added closer to the nucleus where the attraction is greater – causing more energy to be released when the electron is added, increasing the electron affinity. (Noble gases do not follow this trend because of their increased stability, they do not gain electrons easily.)
33. Which atom in each of the following pairs would have the higher electron affinity? a) S, Cl b) At, Rn c) Y, Os d) Ga, In e) Br, I f) O, N 34. Give examples of molecules with the following shapes:
a) linear HCl, CO2, BeCl2 b) trigonal planer BH3, BCl3, AlBr3 c) trigonal pyramidal NH3, NH3 d) tetrahedral CH4, CCl4 e) bent H2O, H2S
35. Use electron dot formulas to show the complete balanced bonding reactions between the following elements. Indicate the type of bond expected. a) sodium and oxygen
b) nitrogen and hydrogen
c) zirconium and sulfur
d) magnesium and chlorine
Chemistry 11 – Final Examination Review – Answers – Page 10 of 27
36. Write the correct names for the following chemical compounds. a) HCl(aq) hydrochloric acid b) KOH potassium hydroxide c) HgOH mercury(I) hydroxide d) FeCl3 iron(III) chloride e) Al2(SO4)3 aluminum sulfate f) N2O5 dinitrogen pentoxide g) HF hydrofluoric acid h) Pb(OH)2 lead(II) hydroxide i) NH4NO3 ammonium nitrate j) NaHCO3 sodium bicarbonate k) Zn(NO2)2 zinc nitrite l) H3PO4(aq) phosphoric acid
m) SO3 sulfur trioxide n) NaC2H3O2 sodium acetate o) HFO2(aq) flourous acid p) Al(BrO4)3 aluminum perbromate q) SbF3 antimony(III) fluoride r) Pd(CN)2 palladium(II) cyanide s) Ca(MnO3)2 calcium manganate t) Be(NO4)2 beryllium pernitrate u) NiSeO4 nickel(II) selenate v) H2SO3(aq) sulfurous acid w) Ba(OH)2 barium hydroxide x) PbS lead(II) sulfide
37. Write the correct chemical formula for each compound and balance the equation.
a) sodium carbonate + calcium hydroxide sodium hydroxide + calcium carbonate Na2CO3 + Ca(OH)2 2NaOH + CaCO3
b) carbon dioxide + water carbonic acid
CO2 + H2O H2CO3
c) phosphorus + oxygen phosphorus pentoxide 2P + 5O2 2PO5
d) sodium + water sodium hydroxide + hydrogen
2Na + 2H2O 2NaOH + H2
e) zinc + sulfuric acid zinc sulfate + hydrogen Zn + H2SO4 ZnSO4 + H2
f) aluminum sulfate + calcium hydroxide aluminum hydroxide + calcium sulfate
Al2(SO4)3 + 3Ca(OH)2 2Al(OH)3 + 3CaSO4 g) calcium oxide + water calcium hydroxide
CaO + H2O Ca(OH)2 h) iron + copper(I) nitrate iron(II) nitrate + copper
Fe + 2CuNO3 Fe(NO3)2 + 2Cu i) iron(II) sulfide + hydrochloric acid hydrogen sulfide + iron(II) chloride
FeS + 2HCl H2S + FeCl2 j) potassium oxide + water potassium hydroxide
K2O + H2O 2KOH
Chemistry 11 – Final Examination Review – Answers – Page 11 of 27
Chemistry 11 – Final Examination Review – Answers – Page 12 of 27
k. carbon + ferric oxide iron + carbon dioxide
3 C + 2 Fe2O3 4 Fe + 3 CO2
l. sulfur tetrafluoride + water sulfur dioxide + hydrofluoric acid
SF4 + 2 H2O SO2 + 4 HF
m. calcium hydroxide + phosphoric acid calcium phosphate + water
3 Ca(OH)2 + 2 H3PO4 Ca3(PO4)2 + 6 H2O
n. ethane + oxygen carbon dioxide + water
2 C2H6 + 7 O2 4 CO2 + 6 H2O
o. aluminum sulfate + ammonia + water aluminum hydroxide + ammonium sulfate
Al2(SO4)3 + 6 NH3 + 6 H2O 2 Al(OH)3 + 3 (NH4)2SO4 38. Identify the type of reaction. Write the correct chemical formulas of the compounds, complete and
balance the equations and name the products formed. a) calcium carbonate + hydrochloric acid calcium chloride + carbonic acid
CaCO3 + 2HCl CaCl2 + H2CO3
double displacement b) iron + sodium bromide
Fe + NaBr no reaction b/c iron is less active than sodium single displacement
c) ammonium acetate + iron(II)chloride ammonium chloride + iron(II) acetate
2NH4C2H3O2 + FeCl2 2NH4Cl + Fe(C2H3O2)2
double displacement d) silver bromide + ammonium sulfate silver sulfate + ammonium bromide
2AgBr + (NH4)2SO4 Ag2SO4 + 2NH4Br double displacement
e) zinc + sulfuric acid hydrogen + zinc sulfate
Zn + H2SO4 H2 + ZnSO4
single displacement f) neon + potassium
Ne + K no reaction b/c noble gases are unreactive combination
g) lead(II )hydroxide + hydrochloric acid lead(II) chloride + water
Pb(OH)2 + 2HCl PbCl2 + 2H2O double displacement
h) iron + sulfur iron(II) sulfide
Fe + S FeS combination
Chemistry 11 – Final Examination Review – Answers – Page 13 of 27
i) potassium chlorate (heated) potassium chloride + oxygen
2KClO3 2KCl + 3O2
decomposition
j) calcium oxide + water calcium hydroxide CaO + H2O Ca(OH)2
combination
11. dinitrogen pentoxide + water nitric acid N2O5 + H2O 2HNO3
combination 12. carbon dioxide + water carbonic acid
CO2 + H2O H2CO3
combination 13. chlorine + chromium(III) bromide bromine + chromium(III) chloride
3 Cl2 + 2 CrBr3 3 Br2 + 2 CrCl3Single displacement
14. sulfur + oxygen sulfur dioxide or sulfur trioxide
S + O2 SO2 or S + O2 SO3
combination
15. zinc + hydrochloric acid zinc chloride + hydrogen
Zn + 2 HCl ZnCl2 + H2
Single displacement 16. sodium + water sodium hydroxide + hydrogen
2 Na + 2 H2O 2 NaOH + H2
single displacement 17. magnesium + water
Mg + H2O no reaction – Mg is not active enough to replace H in water
Single displacement 18. copper + stannic nitrate
Cu + Sn(NO3)4 no reaction – Cu is less active than Sn
Single displacement 19. aluminum + cupric sulfate copper + aluminum sulfate
2 Al + 3 CuSO4 3 Cu + Al2(SO4)3
Double Displacement
Chemistry 11 – Final Examination Review – Answers – Page 14 of 27
Part D – Calculations Show all work. Express your answers using significant digits and include units with your answers. 1. Calculate the average atomic mass of the following elements: a) Mg-24 mass = 23.985 u 78.70% Mg-25 mass = 24.986 u 10.13% Mg-26 mass = 25.983 u 11.17% (0.7870)(23.985) + (0.1013)(24.986) + (0.1117)(25.983) = 24.31 u b) Ir-191 mass = 191.0 u 37.58% Ir-193 mass = 193.0 u 62.42% (0.3758)(191.0) + (0.6242)(193.0) = 192.2 u 2. Calculate the percentage of each of the isotopes of silver if silver-107 has a mass of 106.905 u and silver-109 has a mass of 108.905 u and the average atomic mass of silver is 107.869 u 107Ag = x, 109Ag = y x + y = 1
106.905x + 108.905y = 107.869 -106.905x - 106.905y = -106.905 use elimination or substitution 106.905x + 108.905y = 107.869 2y = 0.964 y = 0.482 x = 0.518 107Ag = 51.8%, 109Ag = 48.2%
Chemistry 11 – Final Examination Review – Answers – Page 15 of 27
*3. Naturally, occurring silicon consists of three isotopes, 28Si, 29Si, and 30Si, whose atomic masses are 27.9769, 28.9765, and 29.9738, respectively. The most abundant isotope is 28Si, which accounts for 92.23 percent of naturally occurring silicon. Given that the observed atomic mass of silicon is 28.0855, calculate the percentages of 29Si and 30Si in nature.
Isotope 28Si 29Si 30Si Average
Mass 27.9769 g 28.9765 g 29.9738 g 28.0855 Percentage 92.23% x y
(eqn 1) (0.9223)(27.9769) + (28.9765)(x) + (29.9738)(y) = 28.0855 (eqn 1) 25.8031 + 28.9765x + 29.9738y = 28.0855
(eqn 1) 28.9765x + 29.9738y = 2.2824 (eqn 2) 0.9223 + x + y = 1 (eqn 2) x + y = 0.0777 use substitution or elimination (eqn 1) 28.9765x + 29.9738y = 2.2824 (-28.9756)(eqn 2) -28.9765x – 28.9765y = -2.2824 y = 0.03093 0.9973y = 0.03093 0.9973 y = 0.0310, x = 0.0467, ∴ 29Si = 3.10% and 30Si = 4.67% 4. Complete the chart below:
Element Atomic # Mass # Protons Neutrons Electrons
calcium-43 20 43 20 23 20
lead-211 82 211 82 129 82
plutonium-242 94 242 94 148 94
chromium-50 24 50 24 26 24
65Cu2+ 29 65 29 36 27
34S2- 16 34 16 18 18
128 53I- 53 128 53 75 54
208 82Pb4+ 82 208 82 126 78
5. Convert each of the following to moles.
a. 8.8 g of potassium carbonate
8.8 g K2CO3 + 138.2052 g/mol = 0.0637 mol b. 0.257 g of arsenic pentachloride
0.257 g AsCl5 + 252.1866 g/mol = 1.02 x 10-3 mol c. 12.5 L of carbon dioxide at STP
12.5 L CO2 + 22.4 L/mol = 0.558 mol d. 5.00 x 1013 atoms of iron
5.00 x 1013 atoms of Fe + 6.022 x 1023 = 0.830 mol e. 8.63 x 1028 molecules of water
8.63 x 1028 molecules of H2O + 6.022 x 1023 = 1.43 x 105 mol f. 450.0 mL helium at STP
0.4500 L He + 22.4 L/mol = 0.0201 mol g. 236.0 g of ammonium phosphate
236.0 g (NH4)3PO4 + 149.086 74 g/mol = 1.58 mol h. 15.0 g of butanoic acid
15.0 g CH3CH2CH2COOH + 88.106 32 g/mol = 0.170 mol
6. Calculate the mass of each of the following. a. 2.60 mol of sodium carbonate
(2.60 mol)(105.988 74 g/mol) = 276 g
b. five million atom of gold
(5 000 000 atoms) + (6.022 x 1023) = 8.30 x 10-18 mol
(8.30 x 10-18 mol)(196.9665 g/mol) = 1.64 x 10-15 g
c. 25.0 mL of carbon dioxide at STP
(0.0250 L) + (22.4 L/mol) = 0.001 12 mol
(0.001 12 mol)(44.0098 g/mol) = 0.0491 g
d. 4.50 x 1021 molecules of decanoic acid
CH3CH2CH2CH2CH2CH2CH2CH2CH2COOH or C10H202
( )( ) gmol
mol
molg 29.12676.17200747.0
00747.010022.61050.4
23
21
=
=××
Chemistry 11 – Final Examination Review – Answers – Page 16 of 27
7. Calculate the molarity of 825 mL of solution, which contains 30.0 g of acetic acid.
L
mol
molg L
gg
COOHCHg606.0
825.04996.0
4996.005256.60
0.30 3 ==
8. What volume of solution can be made from 80.0 g of sodium hydroxide if a 2.00 M solution is required?
L00.100.2
mol00.2Cn
V
mol00.211887.38
NaOHg0.80
Lmol
molg
===
=
9. What mass of calcium chloride is required to produce 750.0 mL of a 0.500 M solution?
( )( )
( )( ) g6.41984.110mol375.0
mol375.0L7500.0500.0VCn
molg
Lmol
=
==×=
10. What volume 0f 14.0 M nitric acid is required to produce 750.0 mL of a 0.250 M solution?
( )( )mL4.13orL0134.0
0.14
L7500.0250.0
CVC
VVCVC
Lmol
Lmol
1
2212211 ====
11. What concentration results when 250.0 mL of a 0.125 M solution of hydrochloric acid is mixed with 125.0
mL of a 1.00 M solution?
( )( ) ( )( )
Lmol
Lmol
Lmol
ba
bbaaab
417.0L375.0
mol125.0mol03125.0
L1250.0L2500.0
L1250.000.1L2500.0125.0
VVVCVC
C
=+
=
+
+=
++
=
Chemistry 11 – Final Examination Review – Answers – Page 17 of 27
12. What volume of 0.225 M sulfuric acid must be mixed with 500.0 mL of a 0.750 M solution in order to obtain a 0.500 M solution?
( ) ( )( )
( )( ) ( )
( )
( )
L455.0275.0
mol125.0V
mol125.0V275.0
mol375.0V225.0mol250.0V500.0
mol375.0V225.0L5000.0V500.0
L5000.0V
L5000.0750.0V225.0500.0
VVVCVC
C
Lmola
aLmol
aLmol
aLmol
aLmol
aLmol
a
Lmol
aLmol
Lmol
ba
bbaaab
==
=
+=+
+=+
+
+=
++
=
E. STOICHIOMETRY - Begin each problem by writing a balanced chemical equation. 1. Carbon dioxide is produced in the reaction between calcium carbonate and hydrochloric acid. How many
grams of calcium carbonate would be needed to react completely with 15.0 g of hydrochloric acid? How many grams of calcium chloride would be formed?
CaCO3 + 2HCl H2O + CO2 + CaCl2
( )
( ) 2molg2
molg
3molg3
molg
CaClg8.22986.110HClmol2
CaClmol1
94460.36
HClg0.15
CaCOg6.200892.100HClmol2
CaCOmol1
46094.36
HClg0.15
=⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
=⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
Chemistry 11 – Final Examination Review – Answers – Page 18 of 27
2. Sulfur dioxide may be catalytically oxidized to sulfur trioxide. How many grams of sulfur dioxide could be converted by this process if 100.0 g of oxygen are available for the oxidation?
2SO2 + O2 2SO3
( ) 2molg
2
2
molg
2SOg4.4000648.64
Omol1
SOmol2
9988.31
Og0.100=
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
3. Phosphoric acid is produced in the reaction between calcium phosphate and sulfuric acid. How much of the phosphoric acid would be produced from 55.0 g of the calcium phosphate?
Ca3(PO4)2 + 3H2SO4 3CaSO4 + 2H3PO4
( ) 43molg
243
43
molg
243POHg8.34995.97
)PO(Camol1
POHmol2
183.310
)PO(Cag0.55=
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
4. How much magnesium sulfate is needed to completely react with 145 g of sodium chloride? How much
sodium sulfate could be produced by this reaction?
MgSO4 + 2NaCl Na2SO4 + MgCl2
( )
( ) 42molg42
molg
4molg4
molg
SONag176043.142NaClmol2
SONamol1
443.58
NaClg145
MgSOg1493686.120NaClmol2
MgSOmol1
443.58
NaClg145
=⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
=⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
5. Gold will dissolve in the acid mixture known as aqua regia according to the following reaction:
Au + HNO3 + 3 HCl AuCl3 + NO + 2 H2O How much gold(III)chloride will be produced in this reaction when one starts with 5.0 mg of gold?
( ) 3
37.73255.303
1
1
9665.196
0.5AuClmg
Aumol
AuClmolAumgmmol
mg
mmolmg
=⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
How much hydrochloric acid must be added initially to dissolve the all this gold?
( ) HClmgAumol
HClmolAumgmmol
mg
mmolmg
8.2461.361
3
9665.196
0.5=
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
Chemistry 11 – Final Examination Review – Answers – Page 19 of 27
6. How many grams of sulfuric acid will react with 400.0 g of aluminum metal?
( ) 42
422181079.98
2
3
98154.26
0.400SOHg
Almol
SOHmolAlgmol
g
molg
=⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
7. It is desired to prepare 50.0 g of water by synthesis. How many litres of hydrogen must be used?
( ) 2
2
222.624.22
2
2
01528.18
0.50HL
OHmol
HmolOHgmol
L
molg
=⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
8. An unknown amount of potassium chlorate was heated until no more oxygen was evolved. 15.824 g of potassium chloride remained in the test tube.
2KClO3 2KCl + 3O2
What mass of potassium chlorate had originally been placed in the tube?
( ) 3
30.265495.122
2
2
5513.74
824.15KClOg
KClmol
KClOmolKClgmol
g
molg
=⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
What volume of oxygen gas was evolved in the process?
( ) 2
213.74.22
2
3
5513.74
824.15OL
KClmol
OmolKClgmol
L
molg
=⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
9. How many grams of carbon can be completely burned in 15.0 L of oxygen?
( ) CgOmol
CmolOLmol
g
molL
04.8011.121
1
4.22
0.15
2
2=
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
How many litres of carbon dioxide gas are produced in this reaction?
( ) 2
2
220.154.22
1
1
4.22
0.15COL
Omol
COmolOLmol
L
molL
=⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
Chemistry 11 – Final Examination Review – Answers – Page 20 of 27
10. How many grams of magnesium metal are required to liberate 250.0 mL of hydrogen gas from hydrochloric acid?
( ) MggHmol
MgmolHLmol
g
molL
271.0305.241
1
4.22
2500.0
2
2=
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
Exactly how much acid would be used up in this reaction?
( ) HClgHmol
HCmolHLmol
g
molL
8141.046094.361
lg2
4.22
2500.0
2
2=
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
11. Will 30.0 L of fluorine gas completely react with 50.0 L of hydrogen gas? Which gas is in excess and by how much? What volume of hydrogen fluoride is formed in this reaction?
( )
( )
( )
excess in L 20.0 needed L 30.0 - available hydrogen of L 50.0
0.304.221
1
4.22
0.30
excess. in is hydrogen and reactant limiting the is Fluorineproduced. is fluoride hydrogen of L 0.60
.1004.221
2
4.22
0.50
0.604.221
2
4.22
0.30
2
22
2
2
2
2
=
=⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
=⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
=⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
neededHFLOmol
HmolFL
HFLHmol
HFmolHL
HFLFmol
HFmolFL
molL
molL
molL
molL
molL
molL
Chemistry 11 – Final Examination Review – Answers – Page 21 of 27
12. A mixture containing 100.0 g of H2 and 100.0 g of O2 is sparked so that water is formed. How much water is formed?
( )
( )
formed. are water of g 113excess. in is hydrogen and reactant limiting the is Oxygen
11301528.181
2
9988.31
0.100
89401528.182
2
01588.2
0.100
2
2
22
2
2
22
OHgomol
OHmolOg
OHgHmol
OHmolHg
molg
molg
molg
molg
=⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
=⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
13. When copper is heated with sulfur, Cu2S is formed. How many grams of Cu2S could be produced if 100.0 g of copper is heated with 50.0 g of sulfur?
( )
( )
formed. is sulfide copper(I) of g 125.2excess. in is sulfur and reactant limiting the is Copper
248158.1591
1
066.32
0.50
2.125158.1592
1
546.63
0.100
2
2
2
2
SCugSmol
SCumolSg
SCugCumol
SCumolCug
molg
molg
molg
molg
=⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
=⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
14. What volume (at STP) of carbon monoxide is required to produce 100.0 g of iron according to the equation: Fe2O3 + CO Fe + CO2 (not balanced)
( ) COLFmol
COmolFegmol
L
molg
2.604.2222
3
847.55
0.100=
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
Chemistry 11 – Final Examination Review – Answers – Page 22 of 27
*15. Hydrozine is a nitrogen-hydrogen compound hoving the formulo NzH+. rt is on oily, colourless liguid thot
freezesot 1.5oC andloils ot 113.5"c. ihe principol use of hydrozine ond certoin compounds derived from it
is o rocket fuels, but it is olso used in fuei cells, in the treotment of woter in boilers to removed dissolved
oxygengos, ond in the plostics industry. One widely used method for the monufoctureol hydrozine is the
Roschig process. The Roschig process involves three reoction steps. rn the first sfep, sodium hydroxide is
reocted with chlorine to proJuce sodium hypochlorite, sodium chloride ond woter. The sodium hypochlorite
produced in the first step is reocted with ommonio in the second step to produce chloromine (NHzcl) ond
sodium hydroxide. The chloromine ond sodium hydroxide produced in the second step is reocted with
ommonio in the third step to produce hydrazine, sodium chloride and woter. A chemicol plone using the
Roschig process obtoins O.2gg k9 of g8.O% hydrozine for every 1.00 k9 of chlorine. Whot ore the
theoreticol, octuol, ond percent yields of pure hydrozine?
2NaOH * Clz ) NaOCI + NaCl * HzON a O C I * N H g t N H 2 C | + N a O H
NH2CI + NaOH * NHg ) NzHr + NaCl * HzO
ctnol
- ORoANIC CHEAAI5TRY
Drow the structure of eoch of the following compounds:
o) 2,3-dinitrophenolot+
,\ro.LO^ do,v
b) 2,3,4-'trimethyloctone
ct{. -cl+ -cil+ ^ Ct\-CAz-Uza\r- C(ltCHz ctl. ctlt
c) 1,3-cyclohexodiene
d) 4,4-dimethyl-2-Pentene
QiltCIlrcH=cH - q
crL
lfr -"r ruaocr]f
Jt 1-", % JtL mot NH,ct)lt mor n,n.l6r.oorr,
;r)t mot naoct )lL mot NH2ct )
actual yield = (98.Oolo[zSS g) = zel g = dctual yield
percentage Yield =actual yield
x 1OO = 64.80/o yieldtheoretical yield
F1.
1OOO g Ct,
70.906
= 452 g NrHo = theoretical Yield
Chemistry 11 - Finol Exomination Review - Answers - Page 23 of ?7
cilt
e) phenylethene
Cl+ = CFl.
f) 2-phenylProPone
l) proponone
ot l
cSg- c - ct{3
m) l-proPoxybutone
C |{tcH ,-CA;o -Ct{>- CilL-CLz'C[!3
9) 1,3-dibromonoPhtholene6v
@."n) ethyl chloroethonoote
o,, erlr_ Ctl,l f t re -D-ct
p) 3-methYl-3-PentonolorII
CA;cHv- l- ' 'Hr-CIlscHr
o) iodobenzene
L
,\| / ) t\Z
-methylphenol
ot^.
Yctf g
q ) 4
.,*rd -c*=
h) 1,2-ethonediol
fil'- ts'otl o l+
i) proponol
ol l
cA r-cr|;cr+
i) pentonoic ocid
Ot,
CLl; ctl;cl;il\;C-o t't
k) propyl ethonoote r) 2-omino-3-phenylproponol o
I c*-- cu - ttCllr-C-c: -CHr{A>- CL A
" IU,\?
Chemistry 11 - Finol Exominotion Review - Answers - Poge 24 of ?7
s) 3-methyl-3-pentonol
cr,c l{t cHr- L -c{r- ctl,
r e l
o|+
t) ethylmethyl ether
CHr'tfit o - c{t
u) butyl butanoote
w) nitromethone
iJ 0 z- ct\3
x) 3-ethyl-5-methyl-2-naPhthol
0r l
CAr-1t ; C$ ; Go - cttg ctl r-cl{ ; t! t
o-t-ou
v) 3-ethylhexonoicocid
CtJ;cU;t[r-ctt-crt]cAzICtlr
Z. Write o bolonced eguotion for each of the reoctions below. Identify the type of reoction ond nome the
products.
o) pentone + bromine )
Ctls- CvI; CII;Cil;Ctl. t
g^,t"r1. S"*t a" nx n
b) 2,3-dichloro-?-penlene + woter )
ci lo-9= t -cl lz-Lt l t + t l"-c) ->
cr c l
ad/i lsn- (xn
c) butcnoic ocid + ethonol )o
Ctle-tl;Crl; ' i-oU' ct\-CH>-oH
(sler ili ealrtm rrYr'l {Vlrf arlw,oo'fu t
t'f oAt l
cHr- ?- i- ctt>- cHtC t c l
?,?- d:Nwo 4 "*+"Jo
+ eLr4lll-cil'-t -o -cLt'c4t + HrO
palor
w:L*.cfit
y) 1,3,5-cyclohexonetriol0uIn
L}-
noAlotl
z) propyl 2,3-dimethylPentonoote
f t
Ctlr-c+,- f - fA
-t-o- cL-ut>-ctt3CH, CH'
&,k - -> " * r ' cL r -c l r - c {> -cd ' I H6 .
t- VNno f-r#*-,, + hgd"+ogt'^ brorv'tolt
Chemistry 11 - Finol Exominotion Review - Answers - Poge 25 of 27
d) benzene + iodine )
V t T - - )
*wbg\L(r^ Yxva
e) *t[f';ti oxYsen ), A
/,',Y n-r + lL O LS/-*/
AOvy'hv{firn rKn
f) 2-nophthol + oxygan )( ( - ' r H c o )
z AryoP -, -zz o z- >
46P,l,.sha*- | x r'r
9) 2,5,6-trimethyl-3-heptyne + fluorine )
c1t,-c+-c= c- 7H - Cl ' l -cHt r'
br+t it+t c{t
aold; lsaw,rF*
llro
r daleY
F>-> ,r,- t;,- 7= i
@t + i l - !
I- iodo fun# + hgd-'ro6t'* ;o/i'J"
to QO. + 4 H"o
w bon d,irr; oh r aa/t'r'
ZD eO> + &
eo.rbun dr'orioL
-c t l -cH -c i ls
brt, b't'
3,4 -d:flrrwp -716,L'hl,*d't^"( - S- huflov*
h) 3,4-diethyl-2-methylhexonoic ocid + 1-Penfonol ) o
t$$$$$;tr ::; - eH - E-o u r [X;ru;cftut{t1-+ c t',,-i;'ti$; :'-'r:or:':*e bil" iU
btl. tl+- clt.
Lu, b*, ?nV s,.t -dicl4/-v,*iii n +*oJ" r woln
i) t-^"d6i{,0*Ztfn" * oxvsen )
cp.-ctlr- LH-ctlL- ct! r I 0, t b cDL 't 1 H-bo
, Ir*. ot'v b"-' d'iry;J' r "laletCdn-bu5'1".;' lrx'^
j) a-pentyne + (2 mol) woter )
| Oil
cH3-c=c-cHL-C{1" t z t+>o ) C}+r - f^ f -CHz-cH,n o f l
/)"/d; h "t' ' fxn g.s -
f/.Jo^'r,il:6(
Chemistry 11 - Finol Exominotion Review - Answers - Poge 26 of 27
3. Name the following compounds.
a) 3-methyl-5-nitro-3-hexene
b) 1,3-dichlorocyclohexane
c) 1,3-diamino-5-nitrobenzene
d) 3,6-dibromo-2-naphthol
e) diethyl ether or ethoxyethane
f) 1,4-cyclohexadiene
g) 2,3-dimethylbutanoic acid
h) 2,3,4-pentanetriol
i) 2-methyl-3-pentanone
j) 3-ethyl-2-methylpentanal
k) methyl propanoate
l) 4,5-dimethyl-7-propyl-1-naphthol
m) 2,4-hexadiyne
n) 1,2-butadiene
o) pentyl 3,3-dimethylbutanoate
p) 1,3,5-cyclohexanetriol
q) 1-amino-2-bromo-4-nitrocyclopentane
r) 2,3-dimethylpentanedioic acid
s) butyl 2-methylpropanoate
t) phenyl-3,4-diaminopentanoate
Chemistry 11 – Final Examination Review – Answers – Page 27 of 27