chemia fizyczna technologia chemiczna ii rok wykład 1 · 2016-10-12 · physical and chemical...
TRANSCRIPT
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Physical Chemistry Green Technologies & Monitoring,
Semester III Lecture 1
Head of the course:
Wojciech Chrzanowski, DSc, PhD
2
Order of lectures is, perhaps, not the most logical one, but it is partially
dictated by my desire to synchronize the lectures and tutorials.
A quote of the day (good for all the semester):
The camel’s hump is an ugly lump
Which you well may see in the Zoo.
But uglier yet is the lump you get
From having too little to do.
Rudyard Kipling
Phys. Chem. GTM 01
3
Definition of a scientific discipline
Its subject: Physical and chemical transformations of the matter (without
defining its type) and associated (related) flows of energy.
Its method: Mathematical-physical, i.a., creation of theoretical models either
based on or verified by experiment. Formulation of hypotheses,
theories and laws of nature related to its subject. Cartesian-
Newtonian paradigm.
What is physical
chemistry?
Phys. Chem. GTM 01
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4
Matter is everything possessing mass (inertion, Newton).
chemical substance is a pure, isolated form of matter (amount of matter and its unit: mole, chemical species)
Energy is ability to perform work (simpl.).
(types of energy, unit: joule, J)
Fundamental concepts (1)
Equivalence of matter and energy
E=mc2
in practice, relativistic effects may be observed in the micro world only, in macroscopic world they can be neglected.
Phys. Chem. GTM 01
5
Kinetic energy – energy of motion:
Ec=½mv2 Ec=½Jω2
Fundamental concepts (2)
Potential energy – depends on the position of a body:
in the gravitational field in the electric field
of the Earth
Ep=mgh Ep=q1q2/(4pe0r)
Phys. Chem. GTM 01
Chem. Fiz. TCH II/01 6
Theoretical model is a certain assumed or imagined
mechanism of the phenomenon in question, or image plus complex of
properties of an object, usually simplified yet attempting to embrace
all its major (essential) features
Hypothesis is certain assumption on the essence of the
phenomenon under consideration, may be an attempt of guessing the
gist based upon already known concepts and laws.
Theory is a hypothesis verified in further studies
(experimentally), when it becomes confirmed (esp. in different labs)
and is applicable to many cases (objects, phenomena), frequently
related.
Fundamental concepts (3)
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Chem. Fiz. TCH II/01 7
Law of nature (physico-chemical law) is a clearly formulated
part of theory usually expressed mathematically, dealing with a
specific phenomenon , i.e., relations and links between some
observables involved in the phenomenon.
Verbal formula: Boyle’s law:
At constant temperature, volume of a gas changes inverse
proportionally to its pressure. At constant temperature, product of
volume nad pressure of a gas is constant.
Formula (equation):
Fundamental concepts (4)
const. VPPVPV ;P
P
V
V then const.if 2211
1
2
2
1 T
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Thermodynamics (incl. thermochemistry)
Phase equilibria
Chemical equilibria
Solutions – thermodynamic charakteristics
Elektrochemistry: ionics & electrodics.
Surface phenomena
Chemical kinetics.
Main branches:
Phys. Chem. GTM 01
9
System (definition)
System is a part of universe subject to
observation or being an object of theoretical
considerations, separated from the rest of
universe (surroundings) physically or just in our
imagination.
system + surroundings = universe
Introduction to
thermodynamics
Phys. Chem. GTM 01
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10
The three types of systems:
Open
Closed
Isolated
Introduction to
thermodynamics (2)
Phys. Chem. GTM 01
11
Ways of the energy transfer:
work
heat.
Types of work
Mechanical (change of volume, change of shape), change of the interface area, electrical.
Introduction to
thermodynamics (3)
Phys. Chem. GTM 01
12
HEAT
Introduction to
thermodynamics (4)
Phys. Chem. GTM 01
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13
Endothermic process (system limited by a diathermic barrier)
Introduction to
thermodynamics (5)
before after
Phys. Chem. GTM 01
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Endothermic process in an adiabatic system
Introduction to
thermodynamics (6)
before after
Phys. Chem. GTM 01
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Physical properties of systems: Extensive (additive), depending on the size of the
system (number of components, their type and amount of each)
(e.g. mass or volume of a system)
Intensive are not additive.
(e.g. temperature, density, specific and molar quantities, refraction index)
Introduction to
thermodynamics (7)
iiXnx
Phys. Chem. GTM 01
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State of a system: The following quantities permit complete characterization of the state of a given system
P, V, T
Equation of state:
f(P,V,T)=0
For a system containing perfect gas only: pV=nRT
Introduction to
thermodynamics (8)
Phys. Chem. GTM 01
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Temperatura and „zeroeth” law of thermodynamics
Two bodies, that reached the state of thermal equilibrium, have the same temperature and heat
is no more exchanged between them.
If body A is in thermal equilibrium with body B and with body C, therefore bodies B and C also remain
in thermal equilibrium.
Phys. Chem. GTM 01
Introduction to
thermodynamics (9)
18
Work of expansion
Introduction to
thermodynamics (10)
dx
Pgas
Pext
dVPSdxPdw extext
FSP
2rS p
Phys. Chem. GTM 01
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Work of expansion (ctd.)
Introduction to
thermodynamics (11)
Three ways of performing the work by the system:
1. Against a constant external pressure (Pext= const).
2. Against a null external pressure (expansion to vacuum, a special
case of the latter), Pext= 0.
VPVVPdVPdww extifext
f
i
ext
f
i
0w
Phys. Chem. GTM 01
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Work of expansion (ctd.)
Introduction to
thermodynamics (12)
Phys. Chem. GTM 01
3. Reversible (quasi-static) isothermal transition: dPPPext
dVV
nRTPdVdVPdw ext
f
i i
f
f
iV
VnRT
V
dVnRTdww ln
i
f
f
i
i
f
P
PnRT
V
VnRT
V
VnRTw lnlnln
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Work of expansion (ctd.)
Introduction to
thermodynamics (13)
Phys. Chem. GTM 01
As the general expression for work of expansion is: PdVdw
f
i
f
i
dVVPdww )(and after integration:
hence, work is represented by the surface area
under the P=f(V) plot on the P-V plane .
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22
Thermochemistry (1)
• Enthalpy is heat exchanged at constant
pressure.
state property
• H < 0 - exothermic process
• H > 0 - endothermic process
initfinHHH
initfinHHH
Phys. Chem. GTM 01
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Thermochemistry (2)
A standard reaction enthalpy is the reaction
enthalpy when reactants in their standard
states are converted to products in their
standard states. Denoted as:
The standard state of a substance is its pure
form at pressure of 105 Pa.
0H
Phys. Chem. GTM 01
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Thermochemistry (3)
• The standard molar enthalpy of formation
of a compound is the standard reaction
enthalpy per mole of compound for the
synthesis of the compound from its
elements in their most stable forms at 105 Pa
and specified temperature. Denoted as:
00 H ;H formf
Phys. Chem. GTM 01
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Thermochemistry (4)
• Standard enthalpies of formation of
elements are equal to ZERO (at 298K).
When several allotropic forms of an
element exist, the statement applies to the
most stable form of the element.
• Standard molar enthalpy of formation of a
compound is standard molar enthalpy of
this compound.
Phys. Chem. GTM 01
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Thermochemistry (5)
ProductsReactants
initfinrreactionHHHH
fin
0
Pri,f,i H =Hn init
0
Rei,f,i H =Hn
0
Rei,f,i
0
Pri,f,i
0
r Hn-Hn=H
Phys. Chem. GTM 01
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Thermochemistry (6)
• The standard molar enthalpy of combustion is
the change in enthalpy per mole of the substance
(fuel) when it is burned (reacts with oxygen)
completely under standard conditions. Denoted as
• conditions superimposed on products in complete
combustion:
H H2O(l); C CO2(g); N N2(g)
00 H ;H combc
Phys. Chem. GTM 01
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Thermochemistry (7)
Using standard molar enthalpies of combustion
one can calculate the reaction enthalpy as follows:
This is an exceptional formula, where a property
of the products is subtracted from that of the
reactants.
0
Pri,c,i
0
Rei,c,i
0
r Hn-Hn=H
Phys. Chem. GTM 01
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Hess law
A reaction enthalpy is the sum of the enthalpies of
any sequence of reactions (all at the same
temperature and pressure) into which the overall
reaction may be divided.
Hess's law results from a rigorous application of the statement
that enthalpy is a state property. It does not matter what was the
way to obtain the substance or into how many steps the overall
reaction was split.
Phys. Chem. GTM 01
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Hess law (2)
Hess law may be applied to each and every state
quantity (not only to enthalpy).
Another wording:
If any reaction (target reaction) may be represented
as a linear combination of some other reactions
(partial reactions) then any state property of this
reaction is the same linear combination of the
respective state properties of the partial reactions.
Phys. Chem. GTM 01
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Hess law (3)
Thermochemical equations:
1. State of matter (phase: solid, liquid, gaseous) and
any specific form of all reactants and products must
be indicated.
2. The heat released or absorbed, i.e., the H must be
shown.
Phys. Chem. GTM 01
CBAT HHH2H
then2 If
CBAT
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Hess law (4)
Rules of manipulation:
1. When the reaction is rewritten in reversed direction,
the sign of its H is changed.
2. When stoichiometric coefficients in the reaction are
multiplied, the H must be multiplied by the same
factor.
3. When two reactions are added, their enthalpy
changes must be added, too.
Phys. Chem. GTM 01
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Hess law. Example
Target reaction:
Component reactions:
Step 1. Begin with the thermochemical equation having at
least one of the reactants or products on the correct side of
the arrow in the target reaction:
?H O(l);H+(g)2CO(g)O2+(g)HC :T 0
T22221
22
mol]226.75[kJ/=H (g);HC(g)H+2C(s) :A 0
A222
mol]-393.5[kJ/=H (g);CO(g)O+C(s) :B 0
B22
mol]-285.9[kJ/=H O(l);H(g)O+(g)H :C 0
C2221
2
Phys. Chem. GTM 01
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Hess law. Example (2)
Hence, we start with reaction B and multiply both sides (as
well as its standard enthalpy) by a factor of 2:
Step 2. To add a reactant or product, add another reaction,
having the desired substance at the same side of the arrow
as in the overall reaction. To cancel a reactant or product
(which is not present in the target reaction), add another
reaction, having the desired substance at the opposite side of
the arrow than in the reaction obtained so far.
2B=D (g);2CO(g)2O+2C(s) 22
Phys. Chem. GTM 01
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Hess law. Example (3)
In our case, to complete the right side of reaction (T), we
add reaction (C) to reaction (D):
Step 3. If the reaction obtained in step 2 is identical with
reaction T, then the procedure is completed, else - repeat
step 2 (do not use reactions already used in it).
In our case, reaction (E) is not yet equal to reaction (T).
We repeat step 2 to eliminate carbon and hydrogen at the
left side of reaction (E), by adding reversed reaction (A) to
reaction (E) or subtracting (A) from (E).
C+2B=E O(l);H+2CO(g)O2+(g)H+2C(s) 22221
2
Phys. Chem. GTM 01
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Hess law. Example (4)
Our goal is achieved. Reaction (F) is equal to reaction (T).
The linear combination we found is T=2B+C–A. We
calculate the change in enthalpy in reaction (T) in the same
manner:
T=A-C+2B=F O(l);H+2CO(g)O2+(g)HC 22221
22
J/mol]-1299.65[k= ...
...=(-226.75)+(-285.5)+-393.52=H-H+H2=H 0
A
0
C
0
B
0
T
Phys. Chem. GTM 01