chem answer paper 2 final
TRANSCRIPT
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8/8/2019 Chem Answer Paper 2 Final
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SULIT 4541/2 (PP)
[Lihat sebelah
4541/2 (PP) 2010 Hak Cipta JKD Kimia Daerah Kluang SULIT
2
Section A
Q no. Explanation MarksTotal
Mark
1 (a) (i) Magnesium / Mg 1 1(ii) Chlorine / Cl2 // Naphthalene / C10H8 1 1
(iii) Potassium iodide / KI 1 1
(b) (i) solid 1 1
(ii)
At least the particles are drawn in 3 columns and 3 rows in a
closely packed arrangement with identical sizes. 1 1
(c) Magnesium / Mg 1 1
(d) (i) T1oC / T1 1 1
(ii) The heat lost to the surroundings is equal to / (is balanced
by) the heat released .. during the formation of the force of attraction between
particles
1
1 2
(iii) The speed of the particles movement is decreasing //
Movement of particles becomes slower.1 1
Total 10
2. (a) A (chemical) formula that shows the simplest (whole no.)
ratio of each atoms of the element in a compound. 1 1
(b) (i) Number of moles of atoms /mol / mole 1 1
(c) (i) Method II 1 1
(ii) Copper is a less reactive metal (than hydrogen) // Copper is
positioned lower than hydrogen in reactivity series
1 1
(iii) To allow air/oxygen to enter the crucible // to let magnesiumburns / reacts with oxygen completely) 1 1
(d) (i) 33.31 32.29 g // 1.02 g 1 1
(ii) [1.02 / 24] mol // 0.0425 mol 1 1
(iii) 33.99 33.31 g // 0.68 g 1 1
(iv) [0.68 / 16] mol // 0.0425 mol 1 1
(v) MgO 1 1
Total 10
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SULIT 4541/2 (PP)
[Lihat sebelah
4541/2 (PP) 2010 Hak Cipta JKD Kimia Daerah Kluang SULIT
3
Q no. Explanation MarksTotal
Mark
3. (a) Group 1 / alkali metals 1 1
(b) 2.8.8.1 / 2,8,8,1 r : 2:8:8:1 1 1
(c) 1. Potassium atom has more number of shells // potassium
atom has bigger size than sodium atom // attractive forces
between nucleus of potassium atom and valence electronsare weaker.
2. Potassium atom can loss / release electron easier.
adp for the word atom
1
1 2
(d) (i) 2Na + Cl2 2 NaCl
Correct formulae of reactants and product
Balance equation
1
1 2
(ii) Ionic bond 1 1
(iii)
- enough no. of shells & electrons for both of ions
- correct charges and labels of ions
1
1 2
Total9
NaCl
+ -
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SULIT 4541/2 (PP)
[Lihat sebelah
4541/2 (PP) 2010 Hak Cipta JKD Kimia Daerah Kluang SULIT
4
Q no. Explanation MarksTotal
Mark
4. (a) Cell X : Electrolytic cell / Electrolysis cell
Cell Y : Daniell cell / Voltaic cell / Chemical cell
1
1 2
(b) Cu2+, SO42-, H+, OH- //or names of the ionsAll ions must be stated 1 1
(c)(i) Remains unchanged / not change 1 1
(ii) Cu2+ + 2e Cu 1 1
(iii) Types of electrode / use active electrode 1 1
(d) (i) Chemical to electrical 1 1
(ii) Becomes thinner / (zinc plate) dissolved 1 1
(iii) Greater (voltmeter) reading (obtained).
r : Increase
1 1
(e) [draw an arrow from S to P trough the external circuit]
1 1
Total 10
P Q R S
Cell X
A
Cell Y
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[Lihat sebelah
4541/2 (PP) 2010 Hak Cipta JKD Kimia Daerah Kluang SULIT
5
Q no. Explanation MarksTotal
Mark
5. (a)(i)Titration Set 1 2 3
Final reading of
burette/ cm3
12.55 25.05 37.50
Initial reading of
burette/ cm3
0.00 12.55 25.05
Volume of
sulphuric acid
used/ cm3
12.55 12.50 12.45
All of the volume values must be stated in two decimal places
1 1
(ii) The average volume of sulphuric acid
= 12.55 + 12.50 + 12.45
3= 12.50 cm
311 2
(b) (The moment) when the colour of phenolphthalein / solution
change from pink to colourless 1 1
(c) Sulphuric acid completely ionizes / dissociates in water //
degree of ionization is 1 // sulphuric acid produces high
concentration of hydrogen ion in water //
Ethanoic acid partially ionizes in water // degree of
ionization is less than 1
1 1
(d) H2SO4 + 2 KOH K2 SO4 + 2 H2OCorrect formulae of reactants and products
Balance equation1
1 2
(e)(i) Number of mole sulphuric acid = (M x V)
= 1.0 moldm-3
x 12.50 cm3
1000 cm3dm
-3//
= 0.0125 mol
1 1
(ii) From the equation,
1 mole of sulphuric acid 2 moles of water
0.0125 mole of sulphuric acid 2 x 0.0125 mole
1Number of moles of water produced = 0.025 mole
0.025 mol KOH = MB x 25.001000
Concentration of KOH , MB = 1.0 mol dm-3
OR, use MAVA / MBVB = a/b
1
1 2
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SULIT 4541/2 (PP)
[Lihat sebelah
4541/2 (PP) 2010 Hak Cipta JKD Kimia Daerah Kluang SULIT
6
Q no. Explanation MarksTotal
Mark
(f) Sulphuric acid is a diprotic acid, for every molecule of sulphuricacid two H
+ions will be produced when added with water. //
Nitric acid is a monoprotic acid,for every molecule of
nitric
acid one H+
ion will be produced when added with water.
1 1
Total 11
6. (a) (i) X : Copper(II) carbonateY : Sulphuric acid (solution)
11 2
(ii)
Salt crystal
[ Functional diagram]- Filter paper must be seen clearly
[Label]
1
1 2
(b) (i) 1. Blue solution is formed
2. Copper(II) carbonate dissolves
3. The effervescence occurred
Any two observation
1
1
2
(ii) To ensure all sulphuric acid react completely.r : acid finished react 1 1
(iii) Crystal / salt is formed 1 1
(iv) Carbon dioxide gas
r : CO2
1 1
(c) Neutralisation
a: reaction between acid and base
1 1
Total 10
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SULIT 4541/2 (PP)
[Lihat sebelah
4541/2 (PP) 2010 Hak Cipta JKD Kimia Daerah Kluang SULIT
7
SECTION B
Q No. Explanation MarksTotal
Mark
7. (a) (i)
(ii)
(iii)
(b) (i)
Electron arrangement of argon atom is 2.8.8
Has 8 valence electrons / outermost shell is occupied by 8
electrons //has achieved stable/ octet electron arrangement
Group 1
Electron arrangement of lithium atom is 2.1, sodium atom 2.8.1and potassium atom 2.8.8.1Has 1 valence electron // has same valence electron
Period 3
Electron arrangement of sodium atom is 2.8.1, magnesium atom
2.8.2 and aluminium atom is 2.8.3
Have 3 shell occupied with electrons // same number of shell
occupied with electrons
1. electron arrangement of carbon atom is 2.4
2. electron arrangement of chlorine is 2.8.7
3. sharing electron4. to achieve octet electron arrangement
5. carbon atom contributes 4 electron and chlorine contributes 1electron // diagram
6. one carbon atom combine with 4 chlorine atom // diagram
1
1
1
11
1
1
1
1
1
11
1
1
2
3
3
6
Cll
Cl
Cl ClC
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8/8/2019 Chem Answer Paper 2 Final
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SULIT 4541/2 (PP)
[Lihat sebelah
4541/2 (PP) 2010 Hak Cipta JKD Kimia Daerah Kluang SULIT
8
Q No. Explanation MarksTotal
Mark
(ii) 1. electron arrangement of oxygen atom is 2.6
2. electron arrangement of sodium atom is 2.8.1
3. to achieve octet electron arrangement
4. sodium atom donate 1 electron to form Na
+
// diagramOxygen atom accept 2 electron to form O2-
5. electrostatic force between sodium ion and oxide ion
6. to form a compound with formula Na2O // diagram
1
1
1
1
1
1 6
Total 20
8. (a)
(b) (i)
(ii)
- Nucleus is at the centre of the atom.
- Atom contains one proton and one neutron //
proton number =1 and nucleon number = 2a : 1 number of proton
r : has 1 proton number, 1 number of nucleon
- electron moves around the nucleus // electron is locatedoutside the nucleus
- electron is negatively charged // the electron has -1 charged.
- electron arrangement is 1[any 4 points]
note : adp atom for element
- The same number of proton // same value of proton number
- The same number of electron // the same number of valence
electron
r : electron number / same valence electron
- The same chemical properties.
- Different number of neutron // different nucleon number
r : number of nucleon , neutron number- Different physical properties
a : comparison of any specific physical properties
[any 4 points]
H31 r: Y1
3
- state correct symbol of element for isotope H-3 ; H
- state correct of proton number (1) and nucleon number (3)
1
1
1
1
1
1
1
1
1
1
1
1
4
4
2
(c) At t0 t1
- element X is in liquid state
- the particles / molecules arrangement are closed but not in
orderly manner // not very closely pack
- the kinetic energy increases (as temperature increase)r : the particles move faster
At t1 t2- element X in (the mixture of) liquid and gas states
1
1
1
1
3
Na NaO
2 -+ +
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8/8/2019 Chem Answer Paper 2 Final
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8/8/2019 Chem Answer Paper 2 Final
9/11
SULIT 4541/2 (PP)
[Lihat sebelah
4541/2 (PP) 2010 Hak Cipta JKD Kimia Daerah Kluang SULIT
10
No Explanation MarksTotal
Mark
(b) (i)
CH2 C2H4
Type of
elements
Carbon and hydrogen Carbon and hydrogen
No of atom in
element
1 carbon atom and 2
hydrogen atoms
2 carbon atoms and 4
hydrogen atoms
Relative mass 14 28
1
1
1 3
(ii) [Experiment to determine the empirical formula of Y oxide]
Materials 10 cm Y ribbon/strip, sand paper
Apparatus crucible with lid, tongs, Bunsen burner, tripod stand,
pipe clay triangle, (electronic) balance
1
1 2
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SULIT 4541/2 (PP)
[Lihat sebelah
4541/2 (PP) 2010 Hak Cipta JKD Kimia Daerah Kluang SULIT
11
No Explanation MarksTotal
Mark
Procedure :
1. A crucible with its lid is weighed.
2. Y strip is cleaned with sandpaper and is placed in a crucible.
3. The crucible, its lid and the contents are weighed again.
4. The crucible is heated strongly (until the Y lights up). As soon as
the Y starts to burn, the crucible is closed by its lid.
5. The heating is continued and the crucible lid is opened once in a
while // (open and shut in short of time.
6. When the magnesium tape is no longer burnt, the lid is
removed and the crucible is heated strongly (to ensure the
complete burning of the magnesium).
7. The crucible and its contents are left to cool to room
temperature and are weighed again.
Max marks for procedures is 5
1
11
1
1
1
1
5
Precautionary step:
The crucible and its contents are heated, cooled and weighed again
until a constant mass is obtained. 1 1
Tabulation of data:
Description Mass(g)
Crucible + lid a
Crucible + lid + Y b
Crucible + lid + Y oxide c 1 1
Calculation :
Mass of Y = b - a Mass of O = c - b
No of mole of Y = b - a no of mole of O = c - b
24 16
Simplest ratio r s
Empirical formula Yr Os
1
1
1 12
Total 20
10. (a) (i)
(ii)
Soluble salts : Potassium sulphate and zinc sulphate
Insoluble salt : Lead (II) sulphate
For K2SO4 : Potassium hydroxide and sulphuric acid (solution)
For ZnSO4 : Sulphuric acid (solution) and zinc (metal) / zinc oxide
1
1
1
1 4
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8/8/2019 Chem Answer Paper 2 Final
11/11
SULIT 4541/2 (PP)
[Lihat sebelah
4541/2 (PP) 2010 Hak Cipta JKD Kimia Daerah Kluang SULIT
12
Heat
No Explanation MarksTotal
Mark
/ zinc carbonate
(b) [Experiment to prepare the dry soluble salt][Labelled diagram]
- functional diagram
- correctly labelled
[Method]
1. Heat the solution/mixture until saturated solution / crystal isformed.
2. Cool the mixture
3. Filter the salt crystals / solids.
4. Dry the salt by using filter papers.
1
1
1
1
1
1 6
(c) Acid A : hydrochloric acid / nitric acid / sulphuric acid.
Acid B : ethanoic acid / methanoic acid (or any organic acid)(examples of acids must be named)
Acid A / HCl is a strong acid.
It dissociates/ionize in water completely // It has the high
concentration of H+
ions in water (that lower the pH value).
Acid B / CH3COOH is a weak acid.
It dissociates/ionize partially in water. // It has low concentration of
H+
ion in water (that higher the pH value).Apply adp for in water
11
1
1
1
1 6
(d) Ethanoic acid / vinegar / lemon juice.
Reasons;
1. weak acid
2. neutralise the alkali
3. does not produce too much heat
4. less/not corrosive
Choose any 3 reasons
1
1
1
1
1
4
Total 20
END OF MARKING SCHEMEPERATURAN PEMARKAHAN BERAKHIR
Salt solution
Evaporating dish