chapter v wave theory 5.1 derivation of one dimensional wave equation v- wave theory.pdf · 5.1...

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71 CHAPTER V WAVE THEORY 5.1 DERIVATION OF ONE DIMENSIONAL WAVE EQUATION The wave equation in the one dimensional case can be derived from Hooke's law in the following way: Imagine an array of little weights of mass m are interconnected with mass less springs of length h and the springs have a stiffness of k . Here () ux measures the distance from the equilibrium of the mass situated at x . The forces exerted on the mass m at the location x h are 2 Newton 2 . () . ( ,) F mat m ux ht t (5.1) Hooke 2 [( 2,) ( , )] [(,) ( , )] x h x F F F kux ht ux ht kuxt ux ht (5.2) The equation of motion for the weight at the location x h is given by equating these two forces. 2 2 ( ,) [( 2,) ( ,) (,) ( , )] ux ht m kux ht ux ht uxt ux ht t (5.3) where the time-dependence of () ux has been made explicit. If the array of weights consists of N weights spaced evenly over the length . L Nh of total mass . M Nm , and the total stiffness of the array K kN then we can write the above equation as: 2 2 2 2 ( ,) [( 2,) 2( ,) ( , )] ux ht KL ux ht ux ht uxt t M h (5.4) Taking the limit , 0 N h (and assuming smoothness) one gets

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Page 1: CHAPTER V WAVE THEORY 5.1 DERIVATION OF ONE DIMENSIONAL WAVE EQUATION V- Wave Theory.pdf · 5.1 DERIVATION OF ONE DIMENSIONAL WAVE EQUATION The wave equation in the one dimensional

71

CHAPTER V

WAVE THEORY

5.1 DERIVATION OF ONE DIMENSIONAL WAVE EQUATION

The wave equation in the one dimensional case can be derived from Hooke's law in

the following way: Imagine an array of little weights of mass m are interconnected

with mass less springs of length h and the springs have a stiffness of k .

Here ( )u x measures the distance from the equilibrium of the mass situated at x . The

forces exerted on the mass m at the location x h are

2

Newton 2. ( ) . ( , )F m a t m u x h t

t

(5.1)

Hooke 2 [ ( 2 , ) ( , )] [ ( , ) ( , )]x h xF F F k u x h t u x h t k u x t u x h t (5.2)

The equation of motion for the weight at the location x h is given by equating these

two forces.

2

2

( , )[ ( 2 , ) ( , ) ( , ) ( , )]

u x h tm k u x h t u x h t u x t u x h t

t

(5.3)

where the time-dependence of ( )u x has been made explicit.

If the array of weights consists of N weights spaced evenly over the length .L N h

of total mass .M N m , and the total stiffness of the array K k N then we can write

the above equation as:

2 2

2 2

( , ) [ ( 2 , ) 2 ( , ) ( , )]u x h t KL u x h t u x h t u x t

t M h

(5.4)

Taking the limit , 0N h (and assuming smoothness) one gets

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2 2 2

2 2

( , ) ( , )u x t KL u x t

t M x

(5.5)

2KL

Mis the square of the propagation speed in this particular case. Taking 2c

2KL

Mwe

have the one dimensional wave equation as

2 2

2 2 2

( , ) 1 ( , )u x t u x t

x c t

(5.6)

with some initial and boundary conditions.

5.2 SOLUTION OF ONE DIMENSIONAL WAVE EQUATION

The one-dimensional wave equation can be solved exactly by D'Alembert's solution,

Fourier transform method, or via separation of variables. D'Alembert devised his

solution in 1746, and Euler subsequently expanded the method in 1748. Let us

consider andx ct x ct . (5.7)

Applying the chain rule to obtain

. .u u u u u

x x x

(5.8)

. .u u u u u

ct t t

(5.9)

2 2 2 2

2 2 22

u u u u u u u u

x x

(5.10)

2 2 2 22 2

2 2 22

u u u u u u u uc c c

t t

(5.11)

Substituting (5.10) and (5.11) in (5.6) we have the wave equation of the following

form

2

0u

(5.12)

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Therefore, the solution of the wave equation takes the form

( , ) ( ) ( )u F G (5.13)

( , ) ( ) ( )u x t F x ct G x ct (5.14)

where F and G are arbitrary functions, with F representing a right-travelling wave

and G represents the left-travelling wave. The function F and G can be found

explicitly by using the boundary condition and the initial conditions.

5.2.1 SEMI-INFINITE STRING WITH FIXED END

For Semi-infinite string with fixed end the wave equation takes the form

2 2

2 2 2

( , ) 1 ( , ), 0, 0

u x t u x tt x

x c t

(5.15)

with boundary condition (0, ) 0u t (5.16)

and the initial condition ( ,0) ( ) ; ( ,0) ( )tu x f x u x g x (5.17)

Clearly the solution of the Eq. 5.15 will take the form

( , ) ( ) ( )u x t F x ct G x ct (5.18)

Applying the boundary condition 5.17 we have

( ) ( ) ( )F x G x f x (5.19)

0

1 1( ) ( ) ( ) ( ) ( ) ( )

x

F x G x g x F x G x g x dxc c

(5.20)

Solving Eqs. 5.19 and 5.20 we have

0 0

1 1 1 1( ) ( ) ( ) and ( ) ( ) ( )

2 2 2 2

x x

F x f x g x G x f x g xc c

(5.21)

Substituting 5.21 in 5.18 we have

0 0

1 1 1 1( , ) ( ) ( ) ( ) ( )

2 2 2 2

x ct x ct

u x t f x ct g x dx f x ct g x dxc c

0

0

1 1 1( , ) ( ) ( ) ( ) ( )

2 2 2

x ct

x ct

u x t f x ct f x ct g x dx g x dxc c

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1 1

( , ) ( ) ( ) ( )2 2

x ct

x ct

u x t f x ct f x ct g x dxc

(5.22)

Now we introducing a function 0

( ) ( )

z

S z g x dx

Therefore, 1 1

( , ) ( ) ( ) ( ) ( )2 2

u x t f x ct f x ct S x ct S x ctc

Applying the boundary condition 5.16 we have

( ) ( ) and ( ) ( )f ct f ct S ct S ct

Therefore, we rewrite the solution as follows

1 1

( , ) ( ) ( ) ( ) ( )2 2

u x t Y x ct Y x ct H x ct H x ctc

(5.23)

where

( ) ( ) 0 ( ) ( ) 0

( ) 0 ( ) 0

Y z f z z H z S z z

f z z S z z

,0

( ) ( )

z

S z g x dx (5.24)

Eqs. 5.22 is implemented in the MATLAB function „Semi_Infinite_String_Calc‟and

is given in Table 5.1.

Table 5.1: Semi_Infinite_String_Calc

%******************************************************************** % Wave Equation For Semi Infinite String Calculation

%******************************************************************** function [X,U]= Semi_Infinite_String_Calc(c,L,t,fx,gx) %c ----> Wave Speed.

%L ----> Max Length upto which you want to view the motion.

%t ----> Time.

%fx ----> Initial displacement function.

%gx ----> Initial velocity function.

%Use MATLAB syntax with mpower concept. Suppose f(x)= e-(x-5)^2. So you

have to write fx= @(x) exp(-(x-5).^2). X=0:0.01:L;

val1= X+c*t;val2= X-c*t; for i=1:1: length(val2) if t== 0 U=gx(X); end if t~=0 Y1= fx(val1(i)); if val2(i)>=0 Y2= fx(val2(i)); end if val2(i)< 0 Y2= -fx(-val2(i)); end YY= (Y1+Y2)*0.5; R1= 0:val1(i)/100:val1(i); vel1= gx(R1);

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H1= trapz(vel1)*val1(i)/100; if val2(i)>=0 R2=0:val2(i)/100:val2(i); end if val2(i)< 0 R2=0:val2(i)/100:-val2(i); end vel2= gx(R2); H2= trapz(vel2)*val2(i)/100; HH= (H1-H2)*0.5/c; U(i)= YY+HH; end end end %-------------------------End of the Function------------------------

Consider a semi infinite string with wave speed 2 m/s where the initial condition are

2( ) exp( ( 5) ) and ( ) 0f x x g x then comparison in the position of the string for

different time are tabulated in the Table 5.2.

Table 5.2 Comparison of the Position of a semi infinite string

Time = 1 sec Time = 2 sec

Time = 3 sec Time = 4 sec

Time = 5 sec Time = 6 sec

Time 7 sec Time 10 sec

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5.2.2 FINITE STRING WITH FIXED END

For finite string with fixed end the wave equation takes the form

2 2

2 2 2

( , ) 1 ( , )u x t u x t

x c t

(5.25)

with boundary condition (0, ) 0 and ( , ) 0u t u L t (5.26)

and the initial condition ( ,0) ( ) and ( ,0) ( )tu x f x u x g x (5.27)

Clearly the solution of the Eq. 5.15 will take the form

( , ) ( ) ( )u x t F x ct G x ct (5.28)

Applying the boundary condition 5.27 we have

1 1

( , ) ( ) ( ) ( )2 2

x ct

x ct

u x t f x ct f x ct g x dxc

Now we introducing a function 0

( ) ( )

z

S z g x dx

Therefore, 1 1

( , ) ( ) ( ) ( ) ( )2 2

u x t f x ct f x ct S x ct S x ctc

Applying the boundary condition 5.26 we have

( ) ( ) and ( ) ( )f ct f ct S ct S ct

( ) ( ) and ( ) ( )f L ct f L ct S L ct S L ct

Setting ct and L ct we have

( ) ( ) and ( ) ( )f f S S

( ) (2 ) and (2 ) ( )f f L S L S

Combining above two we have

( ) ( ( 2 )) ( ) ( ( 2 ))

( 2 ) ( 2 )

f f L S S L

f L S L

Setting 2 wehave ( ) ( 2 ) and ( ) ( 2 ).z L f z f z L H z H z L

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Therefore, both the function are defined for all values of z and also periodic in z ,

repeating itself at intervals of 2L all along its length. Therefore, we rewrite the

solution as follows

1 1

( , ) ( ) ( ) ( ) ( )2 2

u x t Y x ct Y x ct H x ct H x ctc

(5.29)

where

( ) 0

( ) 0

( ) (2 ) 2

( 2 ) 2 3

................

f z L z

f z z L

Y z f L z L z L

f z L L z L

(5.30)

( ) 0

( ) 0

( ) (2 ) 2

( 2 ) 2 3

................

S z L z

S z z L

H z S L z L z L

S z L L z L

, 0

( ) ( )

z

S z g x dx (5.31)

Eqs. 5.29, 5.30 and 5.31 is implemented in the MATLAB function „ Finite _ String _

Calc‟ is given in Table 5.3.

Table 5.3: Finite_String_Calc

%****************************************************************** % Wave Equation For Finite String Calculation %****************************************************************** function [X,U]= Finite_String_Calc(c,L,t,fx,gx) %c ----> Wave Speed. %L ----> String Length %t ----> Time. %fx ----> Initial displacement function. %gx ----> Initial velocity function. %Use MATLAB syntax with mpower concept. Suppose f(x)= e-(x-5)^2. %So you have to write fx= @(x) exp(-(x-5).^2). X= 0:0.1:L; for i=1:1:length(X) Z = [X(i) - c*t, X(i) + c*t]; for m = 1: 1: length(Z) z1=Z(m) ;n1 = z1/L;n2= n1+ 1; if (round (n1)<= n1), n= round(n2); end if (round (n1)> n1), n= round(n1); end if mod(n, 2)== 0 x=n*L- z1; A(m)= - fx(x);

limit = 0: x/100 : x;

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vel= gx(limit); B(m)= trapz(vel)*x/100; end if mod (n, 2)== 1 x=z1- (n-1)*L; A(m)= fx(x); limit = 0: x/100 : x; vel= gx(limit);B(m)= trapz(vel)*x/100; end end U(i) = 0.5*(A(1) + A(2))-0.5*c*(B(1)-B(2))/c; end end %-------------------------End of the Function----------------------

Consider a Finite string of length 10 m with wave speed 2 m/s where the initial

condition are 2( ) exp( 40( 1) ) and ( ) 0f x x g x then comparison in the position of

the string for different time are tabulated in the Table 5.4.

Table 5.4 Comparison of the Position of a finite string

Time = 1 sec Time = 2 sec

Time = 3 sec Time = 4 sec

Time = 5 sec Time = 6 sec

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79

Time 7 sec Time 8 sec

Time 9 sec Time 10 sec

5.3 NON-LINEAR WAVE EQUATION

The wave equation in an ideal fluid can be derived from hydrodynamics and the

adiabatic relation between pressure and density. The equation for conservation of

mass, Euler‟s equation (Newton‟s 2nd Law), and the adiabatic equation of state are

respectively (Jensen et al, 2000)

.( ) 0vt

(5.32)

( ) . 0v

p v vt

(5.33)

22

0 2

1( ) ...........

2S S

p pp p

(5.34)

and for convenience we define the quantity

2

S

pc

(5.35)

where c will turn out to be the speed of sound in an ideal fluid. In the above

equations, is the density, v

the particle velocity, p the pressure, and the subscript

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80

S denotes that the thermodynamic partial derivatives are taken at constant entropy.

The ambient quantities of the quiescent (time independent) medium are identified by

the subscript 0. We use small perturbations for the pressure and density,

0 ( )p p p t (5.36)

0 ( )t (5.37)

and note that ( )v t

is also a small quantity; that is, the particle velocity which results

from density and pressure perturbations is much smaller than the speed of sound.

Retaining higher-order terms in Eq. 5.32 and 5.33 yields a non-linear wave equation.

The non linear effects we include are contained in the quadratic density term in the

equation of state, Eq. 5.34, and the quadratic velocity term (the convection term) in

Euler‟s equation, Eq. 5.33. First multiply Eq. 5.34 by and take its divergence; next,

take the partial derivative of Eq. 5.32 with respect to time. Substituting one into the

other yields

22

2( )i j i jp v v

t

(5.38)

Here the indices ,i j = 1, 2, 3 indicate , ,x y z -components, respectively. Tensor

notation is used; repeated indices signify a summation (e.g., .i iv v ).

The first term on the right side of Eq. 5.38 can be rewritten using Eq. 5.34 and 5.35 as

2 2 2 20( )1( )

cp c

c

(5.39)

The convection term on the right side of the Eq. 5.38 is more difficult to evaluate, but

we can obtain an expression for it in the limit of small propagation angles with

respect to the main direction of propagation, e.g., the x -direction. Then we may

estimate iv using the linear impedance relation, to be later derived as Eq. 5.53,

together with the equation of state 5.34

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2

, ( ) ( )0

i i x

cv O O

(5.40)

where ,i x is the Kroenecker delta symbol, so that

2 2 2

0

1( ) ( )i j i jv v c

(5.41)

Substituting Eq. 5.39 and 5.41 into Eq. 5.38, we obtain the nonlinear wave equation

22 2 2 2 3

2( ) ( , ) ....c O

t

(5.42)

where 0

is the density ratio and 0( )

1c

c

the nonlinear parameter of

the medium.

5.4 LINEAR WAVE EQUATION

The linear approximations which led to the acoustic wave equation, involve retaining

only the first order terms in the hydrodynamic equations. Applying the assumption

5.36 and 5.37 to the hydrodynamic equations Eq. 5.32 to 5.34 and then eliminating

second the order terms (products of small quantities), we have linearized equations as

0 . 0vt

(5.43)

0 ( ) 0v

pt

(5.44)

2p c (5.45)

5.4.1 WAVE EQUATION FOR PRESSURE

Considering that the time scale of oceanographic changes is much longer than the time

scale of acoustic propagation, we will assume that the material properties 0 and 2c are

independent of time t .

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82

Now, we can eliminate v

from Eqs. 5.43 and 5.44 to obtained the wave equation for

pressure and to do so we take the partial derivative of Eq. 5.33 with respect to time t

and then the divergence of Eq.5.44 and combining this two relation we have

0 0. .v

v pt t t

2

0 02. . . ( )

vv p

t t t

2

0 02. . . ( )

v vp

t t t

22

20p

t

Using the Eq. 5.45 we have

22

2 2

10

pp

c t

22

2 2

1. . 0

pi e p

c t

(5.46)

We have omitted the primes using the pressure and density perturbations. This is the

most fundamental equation of acoustics.

It describes the properties of a sound field in space and time and how those properties

evolve. It is quite unlike the incompressible flow equations to which you may be

accustomed because it describes very weak processes which happen over large

distances. The most fundamental obvious property of the wave equation is that it is

linear. This means that the sum of two solutions of the wave equation is also itself a

solution.

If the density is not in-depended of t then the wave equation takes the form

2

2 2

1 1. 0

pp

c t

(5.47)

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5.4.2 WAVE EQUATION FOR PARTICLE VELOCITY

Alternatively, we can take the divergence of Eq. 5.43 and the time derivative of Eq.

5.44, and combine the two using Eq. 5.55 to arrive at the wave equation for the

particle velocity,

22

2

1( . ) 0

vc v

t

(5.48)

and if the density is in-depended of t then the wave equation takes the form

22

2( . ) 0

vc v

t

(5.49)

This form of the wave equation is a vector equation coupling the three spatial

components of the particle velocity. It involves spatial derivatives of both density and

sound speed, and is therefore rarely used, except for uni-axial propagation problems.

5.4.3 WAVE EQUATION FOR VELOCITY POTENTIAL

22

2

1( . ) 0

vc v

t

If the density is constant or slowly varying, the vector equation 5.48 can be

transformed into a simple scalar wave equation by introducing the velocity potential,

defined by

v

(5.50)

Substituting Eq. 5.50 together with the constant density condition 0

, into Eq.

5.48, the latter takes the form

22 2

2( ) 0c

t

(5.51)

This equation is clearly satisfied if satisfies the simple wave equation

22

2 2

10

c t

(5.52)

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which is identical to the pressure wave equation 5.46. Both equations are valid for

varying sound speed, but for constant density only.

We note that there is simple relationship between velocity and pressure for plane-

wave solutions to the wave equation. This impedance relation is easily found using

the velocity potential form of the wave equation with the solution, ( )f x ct .

From Eq. 5.50, ( )xv f x ctx

and from the linearized Euler‟s equation 5.44,

0 ( )p cf x ctx

, where f denotes a derivative with respect to the

argument of the function f . Comparing the pressure and velocity expressions yields

the plane wave impedance relation as,

0

x

pC

v (5.53)

5.4.4 WAVE EQUATION FOR DISPLACEMENT POTENTIAL

By using the kinematics relation between velocity and displacementu

vt

, it is

easily shown that the displacement potential defined by

u (5.54)

and it is as well governed by the following simple wave equation,

22

2 2

10

c t

(5.55)

As was the case for other wave equations 5.46 and 5.52, 5.55 is also valid only for

media with constant density. However, discrete changes in density can be handled

through appropriate boundary conditions between regions of constant density. For

such problems the boundary conditions require continuity of pressure and

displacement (or velocity), and the potentials become discontinuous.

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85

From the kinematic relations between displacements and velocities, Eq. 5.43, 5.45,

and 5.54, we obtain the following expression for the acoustic pressure in terms of the

displacement potential,

2p K (5.56)

with K being the bulk modulus, when

2K c (5.57)

Eq. 5.56 denotes the constitutive relation for an ideal, linearly elastic fluid (Hook‟s

Law). Combination of Eq. 5.55 to 5.57, yields the alternative expression for the

acoustic pressure

2

2p

t

(5.58)

5.5 SOURCE REPRESENTATION

Underwater sound is produced by natural or artificial phenomena through forced mass

injection. Such forcing terms were neglected in the mass conservation equation 5.43,

and therefore also in the derived wave equations. However, such terms are easily

included, leading to inhomogeneous wave equations, e.g., for the displacement

potential

22

2 2

1( , )f r t

c t

(5.59)

where ( , )f r t represents the volume injection as a function of space and time. Similar

inhomogeneous forms of the wave equations for pressure or velocity are easily

derived.

5.6 THE HELMHOLTZ EQUATION

Since the coefficients to the two differential operators in Eq. 5.59 are independent of

time, the dimension of the wave equation can be reduced to three by use of the

frequency-time Fourier transform pair,

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86

1( ) ( )

2

i tf t f e d

(5.60)

1( ) ( )

2

i tf f t e dt

(5.61)

leading to the frequency-domain counterpart of the wave equation, or the Helmholtz

equation,

2 2[ ( )] ( , ) ( , )k r r f r (5.62)

where ( )k r is the medium wave number at radial frequency , and is given by

( )( )

k rc r

(5.63)

It should be pointed out that although the Helmholtz equation 5.62, due to the

reduction in the dimension of this PDE, is simpler to solve than the full wave

equation, Eq. 5.59, this simplification is achieved at the cost of having to evaluate the

inverse Fourier transform, Eq. 5.60. However, many ocean acoustic applications are

of narrow-band nature. The Helmholtz equation, rather than the wave equation,

therefore forms the theoretical basis for the most important numerical methods,

including the Wave number Integration (WI), Normal Mode (NM) and Parabolic

Equation (PE) approaches (Jensen et al, 2000).

It is important to stress the difference between narrow-band processing in Ocean

Acoustics and wide band processing in seismic. The latter approach is viable because

the length scale of the environmental features addressed in seismic experiments is of

the same order of magnitude as the seismic wavelengths, and the time scales of the

experiments are such cross-spectral coherence can be assumed. In other words,

seismic experiments are characterized by very few interactions with any single

boundary, whereas a typical ocean acoustic experiment can have hundreds or

thousands of interactions. This is basically the reason why time-domain approaches

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such as FDM and FEM have never gained widespread popularity in ocean acoustics

whereas they are very important numerical analysis tools in seismic community.

There is, however, much virtue to time-domain solutions in terms of physical

understanding, and time-domain solutions are produced routinely for exactly that

purpose, both by Fourier synthesis and by direct time-domain solutions of the wave

equation.

5.7 THE COORDINATE SYSTEMS

In a homogeneous medium, the homogeneous Helmholtz equation, Eq. 5.62, is easily

solved, with a choice of coordinate system being imposed by the source and boundary

geometry. Thus, if plane wave propagation is considered, a Cartesian coordinate

system r ( , , )x y z is the natural choice, with the Lap lace operator,

2 2 22

2 2 2x y z

(5.64)

yielding plane wave solutions of the form

( , , )r

r

ik

ik

Aex y z

Be

(5.65)

where ( , , )x y zk k k k is the wave vector and A and B are arbitrary amplitudes and r is

the radial coordinate. For a single plane wave component, the coordinate system can

be aligned with the propagation direction, e.g., with , 0y zk ,k yielding the simple

solution ( , , )x

x

ik

ik

Aex y z

Be

(5.66)

which corresponds to a forward and a backward propagating plane wave solution with

time dependence i te .

Similarly, the field produced by an infinite, homogeneous line source is conveniently

described in a cylindrical coordinate system r ( r, ,z ) , for which case given by

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2 22

2 2 2

1 1( )r

r r r r z

(5.67)

where r denotes the radial coordinates, the circumferential coordinate and z the

axial coordinate.

For a uniform line source, the field only varies with range r , reducing the Helmholtz

equation to the Bessel equation,

21( ) ( ) 0r k r

r r r

(5.68)

with the solution

0 0( ) J ( ) or Y ( )r A kr B kr (5.69)

where 0 0J and Y denote the Bessel functions of first and second kinds.

In terms of the Hankel functions, the solution in Eq. (5.66) may be written as

0

(1)

0 0 0

(2)

0 0

CH ( ) C[J ( ) Y ( )]

( )

DH ( ) D[J ( ) Y ( )]

kr kr i kr

r

kr kr i kr

(5.70)

The solution in Eq. (5.67) represents diverging and converging cylindrical and waves

for r , as is clear from the asymptotic form of the Hankel functions for kr ,

( )(1) 40

2H ( )

i kr

kr ekr

(5.71)

( )(2) 40

2H ( )

i kr

kr ekr

(5.72)

These asymptotic also show that the cylindrically symmetric field produced by a line

source decays in amplitude proportionally to 1/ 2r . Approaching the source, the line

source field exhibits a logarithmic singularity (Jensen et al, 2000).

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89

In case of an Omni-directional point source, the field only depends on the range from

the source, and the solution is conveniently described in a spherical coordinate

system, with the reduced Helmholtz equation being

2 21( ) 0r k r

r r r

(5.73)

which has the solutions A B

( ) orikr ikrr e er r

(5.74)

Again the solution in Eq. 5.74 correspond to diverging and converging spherical

waves with amplitude decaying proportional to 1r in spherical range. The term

geometrical spreading loss refers to these amplitude decays. Thus, cylindrical

spreading loss is proportional to 1r and spherical spreading loss is 2r .

5.8 CIRCULAR MEMBRANE

When we studied the one-dimensional wave equation we found that the method of

separation of variables resulted in two Simple Harmonic Oscillator. Here we are

interested in the next level of complexity, when the ODEs which arise upon

separation may be different from the familiar SHO equation. This complexity arises

when non-cartesian coordinate systems are used.

We choose polar coordinate system and therefore the wave equation reduces to

2 2 2

2 2 2 2 2

( , , ) 1 ( , , ) 1 ( , , ) 1 ( , , )u r t u r t u r t u r t

r r r r c t

(5.75)

where ( , , )u r t is the vertical vertical displacement of a point on the membrane at

position ( , )r and time t .

For the sake of the solution of this problem we choose separation of variables and so

substituting ( , , ) ( ) ( ) ( )u r t R r T t (5.76)

in Eq. 5.75 we have

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2 2 2

2 2 2 2 2

1 1 1( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )

R R TT t T t T t R r R r

r r r r c t

2 2 2

2 2 2 22

2

1 1

1

( ) ( ) ( )

R R T

r r r r t kR r c T t

2 22 2 2

22 22 2 2

2and 0

( ) ( )

R Rr r k r R

Tr r m m c TR r t

22 2 2 2

2

22

2

22 2

2

( ) 0

0

0

R Rr r k r m R

r r

m

Tk c T

t

(5.77)

The solution of the above equations 5.77 are well established and the solutions are

( ) ( ) ( ) ;

( ) cos( ) sin( )

( ) cos( ) sin( )

m mR r AJ kr BY kr

C m D m

T t E kct F kct

(5.78)

We see that in this problem of circular membrane the function ( )mY kr are not allowed

as they go to as 0r therefore only the functions ( )mJ kr are permitted as they

are finite at 0r . The profile of the disturbance across the circular membrane will

then be described by functions of the form

( ) ( )

( ) cos( ) sin( )

( ) cos( ) sin( )

mR r AJ kr

B m C m

T t D kct E kct

(5.79)

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91

Boundary conditions:

The boundary condition is that the edge of the circular membrane is fixed so that it

cannot be displaced. This means that if where R be the radius of the membrane then

( ) 0mJ kR (5.80)

This determines the allowed values of k since kR must correspond to a zero of the

function ( )mJ kR .In other words, if mn are the n th positive roots of ( ) 0mJ s then

mnmnk

R

, where 0,1, 2,........and 1, 2,........m n . (5.81)

Therefore from the relation 5.76 we have the complete solution as

0

1

( , , ) cos( ) sin( ) cos( ) sin( ) ( )mn mn mn mn m m m mn

mn

u r t a k ct b k ct c m d m J k r

(5.82)

Initial Conditions:

For practical purpose we assume that the membrane is at rest i.e. ( , ,0) 0tu r and

( ,0, ) 0u r t .

Hence, applying this in Eq. 5.82 it is clear that the term sin( )mnk ct and sin( )m is no

longer needed. Therefore,

01

( , , ) cos( )cos( ) ( )mn mn m mn

mn

u r t a k ct m J k r

(5.83)

With another appropriate initial condition we can easily find mna and using the

equation 5.83 we will have the complete solution.

According to our assumption that the ( , ,0) 0tu r and ( ,0, ) 0u r t the (m, n) th

mode shape will be of the following form

( , ) cos( )cos( ) ( )mn m mnm n k ct m J k r (5.84)

where mnmnk

R

, mn is the n th positive roots of the ( ) 0mJ x . (5.85)

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92

Eq. 5.84 is implemented in the MATLAB function “ModeShape_Circular_Membrane

_Calc‟ and mnk are calculated by the MATLAB function “Find_nth_bessel_root”. is

given in Table 5.5 and 5.6 and the comparison of the mode shape for different values

of t is shown in the Table 5.7.

Table 5.5: ModeShape_Circular_Membrane_Calc

%**************************************************************

% Mode Shape Calculation

%**************************************************************

function [X,Y,U] =

ModeShape_Circular_Membrane_Calc(c,radius,m,n,t) %c ---> Wave Propagation Speed. %radius ---> Radius of the Circular Membrane. %m ---> m th asimuthal number. %n ---> n th root of the bessel function. Nth_root=Find_nth_bessel_root(m, n);

Q= Nth_root /radius;N=20; R1=linspace(0, radius, N);Theta1=linspace(0, 2*pi, N); [R, Theta]=meshgrid(R1, Theta1);[X,Y] = pol2cart(Theta,R); U=cos(c*Q*t)*besselj(m, Q*R).*cos(m*Theta); end

%-------------------------- END -------------------------------

Table 5.6: Find_nth_bessel_root

%**************************************************************

% Finding the n th root of the Bessel function

%**************************************************************

function [root] = Find_nth_bessel_root(k, p) X=0.5:0.5:(10*p+1); Y = besselj(k, X); tol=1e-5; [a, b] = Position_nth_root(X, Y, p); if a~= b check = abs(a-b);i=1; while check>= tol XX=a:(b-a)/100:b; YY = besselj(k, XX); [a, b] = Position_nth_root(XX, YY, 1); i=i+1;check = abs(a-b); end end root=(a+b)/2; end function [a, b] = Position_nth_root(X, Y, n) l=0; m=length(X); for i=1:1:(m-1) if ( Y(i)*Y(i+1) <= 0 ) l=l+1;end; if (l== n) a=X(i); b=X(i+1);return; end end end %-------------------------- END -------------------------------

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93

Table 5.7: Comparison of mode shape Circular Membrane

Time

sec (0,1) (1,1) (1,2)

0

1

2

3

4

5

Time

sec (0,2) (2,1) (2,2)

0

1

2

3

4

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94

5.8 RECTANGULAR MEMBRANE

To find the motion of a rectangular membrane with sides of length xL and yL (in

absence of gravity) use the two-dimensional wave equation of the form

2 2 2

2 2 2 2

( , , ) ( , , ) 1 ( , , )u x y t u x y t u x y t

x y c t

(5.86)

where ( , , )u x y t is the vertical displacement of the membrane at position ( , )x y and

time t .For the sake of the solution of this problem we choose separation of variables

and so substituting ( , , ) ( ) ( ) ( )u x y t X x Y y T t (5.87)

in Eq. 5.86 we have

5

Time

sec (0,3) (3,2) (0,4)

0

1

2

3

4

5

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95

2 2 2

2 2 2 2

1( ) ( ) ( ) ( ) ( ) ( )

X Y TY y T t X x T t X x Y y

x y c t

2 2 2 2 22

2 2 2

1

( ) ( ) ( )

c X c Y Tk

X x x Y y y T t t

2 2 2 22 2

2 2 2 2

1 1and 0x

X Y k Tk k T

X x Y y c t

2 2 22 2 2

2 2 20 ; 0 and 0x y

X X Tk X k X k T

x x t

(5.88)

where 2

2 2

2x y

kk k

c (5.89)

The solution of the above equations 5.88 are well established and the solutions are

( ) cos( ) sin( )

( ) cos( ) sin( )

( ) cos( ) sin( )

x x

y y

X x A k x B k x

Y y C k y D k y

T t E kt F kt

(5.90)

Boundary Condition:

The rectangular membrane fixed at all the boundaries ( 0, 0, , )x yx y x L y L that

means (0, , ) 0 ( ,0, )u y t u x t and ( ,0, ) 0 (0, , )x yu L t u L t .

Applying first two boundary condition we have 0A C and the second set of

boundary condition implies (for non trivial solution) sin( ) 0 sin( )x yk x k y that is

,x y

x y

m nk k

L L

, where 1, 2,........and 1, 2,........m n . (5.91)

Therefore from the relation 5.87 we have the complete solution as

11

( , , ) cos( ) sin( ) sin( )sin( )mn mn x y

mn

u x y t a kt b kt k x k y

(5.92)

where , andx yk k k are given in the Eq. 5.89 and 5.91.

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96

Initial Condition:

For practical purpose we assume that the membrane is at rest i.e. ( , ,0) 0tu x y

Hence, 11

( , , ) cos( )sin( )sin( )mn x y

mn

u x y t a kt k x k y

(5.93)

With another appropriate initial condition we can easily find mna and using the

equation 5.83 we will have the complete solution. According to our assumption that

the (0, , ) 0 ( ,0, )u y t u x t and ( ,0, ) 0 (0, , )x yu L t u L t the (m, n) th mode shape will

be of the following form ( , ) cos( )sin( )sin( )x ym n kt k x k y (5.94)

where 2 2, ,x y x y

x y

m nk k k c k k

L L

(5.95)

Eq. 5.94 and 5.95 is implemented in the MATLAB function

“ModeShape_Rectangular_Membrane_Calc‟ and given in the Table 5.8. The

comparison of the mode shape for different values of t is shown in the Table 5.9

where length and breadth of the membrane are 10 m each and the wave speed 1 m/s.

Table 5.8 : ModeShape_Rectangular_Membrane_Calc

%*****************************************************************

% Mode Shape for Rectangular Membrane

%*****************************************************************

function [X,Y,U] = MoedeShape_Rectangular_Calc(Lx,Ly,c,t,m,n)

%Lx ----> Length of the Membrane %Ly ----> Breadth of the Membrane %c ----> Wave Speed %m ----> Azhimuthal number for X %n ----> Azhimuthal number for Y %t ----> Time

kx= m*pi/Lx;

ky= n*pi/Ly;

k= c*sqrt(kx^2 + ky^2); [X,Y]=meshgrid( (0:0.01:1)*Lx, (0:0.01:1)*Ly); U = 5*cos(k*t)*sin(kx*X).*sin(ky*Y);

end

%---------------------- END ---------------------------

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97

Table 5.9: Comparison of mode shape Rectangular Membrane

Time (1,1) (1,2) (1,3)

0

1

2

3

4

5

Time (2,1) (2,2) (2,3)

0

1

2

3

4

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98

5

Time (3,1) (3,2) (3,3)

0

1

2

3

4

5