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    Conservation of Momentum in Inelastic Collisions

    Learning Goal: To understand the vector nature of momentum in the case in which two objects

    ollide and stick together.

    n this problem we will consider a collision of two moving objects such that after the collision, the

    bjects stick together and travel off as a single unit. The collision is therefore completely inelastic

    You have probably learned that "momentum is conserved" in an inelastic collision. But how does

    his fact help you to solve collision problems? The following questions should help you to clarify

    he meaning and implications of the statement "momentum is conserved."

    Part A

    What physical quantities are conserved in this collision?

    ANSWER:the magnitude of the momentum onlythe net momentum (considered as a vector) only

    the momentum of each object considered individually

    Part B

    Two cars of equal mass collide inelastically and stick together after the collision. Before the

    collision, their speeds are and . What is the speed of the two-car system after the collision?

    Hint B.1 How to approach the problem

    Hint not displayed

    ANSWER:

    The answer depends on the directions in which the cars were moving before

    the collision.

    Part C

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    Two cars collide inelastically and stick together after the collision. Before the collision, the

    magnitudes of their momenta are and . After the collision, what is the magnitude of their

    combined momentum?

    Hint C.1

    Hint not displayed

    ANSWER:

    The answer depends on the directions in which the cars were moving before

    the collision.

    Part D

    Two cars collide inelastically and stick together after the collision. Before the collision, their

    momenta are and . After the collision, their combined momentum is . Of what can one be

    certain?

    Hint D.1 Momentum is a vector

    Hint not displayed

    ANSWER:

    You can decompose the vector equation that states the conservation of momentum into individual

    equations for each of the orthogonal components of the vectors.

    Part E

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    Two cars collide inelastically and stick together after the collision. Before the collision, the

    magnitudes of their momenta are and . After the collision, the magnitude of their combined

    momentum is . Of what can one be certain?

    Hint E.1 How to approach the problem mathematically

    Hint not displayed

    Hint E.2 How to approach the problem empirically

    Hint not displayed

    ANSWER:

    When the two cars collide, the magnitude of the final momentum will always be at most

    value attained if the cars were moving in the same direction before the collision) and at least

    (a value attained if the cars were moving in opposite directions before the collision).

    Momentum and Internal Forces

    Learning Goal: To understand the concept of total momentum for a system of objects and the

    ffect of the internal forces on the total momentum.

    We begin by introducing the following terms:

    ystem:Any collection of objects, either pointlike or extended. In many momentum-related

    roblems, you have a certain freedom in choosing the objects to be considered as your system.

    Making a wise choice is often a crucial step in solving the problem.

    nternal force:Any force interaction between two objects belonging to the chosen system. Let us

    tress that both interacting objects must belong to the system.

    External force:Any force interaction between objects at least one of which does not belong to the

    hosen system; in other words, at least one of the objects is external to the system.

    Closed system:a system that is not subject to any external forces.

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    Total momentum:The vector sum of the individual momenta of all objects constituting the syste

    n this problem, you will analyze a system composed of two blocks, 1 and 2, of respective masses

    and . To simplify the analysis, we will make several assumptions:

    1. The blocks can move in only one dimension, namely, along thexaxis.

    2. The masses of the blocks remain constant.

    3. The system is closed.

    At time , thexcomponents of the velocity and the acceleration of block 1 are denoted by a

    . Similarly, thexcomponents of the velocity and acceleration of block 2 are denoted by

    nd . In this problem, you will show that the total momentum of the system is not changed b

    he presence of internal forces.

    Part A

    Find , thexcomponent of the total momentum of the system at time .

    Express your answer in terms of , , , and .

    ANSWER: =

    Part B

    Find the time derivative of thexcomponent of the system's total momentum.

    Hint B.1

    Hint not displayed

    Hint B.2

    Hint not displayed

    Express your answer in terms of , , , and .

    ANSWER: =

    Why did we bother with all this math? The expression for the derivative of momentum that we jus

    btained will be useful in reaching our desired conclusion, if only for this very special case.

    Part C

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    The quantity (mass times acceleration) is dimensionally equivalent to which of the following

    ANSWER: momentum

    energy

    force

    acceleration

    inertia

    Part D

    Acceleration is due to which of the following physical quantities?

    ANSWER: velocity

    speed

    energy

    momentum

    force

    Part E

    Since we have assumed that the system composed of blocks 1 and 2 is closed, what could be the

    eason for the acceleration of block 1?

    Hint E.1

    Hint not displayed

    ANSWER: the large mass of block 1

    air resistance

    Earth's gravitational attraction

    a force exerted by block 2 on block 1

    a force exerted by block 1 on block 2

    Part FWhat could be the reason for the acceleration of block 2?

    ANSWER: a force exerted by block 2 on block 1

    a force exerted by block 1 on block 2

    Part G

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    Let us denote thexcomponent of the force exerted by block 1 on block 2 by , and thex

    component of the force exerted by block 2 on block 1 by . Which of the following pairs

    equalities is a direct consequence of Newton's second law?

    ANSWER: and

    and

    and

    and

    Note that both and are internal forces.

    Part H

    Let us recall that we have denoted the force exerted by block 1 on block 2 by , and the force

    exerted by block 2 on block 1 by . If we suppose that is greater than , which of the

    following statements about forces is true?

    Hint H.1 Which of Newton's laws is useful here?

    Hint not displayed

    ANSWER:

    Both forces have equal magnitudes.

    Newton's third law states that forces and are equal in magnitude and opposite in direction

    Therefore, theirxcomponents are related by

    Part I

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    Now recall the expression for the time derivative of thexcomponent of the system's total

    momentum: . Considering the information that you now have, choose the best

    alternative for an equivalent expression to .

    Hint I.1 What is ?

    Hint not displayed

    ANSWER: 0

    nonzero constant

    The derivative of the total momentum is zero; hence the total momentum is a constant function of

    ime. We have just shown that for the special case of a closed two-block system, the internal

    forces do not change the total momentum of the system. It can be shown that in any system, the

    nternal forces do not change the total momentum: It is conserved. In other words, total

    momentum is always conserved in a closed system of objects.

    PSS 9.1: Tools of the Trade

    Learning Goal: To practice Problem-Solving Strategy 9.1 for problems involving conservation of

    momentum.

    An astronaut performs maintenance work outside her spaceship when the tether connecting her to

    he spaceship breaks. The astronaut finds herself at rest relative to the spaceship, at a distance

    rom it. To get back to the ship, she decides to sacrifice her favorite wrench and hurls it directly

    way from the spaceship at a speed relative to the spaceship. What is the distance between th

    paceship and the wrench by the time the astronaut reaches the spaceship?

    he mass of the astronaut is ; the mass of the wrench is .

    MODEL:Clearly define the system.

    If possible, choose a system that is isolated ( ) or within which the interactions are

    sufficiently short and intense that you can ignore external forces for the duration of the

    interaction (the impulse approximation). Momentum is conserved.

    If it is not possible to choose an isolated system, try to divide the problem into parts such

    that momentum is conserved during one segment of the motion. Other segments of the

    motion can be analyzed using Newton's laws or, as you'll learn in Chapters 10 and 11,

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    conservation of energy.

    ISUALIZE:Draw a before-and-after pictorial representation. Define symbols that will be used in

    he problem, list known values, and identify what you are trying to find.

    OLVE:The mathematical representation is based on the law of conservation of momentum:. In component form, this is

    ,

    SSESS:Check if your result has the correct units, is reasonable, and answers the question.

    We start by choosing the objects that would make up the system. In this case, it is possible to

    dentify the system that is isolated.

    Part A

    n addition to the astronaut, which of the following are components of the system that should be

    defined to solve the problem?

    A. the spaceship

    B. the wrench

    C. the earth

    Enter the letter(s) of the correct answer(s) in alphabetical order. Do not use commas. For example

    f you think the system consists of all the objects listed, enter ABC.

    ANSWER: B

    Part B

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    Which of the following reasons best explains why the astronaut + wrench can be considered an

    solatedsystem?

    ANSWER: The mass of the wrench is much smaller than that of the astronaut.

    The force that the astronaut exerts on the wrench is very small.

    The force that the astronaut exerts on the wrench is very large.

    The force that the spaceship exerts on the wrench is very small.

    The force that the spaceship exerts on the wrench is very large.

    Now draw a before-and-after pictorial representation including all the elements listed in the

    roblem-solving strategy. Be sure that your sketch is clear and includes all necessary symbols, bot

    nown and unknown. By the time the astronaut reaches the spaceship, the wrench will have cover

    certain distance; on your pictorial representation, label this distance .

    Part C

    After the wrench is thrown, the astronaut and the wrench move

    ANSWER: in opposite directions.

    in the same direction.

    in perpendicular directions.

    Part D

    Which statement about , , and is correct?

    ANSWER:

    Here is an example of what a good before-and-after pictorial representation might look like for

    his problem.

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    Now use the information and the insights that you have accumulated to construct the necessary

    mathematical expressions and to derive the solution.

    Part E

    Find the final distance between the spaceship and the wrench.

    Part E.1 Find

    Part not displayed

    Hint E.2

    Hint not displayed

    Express the distance in terms of the given variables. You may or may not use all of them.

    ANSWER: =

    When you work on a problem on your own, without the computer-provided feedback, only you ca

    ssess whether your answer seems right. The following questions will help you practice the skillsecessary for such an assessment.

    Part F

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    ntuitively, which of the following statements are correct?

    A. For realistic values of the quantities involved, it is possible that .

    B. If the astronaut threw a space pen instead of a wrench, the pen would travel further than th

    wrench would in the time it takes the astronaut to reach the ship. (Assume the space pen

    weighs less than the wrench).

    C. If the astronaut were more massive, the wrench would travel further in the time it takes the

    astronaut to reach the ship.

    Type the letters corresponding to the correct answers. Do not use commas. For instance, if you

    hink that only expressions C and D have the units of distance, type CD.

    ANSWER: BC

    could only be zero if . As you can see from your answer, this would only happen if

    he mass of the astronaut were zero, which is obviously unrealistic.

    Part G

    Which of the following mathematical expressions have the units of distance, where and are

    distances?

    A.

    B.

    C.

    D.

    E.

    F.

    Type the letters corresponding to the correct answers. Do not use commas. For instance, if you

    hink that only expressions C and D have the units of distance, type CD.

    ANSWER: ABE

    The Impulse-Momentum Theorem

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    Learning Goal: To learn about the impulse-momentum theorem and its applications in some

    ommon cases.

    Using the concept of momentum, Newton's second law can be rewritten as

    , (1)

    where is the netforce acting on the object, and is the rate at which the object's

    momentum is changing.

    f the object is observed during an interval of time between times and , then integration of bot

    ides of equation (1) gives

    . (2)

    he right side of equation (2) is simply the change in the object's momentum . The left sid

    called the impulse of the net forceand is denoted by . Then equation (2) can be rewritten as

    .

    his equation is known as the impulse-momentum theorem. It states that the change in an object's

    momentum is equal to the impulse of the net force acting on the object. In the case of a constant n

    orce acting along the direction of motion, the impulse-momentum theorem can be written as

    . (3)

    Here , , and are the componentsof the corresponding vector quantities along the chosen

    oordinate axis. If the motion in question is two-dimensional, it is often useful to apply equation (3

    o thexandycomponents of motion separately.

    he following questions will help you learn to apply the impulse-momentum theorem to the cases

    f constant and varying force acting along the direction of motion. First, let us consider a particle

    mass moving along thexaxis. The net force is acting on the particle along thexaxis. is a

    onstant force.

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    Part A

    The particle starts from rest at . What is the magnitude of the momentum of the particle at

    ime ? Assume that .

    Express your answer in terms of any or all of , , and .

    ANSWER: =

    Part B

    The particle starts from rest at . What is the magnitude of the velocity of the particle at

    ime ? Assume that .

    Express your answer in terms of any or all of , , and .

    ANSWER: =

    Part C

    The particle has momentum of magnitude at a certain instant. What is , the magnitude of its

    momentum seconds later?

    Express your answer in terms of any or all of , , , and .

    ANSWER: =

    Part D

    The particle has momentum of magnitude at a certain instant. What is , the magnitude of its

    velocity seconds later?

    Express your answer in terms of any or all of , , , and .

    ANSWER: =

    et us now consider several two-dimensional situations.

    A particle of mass is moving in the positivexdirection at speed . After a certain constant forc

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    applied to the particle, it moves in the positiveydirection at speed .

    Part E

    Find the magnitude of the impulse delivered to the particle.

    Hint E.1 How to approach the problem

    Hint not displayed

    Part E.2 Find the change in momentum

    Part not displayed

    Express your answer in terms of and . Use three significant figures in the numerical

    coefficient.

    ANSWER: =

    Part F

    Which of the vectors below best represents the direction of the impulse vector ?

    ANSWER: 1

    2

    3

    4

    5

    6

    7

    8

    Part G

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    What is the angle between the positiveyaxis and the vector as shown in the figure?

    ANSWER: 26.6 degrees

    30 degrees

    60 degrees

    63.4 degrees

    Part H

    f the magnitude of the net force acting on the particle is , how long does it take the particle to

    acquire its final velocity, in the positiveydirection?

    Express your answer in terms of , , and . If you use a numerical coefficient, use threeignificant figures.

    ANSWER: =

    o far, we have considered only the situation in which the magnitude of the net force acting on the

    article was either irrelevant to the solution or was considered constant. Let us now consider an

    xample of a varyingforce acting on a particle.

    Part I

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    A particle of mass kilograms is at rest at seconds. A varying force

    is acting on the particle between seconds and

    econds. Find the speed of the particle at seconds.

    Hint I.1

    Hint not displayed

    Part I.2

    Part not displayed

    Express your answer in meters per second to three significant figures.

    ANSWER: = 43.0

    Colliding Balls

    alls A and B roll across a table, then collide elastically. The paths of the two balls are pictured

    viewed from above) in the diagram.

    Part A

    Which set of arrows best represents the change in

    momentum for balls A and B?

    Hint A.1

    Hint not displayed

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    ANSWER: A B C D E

    Part B

    Which of the following arrows indicates the direction of the impulse applied to ball A by ball B?

    Hint B.1 Definition of impulse

    Hint not displayed

    ANSWER: A B C D

    E

    A Game of Frictionless Catch

    Chuck and Jackie stand on separate carts, both of which can slide without friction. The combined

    mass of Chuck and his cart, , is identical to the combined mass of Jackie and her cart. Initiall

    Chuck and Jackie and their carts are at rest.

    Chuck then picks up a ball of mass and throws it to Jackie, who catches it. Assume that the

    all travels in a straight line parallel to the ground (ignore the effect of gravity). After Chuck throw

    he ball, his speed relative to the ground is . The speed of the thrown ball relative to the ground

    .

    ackie catches the ball when it reaches her, and she and her cart begin to move. Jackie's speed

    elative to the ground after she catches the ball is .

    When answering the questions in this problem, keep the following in mind:

    1. The original mass of Chuck and his cart does not include the mass of the ball.

    2. The speed of an object is the magnitude of its velocity. An object's speed will always be a

    nonnegative quantity.

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    Part A

    Find the relative speed between Chuck and the ball after Chuck has thrown the ball.

    Hint A.1

    Hint not displayed

    Express the speed in terms of and .ANSWER:

    =

    Make sure you understand this result; the concept of "relative speed" is important. In general, if

    wo objects are moving in opposite directions (either toward each other or away from each other)

    he relative speed between them is equal to the sum of their speeds with respect to the ground. If

    wo objects are moving in the same direction, then the relative speed between them is the absolute

    value of the difference of the their two speeds with respect to the ground.

    Part B

    What is the speed of the ball (relative to the ground) while it is in the air?

    Hint B.1 How to approach the problem

    Hint not displayed

    Hint B.2 Initial momentum of Chuck, his cart, and the ball

    Hint not displayed

    Part B.3 Find the final momentum of Chuck, his cart, and the thrown ballPart not displayed

    Express your answer in terms of , , and .

    ANSWER: =

    Part C

    What is Chuck's speed (relative to the ground) after he throws the ball?Hint C.1

    Hint not displayed

    Express your answer in terms of , , and .

    ANSWER: =

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    Part D

    Find Jackie's speed (relative to the ground) after she catches the ball, in terms of .

    Hint D.1

    Hint not displayed

    Hint D.2

    Hint not displayed

    Part D.3

    Part not displayed

    Express in terms of , , and .

    ANSWER: =

    Part E

    Find Jackie's speed (relative to the ground) after she catches the ball, in terms of .

    Hint E.1

    Hint not displayed

    Express in terms of , , and .

    ANSWER:

    =

    A One-Dimensional Inelastic Collision

    lock 1, of mass = 2.10 , moves along a frictionless air track with speed = 27.0 . It

    ollides with block 2, of mass = 17.0 , which was initially at rest. The blocks stick together

    fter the collision.

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    Part A

    Find the magnitude of the total initial

    momentum of the two-block system.

    Hint A.1

    Hint not displayed

    Express your answer numerically.

    ANSWER: = 56.7

    Part B

    Find , the magnitude of the final

    velocity of the two-block system.

    Hint B.1

    Hint not displayed

    Express your answer numerically.

    ANSWER: = 2.97

    Catching a Ball on Ice

    Olaf is standing on a sheet of ice that covers the football stadium parking lot in Buffalo, New York

    here is negligible friction between his feet and the ice. A friend throws Olaf a ball of mass.400 that is traveling horizontally at 10.1 . Olaf's mass is 73.5 .

    Part A

    f Olaf catches the ball, with what speed

    do Olaf and the ball move afterward?

    Hint A.1

    Hint not displayed

    Part A.2

    Part not displayed

    Express your answer numerically in

    centimeters per second.

    ANSWER: = 5.47

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    Part B

    f the ball hits Olaf and bounces off his chest horizontally at 7.40 in the opposite direction,

    what is his speed after the collision?

    Hint B.1

    Hint not displayed

    Part B.2

    Part not displayed

    Express your answer numerically in centimeters per second.

    ANSWER: = 9.52