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Page 1: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

© 2010 Pearson Education, Inc.

PowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition

Chapter 8

Equilibrium and Elasticity

Page 2: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

© 2010 Pearson Education, Inc. Slide 8-2

8 Equilibrium and Elasticity

Page 3: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

© 2010 Pearson Education, Inc. Slide 8-3

Page 4: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

© 2010 Pearson Education, Inc. Slide 8-4

Page 5: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

© 2010 Pearson Education, Inc.

Reading Quiz 1. An object is in equilibrium if

A. Fnet = 0. B. τnet = 0. C. either A or B. D. both A and B.

Slide 8-5

Page 6: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

© 2010 Pearson Education, Inc.

Answer 1. An object is in equilibrium if

A. Fnet = 0. B. τnet = 0. C. either A or B. D. both A and B.

Slide 8-6

Page 7: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

© 2010 Pearson Education, Inc.

Reading Quiz 2. An object will be stable if

A. its center of gravity is below its highest point. B. its center of gravity lies over its base of support. C. its center of gravity lies outside its base of support. D. the height of its center of gravity is less than 1/2 its total

height.

Slide 8-7

Page 8: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

© 2010 Pearson Education, Inc.

Answer 2. An object will be stable if

A. its center of gravity is below its highest point. B. its center of gravity lies over its base of support. C. its center of gravity lies outside its base of support. D. the height of its center of gravity is less than 1/2 its total

height.

Slide 8-8

Page 9: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

© 2010 Pearson Education, Inc.

Reading Quiz 3. Hooke’s law describes the force of

A. gravity. B. a spring. C. collisions. D. tension. E. none of the above.

Slide 8-9

Page 10: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

© 2010 Pearson Education, Inc.

Answer 3. Hooke’s law describes the force of

A. gravity. B. a spring. C. collisions. D. tension. E. none of the above.

Slide 8-10

Page 11: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

© 2010 Pearson Education, Inc.

Torque and Static Equilibrium For an extended object to be in equilibrium, the net force and the net torque must be zero.

Slide 8-11

Page 12: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

© 2010 Pearson Education, Inc.

Choosing the Pivot Point

Slide 8-12

Page 13: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

© 2010 Pearson Education, Inc.

Solving Static Equilibrium Problems

Slide 8-13

Page 14: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

© 2010 Pearson Education, Inc.

Checking Understanding What does the scale read?

A. 500 N B. 1000 N C. 2000 N D. 4000 N

Slide 8-14

Page 15: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

© 2010 Pearson Education, Inc.

Answer What does the scale read?

A. 500 N B. 1000 N C. 2000 N D. 4000 N

Slide 8-15

Page 16: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

© 2010 Pearson Education, Inc.

Balance

For an object to balance, its center of gravity must reside over its base of support. That way gravity does not exert a torque.

Base of support

Gravity acts at the center of gravity.

Line of action

This force exerts no torque about her toes.

Slide 8-18

Page 17: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

© 2010 Pearson Education, Inc.

Stability of a Car: Critical angle

Slide 8-19

1tan2cth

θ − =

Page 18: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

© 2010 Pearson Education, Inc.

Tiptoeing Why can’t you stand on tiptoes if your toes are against a wall?

Center of gravity has to be over toes – the base of support – to balance. That requires shifting your body slightly forward. But you can’t shift your body forward if your toes are against the wall.

Slide 8-20

Page 19: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

© 2010 Pearson Education, Inc.

Tiptoeing Why can’t you stand on tiptoes if your toes are against a wall? Stated otherwise, what are the requirements for balance?

Slide 8-17

Page 20: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

Review: Hooke’s Law

An elastic system displaced from equilibrium oscillates in a simple way about its equilibrium position with

Simple Harmonic Motion.

Hooke’s Law describes the elastic response to an applied force.

Elasticity is the property of an object or material which causes it to be restored to its original shape after distortion.

Ut tensio, sic vis - as the extension, so is the force

Page 21: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

Importance of Simple Harmonic Oscillators

Simple harmonic oscillators are good models of a wide variety of physical phenomena

Molecular example If the atoms in the molecule do

not move too far, the forces between them can be modeled as if there were springs between the atoms

The potential energy acts similar to that of the SHM oscillator

Page 23: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

Hooke’s Law It takes twice as much force to stretch a spring twice as far.

The linear dependence of displacement upon stretching force:

appliedF kx=

Page 24: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

Hooke’s Law Stress is directly proportional to strain.

( ) ( )appliedF stress kx strain=

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Hooke’s Law: F = - k x

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Hooke’s Law: F = - k x

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Hooke’s Law: F = - k x

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Hooke’s Law: F = - k x

Page 29: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

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Hooke’s Law: F = - k x

Page 30: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

© 2010 Pearson Education, Inc.

The Spring Force

The magnitude of the spring force is proportional to the displacement of its end:

Fsp = k ∆x Slide 8-21

Page 31: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

© 2010 Pearson Education, Inc.

The spring force is directed oppositely to the displacement. We can then write Hooke’s law as

Hooke’s Law

(Fsp)x = –k ∆x

Slide 8-22

Page 32: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

© 2010 Pearson Education, Inc.

Checking Understanding Which spring has the largest spring constant?

Slide 8-23

Page 33: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

© 2010 Pearson Education, Inc.

Which spring has the largest spring constant?

Answer

A

Slide 8-24

Page 34: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

© 2010 Pearson Education, Inc.

Checking Understanding The same spring is stretched or compressed as shown below. In which case does the force exerted by the spring have the largest magnitude?

Slide 8-25

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© 2010 Pearson Education, Inc.

E. Not enough information to tell.

The same spring is stretched or compressed as shown below. In which case does the force exerted by the spring have the largest magnitude?

Answer

Slide 8-26

Page 36: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

© 2010 Pearson Education, Inc.

Example Problem A 20-cm-long spring is attached to a wall. When pulled horizontally with a force of 100 N, the spring stretches to a length of 22 cm. What is the value of the spring constant?

Slide 8-27

Page 37: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

© 2010 Pearson Education, Inc.

The same spring is now used in a tug-of-war. Two people pull on the ends, each with a force of 100 N. How long is the spring while it is being pulled?

Example Problem

Slide 8-28

Page 38: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

© 2010 Pearson Education, Inc.

The same spring is now suspended from a hook and a 10.2 kg block is attached to the bottom end. How long is the stretched spring?

Example Problem

Slide 8-29

Page 39: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

© 2010 Pearson Education, Inc.

Additional Example Problem A spring with spring constant k = 125 N/m is used to pull a 25 N wooden block horizontally across a tabletop. The coefficient of friction between the block and the table is µk = 0.20. By how much does this spring stretch from its equilibrium length?

Slide 8-34

Page 40: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

© 2010 Pearson Education, Inc.

The Springiness of Materials: Young’s Modulus

The force exerted by a stretched or compressed rod has the same form as Hooke’s law:

Y is Young’s modulus, which depends on the material that the rod is made of.

F = L L YA

Slide 8-30

Page 41: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

© 2010 Pearson Education, Inc.

Beyond the Elastic Limit

Slide 8-31

Page 42: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

© 2010 Pearson Education, Inc.

Summary

Slide 8-32

Page 43: Chapter 8 - Santa Rosa Junior Collegesrjcstaff.santarosa.edu/~lwillia2/20/20ch8_f14.pdfPowerPoint® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 8 Equilibrium

© 2010 Pearson Education, Inc.

Summary

Slide 8-33