chapter 7 part 1 - conservation of momentum in 1 d

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LINEAR MOMENTUM GIANCOLI - CHAPTER 7 MR. SHARICK HONORS PHYSICS

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Page 1: Chapter 7   part 1 - conservation of momentum in 1 d

LINEAR MOMENTUM

GIANCOLI - CHAPTER 7

MR. SHARICK

HONORS PHYSICS

Page 2: Chapter 7   part 1 - conservation of momentum in 1 d

Chapter 7.1 – Linear Momentum and its relation to force

Definition: momentum = mass X velocity

The symbol for momentum is lowercase ‘p’

Originally, it was called “progress”, thus the use of ‘p’

THE UNITS ARE :

Page 3: Chapter 7   part 1 - conservation of momentum in 1 d

Chapter 7.1 – Linear Momentum and its relation to force

Definition: momentum = mass X velocity

The symbol for momentum is lowercase ‘p’

Originally, it was called “progress”, thus the use of ‘p’

THE UNITS ARE : kg m/s

Page 4: Chapter 7   part 1 - conservation of momentum in 1 d

Rate of change of momentum

p

t

Page 5: Chapter 7   part 1 - conservation of momentum in 1 d

Rate of change of momentum

p vm ma

t t

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Rate of change of momentum

amt

vm

t

p

By Newton’s Second Law amFF NET

Page 7: Chapter 7   part 1 - conservation of momentum in 1 d

Rate of change of momentum

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Rate of change of momentum

This is how Newton originally wrote his 2nd Law of motion

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The principle of Conservation of Momentum

Conserved means “doesn’t change” A system can’t change momentum by

itself Something must act on the system – an

External Force Systems can exchange momentum

Ex: Momentum exchange in football https://www.youtube.com/watch?v=-

8ViFZxj2lU

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Conservation of Momentum – Newton’s Cradle

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Example 7.1

Water leaves a hose at the rate of 1.5 kg/s with a velocity of 20 m/s, and is aimed at the side of the car, which brings the water to rest. (We can assume no splash back occurs) What is the force exerted by the water on the car?

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Example 7.1

Follow-up question: What if the water splashes back? Would the force on the car be greater or less?

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Solving conservation of momentum problems1.) Determine your system and your initial and final points. (ensure no net force)2.) Set the momentum at the final point to be equal to the momentum of the initial point3.) Solve for the unknown.

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Conservation of Momentum - Recoil When an object is at rest, it has no

momentum. So if there is some sort of internal explosion, such as in a gun firing or a rocket burning rocket fuel, the momentum going forward will equal the momentum going backwards.

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Conservation of momentum - recoil

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Conservation of momentum – collide and stick together.

A bullet whose mass, m, is 50.0g is fired horizontally with a speed, v, of 1,100 m/s into a large wooden block of mass, M = 6.0 kg that is initially at rest on a horizontal table. If the block is free to slide without friction across the table, what speed will it acquire after it has absorbed a bullet?

 

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Conservation of momentum – Collide & Stick togetherA 10,000 kg railroad car traveling at a speed of 24.0 m/s strikes an identical railroad car that is at rest. If the cars lock together as a result of the collision, what is their common speed afterward?

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Conservation of momentum – Internal Motion Problem A man with a mass of 70 kg is standing on the

front end of a flat railroad car, which has a mass of 1,000 kg and a length of 10 m. The railroad car is initially at rest relative to the track. The man then walks from one end of the car t to the other at a speed of 1.0 m/s relative to the track. Assume there is no friction in the wheels of the railroad car. (a) What happens to the cart while the man is walking? (b) How long does it take him to reach the other end of the car? (c) What happens when the man stops at the rear of the car?

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Collisions and Impulse

Collisions are common in everyday life

Deformation of objects is common due to the large forces

The force jumps from zero at the moment of contact to a very large value, then abruptly returns to zero again.

This begins our discussion on impulse (simply put – change in momentum)

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Impulse

The impulse of the external forces acting on a system is equal to the change in the system’s momentum

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J = IMPULSE is a vector

The letter “J” is sometimes used to represent the “impulse” vector. Feel free to use “J” or “Δp”

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Impulse – Area under the force vs time curve

Page 24: Chapter 7   part 1 - conservation of momentum in 1 d

Impulse and collisions

Collision – When two or more objects come close together or hit and exert forces on each other for a short time Impulse Forces – Forces that are exerted for a short time interval (cause impulse – change in momentum)

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Impulse Forces – Force vs. Time

The average force over time interval is impulse/time

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Impulse Force vs Average ForceThe average force over the time interval is given by:

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Example Problem: Impulse

A pitched 140 g baseball, in horizontal flight with a speed vi of 39 m/s, is struck by a batter. After leaving the bat, the ball travels in the opposite direction with a speed vf, also 39 m/s. What impulse, J

, acts on the ball while it is in contact with the

bat? b. The impact time, t, for the baseball-bat collision is 1.2 ms, a typical value. What average force acts on the baseball?

Page 28: Chapter 7   part 1 - conservation of momentum in 1 d

Series of collisions

A machine gun fires R bullets per second. Each bullet has mass, m and speed, v. The bullets strike a fixed target, where they stop. What is the average force exerted on the target over a time that is long compared with the time between bullets?

The graph shows the instantaneous force on the target.

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Exit Ticket – page 15: #8 and # 98.) A tennis ball may leave the racket of a top player on a serve with a speed of 65.0 m/s. If the ball’s mass is 0.0600 kg and it is in contact with the racket for 0.0300s, what is the average force on the ball? Would this force be large enough to lift a 60 kg person?9.) A golf ball of mass 0.045 kg is hit off the tee at a speed of 45m/s. The golf club was in contact with the ball for 5.0 x 10-3 s. Find (a) the impulse imparted to the golf ball and (b) the average force exerted on the ball by the golf club.

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Elastic – KE conserved Inelastic – KE not conserved – Energy

lost

Collisions – Elastic vs. Inelastic

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Elastic Collisions

Consider a 2 body system:

Assume closed system (no mass enters or leaves)

Assume isolated system (no external forces act on it)

(Think about the collision of two billiard balls)

v1i m1 m2

v2i = 0m/s

Page 32: Chapter 7   part 1 - conservation of momentum in 1 d

Elastic Collisions

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If elastic then:

)()( systemfsystemi pp

i fKE KE

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If elastic then:

)()( systemfsystemi pp

ffi vmvmvm 221111

2 2 21 1 1 1 2 2

1 1 1

2 2 2i f i f fKE KE m v m v m v

Page 35: Chapter 7   part 1 - conservation of momentum in 1 d

Exit Ticket – Page 23 #12-1312. (II) A 0.450-kg ice puck, moving east with a speed of 3.00 m/s, has a head-on collision with a 0.900-kg puck initially at rest. Assuming a perfectly elastic collision, what will be the speed and direction of each object after the collision?

13. (II) A pair of bumper cars in an amusement park ride collide elastically as one approaches the other directly from the rear (Fig. 7-31). One has a mass of 450 kg and the other 550 kg, owing to differences in passenger mass. If the lighter one approaches a 4.50 m/s and the other is moving at 3.70 ms/, calculate (a) their velocities after the collision, and (b) the change in momentum of each.

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Exit Ticket –Page 24 #14

14. (III) In a physics lab, a cube slides down a frictionless incline as shown in Fig. 7-32, and elastically strikes a cube at the bottom that is only one-half its mass. If the incline is 30 cm high and the table is 90 cm off the floor, where does each cube land?

Page 43: Chapter 7   part 1 - conservation of momentum in 1 d

Inelastic Collisions

Inelastic Collision-a collision in which the kinetic energy of the system of colliding bodies is not conserved. EXAMPLE: A ball being dropped to the ground and only rebounding to ½ its initial height is noticeably inelastic.The kinetic energy lost is transformed into some other form of energy, often thermal. EXAMPLE: Putty dropped onto a floor does not rebound at all.Collisions where there is no rebound at all (the particles stick together) are called completely inelastic collisions.   

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Exit Ticket – Page 24 #15

15. (II) An 18-g rifle bullet traveling 230 m/s buries itself in a 3.6-kg pendulum hanging on a 2.8-m-long string, which makes the pendulum swing upward in an arc. Determine the horizontal component of the pendulum’s displacement.

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Center of Mass

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MOMEMTUM of the CENTER OF MASS

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Center of Mass Uses

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