chapter 6 indices

13
Module PMR Indices 64 CHAPTER 6 : INDICES NUMBERS IN INDEX FORM Example: Express in the form of repeated multiplication. a a a a a × × × = 4 1) 5 h 2) ( 3 h - 3) 2 e d 4) 4 5 5) ( 3 1 - 6) 4 3 2 7) 2 4 3 - Example: Write in index notation. h x h x h x h x h x h = 8) g x g x g x g 9). ( ( ( ( 29 ( 29 d d d d d - × - × - × - × - 10) n e n e n e 11) 7 x 7 x7 x 7 x 7 12) (-11)(-11)(-11) 13) 7 2 7 2 7 2 7 2 14) - - 9 7 9 7 Example: Evaluate 2 2 2 2 2 2 5 × × × × = = 32 15) 3 10 16) ( 4 3 - 17) 2 4 3 18) 3 4 1 - 19) 3 2 1 3 20) ( 3 4 . 0 21) ( 2 05 . 0 -

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  • Module PMR

    Indices 64

    CHAPTER 6 : INDICES

    NUMBERS IN INDEX FORM

    Example: Express in the form of repeated multiplication.

    aaaaa =4

    1) 5h 2) ( )3h 3)

    2

    e

    d

    4) 45

    5) ( )31 6)

    4

    32

    7)

    2

    43

    Example: Write in index notation. h x h x h x h x h x h =

    8) g x g x g x g 9). ( ) ( ) ( )( ) ( )dd

    ddd

    10)

    n

    e

    n

    e

    n

    e

    11) 7 x 7 x7 x 7 x 7 12) (-11)(-11)(-11) 13)

    72

    72

    72

    72

    14)

    97

    97

    Example: Evaluate

    2222225 =

    = 32

    15) 310

    16) ( )43 17)

    2

    43

    18) 3

    41

    19)

    3

    213

    20) ( )34.0 21) ( )205.0

  • Module PMR

    Indices 65

    LAWS OF INDICES

    LAW 1 nmnm aaa +=

    Example: Simplify

    35 bb

    35+= b

    8b=

    1) 62 gg 2) 693 hhh 3) ( ) ( )32 ee

    Example: Simplify

    43 22

    432 +=

    72=

    4) 62 55

    5) 683 666 6) ( ) ( )45 33

    Example: Simplify

    32 43 bb ( ) 3243 += b

    512b=

    7) 62 54 yy 8) 43 310 ss 9) 45832 kk

    Example: Simplify

    7265 94 shsh ( ) 767594 ++= sh

    131236 sh=

    10) 232 37 mbm

    11) 234 932

    vvv 12) papa 443 36

    LAW 2 nmnm aaa =

    Example: Simplify

    47 jj

    47= j

    3j=

    1) 49 nn 2) 25

    a

    a

    3) 344 tt

    Example: Simplify 45 42 = 45 - 2 = 43

    4) 54 53

    5) 24

    77

    6) 57 1010

    Example: Simplify

    35 412 aa 35

    412

    = a

    23a=

    7) 45 540 gg 8) 28

    420

    yy

    9) 510 2718 nn

  • Module PMR

    Indices 66

    Example: Simplify

    ( )

    9

    36

    36

    36

    226

    12612

    z

    z

    z

    zz

    =

    =

    =

    +

    10) 85 210 uu 11) 24

    218

    w

    w

    12) 48923 mm

    LAW 3 ( ) nmnm aa =

    Example: Simplify

    ( )15

    53

    53

    hh

    h

    =

    =

    1) ( )24k 2) ( ) 52 g 3) ( )27v

    Example: Simplify

    ( )12

    42

    42

    33

    3

    =

    =

    4) ( )354 5) ( ) 526 6) ( )357

    Example: Simplify ( )

    2015

    5453

    543

    22

    2

    m

    m

    m

    =

    =

    7) ( )234ed 8) ( ) 42352 9) ( )2643 g

    LAW 4 n

    n

    aa

    1=

    Example: Simplify

    rl

    rl1

    =

    1) kc 2) pm3 3) tdv

  • Module PMR

    Indices 67

    Example: Simplify

    32

    = 321

    81

    =

    4) 34 5) 17 6) 23

    Example: Simplify 5

    8

    414

    = 58 44

    = ( )584 +

    = 584

    = 34

    = 64

    7) 23 818 8) ( )223 1010

    1 9) ( )32

    8 1m

    m

    LAW 5 10 =a

    Example: 120 =

    1) 0

    32

    =

    2) ( )03 = 3) ( )05.4 =

    LAW 6 FRACTIONAL INDICES

    Example: Rewrite by using the root and power symbol

    93

    23

    9 =

    1) 31

    64

    2) 51

    32 3) 32

    8

    Example: Write in the form of index

    53223 5 =

    1) 3 8 2) 35 10

    3) 16

  • Module PMR

    Indices 68

    Example: Evaluate

    ( )22

    4

    21

    2

    21

    =

    =

    1) 31

    27 2) 52

    32 3) 43

    81

    Example: Simplify

    2

    36

    32

    34

    32

    34

    99

    9

    99

    =

    =

    =

    +

    1) 35

    32

    1010 2) ( ) 4216 gg 3) ( ) 3214 pp

    COMBINATION OF LAWS

    Example: Simplify

    222

    2

    0

    936

    936

    =

    =

    =

    +

    bb

    bbb

    1) 317 ggg 2) 459

    m

    mm

    3) 435 232 ggg

    Simplify ( )

    33

    3612

    31622

    3123

    442

    2

    yx

    yx

    yxyx

    yxxy

    =

    =

    =

    +

    4) ( ) 1322 xyyx 5) ( ) 24243 yxxy 6) ( ) yxxy 322

    Evaluate

    21

    21

    81

    31

    3

    31

    =

    =

    7) 21

    251

    8) 2

    1

    94

    9) 3

    1

    278

  • Module PMR

    Indices 69

    Evaluate

    ( )( )

    321

    22222

    42

    5

    49

    229

    233

    =

    =

    =

    =

    10) 322 284 11) ( )327 93 12) ( ) 51214 3242

    13) 53

    41

    31

    32168

    14) 232

    327

    15) ( ) 223 999

    16) ( ) 506 rr

    17) ( )2252

    44

    abba

    18) ( ) 2324 666

    19) ( ) 523 xx 20) Given .2166 2 =x Find x .

    21) Given that .1255 3 =x Find x . 22) If 6413

    =y . Find y .

  • Module PMR

    Indices 70

    Common Errors

    Errors

    Correct Steps

    1. 22 22 =

    ( )222 + =

    02 = 2

    1. 22 22 =

    ( )222 + =

    02 = 1

    2. 24 55 =

    245 =

    25

    2. 24 55 =

    ( )245 =

    245 + =

    65

    3. 452

    kkk

    = 452 +k

    = 3k

    3. 452

    kkk

    = )4(52 +k

    = 47+k

    = 11k

    Questions based on PMR Format

    1. Evaluate 31

    23

    16

    2. Evaluate ( )23284 cba

    3. Find the value of 32

    53

    832

  • Module PMR

    Indices 71

    4. Given that 21

    34

    2 8127 =k .Find the value of .k

    5. If 34347 = aa , find the value of .a

    6. Simplify 65

    21

    23 pp

    7. Simplify 275

    333

    8. Simplify 3724

    aaba

    9. Simplify ( ) 521432

    prqrqp

    10. Simplify 3425

    kmmkk

  • Module PMR

    Indices 72

    PMR past year questions

    2004

    1. Given that 162 2 =x , calculate the value of x . ( 2 marks )

    2. Simplify ( ) ( ) 9532422 kmkmk . ( 3 marks )

    2005

    1. Evaluate 32

    21

    21

    8

    123 .

    ( 3 marks )

    2. Given ( )( ),333 212 xx = calculate the value of x . ( 2 marks )

    2006

    1. Simplify 24

    kkk

    .

    ( 2 marks )

  • Module PMR

    Indices 73

    2. Find the value of 23

    21

    2 2183 . ( 3 marks )

    2007

    1. a). Find the value of 21

    23

    55 . b). Simplify ( ) 234 hhg . ( 3 marks )

    2008

    1. Simplify 452

    m

    mm .

    ( 2 marks )

    2. Find the value of a). 13 22 b). ( )3163 32 ( 3 marks )

  • Module PMR

    Indices 74

    CHAPTER 6 : INDICES ANSWERS

    1. hhhhh 2. ( ) ( ) ( )hhh 3.

    e

    de

    d

    4. 5555

    5. ( ) ( ) ( )111 6.

    32

    32

    32

    32

    7.

    43

    43

    8. 4g

    9. ( )5d 10.

    3

    n

    e

    11. 57 12. ( )311

    13. 4

    72

    14.

    2

    97

    15. 1000 16. 81

    17. 169

    18. 641

    19. 8

    343 or

    8742 20. 0.064

    21. 0.0025

    LAW 1 1. 8g 2. 18h 3. ( )5e 4. 85 5. 176 6. ( )93 7. 820y 8. 730s 9. 9

    43 k 10.

    3421 bm 11. 96v 12. 5718 pa

    LAW 2 1. 5n 2. 3a 3. t4 4. 5 5. 72 6. 1210 7. g8 8. 65y

    9. 532

    n 10. 5u13 11. 69w 12. 12

    227

    m

    LAW 3 1. 8k 2. 10g 3. 14v 4. 154 5. 106 6. 157 7. 68ed 8. 81252 9. 1283 g

    LAW 4

    1. kc1

    2. pm

    3 3.

    tv

    d

    4. 341

    5. 71

    6. 231

    7. 8 8. 10 9. 2m

    LAW 5 1. 1 2. 1 3. 1

  • Module PMR

    Indices 75

    LAW 6 1. 3 64 2. 5 32 3.

    23 8

    1. 31

    8 2. 53

    10 3. 21

    16 1. 3 2. 4 3. 27

    4. 101

    5. 7g 6. p

    COMBINATION OF LAWS 1. 3g 2. 10m 3. 43g 4. 458 yx 5. 629 yx 6. 31 yx 7.

    515 1 = 8.

    32

    9. 32

    10. 128 11. 243 12. 8

    13. 32 14. 81 15. 81 16. 5r 17. 834 ba 18. 1 19. x 20. 5=x 21. 6 22. 4

    Questions Based on PMR Format 1.

    41

    2. 3126 cba 3. 32 4. 3

    5. 7 6. 3

    4

    6 p 7. 1031

    8. 2b

    9. qrp

    10. 21

    km

    PMR QUESTIONS

    YEAR SOLUTION AND MARK SCHEME SUB MARK FULL MARK

    2004 42 22 =xx or 42 =x 6=x

    1 1

    2

    2004 9568442 kmkkm 9685416 + km

    5116 km

    1 1 1

    3

  • Module PMR

    Indices 76

    2005

    ( )( )

    234626

    2

    6

    8

    36

    2

    1

    32

    3

    21

    2

    32

    21

    1

    1

    1

    3

    2005 212 += xx 122 += xx

    3=x

    1

    1

    2

    2006 7

    )2(14

    kk +

    1 1

    2

    2006 ( )( ) 21212122

    23

    21

    2

    2233

    2293

    10842723 23

    1

    1

    1

    3

    2007 a) 155 or b)

    123

    3123

    ghhorgh

    1 1

    1

    3

    2008

    morm

    mormormorm

    12

    45263

    +

    1

    1

    2

    2008 a) 1624 = b) = 3

    16313

    32

    499

    21

    32 21

    =

    1

    1

    1

    3