chapter 5 – measures of central tendency 5.1 mean

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Chapter 5 – Measures of Central Tendency Answer Key 5.1 Mean Answers C D The population mean is denoted by “mu,” and its symbol is µ. B The mean is calculated by dividing the sum of all values by the number of values. A 71.5 × 4 = 286 286 (58 + 76 + 88) = 64 The means can be calculated as follows: 171.6 pounds 167.2 × 5 = 836 836 (158.4 + 162.8 + 165.0 + 178.2) = 171.6 1. 2. 3. 4. 5. a. b. c. 6.

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Page 1: Chapter 5 – Measures of Central Tendency 5.1 Mean

Chapter 5 – Measures of Central Tendency Answer Key5.1 Mean

AnswersC

D The population mean is denoted by “mu,” and its symbol is µ.

B The mean is calculated by dividing the sum of all values by the number of values.

A 71.5 × 4 = 286 286 −(58 + 76 + 88) = 64

The means can be calculated as follows:

171.6 pounds 167.2 × 5 = 836 836 − (158.4 + 162.8 + 165.0 + 178.2) = 171.6

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Page 2: Chapter 5 – Measures of Central Tendency 5.1 Mean

171.6 pounds 167.2 × 5 = 836 836 − (158.4 + 162.8 + 165.0 + 178.2) = 171.6

The answers can be calculated as follows:

12×5.1 = 61.2 feet

8×4.8 = 38.4 feet

61.2+38.4 = 99.6 feet. feet

31.0 advertisements

The means can be calculated as follows:

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Page 3: Chapter 5 – Measures of Central Tendency 5.1 Mean

The answers can be calculated as follows:

31×4 = 124

The means can be calculated as follows:

a. No Melanie’s answer is not correct. The temperature of 0◦C was recorded, butshe did not include

it in the total.

She divided the sum of the numbers by 6, but she should have divided by 7. Themean daily temperature should be −2 ◦C.

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Page 4: Chapter 5 – Measures of Central Tendency 5.1 Mean

The means can be calculated as follows:

The Bouncy Baskets had the higher mean score.

5.2 Ungrouped Data to Find the Mean

AnswersThe mean can be calculated as follows:

The mean can be calculated as follows:

The frequency distribution table is as follows:

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Page 5: Chapter 5 – Measures of Central Tendency 5.1 Mean

The mean can be calculated as follows:

The frequency distribution table is as follows:

The mean can be calculated as follows:

The sum of the data values is 108.

There are 12 data values.

The mean of the data values is 9.

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Page 6: Chapter 5 – Measures of Central Tendency 5.1 Mean

The mean of the data values is 9.

The mean of the data is:

The mean of the data is:

The mean of the data is:

5.3 Grouped Data to Find the Mean

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Page 7: Chapter 5 – Measures of Central Tendency 5.1 Mean

The table is created by completing problems 2 – 4

The summation of the values of for each class can be calculated as follows:32 + 150 + 360 + 180 + 48 = 770

The value of N is 100.

The mean weight for a baby can be calculated as follows:

The table is created by completing problems 5 – 7

The summation of the values of for each class can be calculated as follows:

210 + 320 + 800 + 600 + 630 = 2,560

The value of n is 50.

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Page 8: Chapter 5 – Measures of Central Tendency 5.1 Mean

The mean age for a teacher can be calculated as follows:

The table is created by completing problems 8 – 10

The summation of the values of for each class can be calculated as follows:

60,000 + 360,000 + 1,000,000 + 560,000 + 360,000 = 2,340,000

The value of N is 25.

The mean number of miles on a car can be calculated as follows:

5.4 Median

AnswersB An outlier is a value that is very small or very large compared to the majority of valuesin a data set.

B 10, 25, 38, 39, 39, 42, 71, 76 The median is the number in the position: . The numberbelow the 4.5 position is 39, and the number above the 4.5 position is 39. The median is .

D There are 23 seats, which is an odd number. The median is the number in the position:. The median seat is seat number 12.

C 55, 58, 62, 63, 68, 70, 71, 79, 81, 82 The median is the number in the position: . Thenumber below the 5.5 position is 68, and the number above the 5.5 position is 70. Themedian is .

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Page 9: Chapter 5 – Measures of Central Tendency 5.1 Mean

A 32, 34, 36, 38 The median is the number in the position: . The number below the 2.5position is 34, and the number above the 2.5 position is 36. The median is .

B The median is the number of bars sold by the student in the position: . The numberbelow the 15.5 position is 21, and the number above the 15.5 position is 21. The medianis .

The medians can be calculated as follows:a.

The median is the number in the position: . The number below the 5.5 position is $25,200,and the number above the 5.5 position is $26,450. The median retail price for the cars is .

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The median is the number in the position: . The number below the 5.5 position is $21,300,and the number above the 5.5 position is $22,100. The median median dealer’s cost for thecars is .

The median number of power outages can be calculated as follows:

The median is the number in the position: . The number below the 6.5 position is 3, and thenumber above the 6.5 position is 3. The median number of power outages is .

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Page 10: Chapter 5 – Measures of Central Tendency 5.1 Mean

The median number of safety devices aboard the boats can be calculated as follows:

The median is the number in the position: . The number in the 8th position is 8. The mediannumber of safety devices aboard the boats is 8.

The median wage for the teacher’s assistant can be calculated as follows:

The median is the number in the position: . The number in the 7th position is $600. Themedian wage for the teacher’s assistant is $600.

5.5 Median of Large Sets of Data

Answers

To find the answer, enter the frequency table into L1 and L2 and use median command on theMATH menu. The median age of the hockey players is 13.

To find the answer, enter the individual data values into L1 and use 1-Var Stats. The medianscore for the 14 rolls of the die is 3.

To find the answer, enter the frequency table into L1 and L2 and use median command on theMATH menu. The median score for the players is 5.

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Page 11: Chapter 5 – Measures of Central Tendency 5.1 Mean

To find the answer, enter the frequency table into L1 and L2 and use median command on theMATH menu. The median score for Monday’s quiz is 3.

To find the answer, enter the frequency table into L1 and L2 and use median command on theMATH menu. The median number of coins in a student’s pocket is 4.

To find the answer, enter the individual data values into L1 and use 1-Var Stats. The median timeof the participants in the race is 4.8 minutes.

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Page 12: Chapter 5 – Measures of Central Tendency 5.1 Mean

Answer:

Answer

5.6 Mode

AnswersC

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The modes are as follows:

616

There are two modes for the scores on the English quizzes. The modes are 6 and 7.

The mode of the amounts of time spent studying for the math test is 10 - 20 minutes.

The number of questions attempted most by the students was 42.

The mode of the numbers that were rolled is 3.

The mode of the numbers of games that students attended is 8.

The smallest possible value for m is 9.

The data set has two modes: 3 and 5. Each value appears 3 times. The distribution can bedescribed as bimodal.

Answers to this question will vary. Some acceptable responses would be:

A business could use the mode to determine the most popular selling item.A sports team could use the mode to determine which player is most consistent.A teacher could use the mode to determine the length of a test by the number of questionscompleted by the students on previous tests.A business could use the mode to determine the most popular sizes when ordering newstock.

The mode of the temperatures for the month of June is 74◦F.

CK-12 Basic Probability and Statistics Concepts 1

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Page 13: Chapter 5 – Measures of Central Tendency 5.1 Mean