chapter 3-combining factors and spread sheet functions_0

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  • 8/12/2019 Chapter 3-Combining Factors and Spread Sheet Functions_0

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    C 3CF

    F

    L

    E E

    7

    L B

    A 1

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    L :

    . :

    1. D , F, A

    2. C , F, A .

    3.

    M .

    4. D M

    .

    5. D

    .

    2

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    C

    I C 2, , , I ,

    . F ,

    1, /A ,

    0, . F ,

    . , , F .

    , F, A .

    3

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    LEA NING C ME

    4

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    A

    2, 1

    5

    Remember: / / ,

    / / ,

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    E /A F :

    6

    The present worth of the cash flow shown below at i = 10% is:

    (a) $25,304 (b) $29,562 (c) $34,462 (d) $37,908

    P0 = ?

    A = $10,000

    0 1 2 3 4 5 6

    i = 10%

    Solution: (1) Use P/A factor with n = 5 (for 5 arrows) to get P1 in year 1(2) Use P/F factor with n = 1 to move P1 back for P0 in year 0

    0 1 2 3 4 5

    P1 = ?

    Actual year

    Series year

    0 1( / ,10%,1) ( / ,10%,5)( / ,10%,1) 10,000(3.7 08) (0. 0 1) $34,462

    ( )

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    E F/A F :

    How much money would be available in year 10 if $8000 is depositedeach year in years 3 through 10 at an interest rate of 10% per year?

    7

    0 1 2 3 4 5 6 7 8 9 10

    FA = ?

    A = $8000

    i = 10%

    : Re-number diagram to determine n = 8 (number of arrows)

    0 1 2 3 4 5 6 7 8

    Cash flow diagram is:

    FA= 8000(F/A,10%,8)= 8000(11.4359)= $91,487

    Actual year Series year

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    A

    F :

    8

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    E : A

    F 0 10% .

    9

    0 1 2 3 4 5 6 7 8 9 10

    PT = ?

    A = $5000

    i = 10%

    First, re-number cash flow diagram to get n for uniform series:n = 8

    $2000

    0 1 2 3 4 5 6 7 8 9 10

    PT = ?

    A = $5000

    i = 10%

    $2000

    0 1 2 3 4 5 6 7 8

    Solution:

    Actual year Series year

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    E : A

    /A A 2: A = 5000( /A,10%,8) = 5000(5.3349) = $26,675M A 0 /F: 0 = 26,675( /F,10%,2) = 26,675(0.8264) = $22,044

    M $2000 0: 2000 = 2000( /F,10%,8) = 2000(0.4665)

    = $933

    N , 0 2000 : = 22,044 + 933 = $22,977

    10

    A = $5000

    i = 10%

    0 1 2 3 4 5 6 7 8

    Actual year 0 1 2 3 4 5 6 7 8 9 10

    $2000

    PT = ?

    PA

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    E D

    ( F/A /A )

    :

    F/A FA 10: FA = 5000(F/A,10%,8) = 5000(11.4359) = $57,180

    M FA 0 /F: 0 = 57,180( /F,10%,10) = 57,180(0.3855) = $22,043

    M $2000 0: 2000 = 2000( /F,10%,8) = 2000(0.4665) = $933

    N , : = 22,043 + 933 = $22,976 .. A ,

    11

    0 1 2 3 4 5 6 7 8 9 10

    PT = ?

    A = $5000

    i = 10%

    0 1 2 3 4 5 6 7 8

    FA = ?

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    A G

    1 21

    G 2 2

    M 03

    A , 0 (A/ , , )4

    13

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    E : A G J D $5

    4 . I 1 3 $60, 10 12% .

    2 $5 ($60 ) 2 2 = 60( /A,12%,8) + 5( /G,12%,8) = $370.41

    N , 2 0 0 = 2( /F,12%,2) = $295.29

    N , A $60 1 2 A = 60( /A,12%,2) = $101.41

    F , 0 A 0 = 0 + A = $396.70

    14

    0 1 2 3 104 5

    60 60 6065

    70

    95

    PT = ?i = 12%

    G = 5

    0 1 2 3 8 Gradient years

    Actual years

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    G G

    15

    1 2

    ( 1

    ( ) 1 1 (1+ )/(1+ ) /( )

    ( ) 1 1 (1+ )/(1+ ) /( )

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    E : G G 5

    $7000 . , 12%

    8 . I $3 0

    = 15% .

    16

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    E : G G

    G 5 6; 1 2.

    = 7000 1 (1+0.12)/(1+0.15) 9/(0.15 0.12) = $49,401

    M 0

    = 35,000 + 7000( /A,15%,4) + 49,401( /F,15%,4) = $83,232 17

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    N G F , G +

    G :

    F ,

    1 1 (1 )/(1+ ) /( + )

    A

    18

    Changed from + to -

    Changed from + to-

    Changed from - to +

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    E : N A G F ,

    = 10%

    : G G 2

    1 2

    G 0 ( 1);

    $700 1 6 G = 700( /A,10%,6) 50( /G,10%,6) = 700(4.3553) 50(9.6842) = $2565

    F = G(F/ ,10%,6) = 2565(1.7716) = $4544 19

    F = ?

    G = $-50

    0 1 2 3 4 5 6 7

    700 650

    500 450550600

    0 1 2 3 4 5 6

    Actual years

    Gradient years

    i = 10%PG = ?

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    A

    21

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    A

    22