chapter 2 - number system ii
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Chapter 2 :Number System (cont.)
SM0013 Mathematics I
Khadizah GhazaliLecture 4 15/06/2011
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Usingi
Now we can handle quantities thatoccasionally show up in mathematicalsolutions
What about
1a a i a = =
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???
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Warning
Consider It is tempting to combine them
The multiplicative property of radicals only worksfor positive values under the radical sign
Instead; use imaginary numbers
16 49
16 49 16 49 4 7 28 = + = =
216 49 4 7 4 7 28i i i = = =
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Example 2.12 :
Given that the following complex numbers as,
Identify the real part and the imaginary part of
these complex number.
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Solution :
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Example 2.13 :
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Operations on Complex
Numbers
Complex numbers can be combined withAddition
Subtraction
Multiplication
division
( ) ( )3 8 2i i + +
( ) ( )1 4 2i i +
( ) ( )2 4 4 3i i + 6 7i
11 i
6 2i
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Division technique
Multiply numerator and denominator bythe conjugate of the denominator
3
5 2
i
i2
2
3 5 2
5 2 5 2
15 625 4
6 15 6 15
29 29 29
i i
i i
i ii
i
i
+=
+
+=
+
= = +
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Square roots
Ifz2
= a + bi andz =x + yi, therefore
Using the properties of complex numberequality we have
( )
( ) ( )
2
2 2 2
x yi a bi
x y xy i a bi
+ = +
+ = +
2 2y a = 2xy b=and
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Example 2.14 :Example 2.14 :
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Example 2.14 :Example 2.14 :
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Argand Diagram
Any complex number z = a + bican berepresented by any ordered pair (a, b)
and hence plotted on xy-axes with the realpart measured along x-axis and the
imaginary part along the y-axis. Thegraphical representation of the complex
number field is called an Argand diagram.
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Example 2.15:
Represent the following complex numberson an Argand diagram.
(a) z = 3 + 2i
(b) z = 4 5i
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SolutionIm (y)
Re (x)1 2 3 4 5 6-3 -2 -1
-2
-3
-4
-5
2
1
(3,2)
(4,-5)
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Modulus and argument of
complex number
modulus of a complex number
argument of complex number
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Properties of modulus
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Properties of argument
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Polar CoordinatesPolar Coordinates
With siny r =cos ,x r =
z takes the polar form:
)sin(cos
jrz +=
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Using Polar Representation
Recall that a complex number can berepresented as
Then it follows that
What about z3 ?
( )cos sinz r i = +
( ) ( )
( )
2
2
cos sin cos sin
cos 2 sin 2
z r i r i
r i
= + +
= +
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DeMoivre's Theorem
In general (a + bi)n
is
Apply to
Try
( ) ( )( )cos sinn nz r n i n = +
)( )4
3 cos330 sin 330i+
12
2 2
2 2
i
+
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Using DeMoivre to Find Roots
Again, starting with
also
works when n is a fraction Thus we can take a root of a complex number
( )cos sina bi z r i + = = + ( ) ( )( )cos sinn nz r n i n = +
1/ 1/ 360 360cos sinn n k k
z r in n
+ + = +
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Using DeMoivre to Find Roots
Note that there will be n such roots
One each for k = 0, k = 1, k = n 1
Find the two square roots of
Represent as z = r cis
What is r?
What is ?
1/ 1/ 360 360cos sinn n k kz r in n
+ + = +
1 3i +
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Graphical Interpretation of Roots
Solutions are:
( )( )1/ 2
1 3
2 cos120 sin120
120 1202 cos sin
2 2
120 360 120 3602 cos sin2 2
i
i
i
and i
+
= +
= +
+ + +
2 6
2 2i+
2 6
2 2i
Roots will be equally spaced
around a circle with radius r1/2
Roots will be equally spacedaround a circle with radius r1/2
2
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Graphical Interpretation of Roots
Consider cube root of 27
Using DeMoivre's Theorem27 27 0cis=
1/ 33 0 36027 27 cis3
3 cis 0, 3 cis120, 3 cis 240
k
and
+ =
=
3 0i+
3 3 32 2
+
3 3 3
2 2
Roots will be equally spaced
around a circle with radius r1/3
Roots will be equally spaced
around a circle with radius r1/3
S i 2 4
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Section 2.4
Inequalities of Real Numbers
is a statement that shows the relationshipbetween two (or more) expressions with
one of the following five signs:
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b)
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Section 2.7
The Absolute Value in
Real Numbers
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Section 2.5The Absolute Value in Real Numbers
is the distance from thatnumber to the origin (zero) on
the number line. that distance is always given asa non-negative number.
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S ti f b l t l
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Some properties of absolute value:
S ti f b l t l ( t )
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Some properties of absolute value (cont.):
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The Triangle Inequality
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2.18 :