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    Chapter 2 :Number System (cont.)

    SM0013 Mathematics I

    Khadizah GhazaliLecture 4 15/06/2011

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    Usingi

    Now we can handle quantities thatoccasionally show up in mathematicalsolutions

    What about

    1a a i a = =

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    ???

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    Warning

    Consider It is tempting to combine them

    The multiplicative property of radicals only worksfor positive values under the radical sign

    Instead; use imaginary numbers

    16 49

    16 49 16 49 4 7 28 = + = =

    216 49 4 7 4 7 28i i i = = =

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    Example 2.12 :

    Given that the following complex numbers as,

    Identify the real part and the imaginary part of

    these complex number.

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    Solution :

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    Example 2.13 :

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    Operations on Complex

    Numbers

    Complex numbers can be combined withAddition

    Subtraction

    Multiplication

    division

    ( ) ( )3 8 2i i + +

    ( ) ( )1 4 2i i +

    ( ) ( )2 4 4 3i i + 6 7i

    11 i

    6 2i

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    Division technique

    Multiply numerator and denominator bythe conjugate of the denominator

    3

    5 2

    i

    i2

    2

    3 5 2

    5 2 5 2

    15 625 4

    6 15 6 15

    29 29 29

    i i

    i i

    i ii

    i

    i

    +=

    +

    +=

    +

    = = +

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    Square roots

    Ifz2

    = a + bi andz =x + yi, therefore

    Using the properties of complex numberequality we have

    ( )

    ( ) ( )

    2

    2 2 2

    x yi a bi

    x y xy i a bi

    + = +

    + = +

    2 2y a = 2xy b=and

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    Example 2.14 :Example 2.14 :

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    Example 2.14 :Example 2.14 :

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    Argand Diagram

    Any complex number z = a + bican berepresented by any ordered pair (a, b)

    and hence plotted on xy-axes with the realpart measured along x-axis and the

    imaginary part along the y-axis. Thegraphical representation of the complex

    number field is called an Argand diagram.

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    Example 2.15:

    Represent the following complex numberson an Argand diagram.

    (a) z = 3 + 2i

    (b) z = 4 5i

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    SolutionIm (y)

    Re (x)1 2 3 4 5 6-3 -2 -1

    -2

    -3

    -4

    -5

    2

    1

    (3,2)

    (4,-5)

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    Modulus and argument of

    complex number

    modulus of a complex number

    argument of complex number

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    Properties of modulus

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    Properties of argument

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    Polar CoordinatesPolar Coordinates

    With siny r =cos ,x r =

    z takes the polar form:

    )sin(cos

    jrz +=

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    Using Polar Representation

    Recall that a complex number can berepresented as

    Then it follows that

    What about z3 ?

    ( )cos sinz r i = +

    ( ) ( )

    ( )

    2

    2

    cos sin cos sin

    cos 2 sin 2

    z r i r i

    r i

    = + +

    = +

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    DeMoivre's Theorem

    In general (a + bi)n

    is

    Apply to

    Try

    ( ) ( )( )cos sinn nz r n i n = +

    )( )4

    3 cos330 sin 330i+

    12

    2 2

    2 2

    i

    +

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    Using DeMoivre to Find Roots

    Again, starting with

    also

    works when n is a fraction Thus we can take a root of a complex number

    ( )cos sina bi z r i + = = + ( ) ( )( )cos sinn nz r n i n = +

    1/ 1/ 360 360cos sinn n k k

    z r in n

    + + = +

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    Using DeMoivre to Find Roots

    Note that there will be n such roots

    One each for k = 0, k = 1, k = n 1

    Find the two square roots of

    Represent as z = r cis

    What is r?

    What is ?

    1/ 1/ 360 360cos sinn n k kz r in n

    + + = +

    1 3i +

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    Graphical Interpretation of Roots

    Solutions are:

    ( )( )1/ 2

    1 3

    2 cos120 sin120

    120 1202 cos sin

    2 2

    120 360 120 3602 cos sin2 2

    i

    i

    i

    and i

    +

    = +

    = +

    + + +

    2 6

    2 2i+

    2 6

    2 2i

    Roots will be equally spaced

    around a circle with radius r1/2

    Roots will be equally spacedaround a circle with radius r1/2

    2

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    Graphical Interpretation of Roots

    Consider cube root of 27

    Using DeMoivre's Theorem27 27 0cis=

    1/ 33 0 36027 27 cis3

    3 cis 0, 3 cis120, 3 cis 240

    k

    and

    + =

    =

    3 0i+

    3 3 32 2

    +

    3 3 3

    2 2

    Roots will be equally spaced

    around a circle with radius r1/3

    Roots will be equally spaced

    around a circle with radius r1/3

    S i 2 4

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    Section 2.4

    Inequalities of Real Numbers

    is a statement that shows the relationshipbetween two (or more) expressions with

    one of the following five signs:

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    2.16 :

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    b)

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    Section 2.7

    The Absolute Value in

    Real Numbers

    Section 2 5

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    Section 2.5The Absolute Value in Real Numbers

    is the distance from thatnumber to the origin (zero) on

    the number line. that distance is always given asa non-negative number.

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    S ti f b l t l

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    Some properties of absolute value:

    S ti f b l t l ( t )

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    Some properties of absolute value (cont.):

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    2.17 :

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    The Triangle Inequality

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    2.18 :