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Chapter 14 Covalent Bonding: Orbitals

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Chapter 14. Covalent Bonding: Orbitals. SP 3 Hybridization of methane. The 2s orbital and the three 2p orbitals are combined to form four equivalent orbitals, called sp 3 hybrids. SP 2 Hybridization of ethylene. One 2s and two 2p orbitals are used to form these hybrid orbitals. - PowerPoint PPT Presentation

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Page 1: Chapter 14

Chapter 14

Covalent Bonding: Orbitals

Page 2: Chapter 14

SP3 Hybridization of methane

The 2s orbital and the three 2p orbitals are

combined to form four equivalent orbitals,

called sp3 hybrids.

)(2

1

)(2

1

)(2

1

)(2

1

4

3

2

1

zyx

zyx

zyx

zyx

ppps

ppps

ppps

ppps

Page 3: Chapter 14
Page 4: Chapter 14
Page 5: Chapter 14
Page 6: Chapter 14
Page 7: Chapter 14

SP2 Hybridization of ethylene

One 2s and two 2p orbitals are used to form these hybrid orbitals.

Use px and py to hybridize.

Page 8: Chapter 14
Page 9: Chapter 14
Page 10: Chapter 14
Page 11: Chapter 14
Page 12: Chapter 14
Page 13: Chapter 14
Page 14: Chapter 14

SP Hybridization of CO2

Page 15: Chapter 14

SP Hybridization of CO2

Page 16: Chapter 14

SP Hybridization of CO2

Page 17: Chapter 14

SP Hybridization of CO2

Page 18: Chapter 14

SP Hybridization of CO2

Page 19: Chapter 14
Page 20: Chapter 14

dsp3 Hybridization

Page 21: Chapter 14

dsp3 Hybridization

Page 22: Chapter 14

d2sp3 Hybridization

Page 23: Chapter 14
Page 24: Chapter 14

The combination of hydrogen 1s atomic orbitals to form MOs

Page 25: Chapter 14

sg1

eu: ungerad

s σ*u1

Page 26: Chapter 14

The rules of molecular orbital theory

1. The electron probability of both MOs is centered along the line passing through the two nuclei.2. The MOs are available for occupation by

electrons. The 1s atomic orbital of the hydrogen atoms no longer exist.

3. If the two electrons occupy the lower energy MO, this situation favors molecule formation. (Bonding)

Page 27: Chapter 14

The rules of molecular orbital theory

4. If the two electrons were forced to occupy the higher energy MO, the separated state would be favored. (Antibonding)

5. The electrons have the greatest probability of being between the nuclei on bonding MO.

6. Bonding MO:σ1s Antibonding MO:σ1s*

7. Electrons configuration 1σ1s2

Page 28: Chapter 14
Page 29: Chapter 14

12 1s)(σon for Honfiguratielectron c g

Page 30: Chapter 14

2*22 )1(1s)( son for Heonfiguratielectron c

Page 31: Chapter 14

1*2

2 )1(1s)( son for Heonfiguratielectron c

Page 32: Chapter 14

Molecular Orbitals of Li2 (1s22s1)

22*21212

2

)2s()1(1s)( 2121 sssss

on for Lionfiguratielectron c

Page 33: Chapter 14

Bond Order

Larger bond order indicates the

greater bond strength.

2

electrons gantibondin ofnumber -electrons bonding ofnumber order bond

Page 34: Chapter 14

Molecular Orbitals of B2 (1s22s22p1)

Page 35: Chapter 14
Page 36: Chapter 14

Molecular Orbitals of B2

22*22*2

122122

2

)2p()2()2s()1(1s)(

221221

ss

psspss

on for Bonfiguratielectron c

Page 37: Chapter 14
Page 38: Chapter 14

Paramagnetism and Diamagnetism

Paramagnetism causes the substance to be attracted toward the including magnetic.

Diamagnetism causes the substance to be repelled from the including magnetic.

Paramagnetism is associated with unpaired electrons, and diamagnetism is associated with paired electrons.

Page 39: Chapter 14
Page 40: Chapter 14

When liquid oxygen is poured into the space between the poles of a strong magnet, it remains there until it boils away.

Page 41: Chapter 14

Bond order

=?

Page 42: Chapter 14

The Correctly Molecular Orbitals of B2

The σ2p orbital is changed by p-s mixing, the energies of π2p and σ2p orbitals are reverse.

The p-s mixing also changes the energies σ2p and σ2p

* such that they are no longer equally spaced relative to the energy of the free 2s orbital.

Page 43: Chapter 14
Page 44: Chapter 14

The Order in MOs Filling

pPP

PσPπPπ

ssss

222

)222(

2211

*1

*1

*

11

**

Page 45: Chapter 14
Page 46: Chapter 14

Electron Characterization in MO

Degenerate orbitals: electrons in an atomic subshell are orbitals at identical energy levels.

Multiplicity: M=2S+1

M=1 singlet M=2 doublet M=3 triplet

Page 47: Chapter 14

NO

Page 48: Chapter 14

NO+ and CN-

Page 49: Chapter 14
Page 50: Chapter 14

Molecular Orbital of HF

Page 51: Chapter 14
Page 52: Chapter 14

The resonance structures for O3 and NO3

-

Page 53: Chapter 14

The benzene molecule consists of a ring of six carbon atoms with one hydrogen atom bound to ach carbon; all atoms are in the same plane.

Page 54: Chapter 14

The s bonding system in the benzene molecule

Page 55: Chapter 14

The MO system in benzene is formed by combining the six p orbitals

Page 56: Chapter 14

The p orbitals used to form the bonding system in the NO3

- ion

Page 57: Chapter 14

The MO Diagram for System

highest energy bonding pi-orbital (HOMO)

lowest energy antibonding pi-orbital (LUMO)

Page 58: Chapter 14

Molecular Spectroscopy

Etotal=Etrans+Eelec+Evib+Erot+Enucl

Eelec: electronic transitions (UV, X-ray)

Evib: vibrational transitions (Infrared)

Erot: rotational transitions (Microwave)

Enucl: nucleus spin (nuclear magnetic

resonance) or (MRI: magnetic resonance

imaging)

Page 59: Chapter 14
Page 60: Chapter 14

UV/VIS

Vacuum UV or Far UV (λ<190 nm )

Page 61: Chapter 14
Page 62: Chapter 14

The molecular orbital diagram for the ground state of NO+

Selection Rule: does not change M=2S+1 during electron transition

Page 63: Chapter 14

The molecular structure of beta-carotene

Page 64: Chapter 14

Vibrational Spectroscopy

...), , , (vn

v

) (nhvE

kmm

mm μ

μ

kv

)Rk(RF

l energy vvibrationa

ator.nic oscillas a harmo

ed n be treat (bond) cafrom Rlacements Small disp

v

vvv

e

e

3210number quantum al vibrationthe

vibration theoffrequency sticcharacteri the

1Δn2

1

constant) force ,mass (reduced2

1

0

0

21

21

Page 65: Chapter 14

The potential curve for a diatomic molecule

Page 66: Chapter 14

Morse energy curve for a diatomic molecule.

Page 67: Chapter 14

Selection Rule of Infrared Spectrum

Molecule must have change in dipole moment due to vibration or rotation to absorb IR radiation.

Homonuclear diatomic molecules will have no IR spectrum.

Molecule dipole moment interacts with IR photon electric field.

Absorption causes increase in vibration amplitude/rotation frequency.

Page 68: Chapter 14

Molecules with permanent dipole moments (µ) are IR active

Page 69: Chapter 14

Types of Molecular VibrationsStretch- change in bond length

symmetric stretching

asymmetric stretching

Page 70: Chapter 14
Page 71: Chapter 14

Types of Molecular Vibrations Bend- change in bond angle

scissoring

wagging

rocking

twisting/torsion

Page 72: Chapter 14
Page 73: Chapter 14

Normal Modes of Vibration

Linear molecule of N atoms: normal modes = 3N - 5  

Nonlinear molecule of N atoms: normal modes = 3N - 6

Page 74: Chapter 14
Page 75: Chapter 14

IR spectrum

Page 76: Chapter 14

The three fundamental vibrations for sulfur dioxide

Page 77: Chapter 14

Rotational Spectroscopy

nd lengthaverage boR

mm

mmssreduced maμ

μRI

e molaculertia of thent of ineI: the mom

....), , , number (Jal quantumJ:rotation

J)J(JI

E

e

e

J

21

21

2

2

3210

1 12

Selection Rule: A molecule must have a permanent dipole moment

Page 78: Chapter 14
Page 79: Chapter 14

Rotational Spectroscopy

http://en.wikipedia.org/wiki/Rovibrational_coupling

Page 80: Chapter 14

(cm-1)

Abs

e

R BranchP Branch

l=-5

l=-4

l=-3

l=-2

l=-1 l=1

l=2

l=3

l=4

l=5

2B 4B 6B 8B

Vibrational-Rotational Spectrum

Page 81: Chapter 14
Page 82: Chapter 14
Page 83: Chapter 14

Calculate Bond Length of Heteronuclear Diatomic Molecule

21

21

2

2

2

8

1 )1(12

mm

mmI

hB

μRI

JJhBJ)J(JI

E

e

J

轉動慣量

縮減質量

Page 84: Chapter 14

Nuclear Magnetic Resonance Spectroscopy

The rules for determining the net spin of a nucleus1. If the number of neutrons and the number of protons

are both even, then the nucleus has NO spin.

2. If the number of neutrons plus the number of protons is odd, then the nucleus has a half-integer spin (i.e. 1/2, 3/2, 5/2)

3. If the number of neutrons and the number of protons are both odd, then the nucleus has an integer spin (i.e. 1, 2, 3)

Page 85: Chapter 14

Nuclei Unpaired Protons

Unpaired Neutrons

Net Spin

1H 1 0 1/2 2H 1 1 1 31P 1 0 1/2

23Na 1 2 3/2 14N 1 1 1 13C 0 1 1/2 19F 1 0 1/2

A nucleus of spin I will have 2I + 1 possible orientations.

分裂能階數目

Page 86: Chapter 14

Larmor Precession

Page 87: Chapter 14

In the absence of an external magnetic field, these orientations are of equal energy.

If a magnetic field is applied, then the energy levels split. Each level is given a magnetic quantum number, m.

Page 88: Chapter 14

Nucleus in a Magnetic Field

The lower energy level will contain slightly more nuclei than the higher level.

It is possible to excite these nuclei into the higher level with electromagnetic radiation.

The frequency of radiation needed is determined by the difference in energy between the energy levels.

Page 89: Chapter 14

Calculating transition energy

2

hBE

: magnetogyric ratio and is a fundamental nuclear constant which has a different value for every nucleus.B: the strength of the magnetic field at the nucleus ∆E↑B↑

分裂能階大小與磁場強弱成正比

Page 90: Chapter 14

The Absorption of Radiation by a Nucleus in a Magnetic Field

If energy is absorbed by the nucleus, then the angle of precession, q, will change.

For a nucleus of spin 1/2

, absorption of radiation "flips" the magnetic moment so that it opposes the applied field.

Page 91: Chapter 14

Chemical Shift

The magnetic field at the nucleus is not equal to the applied magnetic field; electrons around the nucleus shield it from the applied field.

The difference between the applied magnetic field and the field at the nucleus is termed the nuclear shielding.

Page 92: Chapter 14

Electrons in s-orbitals Spherical symmetry and circ

ulate in the applied field A magnetic field which oppo

ses the applied field. Applied field strength must b

e increased for the nucleus to absorb at its transition frequency.

This upfield shift is also termed diamagnetic shift.

Page 93: Chapter 14

Electrons in p-orbitals

No spherical symmetry. They produce comparatively large magnetic

fields at the nucleus, which give a low field shift.

This "deshielding" is termed paramagnetic shift.

Page 94: Chapter 14

Proton Chemical Shift Ranges

= ( - ref) ×106 / ref

tetramethylsilane, Si(CH3)4, (TMS)

Page 95: Chapter 14

Spin - Spin coupling

The protons on neighboring carbons will generate magnetic fields whose magnetic moments will interact with the magnetic moment of the external magnetic field.

This results in the splitting of the NMR signal.

Page 96: Chapter 14

NMR of Ethanol

-CH2-

-CH3

Page 97: Chapter 14

Methyl peak splitting into a triplet

the ratio of areas 1:2:1

Page 98: Chapter 14

Methylene peak splitting into a quartet

the ratio of areas 1:3:3:1

Page 99: Chapter 14

Configuration Peak Ratios

A 1

AB 1:1

AB2 1:2:1

AB3 1:3:3:1

AB4 1:4:6:4:1

AB5 1:5:10:10:5:1

AB6 1:6:15:20:15:6:1

Pascal's triangle

Page 100: Chapter 14

The molecular structure of bromoethane

Page 101: Chapter 14

The NMR spectrum of CH3CH2Br (bromoethane) with TMS reference

tetramethylsilane, Si(CH3)4

Page 102: Chapter 14

The molecule (2-butanone)

Page 103: Chapter 14
Page 104: Chapter 14

(B) (C)

(D)

(A)

Page 105: Chapter 14

(B)

(A)

(C)

Page 106: Chapter 14

A technician speaks to a patient before heis moved intot eh cavity of a magnetic resonance imaging (MRI).

Page 107: Chapter 14

A colored Magnetic Resonance Imaging (MRI) scan through a human head, showing a healthy brain in side view.