chapter 12: solutions chem 1110 figures: basic chemistry 3 rd ed., timberlake and timberlake

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Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

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Page 1: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Chapter 12:Solutions

Chem 1110

Figures: Basic Chemistry 3rd Ed., Timberlake and Timberlake

Page 2: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Examples of Common Solutions

Solid Solutions:

• Brass (65% Cu, 35% Zn)• White Gold (60% Au, 40% Pt)

Liquid Solutions:

• Vinegar (95% water, 5% acetic acid) • Solutions used in lab

Gas Solutions:• Air (78% N2, 20% O2, 1% Ar, 0.5% CO2, 0.5% H2O)

Page 3: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Solutions

We need to define the important components in a solution:

• Solvent: The most abundant substance in a solution

• Solute: Any substance dissolved in the solvent

• Aqueous Solution: a solution of any solute in water. Water is the solvent.

Page 4: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Solid Solutions

Solid Solutions: An Alloy is a solid solution of metals:

• If one of the metals is mercury (Hg) we call this solution an amalgam

• Amalgams were commonly used in older dental work

• Brass (65% Cu, 35% Zn)• White Gold (60% Au, 40% Pt)

Page 5: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Solutions

Concentration is the amount of solute in a given volume of solution

• Concentrated Solution has a large amount of solute per volume

• Dilute Solution has a small amount of solute

• This is a Qualitative distinction, of course we will have to consider Quantitative values

Page 6: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Saturated Solutions

We can add solute to a solvent until NO more solid will dissolve to form a Saturated Solution

• Saturation defines the solubility of the solute

• Solubility is the maximum amount of solute that can be dissolved in a given solvent

Page 7: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Solubility is based on:

1. Pressure applied to the system

2. Temperature of the solution

3. Nature of the solvent and solute interaction

Solubility

Page 8: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Solubility increases as temperature increases:

Solubility in Water

Page 9: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Supersaturated Solutions

If we heat a saturated solution to dissolve more solute, we can create a Supersaturated Solution:

• Supersaturated Solutions are:

• An Unstable State because there is too much solute for the amount of solvent

• Will precipitate out very easily

• Used to make hot packs for injuries

Page 10: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Temperature and Pressure affect solubility:

• For solid or liquid solutes:

• Increasing T, increases solubility

• Supersaturated Solution

• Increasing P has NO effect on solubility

• For a gaseous solute:

• Increasing T, decreases solubility

• Increasing P, increases solubility

Henry’s Law

Solubility

Page 11: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Attractive Forces in Solutions

Interactions between solutes and solvents that:

• are similar in polarity will form a solution

• are not similar will not form a solution

“Like dissolves like”

Page 12: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Water as a Polar Solute

Page 13: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Solubility

Two liquids that dissolve into each other are said to be miscible

• If you consider Intermolecular Forces:

“Like dissolves like”

Ethanol and water are miscible

Hexane and water are immiscible

Page 14: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Like Dissolves Like

Solvents Solutes

Water (polar) Ni(NO3)2

CH2Cl2(nonpolar) (polar)

I2

(nonpolar)

Page 15: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Units of Concentration

We report the concentration of solutions in many different units:

• There are several important Career specific units to consider:

• Percent by Mass (m/m)

• Percent by Volume (v/v)

• Concentrations in chemistry are most often reported in Molarity (M)

Page 16: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Percent by Mass

Percent by Mass (m/m) is used most often in engineering or agricultural applications

• Commonly measured in grams

Percent by Mass = mass of solute x 100%

mass of solution

• 6.0 % (m/m): 6.0 g of solute dissolved in a total of 100 g of solution (6 g solute and 94 g solvent)

Page 17: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Percent by Mass

Low fat milk has 1% (m/m) milkfat

• This means that in this sample of milk there is…

© Brooks/Cole, Cengage Learning. All rights reserved.

Page 18: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Percent by Volume

Percent by Volume (v/v) is used most often when both solute and solvent are liquids or gases:

Percent by volume = volume of solute x 100%

volume of solution

• 17.0 % (v/v): 17.0 mL of solute dissolved in a total of 100 mL of solution (17 mL solute and 83 mL solvent)

Page 19: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Percent by Volume

Rubbing alcohol is 70% (v/v) isopropanol in a solution with water

• This means that in the bottle there are…

© Brooks/Cole, Cengage Learning. All rights reserved.

Page 20: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Molarity

Molarity (M) is the unit of concentration most often used in chemistry labs:

Molarity (M) = moles of solute

1 liter of solution

• A solution that has 1 mole of solute dissolved in a total of 1 liter of solution is said to be 1 molar (1 M)

Molarity (M) = moles

liter

Page 21: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Learning CheckHow many grams of CuSO4 (159.10 amu) are needed to make exactly 500 mL of a 1.00 M solution?

Page 22: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Learning Check

How many moles of CuSO4 are in 150 mL of the 1.00 M solution?

Page 23: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Dilution

We decrease the concentration (or dilute) aqueous solutions by adding water

• The moles of solute STAYS THE SAME

• The volume of the solution changes

• Results in a change of molarity (M)

Molarity decreases

Page 24: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

DilutionIn a dilution:• water is added• volume increases• concentration decreases

Page 25: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Dilution

Initially:

Molarity (M1) x volume (V1) = # moles solute

After Dilution:

New molarity (M2) x volume (V2) = # moles solute

# moles solute = # moles solute

M1V1 = M2V2

V2 = V1 + Vadded

Page 26: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

DilutionWhat is the molarity of a the final solution after diluting 150 mL of a 1.0 M CuSO4 solution with 200 mL of water?

Page 27: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Molarity in a Chemical Equation

How many milliliters of a 3.00 M HCl solution are needed to react with 4.85 g of CaCO3?

2HCl(aq) + CaCO3(s) CaCl2(aq) + CO2(g) + H2O(l)

Page 28: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Learning Check

How many liters of H2 gas at STP are produced when 6.25 g of Zn react with 20.0 mL of a 1.50 M HCl solution?

Zn(s) + 2 HCl(aq) ZnCl2 (aq) + H2(g)

Page 29: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Colligative Properties

Homogeneous solutions may have different physical properties than the pure substances that they contain

• Properties of substances in a solution may be different:

– We will talk about adding nonvolatile solute leads to

• Increased melting point• Increased boiling point• Decreased vapor pressure

Page 30: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Colligative Properties

Colligative Properties are properties of solutions that depend on the number of particles dissolved in the solvent

• Colligative Properties do not depend on the identity of the particle:

o IonsoCovalent Molecules

• It is the concentration of particles that matters, particle molarity

Page 31: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Colligative Properties

Dissolved Particles in a solution:

• 1 sugar molecule → 1 sugar molecule

o Total of 1 particle in solution

• 1 NaCl formula unit → 1 Na+ ion + 1 Cl- ion

o Total of 2 particles in solution

• (NH4)3PO4 →

Page 32: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Particle Molarity

Dissolved Particles in a solution:

• 1 M sugar molecule → 1 M sugar molecule

o Total of 1 M particles in solution

• 1 M NaCl formula unit → 1 M Na+ + 1 M Cl-

o Total of 2 M particles in solution

• 1 M (NH4)3PO4 → 3 M NH4+ + 1 M PO4

3-

o Total of 4 M particles in solution

Page 33: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Learning CheckWhat is the molarity of particles in a solution of 125 g of MgCl2, a strong electrolyte, dissolved in 0.500 L of water?

Page 34: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Colligative Properties

A large number of solute particles may cause interruptions or “get in the way” of the solution surface:

• Dissolved particles may disrupt intermolecular forces

• The pure substance is “diluted” by the solute

• Decrease solvent-solvent interactions on the surface

Page 35: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Colligative Properties

Solute particles (ionic or molecular) can:

• Interrupt the intermolecular forces holding the molecules of a solvent together

• Weaken the intermolecular forces of the solvent

• “Get in the way” on the surface of a solution and make it more difficult for molecules to escape

Page 36: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Colligative Properties

Colligative Properties may include:

1. Boiling Point Elevation

2. Freezing Point Depression

3. Osmotic Pressure

Page 37: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Colligative Properties

Effect on Boiling Point…

It is common to add salt to water when boiling, why?

• Adding a non-volatile solute may lower vapor pressure

• Ions interfere with solvent-solvent interactions on the surface

• Ions make it harder for water molecules to escape

– Fewer solvent (water) particles on the surface

Page 38: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Colligative Properties: Boiling Point Effects

• Ions make it harder for water molecules to escape

– Fewer solvent (water) particles on the surface

Page 39: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Colligative PropertiesBoiling Point Effects:

• A higher temperature is needed to get the vapor pressure to equal atmospheric pressure

• DECREASE the vapor pressure of the solution • INCREASE the boiling point of the solution• INCREASE number of particles for a larger effect

• Adding salt to water raise boiling temperature:

1 mole of particles raises boiling point by 0.52 °C

• Antifreeze in car engines raises boiling point in radiator

Page 40: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Colligative Properties

Effect on Freezing Point…

Why do we add salt to roads in winter?

• Salt interferes with intermolecular forces holding the H2O molecules together

• Water molecules are not able to organize into ice crystals since solute is in the way

• A lower temperature is needed to reach the solid state

• The Freezing Point is DECREASED

Page 41: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Colligative PropertiesWhy do we add salt to roads in winter?

• Salt interferes with intermolecular forces holding the H2O molecules together

• Water FREEZES at a lower temperature

• Salt prevents roads from re-freezing but it DOES NOT melt the ice!!

• CaCl2 (Ice Melter®) melts ice and lowers the melting temperature even colder

The oceans never freeze solid due to higher salt concentrations

Page 42: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Osmosis

OSMOSIS: the transport of a solvent across a semi-permeable membrane

• We will limit our discussion to water as the solvent

• Water moves across the membrane to create an isotonic system

Page 43: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Example of Osmosis

A semi-permeable membrane separates a 4% starch solution from a 10% starch solution. Starch is a colloid and cannot pass through the membrane, but water can. What happens?

10% starch4% starchH2O

Semi-permeable membrane

Page 44: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Example of Osmosis (continued)

The 10% starch solution is diluted by the flow of water out of the 4% solution, and its volume increases

• The 4% starch solution loses water, and its volume decreases

• Eventually, the water flow between the two becomes equal

7% starch H2O

7% starch

H2O

Page 45: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Osmotic Pressure

• Water flows from less concentrated to more concentrated side of a semi-permeable membrane

• Movement of water molecules sets up a pressure differential

• Osmotic Pressure is the pressure required to make these two sides equal equilibrate

Page 46: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Hypotonic, Hypertonic,Isotonic Solutions

• Maintaining appropriate solution conditions are very important in your body and chemistry

• Consider the possible negative effects…

Page 47: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Isotonic Fluid

Consider, an isotonic solution such as blood:

Blood plasma (liquid) should have the same osmotic pressure as in your red blood cells:

o 5.0% (m/v) glucose o 0.9% (m/v) NaCl

Page 48: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Red Blood Cell: Isotonic Solution

Dr. Stanley Flegler/Getty Images

• Composition of cell is similar to the isotonic solution it is in – no significant osmosis

Page 49: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Red Blood Cell in Hypotonic Solution

Hemolysis

David H. Phillips/Photo Researchers

• Water flows into the cell to dilute the solution inside (from the hypotonic solution)

Page 50: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Red Blood Cell in Hypertonic Solution

Crenation

David H. Phillips/Photo Researchers

• Water flows out of the cell to dilute the hypertonic solution outside

Page 51: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Colloidal Solution

oNo solute or solvent

• Contains dispersed particles that are intermediate in size between those of a solution and those of an ordinary heterogeneous mixture

• So, have dissolved solids in solvent

o FogoMilk

• A homogeneous mixture, NOT a true solution

Page 52: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Tyndall Effect• Colloidal Solutions scatter light (Tyndall Effect):

True Solution:

No Scattering

Colloidal Solution:

Light Scatters

Page 53: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Suspension

Suspension: a heterogeneous mixture containing dispersed particles that are heavy enough to settle out under the influence of gravity:

• Muddy water• Blood• Fine precipitates

Page 54: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Colloidal Dispersion

• Homogeneous

• Groups of small particles or individual larger molecules

• Scatters light (Tyndall effect)

• Particles do not settle

• Particles cannot be filtered out

Suspension

• Heterogeneous

• Very large particles, which are often visible

• Not transparent

• Particles settle rapidly

• Particles can be filtered out

Page 55: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Solutions, Colloids, and Suspensions

Page 56: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Dialysis• Dialysis is similar to osmosis

• Uses a semi-permeable membrane that allows the passage of solvent, dissolved ions, and small molecules, but blocks the passage of colloidal-sized particles and large molecules:

Page 57: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Removing Colloidal Impurities

Page 58: Chapter 12: Solutions Chem 1110 Figures: Basic Chemistry 3 rd Ed., Timberlake and Timberlake

Artificial Kidney Machine