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    Chapter 1 : Indices & Logarithms 1

    CHAPTER 1 : INDICES &

    LOGARITHMS

    1.1 EXPONENT

    1.2 LOGARITHMS

    1.3 EXPONENT & LOGARITHMSEQUATION

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    Chapter 1 : Indices & Logarithms 2

    INTRODUCTION

    Why study exponential & logarithmic

    functions?

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    Chapter 1 : Indices & Logarithms 3

    They are very important in many technical areas, suchas business, finance, nuclear technology, acoustics,electronics & astronomy.

    Many of the applications will involve growth(INCREASING)or decay (DECREASING).

    There are many things that grow exponentially, forexample population, compound interest & charge incapacitor.

    We can also have exponentially decay for example

    radioactive decay. Logarithm is a method of reducing long multiplications

    into much simpler additions (and reducing divisionsinto subtractions).

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    Chapter 1 : Indices & Logarithms 5

    1.1 EXPONENT

    Law Example Try

    aman= am+n x3x7=x3+7=x10 x2x-5=

    aman=am-n

    (am)n= amn (43)2= 43(2)=46 (55)2=

    (ab)n= anbn (2b)3= 23b3= 8b3 (3xy)4=

    264

    6

    4 kk

    k

    k

    Law of exponents

    2

    5

    h

    h

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    Chapter 1 : Indices & Logarithms 6

    1.1 EXPONENT

    Law Example Try

    n

    nn

    b

    a

    b

    a

    n

    nn

    a

    bba

    Law of exponents

    n

    n

    aa

    1

    8116

    32

    32 4

    44

    2

    4w

    8

    1

    2

    12

    3

    3 23

    425

    2

    552

    2

    22

    3

    34

    Ex 2 pg 5

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    Chapter 1 : Indices & Logarithms 7

    Radical : the positive square root of

    1.1 EXPONENT

    abba nn means

    Radical

    a 0, b 0

    nth root,nany +ve

    integer

    Ex 3 pg 6 - 7

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    Chapter 1 : Indices & Logarithms 8

    1.1 EXPONENT

    Law Example Try

    Properties of nth roots

    0for

    evenisif,

    oddisif,

    a

    na

    naa

    n n

    nnn baab

    mnmn aa

    n

    n

    n

    b

    a

    b

    a

    3333 288 zzz 5 243m

    3

    2

    27

    8

    27

    83

    3

    3 4256

    81

    242564 3 729

    612966

    62166

    44 4

    33 3

    8 8

    5 5

    6

    2

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    Chapter 1 : Indices & Logarithms 9

    1.1 EXPONENT

    Rational, - ve & Zero exponent

    Rational exponent : n mm

    nnm

    aaa

    10 a

    m& n are

    integers, n> 0

    Negative exponent:n

    n

    a

    a1

    Zero exponent :

    Ex 4 pg 89

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    Chapter 1 : Indices & Logarithms 10

    Logarithm function with base a, denoted by logais

    defined by;

    1.2 LOGARITHMS

    813

    8238log

    12553125log

    4

    32

    35

    Definition

    base

    Exponent

    (index / power)

    formlexponentiaformlogaritmic

    log yaxy xa

    Example:

    Equivalent

    form

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    Chapter 1 : Indices & Logarithms 11

    b

    x

    b

    x

    b

    xx

    a

    ab

    ln

    ln

    log

    log

    log

    loglog

    10

    10

    Common logarithm: Logarithm with base 10, denoted by,

    Natural logarithm: Logarithm with base e, denoted by

    Base conversion:

    Type of Log

    yy 10loglog

    yye

    logln

    Any

    base Base

    10

    Base e

    1.2 LOGARITHMS

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    Chapter 1 : Indices & Logarithms 12

    Example 1

    1. Rewrite each function below in exponential orlogarithm form.

    a) 72= 49

    b) Log2128 = 7

    c) 5-2= 1/25

    d) Logb1=0

    2. Determine the value of log27 and log312.

    8074.22log

    7log

    7log 10

    10

    2

    Ex 5 & 6 pg 1011

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    Chapter 1 : Indices & Logarithms 13

    Logarithms Example

    logaxy= log

    ax+ log

    ay log

    45x= log

    45 + log

    4x

    loga(x/y) = logax logay ln 8ln 2 = ln (8/2) = ln 4

    loga(xn) = nlogax log 5

    3 = 3log 5

    logaa = 1 log33 = 1

    loga1 = 0 ln 1 = 0

    Law of logarithms

    1.2 LOGARITHMS

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    Chapter 1 : Indices & Logarithms 14

    Example 2

    1. Use the property of logarithms to rewrite each of thefollowing:

    a) ln 18 = ln (2.3.3) =

    b) log 5 + log 2 =

    c) log (3/5) =d) log 8x2log 2x=e) Log 1003.4= log (102)3.4=

    2. Simplify & determine the value of ;2log 5 + 3log 44log 2

    Ex 7 pg 1213

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    Chapter 1 : Indices & Logarithms 15

    Example 2

    3. If log 2 = 0.3010, log 3 = 0.4771 and log 5 = 0.6990,determine each of the following without using a calculator:

    a) log 6 = log 2x3 = log 2 + log 3

    = 0.3010 + 0.4771 = 0.7781

    b) log 81

    c) log 1.5

    d) log 5

    e) log 50

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    Chapter 1 : Indices & Logarithms 16

    Exponential Equation The variable occurs

    in the exponent.

    E.g. 2x= 7

    To solve:1) Use the properties of

    exp.

    2) Rewrite in equivalentform.

    3) Solve the resultingequation.

    Logarithmic Equation A logarithmof the

    variable occurs.

    E.g. log2 (x+2) = 5

    To solve:1) Use the properties of

    log.

    2) Rewrite in equivalentform.

    3) Solve the resultingequation.

    1.3 EXPONENTIAL & LOGARITHS

    EQUATION

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    Chapter 1 : Indices & Logarithms 17

    calculatorause,forSolve43ln

    81ln

    exponent)thedown(bring3Law81ln3ln

    sideeachoflnTake81ln3ln

    xx

    x

    x

    Example 3

    Solve each of the following;a) 3x= 81

    b) 52x+1= 254x-1

    2

    1

    forSolve2812

    4Lawand3LawlyApp5log285log12

    sideeachoflogTake5log5log

    55

    55

    528

    512

    5

    14212

    x

    xxx

    xx

    xx

    xx

    Ex 10 pg 1516

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    Chapter 1 : Indices & Logarithms 18

    forSolve0.4582x

    lnofProperty0.91632x

    sideeachoflnTake5.2lnln

    8byDivide

    8

    20

    208

    2

    2

    2

    x

    e

    e

    e

    x

    x

    x

    Example 3

    Solve each of the following;c) 8e2x= 20

    Ex 14 pg 1920

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    Chapter 1 : Indices & Logarithms 19

    Example 4

    0127 24 kkSolve for k, if

    aaaaa

    ka

    kk

    forsolve&Factor043

    factorizeandReplace0127

    ;Let

    exponentofLaw0127

    2

    2

    222

    24

    4

    4

    04

    2

    k

    k

    a

    a

    3

    3

    3

    03

    2

    k

    k

    a

    a

    Step 1

    Step 2

    Step 3

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    Chapter 1 : Indices & Logarithms 20

    Example 5

    aaa

    aa

    a x

    xx

    forsolve&Factor023

    factorizeandReplace06

    ;5Let

    exponentofLaw0655

    2

    2

    25

    2

    02

    x

    a

    a

    Solve for mif 52x

    - 5x

    6 = 0Step 1

    Step 2

    Step 3

    0.6826x

    ln5

    3lnx

    3ln5ln

    35

    3

    03

    x

    x

    a

    a Or

    No solution,xisundefined

    Ex 13 pg 8

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    Chapter 1 : Indices & Logarithms 21

    calculatorUse1096.6

    formEquivalent7

    ex

    Solve each of the following;a) ln x = 7

    b) log2 (x+2) = 5

    c) Log2(25x) = 3

    30

    forSolve232

    formlExponentia22

    52log

    5

    2

    xx

    x

    x

    Example 6

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    Chapter 1 : Indices & Logarithms 22

    2byDivide5000formlExponentia102

    3byDivide42log

    4Subtract122log3

    4

    xx

    x

    x

    Solve each of the following;d) 4 + 3Log 2x= 16

    e) c

    Example 6

    4ln3ln2 xx