ch 9.1 power series calculus graphical, numerical, algebraic by finney, demana, waits, kennedy
TRANSCRIPT
Ch 9.1 Power SeriesCalculus Graphical, Numerical, Algebraic byFinney, Demana, Waits, Kennedy
What You Will Learn
• All continuous functions can be represented as a polynomial
• Polynomials are easy to integrate and differentiate
• Calculators use polynomials to calculate trig functions, logarithmic functions etc.
• Downfall of polynomial equivalent functions is that they have an infinite number of terms.
For Example
• Power Series: an infinite sum of variables to a power.
• y = sin (x) can be represented as a power series:
Every time you add a term to the series it fits sin x even better.
Let’s check this out using the calculator and then the geometer sketchpad.
3 5 7 9x x x xsin x = x - + - + - ....
3! 5! 7! 9!
2.5
2
1.5
1
0.5
-0.5
-1
-1.5
-2
-1 1 2 3 4 5 6 7
g x = x-x3
32
f x = sin x
2.5
2
1.5
1
0.5
-0.5
-1
-1.5
-2
-1 1 2 3 4 5 6 7
g x = x-x3
32 +
x5
5432 -
x7
765432
f x = sin x
2.5
2
1.5
1
0.5
-0.5
-1
-1.5
-2
-1 1 2 3 4 5 6 7
g x = x-x3
32 +
x5
5432 -
x7
765432 +
x9
98765432
f x = sin x
2.5
2
1.5
1
0.5
-0.5
-1
-1.5
-2
-1 1 2 3 4 5 6 7
g x = x-x3
32 +
x5
5432 -
x7
765432 +
x9
98765432 -
x11
111098765432
f x = sin x
2.5
2
1.5
1
0.5
-0.5
-1
-1.5
-2
-1 1 2 3 4 5 6 7
g x = x-x3
32 +
x5
5432 -
x7
765432 +
x9
98765432 -
x11
111098765432 +
x13
1312111098765432
f x = sin x
2.5
2
1.5
1
0.5
-0.5
-1
-1.5
-2
-1 1 2 3 4 5 6 7
g x = x-x3
32 +
x5
5432 -
x7
765432 +
x9
98765432 -
x11
111098765432 +
x13
1312111098765432 -
x15
15141312111098765432 +
x17
171615141312111098765432
f x = sin x
Power Series for cos x
If sin x can be represented by the power series:
3 5 7 9x x x xsin x = x - + - + - ....
3! 5! 7! 9!
Then cos x can be represented by the power series derived from taking the derivative of sin x:
2 4 6 8 2n
nx x x x xcos x = 1 - + - + - ....+(-1)
2! 4! 6! 8! 2n !
Let’s check it out on the calculator…
Power Series for cos x
Geometric Series
n
n
1 - rS = a
1 - r
Partial Sum of a Geometric Series:
Sn = a + ar + ar2 + ar3 + … + arn-1
-[r Sn = ar + ar2 + ar3 + … + arn ]
Sn – r Sn = a + arn
Sn (1 – r) = a (1 - rn)
Sum of Converging Series
nn
nn
1 - rlim S = a , if r < 1, then r goes to
1 - r
zero and
a S =
No
1 - rif r > 1, the series diverges.
te: The interval of convergence is r < 1
Power Series Using Calculator
102
x = 1
2
To calculate a partial sum of a power series on the calculator,
x
you can find the expanded form by entering:
seq x , x, 1, 10
to get 1 4 9 16 2
2
5 36 49 64 81 100
and the sum by entering:
sum seq x , x, 1, 10
to get 385
Example of a Power Series
nn
n=0
2 3
1The function y = can be written as the power series:
1 - x
S = x which converges only for x < 1
this expands to 1 + x + x + x + ... this is an infinite series
that converges
1
n2
1
2
1to S = .
1 - x1
On your calculator, enter y = and 1 - x
y = sum seq x , n, 0, 20
Then test a value at home:
Enter y (.5)
Enter y (.5)
What do you notice?
Convergent Series
Only two kinds of series converge:
1) Geometric whose | r | < 1
2) Telescoping series
Example of a telescoping series: the middle terms cancel out
n 1 n = 1
n
1 1 1 = -
n n + 1 n n + 1
1 1 1 1 1 1 1 = 1 - + - + - + - +...
2 2 3 3 4 4 5
= sum of 1 - last term
= 1 + lim
1 -
n + 1
= 1 + 0 = 1
n 1
n 1
15
2
n 1
n 1
15
2
Graph both of these functions on your calculator!
Now graph both
y = ln (1+x)
And the power series below and check the fit!
Finding Power Series for Functions
Given that 1/(1-x) is represented by the power series:
1 + x + x2 + … + xn + …
On the interval (-1,1),
1. Find a power series that represent 1/(1+x) on (-1,1).
2. Find a power series that represents x/(1+x) on (-1,1).
3. Find a power series that represents 1(1-2x) on (- ½ , ½ )
4. Find a power series that represents
5. Find a power series that represents
and give its interval of convergence
1 1 = on (0,2)
x 1 + (x - 1)
1 1 1 =
3x 3 1 + (x - 1)
Finding Power Series for Functions
Given that 1/(1 - x) is represented by the power series:
1 + x + x2 + … + xn + … on the interval (-1,1),
1. Find a power series that represent 1/(1+x) on (-1,1)
1 - x + x2 – x3 … + (-x)n + …
2. Find a power series that represents x/(1+x) on (-1,1).
x – x2 + x3 – x4 + x5 – x6…. + (-1)n xn+1 + …
3. Find a power series that represents 1/(1 - 2x) on (- ½ , ½ )
1 + 2x + 4x2 + 8x3 + … + (2x)n + …
4. Find a power series that represents
1 – (x-1) + (x-1)2 – (x-1)3 + … + (-1)n (x-1)n + …
5. Find a power series that represents
1 1 = on (0,2)
x 1 + (x - 1)
1 1 1 =
3x 3 1 + (x - 1)
2 31 1 1 1 - (x-1) + (x-1) - (x-1) + ... on (0,2)3 3 3 3
Finding a series for tan-1 x
1. Find a power series that represents on (-1,1)
2. Use integration to find a power series that represents
tan-1 x.
3. Graph the first four partial sums. Do the graphs suggest convergence on the open interval (-1, 1)?
4. Do you think that the series for tan-1 x converges at x = 1?
21
(1 x )
Finding a series for tan-1 x
1. Find a power series that represents on (-1,1)
2. Use integration to find a power series that represents
tan-1 x.
3. Graph the first four partial sums. Do the graphs suggest convergence on the open interval (-1, 1)?
yes
4. Do you think that the series for tan-1 x converges at x = 1? Yes to
21
(1 x )2 4 6 n 2n1 - x + x - x + ...+ (-1) x + ...
3 5 7 2n 1n
2
1 x x x x dx = x - + - +...+ (-1) +...
1 x 3 5 7 2n 1
4
Guess the function
Define a function f by a power series as follows:
2 3 4 nx x x xf (x) = 1 + x + + + +...+ + ...
2! 3! 4! n!
Find f ‘(x).
What function is this?
Guess the function
Define a function f by a power series as follows:
2 3 4 nx x x xf (x) = 1 + x + + + +...+ + ...
2! 3! 4! n!
Find f ‘(x).
What function is this? ex
2 3 4 nx x x xf (x) = 1 + x + + + +...+ + ...
2! 3! 4! n!