ch 17 (project management).ppt
TRANSCRIPT
7/27/2019 Ch 17 (Project Management).ppt
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ProjectManagement
McGraw-Hill/Irwin Copyright © 2012 by The McGraw-Hill Companies, Inc. All rights reserved.
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You should be able to:1. Discuss the behavioral aspects of projects in terms of
project personnel and the project manager2. Explain the nature and importance of a work breakdown
structure in project management
3. Give a general description of PERT/CPM techniques4. Construct simple network diagrams5. List the kinds of information that a PERT or CPM analysis
can provide6. Analyze networks with deterministic times7. Analyze networks with probabilistic times
8. Describe activity ‘crashing’ and solve typical problems
Instructor Slides 17-2
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ProjectsUnique, one-time operations designed to
accomplish a specific set of objectives in alimited time frame
Examples: The Olympic Games
Producing a movieSoftware development
Product developmentERP implementation
Instructor Slides 17-3
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Instructor Slides 17-4
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Projects go through a series of stages– a lifecycle
Projects bring together people with adiversity of knowledge and skills, most of whom remain associated with the project forless than its full life
Organizational structure affects how projectsare managed
Instructor Slides 17-5
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The project manager is ultimately responsible forthe success or failure of the project
The project manager must effectively manage: The work
The human resources Communications
Quality
Time
Costs
Instructor Slides 17-6
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Behavioral problems can be created orexacerbated byDecentralized decision making Stress of achieving project milestones on time and
within budget Surprises
The team must be able to function as a unit Interpersonal and coping skills are very important
Conflict resolution and negotiation can be an important
part of a project manager’s job
Instructor Slides 17-7
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Many problems can be avoided or mitigatedby: Effective team selection Leadership
MotivationMaintaining an environment of
Integrity Trust
Professionalism
Being supportive of team efforts
Instructor Slides 17-8
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Project championA person who promotes and supports a projectUsually resides within the organization
Facilitate the work of the project by ‘talking up’ the
project to other managers, and who might beasked to share resources with the project team aswell as employees who might be asked to work onparts of the project
The project champion can be critical to the success
of a project
Instructor Slides 17-9
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Planning Planning
ObjectivesObjectives
ResourcesResources
Work break-downWork break-downscheduleschedule
OrganizationOrganization
Scheduling Scheduling
Project activitiesProject activities
Start & end timesStart & end times
Network Network
Controlling Controlling
Monitor, compare, revise, actionMonitor, compare, revise, action
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WBSA hierarchical listing of what must be done
during a projectEstablishes a logical framework for identifying the
required activities for the project1. Identify the major elements of the project
2. Identify the major supporting activities for each of the major elements
3. Break down each major supporting activity into a
list of the activities that will be needed toaccomplish it
Instructor Slides 17-11
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Instructor Slides 17-12
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Instructor Slides 17-13
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PERT (program evaluation and reviewtechnique) and CPM (critical path method)are two techniques used to manage large-scale projects
By using PERT or CPM Managers can obtain:1. A graphical display of project activities
2. An estimate of how long the project will take
3. An indication of which activities are most critical totimely project completion
4. An indication of how long any activity can be delayedwithout delaying the project
Instructor Slides 17-14
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Network diagram Diagram of project activities that shows sequential
relationships by use of arrows and nodes
Activity on arrow (AOA)Network diagram convention in which arrows designate
activities Activity on node (AON)
Network convention in which nodes designate activitiesActivities
Project steps that consume resources and/or time
Events The starting and finishing of activities
Instructor Slides 17-15
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Deterministic Time estimates that are fairly certain
Probabilistic Time estimates that allow for variation
Instructor Slides 17-17
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Finding ES and EF involves a forwardpass through the network diagram Early start (ES)
The earliest time an activity can startAssumes all preceding activities start as early as possible For nodes with one entering arrow ES = EF of the entering arrow
For activities leaving nodes with multiple entering arrows ES = the largest of the largest entering EF
Early finish (EF) The earliest time an activity can finish
EF = ES + t
Instructor Slides
17-18
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Finding LS and LF involves a backward passthrough the network diagram Late Start (LS)
The latest time the activity can start and not delay theproject
The latest starting time for each activity is equal to its latestfinishing time minus its expected duration: LS = LF - t
Late Finish (LF) The latest time the activity can finish and not delay the
project For nodes with one leaving arrow, LF for nodes entering that
node equals the LS of the leaving arrow For nodes with multiple leaving arrows, LF for arrows entering
node equals the smallest of the leaving arrows
Instructor Slides
17-19
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Slack can be computed one of two ways:Slack = LS – ESSlack = LF – EF
Critical path The critical path is indicated by the activities
with zero slack
Instructor Slides
17-20
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Knowledge of slack times providesmanagers with information for planningallocation of scarce resources
Control efforts will be directed toward those activitiesthat might be most susceptible to delaying the project
Activity slack times are based on the assumption that allof the activities on the same path will be started asearly as possible and not exceed their expected time
If two activities are on the same path and have the
same slack, this will be thetotal slack
available to both
Instructor Slides
17-21
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Activity Activity DescriptionDescriptionImmediateImmediate
PredecessorsPredecessors
A A Build internal componentsBuild internal components ——
BB Modify roof and floor Modify roof and floor ——
C C Construct collection stack Construct collection stack A A
DD Pour concrete and install framePour concrete and install frame A, B A, B
E E Build high-temperature burner Build high-temperature burner C C
F F Install pollution control systemInstall pollution control system C C
G G Install air pollution deviceInstall air pollution device D, E D, E
H H Inspect and test Inspect and test F, G F, G
Milwaukee Paper Manufacturing's Activities andMilwaukee Paper Manufacturing's Activities andPredecessorsPredecessors
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A
Start
BStart Activity
Activity A(Build Internal Components)
Activity B(Modify Roof and Floor)
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C
D
A
Start
B
Activity A Precedes Activity C
Activities A and B Precede Activity D
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G
E
F
H
C A
Start
DB
Arrows Show PrecedenceRelationships
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HH
(Inspect/(Inspect/Test)Test)
77DummyDummy Activity Activity
66
F F ( I n s t a l l
( I n s t a l l
C o n t r o l s )
C o n t r o l s ) E E
( B
u i l d
B u r n
e r
)
( B
u i l d
B u r n
e r
)
G G
( I n s t a
l l
( I n s t a
l l
P o l l u
t i o n
P o l l u
t i o n
D e v i c
e )
D e v i c
e )
55DD
(Pour (Pour Concrete/Concrete/
Install Frame)Install Frame)
44CC
(Construct(ConstructStack)Stack)
11
33
22
B B ( M o d i f y
( M o d i f y
R o o f / F l o o r )
R o o f / F l o o r )
A A
( B u i l d
I n t e r n a
l
( B u i l d
I n t e r n a
l
C o m
p o n e
n t s )
C o m
p o n e
n t s )
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Perform a Critical Path AnalysisPerform a Critical Path Analysis
The critical path is the longest pathThe critical path is the longest path
through the networkthrough the network The critical path is the shortest time inThe critical path is the shortest time in
which the project can be completedwhich the project can be completed
Any delay in critical path activities delays Any delay in critical path activities delaysthe projectthe project
Critical path activities have no slack timeCritical path activities have no slack time
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Perform a Critical Path AnalysisPerform a Critical Path Analysis
Activity Description Time (weeks)
A Build internal components 2B Modify roof and floor 3
C Construct collection stack 2
D Pour concrete and install frame 4
E Build high-temperature burner 4
F Install pollution control system 3
G Install air pollution device 5
H Inspect and test 2
Total Time (weeks) 25
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Perform a Critical Path AnalysisPerform a Critical Path Analysis
Activity Description Time (weeks)
A Build internal components 2
B Modify roof and floor 3C Construct collection stack 2
D Pour concrete and install frame 4
E Build high-temperature burner 4
F Install pollution control system 3
G Install air pollution device 5
H Inspect and test 2
Total Time (weeks) 25
Earliest start (ES) = earliest time atwhich an activity can start, assuming allpredecessors have been completed
Earliest finish (EF) = earliest time atwhich an activity can be finished
Latest start (LS) = latest time atwhich an activity can start so as to notdelay the completion time of the entire
project
Latest finish (LF) = latest time bywhich an activity has to be finished so asto not delay the completion time of theentire project
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Perform a Critical Path AnalysisPerform a Critical Path Analysis
A
Activity Name or Symbol
EarliestStart ES
EarliestFinishEF
LatestStart
LS LatestFinish
LF
Activity Duration
2
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Begin at starting event and work forwardBegin at starting event and work forward
Earliest Finish Time Rule:
The earliest finish time (EF) of an activity isthe sum of its earliest start time (ES) and itsactivity time
EF = ES + Activity time
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Start
0
0
ES
0
EF = ES + Activity time
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Start
0
0
0
A
2
2
EF of A =ES of A + 2
0
ESof A
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B
3
Start
0
0
0
A
2
20
3
EF of B =ES of B + 3
0
ESof B
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C
2
2 4
B
3
0 3
Start
0
0
0
A
2
20
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C
2
2 4
B
3
0 3
Start
0
0
0
A
2
20
D
4
73
= Max (2, 3)
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D
4
3 7
C
2
2 4
B
3
0 3
Start
0
0
0
A
2
20
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E
4
F
3
G
5
H
2
4 8 13 15
4
8 13
7
D
4
3 7
C
2
2 4
B
3
0 3
Start
0
0
0
A
2
20
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Begin with the last event and work backwardsBegin with the last event and work backwards
Latest Finish Time Rule:
If an activity is an immediate predecessor for just a single activity, its LF equals the LS of theactivity that immediately follows it
If an activity is an immediate predecessor tomore than one activity, its LF is the minimum
of all LS values of all activities thatimmediately follow it
LF = Min {LS of all immediate following activities}
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Begin with the last event and work backwardsBegin with the last event and work backwards
Latest Start Time Rule:
The latest start time (LS) of an activity is thedifference of its latest finish time (LF) and itsactivity time
LS = LF – Activity time
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E
4
F
3
G
5
H
2
4 8 13 15
4
8 13
7
D
4
3 7
C
2
2 4
B
3
0 3
Start
0
0
0
A
2
20
LF = EFof Project
1513
LS = LF – Activity time
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E
4
F
3
G
5
H
2
4 8 13 15
4
8 13
7
13 15
D
4
3 7
C
2
2 4
B
3
0 3
Start
0
0
0
A
2
20
LF = Min(LS of followingactivity)
10 13
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E
4
F
3
G
5
H
2
4 8 13 15
4
8 13
7
13 15
10 13
8 13
4 8
D
4
3 7
C
2
2 4
B
3
0 3
Start
0
0
0
A
2
20
LF = Min(4, 10)
42
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E
4
F
3
G
5
H
2
4 8 13 15
4
8 13
7
13 15
10 13
8 13
4 8
D
4
3 7
C
2
2 4
B
3
0 3
Start
0
0
0
A
2
20
42
84
20
41
00
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After computing the ES, EF, LS, and LF times for After computing the ES, EF, LS, and LF times for all activities, compute the slack or free time for all activities, compute the slack or free time for each activityeach activity
Slack is the length of time an activitycan be delayed without delaying theentire project
Slack = LS – ES or Slack = LF – EF
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Earliest Earliest Latest Latest OnStart Finish Start Finish Slack Critical
Activity ES EF LS LF LS – ES Path
A 0 2 0 2 0 Yes
B 0 3 1 4 1 No
C 2 4 2 4 0 Yes
D 3 7 4 8 1 No
E 4 8 4 8 0 Yes
F 4 7 10 13 6 No
G 8 13 8 13 0 Yes
H 13 15 13 15 0 Yes
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E
4
F
3
G
5
H
2
4 8 13 15
4
8 13
7
13 15
10 13
8 13
4 8
D
4
3 7
C
2
2 4
B
3
0 3
Start
0
0
0
A
2
20
42
84
20
41
00
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Activity Predecessor Durationa -- 5 days
b -- 4
c a 3
d a 4
e a 6
f b, c 4
g d 5
h d, e 6
i f 6
j g, h 4