cementing calculation

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2/10/2014 1 Dr. Syahrir Ridha Cementing Calculation The following calculations must be undertaken before cement job performed 1. Slurry Requirement 2. Number of Sacks of Cement 3. Volume of Mixwater 4. Volume of Additives 5. Displacement Volume Duration of Operation These calculations will form the basis of the cementing operation

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Cementing Calculation

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  • 2/10/2014

    1

    Dr. Syahrir Ridha

    Cementing Calculation

    The following calculations must be undertaken before cement job performed

    1. Slurry Requirement2. Number of Sacks of Cement3. Volume of Mixwater4. Volume of Additives5. Displacement Volume Duration of Operation

    These calculations will form the basis of the cementing operation

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    1. Cement Slurry Requirement

    An additional slurry will generally mixed and pumped to accommodate any errors in the calculated volumes.

    It may be due to washouts etc.

    Common practice is to add an extra 10-20% of the calculated volumes.

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    (Single Stage Cementing Operation)

    (Two-Stage Cementing Operation)

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    2. Number of Sacks of Cement

    1 sack of cement = 1 cu ft = 43 kg = 94 lb

    The amount of cement slurry that can be produced from a sack of cement yield of cement

    It depend on the type of cement powder (API classification) and the amount of mixwater.

    Number of sacks cement required for cement job:

    No. of Sacks = Total Volume of Slurry

    Yield of Cement

    3. Mixwater Requirements

    The amount of mixwater required for the operation will depend on the type of cement powder used.

    The volume of mixwater required for cement slurry:

    Mixwater Vol. = Mixwater per sack x No of Sacks

    4. Additive Requirements

    The amount of additives is quoted as a percentage of the cement powder used.It used weight rather that volume.This can then be related to the number of sacks of additive.

    Number of sacks of additive = No. sacks Cement x % Additive

    Weight of additive = No. sacks of Additive x 94 (lb/sk)

    5. Displacement Volume

    This is the volume of mud used to displace the cement from the cement stinger or the casing during cementing operation

    a. Stinger OperationThe displacement volume can be calculated from volumetric capacity of the cement stinger and the depth of casing shoe. The cement commonly displaced by 1 2 bbls of liquid.

    Displacement Vol. = Vol. Capacity of Stinger x Depth of Casing

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    b. Conventional OperationFor this , the displacement volume is calculated from the volumetric capacity of the casing and the depth of the float collar in the casing

    Displacement Vol. = Vol. Capacity of Casing x Depth of Float Collar

    c. Two-stage Cementing OperationFor this , the first stage is firstly displaced by a volume of mud (single stage operation). The second stage is based on volumetric capacity of the casing and the depth of the second stage collar.

    1st Stage:Displacement Vol. = Vol. Capacity of Casing x Depth of Float Collar

    2nd Stage:Displacement Vol. = Vol. Capacity of Casing x Depth of Multi-stage Collar

    d. Duration of Operation

    It is used to determine the require setting time for the cement formulation. The operation duration is calculated based on the mixing rate for the

    cement, pumping rate of slurry and pumping rate for the displacing mud. Contingency Time, an additional period of time to account for any

    operational problems during operation ( normally 1 hr).

    = .

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    + . +

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    EXAMPLE:

    Float collar at: 13740

    The operation is under Stinger pipe 5 with capacity 0.0997 ft3/ft

    1. Slurry volume between the casing and hole?2. Slurry volume below the float collar?3. Slurry volume in the rathole?4. Amount of cement and mixwater?5. Amount of additive?6. Displacement volume?7. Displacement time with mixing & pumping time is 28 ft3/min.

    Determine:

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    7. Displacement Time

    Total displacement time = Time to mix and pump + time to displace cement

    Total volume of cement = 1177 ft3 (including additives)

    Displacement volume: 5647 ft3

    Total volume to mix and displace = 1177 + 5647 = 6824 ft3

    Total time @ 28 ft3/min = 6824 / 28 = 243 min = 4 hrs