calculator technique session 1
TRANSCRIPT
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Calculator TechniquesPrepared By: Engr. Jamille G. Quindara
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Lesson 1. Calcu Tech/ Theory / Practice
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Quadratic Equation
A quadratic equation is a second order polynomial equation in a single variable. Because it is second-order polynomial equation, the fundamental theorem of algebra guarantees that it has two solutions.
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General Formula:
Roots
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Problem 1. Find the roots of X2 + 5x + 6a. -2 , -3b. 10, 5c. 6, -3d. -8, 1
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Solution :
Mode (5) (3)
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Solution :
Mode (5) (3)
*Input value of a b and c
1 (=) 5 (=) 6 (=)
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Solution :
Mode (5) (3)
*Input value of a b and c
1 (=) 5 (=) 6 (=)
Ans. -2 , -3
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Problem 2.
Find the sum of the roots of the equation 3X2-11x-4=O
a. -1/4b. 10/6c. 1/4d. 11/3
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Solution :
Mode (5) (3)
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Solution :
Mode (5) (3)
*Input values of a b and c
3 (=) -11 (=) -4 (=)
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Solution :
Mode (5) (3)
*Input values of a b and c
3 (=) -11 (=) -4 (=)
X1 = 4 , X2 = -1/3
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Solution :
Mode (5) (3)
*Input values of a b and c
3 (=) -11 (=) -4 (=)
X1 = 4 , X2 = -1/3
4 + (-1/3) = 11/3
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Problem 3.
The equation whose roots are the reciprocals of the roots of the equation, 2X2 - 3x – 5 = 0
a. 2X2 – 5x – 3 = 0b. 5X2 – 2x – 3 = 0c. 5X2 + 3x – 2 = 0d. 3X2 – 5x – 2 = 0
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Lesson 2: Calculator Functions/ Mode/ Setup
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Default Calculator Mode:
Press : ON Shift
Mode Setup 1 (Mth I0) 1 (Math0) Mode Setup 1 (Comp)
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Clearing Cache
Press : ON Shift 9
3 (All) = (yes) AC
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Press Mode
1: Comp 2: Cmplx 3: Stat 4: Base-N 5: Eqn 6: Matrix 7: Table 8: Vector
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Mode 1. Comp Includes basic computation/basic functions
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Lesson 3. Mode 1 ( Comp)
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LESSON 3.1 SHIFT SOLVE
Problem. 1Solve x in the equation 2log 4 x - log 4 9 = 2
a. 12b. 10c. 11d. 12
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Solution:
Input 2log 4 x - log 4 9 = 2
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Solution:
Input 2log 4 x - log 4 9 = 2
Alpha XAlpha )
log
Alpha Calc
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Solution:
Input 2log 4 x - log 4 9 = 2
Press Shift CalcInput Any number from the choices
Alpha )
log
Alpha Calc
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225 = Find n
log x2 – log 5x = log 20 ; Find x
½(x^2+3x) – ½(x^2-3x) = 21 Find x
4(72n+1) – 10(52n-1)
2(42n) 661/16
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LESSON 3.2 REMAINDER THEORM
Problem 2. When you divide X2 – 2x + 2 = 0 by (x – 2), find the remainder.
a. 2b. 4c. 5d. 8
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Solution:
Input the equation X2 – 2x + 2
Replace X by 2
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Solution:
Input the equation X2 – 2x + 2
(2)2 – 2(2) + 2
Replace X by 2
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Solution:
Input the equation X2 – 2x + 2
(2)2 – 2(2) + 2 = 2
Replace X by 2
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If (x+3) is a factor of X3 + 3X2 + 4X + K , f ind K
a. 11b. 12c. 13d. 14