calculations - integration with studio 5

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Project 2 : Lighting and Acoustics Integration with Design Studio 5 Tutor : Mr. Sanjey Raman Nadia Othman 0303423 1

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Page 1: CALCULATIONS - Integration with Studio 5

Project 2 : Lighting and Acoustics Integration with Design Studio 5

Tutor : Mr. Sanjey Raman

Nadia Othman 0303423

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Page 2: CALCULATIONS - Integration with Studio 5

1.0 Lighting

1.1 Daylighting _____________________________________________________________________ 3

I) Market

II) Reading Area

III) Spa

1.2 Artificial lighting _________________________________________________________________4

I) Market

II) Reading Area

III) Spa

2.0 Acoustic

2.1 Reverberation time ______________________________________________________________10

I) Market

II) Reading Area

III) Spa

2.2 External noise sound pressure level _________________________________________________13

2.3 Sound transmission class _________________________________________________________14

I) Market

II) Reading Area

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Page 3: CALCULATIONS - Integration with Studio 5

1.1 Daylighting

DF =

EiEo X 100%

I) Market

DF = 800/32000 X 100%

= 2.5%

This space has a fair daylight factor, the usage of artificial light would be sufficient to the space.

II) Reading

DF = 700/32000 X 100%

= 2.19%

This space has a fair daylight factor, the usage of artificial light would be sufficient to the space.

III) Spa

DF = 600/32000 X 100%

= 1.88%

This space has a fair daylight factor, the usage of artificial light would be sufficient to the space.

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Page 4: CALCULATIONS - Integration with Studio 5

1.2 Artificial Lighting

I) Market

Referring to MS 1525, the lighting level required for a market is 500lux.

Location Ground floorRoom Name MarketRoom Dimension L=3.0 m , W=3.0mTotal Floor Area (m²) 9.0Standard Illuminance required (lux) 500Assumption of Reflectance valueMounting Height (hm) 4.5 – 1.0 = 3.5mRoom Index (K) (3 x 3) / (3 + 3) x (4.5-1.0)

= 0.43Utilization Factor (UF) 0.43Maintenance Factor (MF) 0.31

N =

E×AF×UF×MF

= (500 x 9) / (3500x 0.43 x 0.31)

= 9.6 ≈ 10

Type of Lighting Quantity Luminous Flux (lm)

LUMILUX XT T8Wattage : 58WColor temperature : 3000K

10 3500

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Page 5: CALCULATIONS - Integration with Studio 5

II) Reading Area

Referring to MS 1525, the lighting level required for a reading area is 300.

Location First FloorRoom Name Reading AreaRoom Dimension L=6.5m , W=7.5mTotal Floor Area (m²) 48.75Standard Illuminance required (lux) 300Assumption of Reflectance valueMounting Height (hm) 3.5 – 0.8 = 2.7mRoom Index (K) (6.5 x 7.5) / (6.5 + 7.5) x 2.7

= 1.29Utilization Factor (UF) 0.46Maintenance Factor (MF) 0.35

N =

E×AF×UF×MF

= (300 x 48.75) / (3500x 0.46 x 0.35)

= 25.9 ≈ 26

Type of Lighting Quantity Luminous Flux (lm)

Luminous flux : 11000 lm

Color temp: 3000 K

Lifespan: 300 h

26 3500

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Page 6: CALCULATIONS - Integration with Studio 5

III) Spa

Referring to MS 1525, the lighting level required for a spa/bedroom is 150

Location Second FloorRoom Name SpaRoom Dimension L=5.6m , W=3mTotal Floor Area (m²) 16.8Standard Illuminance required (lux) 150Assumption of Reflectance valueMounting Height (hm) 3.5- 1.0 = 2.5 mRoom Index (K) (5.6 x 3)/ (5.6 + 3) x (3.5-1.0)

= 0.8Utilization Factor (UF) 0.40Maintenance Factor (MF) 0.35

N =

E×AF×UF×MF

= (150 x 16.8) / (1100 x 0.4 x 0.35)

= 16.3 ≈ 18

Type of Lighting Quantity Luminous Flux (lm)

OSRAM DULUX INTELLIGENT DIM CFLLuminous flux: 1100 lm

Color temp: 2500 K

Lifespan: 20000 h

18 1100

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Page 7: CALCULATIONS - Integration with Studio 5

Acoustics

Market

Component Material Function Area(m²) Absorption Coefficient (2000Hz)

Sound Absorption (SA)

CEILING Glass Ceiling 255 0.05 12.75WALL Brick

GlassGlass

WallWindowDoor

127.276.838.7

0.040.070.03

5.0885.3761.161

FLOOR Concrete Floor 255 0.06 15.3FURNITURE Wood Chairs

Tables 1616

0.280.06

4.482.76

Total Absorption

46.92

RT =

0 .16×VA

RT = 0.16 x 2805 / 46.92

RT = 9.6s

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Page 8: CALCULATIONS - Integration with Studio 5

Reading Room

Component Material Function Area(m²) Absorption Coefficient (2000Hz)

Sound Absorption (SA)

CEILING Concrete Ceiling 48.75 0.06 2.93WALL Concrete

GlassWallWindow

76.916.2

0.060.07

4.61.1

FLOOR Carpet Floor 48.75 0.60 29.25FURNITURE

PEOPLE

Fabric Chair ChairsTables

10210

0.960.060.46

9.60.124.6

Total Absorption

52.2

RT =

0 .16×VA

RT = 0.16x 170.63 / 52.2

RT = 0.52s

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Page 9: CALCULATIONS - Integration with Studio 5

Spa

Component Material Function Area(m²) Absorption Coefficient (2000Hz)

Sound Absorption (SA)

CEILING Concrete Ceiling 16.8 0.06 1.008WALL Concrete

Glasswood

WallWindowDoor

7.533

0.060.070.03

0.450.210.09

FLOOR Carpet Floor 16.8 0.60 10.08FURNITURE

PEOPLE

Fabric Wood

ChairsTables

212

0.960.060.46

1.920.060.92

Total Absorption

14.74

RT =

0 .16×VA

RT = 0.16 x 58.8 / 14.74

RT = 0.64s

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Page 10: CALCULATIONS - Integration with Studio 5

External noise

Sound pressure level

Traffic noise: 83dB

Activity noise: 60dB

Traffic

83 = 10 log (I₁/I₀)

log¯ⁱ 8.3 = I₁/I₀

log¯ⁱ 8.3 = I₁/(1.0 x 10¯ⁱ²)

I₁ = 1.995 x 10¯⁴

Activity

65 = 10 log (I₁/I₀)

log¯ⁱ 6.5 = I₁/I₀

log¯ⁱ 6.5 = I₁/(1.0 x 10¯ⁱ²)

I₁ = 3.16 x 10¯⁶

Combine intensity

(1.995 x 10¯⁴) + (3.16 x 10¯⁶)

= 2.03 x 10¯⁴

Combined SPL

10 log (I₁/I₀)

= 10 log (2.03 x 10¯⁴/1 x 10¯ⁱ²)

= 10 log 2.03 x 10⁸

=83dB

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Page 11: CALCULATIONS - Integration with Studio 5

Sound Transmission Class

Reading Room

TL for brick wall TL for glass window

42 = 10log

1T 37 = 10log

1T

log¯ⁱ4.2 =

1T log¯ⁱ3.7 =

1T

T = 1/ (1.585 x 10⁴) T = 1/ (5.01 x 10³)

= 6.309 x 10¯⁵ T = 1.995 x 10¯⁴

Average Transmission Coefficient of Materials

Toverall = (7.164 x 10¯4) + (1.407 x 10¯3)/25.9

= 8.19x 10¯⁵

Total SRI of Wall

SRI = 10log 1/8.19 x 10¯⁵

= 10log (12210)

= 40.87

83 – 40.87

= 42.13dB

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Page 12: CALCULATIONS - Integration with Studio 5

Market

TL for brick wall TL for glass window

42 = 10log

1T 37 = 10log

1T

log¯ⁱ4.2 =

1T log¯ⁱ3.7 =

1T

T = 1/ (1.585 x 10⁴) T = 1/ (5.01 x 10³)

= 6.309 x 10¯⁵ T = 1.995 x 10¯⁴

Average Transmission Coefficient of Materials

Toverall = (2.47 x 10¯2) /187

= 1.32 x 10¯4

Total SRI of Wall

SRI = 10log 1/1.32 x 10¯4

= 10log (7575)

= 38.79

83 – 38.79

= 44.21dB

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Page 13: CALCULATIONS - Integration with Studio 5

References

1. LED light colour, CRI and experiments. (n.d.). LED light colour, CRI and experiments. Retrieved December 4, 2014, from http://swhs.home.xs4all.nl/fiets/tests/verlichting/experimenten/index_en.html#cri 

2. Sanjeh R. (2014). Lumen Method, Lecture Notes. Taylor’s University.

3. Sivaraman K. (2014). Acoustic Calculations, Lecture Notes. Taylor’s University.

4. Binggeli, C. (2003). Building System for Interior Designers. New Jersey: John Wiley & Sons.

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