Balancing Equation Notes

Balancing Equation NotesWhy do we need to be balanced?

Why do we need to be balanced?So all atoms that are on the reactant side are also on the product sideRemember the Conservation of Mass Law

Steps to balancing EquationsCount the # of atoms of Each SideAdd Coefficients where necessaryRecount the # of atoms on each sideContinue adding coefficients until the number of atoms on each side are equal.Step 1: Count the # of atoms of Each SideMg = O = Mg = O = Mg + O2 MgOStep 1: Count the # of atoms of Each SideMg = 1 O = 2Mg = 1O = 1Mg + O2 MgOStep 2: Add Coefficients where necessaryAre the numbers on both sides even?NO!Add coefficientsMg = 1 O = 2Mg = 1O = 1Mg + O2 MgO7Step 2: Add Coefficients where necessaryAre the numbers on both sides even?NO!Add coefficientsMg = 1 O = 2Mg = 1O = 1Mg + O2 2MgO8Step 3: Recount the # of atoms on each sideAre the atoms even now?No!Mg = 1 O = 2Mg = 1 2O = 1 2Mg + O2 2MgO9Step 4: Continue adding coefficients until the number of atoms on each side are equal.

Mg = 1 O = 2Mg = 1 2O = 1 2Mg + O2 2MgO10Step 4: Continue adding coefficients until the number of atoms on each side are equal.

Mg = 1 2 O = 2Mg = 1 2O = 1 22Mg + O2 2MgO11Are they equal now?YESThe equation is balanced!!!Step 4: Continue adding coefficients until the number of atoms on each side are equal.

Mg = 1 2 O = 2Mg = 1 2O = 1 22Mg + O2 2MgO12Practice Balancing EquationsNa + Cl2 NaClPractice Balancing EquationsStep 1: Count atoms Na + Cl2 NaClNa = 1Na = 1Cl = 2Cl = 1Practice Balancing EquationsStep 2: Add Coefficients Na + Cl2 2 NaClNa = 1Na = 1Cl = 2Cl = 1Practice Balancing EquationsStep 3: Recount Atoms Na + Cl2 2 NaClNa = 1Na = 1 2Cl = 2Cl = 1 2Practice Balancing EquationsStep 4: Continue adding coefficients until atoms are equal 2 Na + Cl2 2 NaClNa = 1 2Na = 1 2Cl = 2Cl = 1 2Additional PracticeCH4 + O2 CO2 + H2OLi + HNO3 LiNO3 + H2Al + O2 Al2O3Additional PracticeCH4 + O2 CO2 + H2OC = 1C = 1H = 4H = 2O = 2O = 3Additional PracticeCH4 + O2 CO2 + 2H2OC = 1C = 1H = 4H = 2 4O = 2O = 3 6Additional PracticeCH4 + 3O2 CO2 + 2H2OC = 1C = 1H = 4H = 2 4O = 2 6O = 3 6Additional PracticeLi + HNO3 LiNO3 + H2Li = 1Li = 1H = 1H = 2N = 1N = 1O = 3O = 3Additional PracticeLi + 2HNO3 LiNO3 + H2Li = 1Li = 1H = 1 2H = 2N = 1 2N = 1O = 3 6O = 3Additional PracticeLi + 2HNO3 2LiNO3 + H2Li = 1Li = 1 2H = 1 2H = 2N = 1 2N = 1 2O = 36O = 3 6Additional Practice 2Li + 2HNO3 2LiNO3 + H2Li = 12Li = 1 2H = 1 2H = 2N = 1 2N = 1 2O = 36O = 3 6Additional PracticeAl + O2 Al2O3Al = 1Al = 2O = 2O = 3Additional Practice 2Al + O2 Al2O3Al = 1 2Al = 2O = 2O = 3Additional Practice 2Al + O2 2Al2O3Al = 1 2Al = 2 4O = 2O = 3 6Additional Practice 2Al + 3O2 2Al2O3Al = 1 2Al = 2 4O = 2 6O = 3 6Additional Practice 4Al + 3O2 2Al2O3 Al = 1 2 4Al = 2 4 O = 2 6 O = 3 6