averages and range. range range = highest amount - lowest amount
TRANSCRIPT
Averages and Range
Range
Range = highest amount - lowest amount
Types of average
– Sometimes we are told that the average family has 2.4 children.
– There are three types of average: mode, median and mean
• Mean• If amounts are shared out
equally, then each person (or item) will get the same amount which is the mean. If the total number of children are shared out between all the families then there are 2.4 children per family.
ModeThe mode is the most common amount. Most families have 2 children so the mode of the number of children is 2.
MedianWhen the amounts are arranged in order, the middle one is the median.
– A die is tossed 15 times and the scores were:– 6, 5, 4, 3, 4, 1, 1, 2, 4, 4, 3, 2, 3, 5, 4
– Score Frequency– 1 2– 2 2– 3 3– 4 5– 5 2– 6 1
From the table we can see that the score with the highest frequency is 4, so the mode is 4.
– Writing the scores in order gives– 1, 1, 2, 2, 3, 3, 3, 4, 4, 4, 4, 4, 5, 5, 6
– The median is the middle one i.e. 4
– The mean is found by adding together all the scores and dividing by the number of scores (15)
– 1+1+2+2+3+3+3+4+4+4+4+4+5+5+6 = 51
3.4 1551
Mean
The mean height of this mountain range is 1000m
1000 m
The mean height of this mountain range is also 1000m. The mean can mask extreme values.
1000m
Mean, Mode and Median of Frequency Distributions
– The ages of 50 people in a maths club are given below
– Find the mean, mode and median of their ages.•
– 23 has the highest frequency, so the mode is 23•
– where f is the total of the frequencies and fx is the total of the frequencies ×
values
Age 20 21 22 23 24 25 26 27 28 29 30
Frequency 3 5 4 8 3 6 7 4 4 4 2
f
fx x
– To find the mean, rewrite the frequency table as shown
Age(x)
Frequency(f)
Frequency × age(f × x)
2021222324252627282930
35483674442
y 24.74 50
1237
f
fx
mean60
105
88
184
72
150
182
108112
11660
50 1237
– To find the mean and median, put the data into a frequency table.
Number of children (x)
Number of families (f) f × x
0123
515105
0152015
35 50
1.43 3550
ffx
Mean
18th 2
36
21 35
position Median
The first 5 families have 0 children, the next 15 families have 1 child. Therefore the 18th family has 1 child.
Grouped Data– For a grouped frequency distribution the modal
class is the group (or class) with the highest frequency.
– An estimate for the mean can be found by assuming that each value in a class is equal to the value of the mid-point of the class and then using the formula
f
fx
frequency
midpoint frequency Mean
• Example– At a supermarket, the manager recorded the lengths of time
that 80 customers had to wait in the check-out queue.– Find the modal class and calculate an estimate for the
mean.
Waiting time (t) Mid-pointx
Frequencyf f × x
0 ≤ t < 5050 ≤ t < 100
100 ≤ t < 150150 ≤ t < 200200 ≤ t < 250
250 ≤ t < 300
2575
125175225275
58
10162813
125600
1250280063003575
80 14650
– The class with the highest frequency is the 200 ≤ t < 250 class. The modal class is 200 ≤ t < 250
– The mean is
Waiting time (t) Mid-pointx
Frequencyf f × x
0 ≤ t < 5050 ≤ t < 100
100 ≤ t < 150150 ≤ t < 200200 ≤ t < 250
250 ≤ t < 300
2575
125175225275
58
10162813
125600
1250280063003575
80 14650
183.1 80
14650
ffx
Histograms• Histograms are used to represent information
contained in grouped frequency distributions.
• The horizontal axis is a continuous scale• There are no gaps between the bars
Histogram yn dangos Taldra Bechgyn Histogram representing Boys’ Heights
1.3 1.4 1.5 1.6 1.7 1.8 1.9 2 2.1
1
2
3
4
5
x
f
Histogram yn dangos Taldra GenethodHistogram representing Girls’ Heights
1.3 1.4 1.5 1.6 1.7 1.8 1.9 2 2.1
1
2
3
4
5
x
f
Frequency Polygons• Frequency polygons are often used instead of
histograms when we need to compare two or more groups of data
• To draw a frequency polygon:Plot the frequencies at the midpoint of each class interval Join successive points with straight lines
• To compare data, frequency polygons for different groups of data can be drawn on the same diagram
Polygon Amlder a Histogram o Daldra BechgynFrequency Polygon and Histogram of Boys Heights
1.3 1.4 1.5 1.6 1.7 1.8 1.9 2 2.1
1
2
3
4
5
x
f
Polygon Amledd a Histogram o Daldra GenethodFrequency Polygon and Histogram of Girls Heights
1.3 1.4 1.5 1.6 1.7 1.8 1.9 2 2.1
1
2
3
4
5
x
f
Defnyddio polygonau amledd i gymharu dwy set o ddata
Using frequency polygons to compare two sets of data
1.3 1.4 1.5 1.6 1.7 1.8 1.9 20
1
2
3
4
5
6
x
f
Boys Heights (m)
Girls Heights (m)