application of quantum in chemistry. the particle in a box
TRANSCRIPT
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Application of quantum in chemistry
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The Particle in A Box
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The ‘Classical’ Case
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The ‘Quantum’ Case
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The absolutely small particle in the nanometer size box is a quantum particle, and it must obey the Uncertainty Principle, that is, ΔxΔp= h/4π. If V=0 and x= L/2, we know both x and p. The result would be ΔxΔp 0, the same as the classical racquetball.
This is impossible for a quantum system. Therefore, V cannot be zero. The particle cannot be standing still at a specific point. If V cannot be zero, then Ek
can never be zero. The Uncertainty Principle tells us that the lowest energy that a quantum racquetball can have cannot be zero. Our quantum racquetball can never stand still.
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Energies of a Quantum Particle in a Box
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Wave functions must be zero at the walls
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Nodes are the points where the wave function crosses zero
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Energies are quantized
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A Discreet set of energy levels
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Why are Cherries Red and Blueberries blue ?
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The Colour of Fruit
This energy corresponds to
Deep Red Colour
If L=0.7 nm, =540 nmIf L=0.6 nm, =397 nm
Green ColourBlue Colour
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Particle in a box
Step 1: Define the potential energy
Step 2: Solve the Schrodinger equation
Step 3: Define the wave function
Step 4: Determine the allowed energies
Step 5: Interpret its meaning
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Particle in 1-dimensional box
• Infinite walls
V(x)=0 V(x)=∞V(x)=∞
0 L x
Region I Region II Region III KE PE TE
ExV
dx
xd
m
)(
)(
2 2
22
Time Independent Schrödinger Equation
Applying boundary conditions:
E
dx
xd
m
*
)(
2 2
22
Region I and III:
02
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2
2 2
( ) 2( )
d x mEx
dx
Second derivative of a function equals anegative constant times the same function.
22
2
sin( )sin( )
d axa ax
dx
22cos( )cos( )
d axa ax
dx
Functions with this property sin and cos.
Copyright – Michael D. Fayer, 2007
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E
dx
xd
m
2
22 )(
2
Region II:
E
m
dx
xd22
2 2)(
22
2 )(k
dx
xd
kxBkxA cossin
Applying boundary conditions:
kBkA 0cos0sin0
0
1*00
B
B
b) x=L ψ=0
0ButA
kLAsin0
nkL
This is similar to the general differential equation:
a) x=0 ψ=0
L
xnAII
sin
Thus, wave function:
But what is ‘A’?
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Normalizing wave function:
1)sin(0
2 L
dxkxA
14
2sin
20
2
L
k
kxxA
14
2sin
2
2
Ln
LLn
LA
12
2
L
A
LA
2
Thus normalized wave function is:
L
xn
LII
sin2
22 2
mE
k
m
kE
2
22
2
22
42 m
hkE )
2(
h
2
2
2
22
42
m
h
L
nE
2
22
8mL
hnE
Calculating Energy Levels:
Thus Energy is:
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Particle in a 1-Dimensional Box
L
xn
LII
sin2
2
2sin
2
L
xn
LII
+
+ +
+
+
-
E
1) Difference b/w adjacent energy levels:
2) Non-zero zero point energy
3) Probability density is structured with regions of space demon- -strating enhanced probability.
At very high n values, spectrum becomes continous-
convergence with CM (Bohr’s correspondance principle)
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Particle in a 3-D box
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Question: An electron is in 1D box of 1nm length. What is the probability of locating the electron between x=0 and x=0.2nm in its lowest energy state?
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Question: An electron is in 1D box of 1nm length. What is the probability of locating the electron between x=0 and x=0.2nm in its lowest energy state?
Solution:
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Question: What are the most likely locations of a particle in a box of length L in the state n=3
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Example: What are the most likely locations of a particle in a box of length L in the state n=3
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Expectation value of position and its uncertainty
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Expectation values
Position
Uncertainity
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Expectation value of Momentum
And square of momentum
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Momentum
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Estimating pigment length
Assumptions:
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Wavelength of transition for Anthracene
Particle in a Box Simple model of molecular energy levels.
Anthracene
L 6 AL
electrons – consider “free”in box of length L.
Ignore all coulomb interactions.
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Pigments and Quantum mechanics
• Electrons have wave properties and they don’t jump off the pigments when they reach its ends.
• These electrons resonances determine which frequencies of light and thus which colors, are absorbed & emitted from pigments
High degree of conjugation!!
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Electron resonances in a cyclic conjugated molecule
A crude quantum model for such molecules assumes that electrons move freely in a ring.
Resonance condition:
R: radius of molecule, λ wavelength of electron
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Energy is once again quantized. It depends on variable n which posseses discrete values only