ap physics b - thermodynamics (1)
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Thermodynamics
AP Physics B
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Work done by a gas
Suppose you had a piston filled with aspecific amount of gas. As you addheat, the temperature rises andthus the volume of the gasexpands. The gas then applies aforce on the piston wall pushing it a
specific displacement. Thus it canbe said that a gas can do WORK.
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Work is the AREA of a P vs. V graph
positiveW
negativeW
V
V
VPW
on
by
!
!
!!(
!!(
(!
gastheONdoneisWork
gastheBYdoneisWork
The negative sign in the
equation for WORK is often
misunderstood. Since work done
BY a gas has a positive volume
change we must understand that
the gas itself is USING UP
ENERGY or in other words, it islosing energy, thus the negative
sign.
When work is done ON a gas the change in volume is negative. This cancels out
the negative sign in the equation. This makes sense as some EXTERNAL agent is
ADDING energy to the gas.
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Internal Energy ((U) and Heat Energy (Q)
All of the energy inside asystem is called INTERNALENERGY, (U.
When you add HEAT(Q), youare adding energy and theinternal energyINCREASES.
Both are measured in joules.
But when you add heat,there is usually an increasein temperature associatedwith the change.
0,0,
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o(o(
((
UTif
UTif
TUE
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First Law of Thermodynamics
The internal energy of a system tend to increase
when HEAT is added and work is done ON the
system.
byAdd
onAdd
WQUor
WQUWQU
!(
!(p!(
Suggests a CHANGE or subtraction
You are really adding a negative
here!The bottom line is that if you ADD heat then transfer work TO the gas,
the internal energy must obviously goup as you have MORE than
what you started with.
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Example continued
a) The gas is then
compressed at a constant
pressure of 2.0 atm from a
volume of 3.0 L to 1.0 L.
b) The gas is then heated
until its pressureincreases from 2.0 atm to
3.0 atm at a constant
volume.
!!(! )003.001(.102 5xVPWON -400 J
0since
0
!(
!(!
V
VPW
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Example continued
What is the NETWORK?
NET work is
the area inside
the shape.
600 J + -400 J = 200 J
Rule of thumb: If the systemrotates CW, the NET work is
positive.
If the system rotates CCW,
the NET work is negative.
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ExampleA series of thermodynamic processes is shown in the pV-diagram.
Inprocess ab 150 J of heat is added to the system, and inprocess bd , 600J of heat is added. Fill in the chart.
150
600
750
0
240
240
150 J
840 J
990 J
900
90 990 J900
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Thermodynamic Processes - IsothermalTo keep the temperature
constant both thepressure and volumechange to compensate.(Volume goes up,pressure goes down)
BOYLES LAW
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Thermodynamic Processes - IsobaricHeat is added to the gas
which increases theInternal Energy (U)Work is done by the gasas it changes in volume.
The path of an isobaricprocess is a horizontalline called an isobar.
U = Q - W can be used
since the WORK isPOSITIVE in this case
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Thermodynamic Processes - Adiabatic
ADIABATIC- (GREEK-adiabatos-
"impassable")
Inother words, NO
HEAT can leave orenter the system.
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In Summary
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Second Law of Thermodynamics
Heat will not flow spontaneously from a colder body toa warmer body AND heat energy cannot be
transformed completely into mechanical work.
The bottom line:1) Heat always flows from a hot body to a cold body
2) Nothing is 100% efficient
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EnginesHeat flows from a HOT
reservoir to a COLD
reservoir
CHoutput
CH
QQW
QWQ
!
!
QH = remove from, absorbs = hotQC= exhausts to, expels = cold
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Engine EfficiencyInorder to determine the
thermal efficiencyofan engine you have to
look at how much
ENERGY you get OUT
based on how muchyou energy you take IN.
Inother words:
H
C
H
CH
hotthermal Q
Q
Q
QQ
Q
W
e !
!! 1
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Rates of Energy UsageSo
metimes it isusef
ul to
express theenergy usage of an engine as a
RATE.
For example:
The RATE at which heat is absorbed!
The RATE at which heat is expelled.
The RATE at which WORK is DONE
P WERt
W
t
Q
t
Q
C
H
!
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Efficiency in terms of rates
t
Q
t
Q
P
e
P
t
Q
tQ
P
tQ
tW
Q
We
CH
H
HHH
thermal
!
!
pp!
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Is there an IDEAL engine model?Our goal is to figure out just how efficient
such a heat engine can be: whats the mostwork we canpossibly get for a given amount
of fuel?
The efficiency question was first posedand solvedby Sadi Carnot in 1820,
not long after steam engines had become efficient enough to begin replacingwater wheels, at that time the mainpower sources for industry. Not surprisingly,
perhaps, Carnot visualized the heat engine as a kind of water wheel in which
heat (the fluid) dropped from a high temperature to a low temperature,
losing potential energy which the engine turned into work done, just like a
water wheel.
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Carnot EfficiencyCarnot a believed that there was an
absolute zeroof temperature, fromwhich he figured out that on beingcooled to absolute zero, the fluid wouldgive upallits heat energy. Therefore, ifit falls only half way to absolute zerofrom its beginning temperature, it willgive up half its heat, and an engine
taking in heat at Tand shedding it at Twill be utilizing half the possible heat,and be 50% efficient. Picture a waterwheel that takes in water at the topof awaterfall, but lets it out halfwaydown. So, the efficiency of an idealengine operating between two
temperatures will be equal to thefractionof the temperature drop towardsabsolute zero that the heat undergoes.
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Carnot EfficiencyCarnot temperatures must be
expressed in KELVIN!!!!!!
The Carnot model has 4parts
An Isothermal Expansion
AnAdiabatic ExpansionAn Isothermal Compression
AnAdiabatic Compression
The PV diagram in a way shows us that the ratioof the heats are symbolic to
the ratioof the 2 temperatures
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ExampleThe efficiency of a Carnot engine is 30%. The engine absorbs 800
J of heat per cycle from a hot temperature reservoir at 500 K.Determine (a) the heat expelled per cycle and (b) the
temperature of the cold reservoir
!
!p!
!
!p!
!!p!
C
C
H
CC
C
CCH
H
T
T
T
Te
Q
QWQQW
WJ
W
Q
W
e
500130.01
800
80030.0240 J
560 J
350 K