ap physics b - thermodynamics (1)

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  • 8/6/2019 AP Physics B - Thermodynamics (1)

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    Thermodynamics

    AP Physics B

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    Work done by a gas

    Suppose you had a piston filled with aspecific amount of gas. As you addheat, the temperature rises andthus the volume of the gasexpands. The gas then applies aforce on the piston wall pushing it a

    specific displacement. Thus it canbe said that a gas can do WORK.

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    Work is the AREA of a P vs. V graph

    positiveW

    negativeW

    V

    V

    VPW

    on

    by

    !

    !

    !!(

    !!(

    (!

    gastheONdoneisWork

    gastheBYdoneisWork

    The negative sign in the

    equation for WORK is often

    misunderstood. Since work done

    BY a gas has a positive volume

    change we must understand that

    the gas itself is USING UP

    ENERGY or in other words, it islosing energy, thus the negative

    sign.

    When work is done ON a gas the change in volume is negative. This cancels out

    the negative sign in the equation. This makes sense as some EXTERNAL agent is

    ADDING energy to the gas.

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    Internal Energy ((U) and Heat Energy (Q)

    All of the energy inside asystem is called INTERNALENERGY, (U.

    When you add HEAT(Q), youare adding energy and theinternal energyINCREASES.

    Both are measured in joules.

    But when you add heat,there is usually an increasein temperature associatedwith the change.

    0,0,

    !(!(

    o(o(

    ((

    UTif

    UTif

    TUE

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    First Law of Thermodynamics

    The internal energy of a system tend to increase

    when HEAT is added and work is done ON the

    system.

    byAdd

    onAdd

    WQUor

    WQUWQU

    !(

    !(p!(

    Suggests a CHANGE or subtraction

    You are really adding a negative

    here!The bottom line is that if you ADD heat then transfer work TO the gas,

    the internal energy must obviously goup as you have MORE than

    what you started with.

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    Example continued

    a) The gas is then

    compressed at a constant

    pressure of 2.0 atm from a

    volume of 3.0 L to 1.0 L.

    b) The gas is then heated

    until its pressureincreases from 2.0 atm to

    3.0 atm at a constant

    volume.

    !!(! )003.001(.102 5xVPWON -400 J

    0since

    0

    !(

    !(!

    V

    VPW

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    Example continued

    What is the NETWORK?

    NET work is

    the area inside

    the shape.

    600 J + -400 J = 200 J

    Rule of thumb: If the systemrotates CW, the NET work is

    positive.

    If the system rotates CCW,

    the NET work is negative.

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    ExampleA series of thermodynamic processes is shown in the pV-diagram.

    Inprocess ab 150 J of heat is added to the system, and inprocess bd , 600J of heat is added. Fill in the chart.

    150

    600

    750

    0

    240

    240

    150 J

    840 J

    990 J

    900

    90 990 J900

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    Thermodynamic Processes - IsothermalTo keep the temperature

    constant both thepressure and volumechange to compensate.(Volume goes up,pressure goes down)

    BOYLES LAW

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    Thermodynamic Processes - IsobaricHeat is added to the gas

    which increases theInternal Energy (U)Work is done by the gasas it changes in volume.

    The path of an isobaricprocess is a horizontalline called an isobar.

    U = Q - W can be used

    since the WORK isPOSITIVE in this case

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  • 8/6/2019 AP Physics B - Thermodynamics (1)

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    Thermodynamic Processes - Adiabatic

    ADIABATIC- (GREEK-adiabatos-

    "impassable")

    Inother words, NO

    HEAT can leave orenter the system.

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    In Summary

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    Second Law of Thermodynamics

    Heat will not flow spontaneously from a colder body toa warmer body AND heat energy cannot be

    transformed completely into mechanical work.

    The bottom line:1) Heat always flows from a hot body to a cold body

    2) Nothing is 100% efficient

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    EnginesHeat flows from a HOT

    reservoir to a COLD

    reservoir

    CHoutput

    CH

    QQW

    QWQ

    !

    !

    QH = remove from, absorbs = hotQC= exhausts to, expels = cold

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    Engine EfficiencyInorder to determine the

    thermal efficiencyofan engine you have to

    look at how much

    ENERGY you get OUT

    based on how muchyou energy you take IN.

    Inother words:

    H

    C

    H

    CH

    hotthermal Q

    Q

    Q

    QQ

    Q

    W

    e !

    !! 1

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    Rates of Energy UsageSo

    metimes it isusef

    ul to

    express theenergy usage of an engine as a

    RATE.

    For example:

    The RATE at which heat is absorbed!

    The RATE at which heat is expelled.

    The RATE at which WORK is DONE

    P WERt

    W

    t

    Q

    t

    Q

    C

    H

    !

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    Efficiency in terms of rates

    t

    Q

    t

    Q

    P

    e

    P

    t

    Q

    tQ

    P

    tQ

    tW

    Q

    We

    CH

    H

    HHH

    thermal

    !

    !

    pp!

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    Is there an IDEAL engine model?Our goal is to figure out just how efficient

    such a heat engine can be: whats the mostwork we canpossibly get for a given amount

    of fuel?

    The efficiency question was first posedand solvedby Sadi Carnot in 1820,

    not long after steam engines had become efficient enough to begin replacingwater wheels, at that time the mainpower sources for industry. Not surprisingly,

    perhaps, Carnot visualized the heat engine as a kind of water wheel in which

    heat (the fluid) dropped from a high temperature to a low temperature,

    losing potential energy which the engine turned into work done, just like a

    water wheel.

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    Carnot EfficiencyCarnot a believed that there was an

    absolute zeroof temperature, fromwhich he figured out that on beingcooled to absolute zero, the fluid wouldgive upallits heat energy. Therefore, ifit falls only half way to absolute zerofrom its beginning temperature, it willgive up half its heat, and an engine

    taking in heat at Tand shedding it at Twill be utilizing half the possible heat,and be 50% efficient. Picture a waterwheel that takes in water at the topof awaterfall, but lets it out halfwaydown. So, the efficiency of an idealengine operating between two

    temperatures will be equal to thefractionof the temperature drop towardsabsolute zero that the heat undergoes.

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    Carnot EfficiencyCarnot temperatures must be

    expressed in KELVIN!!!!!!

    The Carnot model has 4parts

    An Isothermal Expansion

    AnAdiabatic ExpansionAn Isothermal Compression

    AnAdiabatic Compression

    The PV diagram in a way shows us that the ratioof the heats are symbolic to

    the ratioof the 2 temperatures

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    ExampleThe efficiency of a Carnot engine is 30%. The engine absorbs 800

    J of heat per cycle from a hot temperature reservoir at 500 K.Determine (a) the heat expelled per cycle and (b) the

    temperature of the cold reservoir

    !

    !p!

    !

    !p!

    !!p!

    C

    C

    H

    CC

    C

    CCH

    H

    T

    T

    T

    Te

    Q

    QWQQW

    WJ

    W

    Q

    W

    e

    500130.01

    800

    80030.0240 J

    560 J

    350 K