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AP Biology AP Biology Measuring Evolution of Populations

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Page 1: AP Biology Measuring Evolution of Populations AP Biology There are 5 Agents of evolutionary change MutationGene Flow Genetic DriftSelection Non-random

AP BiologyAP Biology

MeasuringEvolution of Populations

Page 2: AP Biology Measuring Evolution of Populations AP Biology There are 5 Agents of evolutionary change MutationGene Flow Genetic DriftSelection Non-random

AP Biology

There are 5 Agents of evolutionary changeMutation Gene Flow

Genetic Drift Selection

Non-random mating

Page 3: AP Biology Measuring Evolution of Populations AP Biology There are 5 Agents of evolutionary change MutationGene Flow Genetic DriftSelection Non-random

AP Biology

Populations & gene pools

a population is a localized group of interbreeding individuals

gene pool is a collection of alleles in a particular population (remember difference between alleles & genes!)

allele frequency is how common that allele is in the population (how many of A or a in whole population)

Page 4: AP Biology Measuring Evolution of Populations AP Biology There are 5 Agents of evolutionary change MutationGene Flow Genetic DriftSelection Non-random

AP Biology

Evolution of populations Evolution is a change in allele frequencies in a

population What conditions would cause allele frequencies

not to change? In a non-evolving population you would need to

remove all agents of evolutionary change Eg:

very large population size (no genetic drift)

no migration (no gene flow in or out)

no mutation (no genetic change)

random mating (no sexual selection)

no natural selection (everyone is equally fit)

Page 5: AP Biology Measuring Evolution of Populations AP Biology There are 5 Agents of evolutionary change MutationGene Flow Genetic DriftSelection Non-random

AP Biology

Hardy-Weinberg equilibrium In a non-evolving population allele frequencies are

preserved (they are said to be in Hardy-Weinberg equilibrium), but: natural populations are rarely in Hardy-Weinberg

equilibrium However it provides a useful model to measure if

evolutionary forces are acting on a population

W. Weinbergphysician

G.H. Hardymathematician

Page 6: AP Biology Measuring Evolution of Populations AP Biology There are 5 Agents of evolutionary change MutationGene Flow Genetic DriftSelection Non-random

AP Biology

Hardy-Weinberg theory Counting Alleles

assume 2 alleles = B, b frequency of dominant allele (B) = p frequency of recessive allele (b) = q

frequencies must add up to 1 (100%), so:

p + q = 1

bbBbBB

Page 7: AP Biology Measuring Evolution of Populations AP Biology There are 5 Agents of evolutionary change MutationGene Flow Genetic DriftSelection Non-random

AP Biology

Hardy-Weinberg theory Counting Genotypes

frequency of homozygous dominant: p x p = p2 frequency of homozygous recessive: q x q = q2 frequency of heterozygotes: (p x q) + (q x p) = 2pq

frequencies of all individuals must add to 1 (100%), so:

p2 + 2pq + q2 = 1

bbBbBB

Page 8: AP Biology Measuring Evolution of Populations AP Biology There are 5 Agents of evolutionary change MutationGene Flow Genetic DriftSelection Non-random

AP Biology

H-W formulas Alleles: p + q = 1

Genotypes: p2 + 2pq + q2 = 1

bbBbBB

BB

B b

Bb bb

Page 9: AP Biology Measuring Evolution of Populations AP Biology There are 5 Agents of evolutionary change MutationGene Flow Genetic DriftSelection Non-random

AP BiologyWhat are the genotype frequencies?What are the genotype frequencies?

Using Hardy-Weinberg equationpopulation: 100 cats84 black, 16 whiteHow many of each genotype?

population: 100 cats84 black, 16 whiteHow many of each genotype?

bbBbBB

Must assume population is in H-W equilibrium

What does this mean?

Must assume population is in H-W equilibrium

What does this mean?

First calculate frequency of b from the known number of bb genotypes.

Page 10: AP Biology Measuring Evolution of Populations AP Biology There are 5 Agents of evolutionary change MutationGene Flow Genetic DriftSelection Non-random

AP BiologyWhat equation is used for genotype frequency calculation?What equation is used for genotype frequency calculation?

Using Hardy-Weinberg equation

q2 (bb)= 16/100 = .16

q (b): √.16 = 0.40.4

Now work out pNow work out p

p (B)= 1 - 0.4 = 0.60.6

q2 (bb)= 16/100 = .16

q (b): √.16 = 0.40.4

Now work out pNow work out p

p (B)= 1 - 0.4 = 0.60.6

population: 100 cats84 black, 16 whiteHow many of each allele?

population: 100 cats84 black, 16 whiteHow many of each allele?

bbBbBB

Page 11: AP Biology Measuring Evolution of Populations AP Biology There are 5 Agents of evolutionary change MutationGene Flow Genetic DriftSelection Non-random

AP Biology

Using Hardy-Weinberg equationq2 (bb): 16/100

= .16

q (b): √.16 = 0.40.4

p (B): 1 - 0.4 = 0.60.6

Now work out Now work out genotype genotype frequenciesfrequencies

q2 (bb): 16/100 = .16

q (b): √.16 = 0.40.4

p (B): 1 - 0.4 = 0.60.6

Now work out Now work out genotype genotype frequenciesfrequencies

population: 100 cats84 black, 16 whiteHow many of each genotype? p2 + 2pq + q2 = 1

population: 100 cats84 black, 16 whiteHow many of each genotype? p2 + 2pq + q2 = 1

bbBbBB

p2=0.36p2=0.36 2pq=0.482pq=0.48 q2=0.16q2=0.16

Page 12: AP Biology Measuring Evolution of Populations AP Biology There are 5 Agents of evolutionary change MutationGene Flow Genetic DriftSelection Non-random

AP Biology

Hardy Weinberg problemsNow have a go at sorting out some: Allele frequencies Genotype frequencies Phenotype frequencies

And use the frequencies to make deductions about data

Page 13: AP Biology Measuring Evolution of Populations AP Biology There are 5 Agents of evolutionary change MutationGene Flow Genetic DriftSelection Non-random

AP Biology

Application of H-W principle Sickle cell anemia

Caused by inheriting a mutation in the gene coding for haemoglobin oxygen-carrying blood protein recessive allele = HsHs

normal allele = Hb

low oxygen level causes RBC to sickle clogging small blood vessels depriving tissues of oxygen damage to organs

The condition is often lethal

Page 14: AP Biology Measuring Evolution of Populations AP Biology There are 5 Agents of evolutionary change MutationGene Flow Genetic DriftSelection Non-random

AP Biology

Sickle cell frequency High frequency of heterozygotes

1 in 5 in Central Africans = HbHs

unusual for allele with severe detrimental effects in homozygotes 1 in 100 = HsHs

usually die before reproductive age

Why is the Hs allele maintained at such high levels in African populations?Why is the Hs allele maintained at such high levels in African populations?

Suggests some selective advantage of being heterozygous…Suggests some selective advantage of being heterozygous…

Page 15: AP Biology Measuring Evolution of Populations AP Biology There are 5 Agents of evolutionary change MutationGene Flow Genetic DriftSelection Non-random

AP Biology

Malaria Single-celled eukaryote parasite (Plasmodium) spends part of its life cycle in red blood cells

Single-celled eukaryote parasite (Plasmodium) spends part of its life cycle in red blood cells

1

2

3

Page 16: AP Biology Measuring Evolution of Populations AP Biology There are 5 Agents of evolutionary change MutationGene Flow Genetic DriftSelection Non-random

AP Biology

Heterozygote Advantage In tropical Africa, where malaria is common:

homozygous dominant (normal) die or reduced reproduction from malaria: HbHb

homozygous recessive die or reduced reproduction from sickle cell anemia: HsHs

heterozygote carriers are relatively free of both: HbHs

survive & reproduce more, more common in population

Frequency of sickle cell allele & distribution of malaria

Page 17: AP Biology Measuring Evolution of Populations AP Biology There are 5 Agents of evolutionary change MutationGene Flow Genetic DriftSelection Non-random

AP BiologyAP Biology

Any Questions??Any Questions??Any Questions??