announcements change of plans for today: demos on light and selected review for today

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Announcements nge of plans for today: Demos on light and selected review for tod

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Page 1: Announcements Change of plans for today: Demos on light and selected review for today

Announcements

Change of plans for today:Demos on light and selected review for today

Page 2: Announcements Change of plans for today: Demos on light and selected review for today

Faraday’s Law

3 m/s 2 m

10 m

5 T10

What is the current induced in this circuit?

A) AB) AC) 10A

D) 6A

Page 3: Announcements Change of plans for today: Demos on light and selected review for today

Faraday’s Law

Bd

dt

E

3 m/s 2 m

10 m

5 T10

As the bar moves a current is induced!

There are no batteries anywhere, so we say that a current is induced, by an induced emf.

Hence, an electric current can be induced in a circuit by a changing magnetic field, in the opposite direction to the change in flux.

Page 4: Announcements Change of plans for today: Demos on light and selected review for today

Comparision of Induction

BdE ds

dt

0 0 0Ed

B ds Idt

•No magnetic monopole, hence no magnetic current•Electric fields and magnetic fields induce in opposite fashions

Page 5: Announcements Change of plans for today: Demos on light and selected review for today

Faraday’s Law and Electric Fields

BdE ds

dt

. A cylindrical region of radius R = 3.0 cm contains a uniform magnetic field parallel to its axis. The field is 0 outside the cylinder. If the field is changing at the rate 0.60 T/s, the electric field induced at a point 2R from the cylinder axis is:

Using Faraday’s law: 2 (2R)E =-(R2) dB/dt, so E= (-(R2) /4) dB/dt=0.0045 V/m

Page 6: Announcements Change of plans for today: Demos on light and selected review for today

Maxwell’s Equations

BdE ds

dt

Integral Form

0 0 0Ed

B ds Idt

0S

B dA

0

in

S

qE dA

Gauss’s laws, Ampere’s law and Faraday’s law all combined!

They are nearly symmetric with respect to magnetism and electricity.

The lack of magnetic monopoles is the main reasonwhy they are not completely symmetric.

Page 7: Announcements Change of plans for today: Demos on light and selected review for today

Quiz

The diagrams show three circuits with identical batteries, identical inductors, and identical resistors. Just after the switch is closed which has the least current through the battery?

The diagrams show three circuits with identical batteries, identical inductors, and identical resistors. Just after the switch is closed which has the greatest current through the battery?

The diagrams show three circuits with identical batteries, identical inductors, and identical resistors. A very long time later, which has the least current through the battery?

Page 8: Announcements Change of plans for today: Demos on light and selected review for today

RL - Circuits

E–

+

•What happens when the switch S is closed at t = 0? R

L

S

•Let I be the current in the circuit

I

•Use Kirchoffs rule for loops on the circuit

0 E RIdI

Ldt

dI R

Idt L L

E

) ) )/ /1 1Rt L tI t e eR R

E E

/L R

Page 9: Announcements Change of plans for today: Demos on light and selected review for today

RC–Circuits vs RL-Circuits

L

tRe

RI 1

RCt

eR

I

•At t=0, ordinary wire

•As t-> infinity, broken wire•At t=0, broken wire, little currentfor small t

•As t-> infinity, ordinary wire

•In terms of current control, an inductor can often be considered as the opposite of a capacitor

Page 10: Announcements Change of plans for today: Demos on light and selected review for today

)sinI C t E

LC – Circuits and Energy

+– L

C

S1S2

)cosV t E

1/ LC At an arbitrary time t, where is the energy stored in this circuit?A) In the capacitorB) In the inductorC) Alternately in the capacitor or the inductorD) What energy?

212LU LI

)212CU C V )2 21

2 cosC t E

)2 2 2 212 sinLC t E )2 21

2 sinC t E

212totU C E

Page 11: Announcements Change of plans for today: Demos on light and selected review for today

LC - Circuits

+–

EL

C

S1S2

•Switch S1 is closed, then opened.•At t = 0, switch S2 is closed.•What happens?

)0V t E

Q C V dQ

Idt

I

dIV L

dt

2

2

d QL

dt )2

2

d VCL

dt

Page 12: Announcements Change of plans for today: Demos on light and selected review for today

LC – Circuits and Harmonic Oscillators

)2

2

d VV CL

dt

)cosV t E

These equations

2

2

dt

xd

k

mx

)cos( tAx

There are many correspondances between electrical and mechanical systems!

Page 13: Announcements Change of plans for today: Demos on light and selected review for today

RLC circuits in Series IIL CR

S

RIdt

dU 2

22

22 LI

C

QU

dt

dILI

dt

dQ

C

Q

dt

dU

Do some algebra, and use

dt

dQI

02

2

C

Q

dt

dQR

dt

QdL

Page 14: Announcements Change of plans for today: Demos on light and selected review for today

RLC circuits and Harmonic Oscillators

LC

R

S

RIdt

dU 2

A damped harmonic oscillator!

02

2

C

Q

dt

dQR

dt

QdL

02

2

kxdt

dxb

dt

xdm

Hence, the charge oscillations are the same as the motion of a damped harmonic oscillator.

Page 15: Announcements Change of plans for today: Demos on light and selected review for today

Quiz

A.B.

C.

D.

Page 16: Announcements Change of plans for today: Demos on light and selected review for today

Electromagnetic Waves

0 0kE Bck 0 0E cB y zE cB

)0 cosyE E kx t )0 coszB B kx t

Electric FieldMagnetic

Field

Direction of Motion

Page 17: Announcements Change of plans for today: Demos on light and selected review for today

y x zE E B

x y t

yx zBE E

z x t

y xzE BE

y z t

0 0y x z

B B E

x y t

0 0yx z

EB B

z x t

0 0y xz

B EB

y z t

Using Maxwell’s Equations

Page 18: Announcements Change of plans for today: Demos on light and selected review for today

y zE B

x t

0 0

yzEB

x t

Electromagnetic Waves

•These equations look like sin functions will solve them.

)0 cosyE E kx t )0 coszB B kx t

) ) ) )

0 0

0 0 0 0

sin sin

sin sin

kE kx t B kx t

kB kx t E kx t

0 0 0 0 0 0 kE B kB E

Page 19: Announcements Change of plans for today: Demos on light and selected review for today

Electromagnetic Waves

0 0 0 0 0 0 kE B kB E

•These equations imply

2 20 0 0 0 0 0k E B B E

2

20 0

1

k

0 0

1

k

82.998 10 m/sc

•The speed of light (in vacuum)