angrenajul permanent ali

7/23/2019 Angrenajul Permanent Ali

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Angrenajul permanent

Is1 = 5.2

Is1 = i p* is1’

i p = is1’ => i p = is1’ = √ is 1

I p = Is1’ = √ I s1 = √ 5.2 = 2.28

Aleg : zp1 = 19 ; zp2 = 44 ;

i p.real = z p 2

z p1=

44

19 = 2.31

C =

1

2 * mn * (zp1 + zp2) *

1

cosγ p1,2 => cos p1!2 =

mn∗( z p 1+ z p 2)

2∗C =>

cos p1!2 =4.5∗(19+44)

2∗169 = ".838 => p1!2 = 32!99 #

Treapta I:

is1’ =

i s1

i p

= 5.2

2.31 = 2.24

Aleg : z1 = 23 ; z2 = 52 ;

is1’real = z 2

z 1=52

23 = 2.2$

C =1

2 * mn * (z1 + z2) =>

C =1

2 * 4.5 * (23 % 52& = 1$8.'5 mm) ! penr+ ,an+ra ,reapa

Treapta II:



is2’ =i s 2

i p=

3.81

2.31 = 1.$5

Aleg : z3 = 23 ; z4 = 38 ;

is2’real = z 4

z3=38

23 = 1.$5

C =1

2 * mn * (z3 + z4) *1

cosγ 3,4 => cos 3!4 =mn∗( z 3+ z p 4 )

2∗C =>

cos 3!4 =4.5∗(23+38)

2∗169 = ".812 => 3!4 = 35!$9 #

Treapta III:

is3’ =i s3

i p=2.68

2.31 = 1.1$

Aleg : z5 = 31 ; z6 = 3$ ;

is3’real = z 6

z 5=

36

31 = 1.1$

C =1

2 * mn * (z5 + z6) *1

cosγ 5,6 => cos 5!$ =mn∗( z 5+ z p 6)

2∗C =>

cos 5!$ =4.5∗(31+36)

2∗169 = ".892 => 5!$ = 2$!8' #



Treapta IV:

is4’ =i s 4

i p=

1.93

2.31 = ".83

Aleg : z7 = 35 ; z8 = 29 ;

is4’real = z 8

z 7=29

35 = ".82

C =1

2 * mn * (z7 + z8) *1

cosγ 7,8 => cos '!8 =mn∗( z 7+ z p 8)

2∗C =>

cos '!8 =4.5∗(35+29)

2∗169 = ".852 => '!8 = 31!5$ #

Treapta V:

is5’ =i s5

i p=1.39

2.31 = ".$

Aleg : z = 41 ; z1! = 25 ;

is5’real = z 10

z 9=

25

31 = ".$



C =1

2 * mn * (z + z1!) *1

cosγ 9,10 => cos 9!1" =mn∗( z 9+ z p 10)

2∗C =>

cos 9!1" =

4.5∗(41+25)

2∗169 = ".8'8 => 9!1" = 28!51 #

Treapta VI:

Is$=1 ! penr+ reapa ,e pri-a ,ireca

i p.real = 2.31

angrenajul permanent ali

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