analog controller
TRANSCRIPT
-
8/4/2019 Analog Controller
1/7
A Simple Analog Controller for Single-Phase Half-Bridge Rectifier and its
Application to Transformerless UPS
Rajesh Ghosh G. Narayanan
Power Electronics Group, Department of Electrical Engineering,
Indian Institute of Science, [email protected] [email protected]
Abstract A simple, low-cost, constant frequency, analogcontroller is proposed for the front-end half-bridge
rectifier of a single-phase transformerless UPS system to
maintain near unity power factor at the input and zero
dc-offset voltage at the output. The controller generates
the required gating pulses by comparing the input
current with a periodic, bipolar, linear carrier withoutsensing the input voltage. Two voltage controllers and a
single integrator with reset are used to generate the
required carrier. All the necessary control operations
can be performed without using any PLL, multiplier
and/or divider. The controller can be fabricated as a
single integrated circuit. The control concept is validated
through simulation and also experimentally on an 800W
half-bridge rectifier. Experimental results are presented
for ac-dc application, and also for ac-dc-ac UPS
application with both sinusoidal and nonlinear loads.
The simulation and experimental results agree well.
I. INTRODUCTION
Single-phase UPS systems are widely used in low powerapplications like data storage, computer systems, medicalfacilities and telecommunications. In many cases the inputside is a diode bridge rectifier, which draws non-linearcurrent from the source. To meet the necessary harmonicstandards, various topologies such as half-bridge and full-
bridge with power factor correction feature have beenreported for the front-end-converter [1]. Compared to full-bridge topology, half-bridge topology offers advantages like
simpler power conversion circuit, fewest switching devicecount, no need for isolation transformer, common groundconnected to input and output etc [2].
A single-phase transformerless UPS system is shown inFig. 1. It has a half-bridge front-end-converter (FEC), toconvert the input unregulated ac to regulated dc, and a half-bridge inverter to convert the dc back to regulated ac powerto feed the load. Both the FEC and the inverter share acommon dc bus. The system has a common input-output
neutral, connected to the mid point of the dc bus.The FEC is required (i) to draw sinusoidal input current
at near unity power factor, and (ii) to maintain equal voltageacross each half of the dc bus. The latter is required to
prevent any dc voltage offset at the output of the UPS. Anumber of controllers have been proposed for the half-
bridge rectifier to achieve the above objectives [1-3].
Input Output
AC-DC DC-AC Filter
L C1
C2
N N
S1
S2
S3
S4
+
+
_
_
Battery
Fig. 1 Single-phase UPS system
These require input synchronization (PLL), DQtransformation [3], and multiplier and divider circuit along
with input voltage sensing [1-3]. These increase both
controller cost and complexity. As the single-phaseconverters are used for low power applications, a low-costcontroller solution is desirable.
Current mode control techniques using modulatorapproach have been reported in [4-7]. The required
switching instants are determined by comparing the inputcurrent/switch current with a suitably generated carrier in
the modulator without using any input PLL, multiplier,divider and input voltage sensor.
The purpose of this paper is to propose a simple, constantswitching frequency based controller for the single-phase
transformerless UPS application that has the simplicity ofthe controllers reported in [4-7] and the performance of the
control techniques reported in [1-3].
II. CONTROL SCHEME
A. Half-bridge rectifier
A half-bridge rectifier system is shown in Fig. 2. In each
switching cycle Ts the converter switches S1 and S2 areturned on and turned off by complementary gating pulses.S2 is turned on for a duration ofDTs and S1 for (1-D)Ts,whereD is the duty ratio. With S2on and S1 off, the voltageapplied across inductorL is (Vg+Vo2). Again, with S1 on andS2 off, the same is (vg-Vo1). The switching frequency (fsw =
1/Ts) is assumed to be high. The duty ratio D is given by thevolt-second balance across the inductor as shown in (1).
13060-7803-9033-4/05/$20.00 2005 IEEE.
http://l/[email protected]://l/[email protected]://l/[email protected]://l/[email protected] -
8/4/2019 Analog Controller
2/7
LC 1
C 2
N
S1
S2
+
+
_
_
V o1
V o2
+
_vg
R
R
ig V dc
Io
Ic 1V p
Fig. 2 Single-phase half-bridge rectifier
vg= Vo1 D (Vo1 + Vo2) (1)
One control objective is to modulate the converter switchduty ratioD such that the input current ig is proportional to
the input voltage vg as per (2), where Re is the emulatedresistance of the converter.
ig= vg/Re (2)
In [4 -6], Re is controlled using Vmas shown in (3), whereVmis the output of the PI voltage controller, Rsis the gain inthe current sensing path and Vdcis the dc output voltage.
Vm = (Vdc.Rs)/Re (3)
Since a half-bridge converter has a split dc bus, both the
output voltages Vo1 and Vo2must be controlled. These twomust also be equal in the steady state. A single voltagecontroller for the entire dc bus voltage (Vdc= Vo1+Vo2), withan additional voltage balancing circuit has been reported in
[2]. Instead of such a scheme, this work proposes a PIcontroller each for controlling Vo1and Vo2 as shown in Fig.
3. The outputs of the two controllersPI1 andPI2 are Vm1andVm2 , respectively . The two outputs Vm1and Vm2 are used tocontrol the emulated resistance,Re, of the whole converter.
+_ +_
+_ ++
RClock
Vdc*
1/2 Vo1
Vm1
Vm2
Vo2PI2
PI1
Reset
Integrator
Vc
S2
S1
D
(1-D)
+_igRs
Vc
Comparator
Fig. 3 Proposed controller
These are related to Re and also to their respective outputvoltages as shown in (4) and (5).
Vm1 = (Vo1.Rs)/Re (4)
Vm2 = (Vo2.Rs)/Re (5)
Using (1), (2), (4) and (5) the control equation (6) for theproposed controller is obtained. Note that the left hand side
of (6) is the output of the input current sensor with gainRs.
ig.Rs = Vm1 -D(Vm1+ Vm2) (6)
B. Carrier
For determination of the duty ratio D, in any switchinginterval Ts, consider a carriervc (t) as defined in (7).
Vc(t) = Vm1 - (Vm1+ Vm2)t/Ts ; (0 < t< Ts) (7)
In the beginning of the interval, i.e. at t = 0, vc (t) isequal to (Vm1). It is (-Vm2) at the end of the interval t =Ts.Observe that the carriervc(t) equals igRs at the instant t=DTs
as in (6). Thus the switching instants can be determined bycomparing the input current igRs with vc(t) in an analog
comparator as shown Fig. 3.Because of high switching frequency, in any switching
interval Ts, Vm1, Vm2 and ig can be considered constant. Ineach switching interval the carriervc(t) can be generated bythe analog integration as shown in (8).
+=
t
s
mmmc dt
T
VVVtV
0
211 .1
)()( ; (0 < t< Ts) (8)
C. Generation of gating pulses
A single analog integrator, with reset, generates thecarrier (8) in each switching cycle Ts. The integrator is reset
by the rising edge of the clock as shown in Fig. 3. Equation(6) is solved in an analog comparator forD, whose output
directly drives the switch S2. The complementary pulsesdrive S1. Gating pulses generated by the controller are
shown in Fig. 4.
ClockigRs
Vc
Gate pulse forS2
Fig. 4 Experimental gating pulses ofS2
1307
-
8/4/2019 Analog Controller
3/7
m1V
m2-V
''m1V
g si R
2S
1S
''2S
''1S
cV
''cV
ST
0
Fig. 5 Voltage balancing
D. Balancing the output voltagesVo1 and Vo2
Referring to Fig. 5, consider Vc is the required carrier
when Vo1 =Vo2, and Vm1 = Vm2. The corresponding switchinginstants forS1 and S2 are determined by the intersection ofVc with igRs. It should be noted that the positive and thenegative peaks ofVc are (Vm1) and (-Vm2)respectively, as per(7). Now if Vo1 tends to become less than the desiredreference level, while Vo2 is equal to the reference, the
voltage controller, controlling Vo1 will ensure (Vm1= )
>Vm2 (Fig. 6). Now is the modified carrier; and
are the modified gating pulses for S2 and S1 respectively.
Note that S2 is turned on for longer duration. This results intransfer of excess energy, stored in C2, to C1 to balance bothVo1 and Vo2. Similar explanation may be given for otherpossible cases of voltage unbalance.
''1mV
''cV
''2S
''1S
III. SELECTION OFL AND C
A. Input side inductor L
At steady state Vo1=Vo2=Vo. The expression forD is as
shown in (9), where vg=Vgmsin(t) and Mg=Vgm /Vo.
( )
= =
1 11- 1- sin
2 2
g
go
vD M
Vt
(9)
The peak-to-peak ripple in the inductor current ig, in a
switching interval Ts, is given in (10).
+ = =
2
2
g o g sg s o
o
v V v Ti DT V
L V L (10)
It has a maximum value ofig max when vg equals zero, asshown in (11).
=max 2
o sg
V Ti
L (11)
The inductor value L (Henry) is determined using the
highest permissible igmax
as shown in (12), whereIm
is thepeak input current, fsw is the switching frequency (Hz) andPo is the output power.
-15
-10
-5
0
5
10
15
0 60 120 180 240 300 360
g= 0.636
1 2 = 1800-1
Vg
C1
Fig. 6. Variation of capacitor currentIC1
= =
2
max max
2 4
o go s
g g
m o sw m m
V MV TL
i
I P fI I
i (12)
B. DC bus capacitors C1 and C2
Here switching frequency current ripples are neglectedand capacitors are designed for low frequency currents.Referring to Fig. 2, the expression for low frequencycomponent of capacitor currentIc1 is given in (13).
= =
12
(1- ) - sin( ) - cos(2 )C g o og
I D i I I t M
t (13)
Assuming unity power factor operation, the variation of
ic1 over a fundamental cycle is shown in Fig. 6. The zerocrossing instants ofIc1, namely 1 and 2, are given in (14).
= +
2-1 01 2
1sin ( (1 2 ) -1) ; =(180 - )
2g
g
MM
1 (14)
The peak-peak voltage ripple in Vo can be obtained by (15).
= 2
1
11
1o cV I
Cd t (15)
With this, an expression forC1 can be obtained as given in
(16), wherefis the fundamental frequency in Hz.
= +
1 1
2
4cos( ) sin(2 )
4 ( / )
o
go o o
PC
MV f V V 1 (16)
Considering the operating range to be (0.6 < Mg< 0.9),the above expression can be approximated as shown in (17).
= =
1 2 2
0.876 (1 - 0.636 )
( / )
o g
o o o
P MC C
V f V V (17)
IV. SMALL SIGNAL AC MODELS
Small signal ac models are required to design the voltage
controllers. It is assumed that the switching frequency isvery high. In this section the switching cycle average
models of the converter and the controller are described.
1308
-
8/4/2019 Analog Controller
4/7
(1-D)2VO1/
1
L
L
R
ST+ 1 C
R
ST+
O1Vd
d
(1 )(1 )
P
L C
G
ST ST + +
O1V
Inverter+
-1/
1
L
L
R
ST+
(1-D)
D
1 C
R
ST++
+
Vo1
Vo2
VdcIg
Vo1 Vo2
VP
D
Vg
1 C
R
ST+(a)
(b) (c)
-
Fig. 7 Small signal ac model of the converter
A. Small signal model of the converter
The switching cycle average model of the converter isshown in Fig. 7(a). This has been derived from Fig. 2. RL isthe inductor resistance and R is the equivalent loadresistance across each half of the dc bus. TL =L/RL and TC =RCare the time constants, where C= C1 = C2. The inverter
has three inputs Vo1, Vo2 andD. The output of the inverter isthe pole voltage VP. Considering Vo1 =Vo2 = Vo the averagepole voltage VPover a switching cycle is shown in (18).
VP= (1 2D) VO = (D, Vo) (18)
Assuming Vo to be a constant voltage the small signal
relationship between VPandD is shown in (19).
( 2 ).OPv V= d (19)
In order to design the voltage controllers it is required tohave a transfer function relating the output voltages Vo1, Vo2to the duty ratioD. In Fig. 7(a) it is shown that there are two
identical paths forVo1 and Vo2. For designing the parameterof the voltage controller it is sufficient to consider any oneof them. The small signal transfer function between Vo1 andD is shown in (20).
1
0
0(1 )(1 )
2 (1 )
o
g
o P
L C
P
L
I
V
V G
ST ST d
Vo D RG
R
=
==
+ +
=
(20)
The derivation of the above transfer function is shown inFigs. 7(a) 7(c).
B. Small signal model of the modulator
Referring to Fig. 8(a) it can be seen that the proposed
controller has a modulator that determines the required dutyratioD. The modulator has three inputs Vm1, Vm2 andIg. The
converter duty ratio D is the output of the modulator.
Equation (6) is used to relate the output D with the inputs asshown in (21).
Vg
Converter
Modulator
D
Vo1Vo2
Vm2
Vm1
IgVo
*
+-
+
-
1mV
2mV
gi
dX1
X2
X3
+-
-
(a) (b)
PI1
PI2
Fig. 8 Small signal model of the modulator
1
1 2( )
m g S
m m
V i RD
V V
=
+(21)
Equation (21) is nonlinear. The small signal model of theabove equation is shown in (22). The linearised modulator isshown in Fig. 8(b).
1 1 2 2 3
2 1
1 22
1 2 1 2
3
1 2
. . .
;( ) ( )
( )
m m g
m g S m g S
m m m m
S
m m
d X V X V X i
V I R V I RX X
V V V V
RX
V V
=
+ = =
+ +
=+
2(22)
C. Voltage loop
Equations (2), (4), (5), (20) and (22) yield the small-
signal transfer function relating Vm1 to Vo1 as shown in
(23a), where Vgm is the peak of the input voltage VgandPo isthe output power. The dc gain H1 is a function of mg asshown in (23b).
2
1 1
1
2 2
1
0
0
( )( ) (23a)
(1 )(1 )( )
.(1 ) ; (23b)8
m
o
m L C
g
gm g g
L S O o
g
VHV S
H SST ST V S
VRH V m m
R R P V
i
=
=
= =+ +
= + =
Over a fundamental cycle mg varies sinusoidally as
shown in (24), where is the supply angular frequency and is the fundamental angle.
mg= (Vgm/Vo).sin( t) = (Vgm/Vo).sin() (24)
The Bode plot ofH(S) (equation (23)) is shown for
different values of in Fig. 9. The parameters are given inTable-I. The two time constants TL and TC are found to be
0.05s and 0.27s, respectively. These are independent of .Hence, the phase plots are identical as seen from Fig. 9.
It can be concluded that over a fundamental cycle the dcgain H1 of the transfer function H(S) (equation (23)) varies
with while maintaining a constant phase. The equivalent
voltage loop is shown in Fig. 10. The voltage controllers canbe designed as given in [6].
1309
-
8/4/2019 Analog Controller
5/7
= 900, 1350,1800, 2250,2700
Fig. 9 Bode plot of transfer functionH(s)
Vo*
+-
Vo1
G(s)Vo1
Voltagecontroller
H(s)
Fig. 10 Equivalent voltage loop
D. Current loop
The converter does not have any current loop. It has amodulator, which determines the switching instants for theconverter switches. In this section it is shown that instead ofa physical current loop the modulator can be analyzed to be
an equivalent current loop. This may be required to evaluate
the bandwidth of the current loop. The current loop isderived from Figs. 7 and 8 as shown in Fig. 11(a). Thesimplified current loop is shown in Fig. 11(b). The outputsof both voltage controllers Vm1 and Vm2, set the referencecurrentIg
*for the equivalent current loop. The gain X3 may
be considered to be an equivalent proportional controller.Equations (4) and (5) can be used to simplify (22) as shown
in (25), where Vo1 =Vo2 =Vo. It is shown that at steady stateX3 is a constant.
3
1 2
.
( ) 2
s e e
o o s
R R RX
V V R V = =
+ o(25)
The closed loop transfer function of the equivalentcurrent loop is shown in (26).
1mV
2mV
gidX1
X2
X3
+-
- 2VO1/
1
L
L
R
ST+
1mV
2mV
*
gIX1/X3
X2/X3
+-
-+
gi
X3
gi(2 / )
1
o L
L
V R
ST+
Equivalent current
controller
(a)
(b)
Fig. 11 Equivalent current loop
* (1 )
1;
1 /
g CUR
CURg
eCUR CUR L
L e
I G
STI
RG T T
R R
=+
= =
+ LR
(26)
The bandwidth of the equivalent current loop FBW (Hz)can be obtained by (27). The full load bandwidth of theequivalent current loop is found to be 245 Hz. Bandwidth
increases as the load reduces.
1
2BW
CUR
FT
= (27)
V. EXPERIMENTAL RESULTS
The proposed control concept has been verified through
simulation using MATLAB/SIMULINK and alsoexperimentally on an 800W laboratory prototype. Theexperimental set up is shown in Fig. 12. The arrangementfor sensing the output voltages Vo1, Vo2 and the input currentigare also shown. All measurements are made with respectto the mid-point of the dc bus. Hence no electrical isolationis required. The system parameters are given in Table-I. Theswitching frequency is set at 10kHz. The current transducergain is set at 100mV/A. The converter is tested for twoapplications, namely (A) ac-dc rectification and (B) UPS
application.
Input Output
LC1
C2
N N
S1
S2
S3
S4
+
+
_
_
-igRs
ig
Vo1-Vo2
Rs
R1
R2
R1
R2
G1
G2
-igRs
+
-R3
R5
R6
op1
+
-
R4
R3
R5
R6
op1
Vo1
+
--Vo2
Vo*+
-
+
-
+
-
+
-
+
-
Clock
G2
G1
Comparator
R6
R6
R6
R6
R6
R6 R6
R6
R6
R6
R7
Power circuit
Control circuit
R4
T
C3
C4 C5
C3
C4
Fig. 12 Experimental setup
1310
-
8/4/2019 Analog Controller
6/7
Vo1
Vo2
0V level
(b)
Vg
ig
50Hz (a)
Fig. 13. AC-DC application. (a) Input voltage and inputcurrent. (b) Output voltages Vo1 and Vo2.
A. Ac-dc rectification
The test circuit under consideration is same as shown in
Fig. 2 except that a single load resistor of 250 is connectedacross the entire dc bus. The experimental resultscorresponding to 775W output power is shown in Fig. 13.
B. Ac-dc-ac UPS application
The test circuit is same as Fig. 1 except that the battery
interface is not connected. The inverter is operated withsine-triangle PWM (not shown here). Two test conditionsare considered:
(i) Sinusoidal load
An inductive load (R = 25 and L = 10mH) is connected
Voinv
ioinv
50Hz.
(a)
Fig. 14(a) voltage and current across load
Vo1
Vo2
(b)
0V level
Fig. 14 (b) dc bus voltages Vo1 and Vo2
Vg
ig
50Hz(c)
Fig. 14 (c) input voltage and input current
at the UPS output. Output power = 500W, Vg= 110V(rms),Vo1 = Vo2 = 220V, switching frequency 10kHz and inverter
output frequency = 50Hz. Fig. 14 shows the correspondingexperimental results.
(ii) Nonlinear load
A diode bridge rectifier load in series with a 10mHinductor is connected across UPS output. Output power is700W, Vg = 110V(rms), Vo1 = Vo2 = 220V, switching
frequency 10kHz and inverter output frequency = 60Hz.The corresponding results are shown in Fig. 15. Thedifference between the input (mains) frequency and theinverter output frequency causes distortion in Vo1 and Vo2.The non-sinusoidal current drawn by the rectifier load
further adds up to this distortion.
Voinv
ioinv
60Hz.
(a)
Fig. 15(a) voltage and current across load
1311
-
8/4/2019 Analog Controller
7/7
Vo1
Vo2
0V level
(b)
Fig. 15 (b) dc bus voltages Vo1 and Vo2
Vg
ig
50Hz
(c)
Fig. 15 (c) input voltage and input current
VI. CONCLUSION
A single-phase transformerless UPS requires connectingthe input and output side neutrals to the mid point of thesplit dc bus. The front-end half-bridge PWM rectifier needsto maintain near unity power factor at the input, holdingequal voltage across each half of the dc bus. The latter is
required to prevent dc voltage offset in the UPS output. Asimple, low-cost, constant frequency analog controller isproposed for the half-bridge PWM rectifier. The proposedcontroller is suitable for operation under continuousconduction mode (CCM). It has two voltage controllers forthe two halves of the dc bus. Instead of a current controller
it has a modulator that provides the necessary gating pulsesto the devices of the half-bridge rectifier. The switchinginstants are determined by comparing the source currentwith a suitably generated periodic, linear carrier. Allnecessary control operations can be performed withoutsensing the input voltage and without using any
multiplication or division operation. The proposed controllercan be fabricated into a single integrated circuit. A designprocedure for selecting the converter parameters L and Cisgiven. The averaged small signal ac models are presented todesign the voltage controller and also to find out the bandwidth of the equivalent current loop. The control
concept is validated through simulation and experiments.
The experimental results are presented.
REFERENCES
[1] Takeshi U, et. Ai., A Study of the High Performance Single-
phase UPS, IEEE PESC, 1998, Vol. 2, pp. 1872-1878.
[2] Gui-Jia Su, and Tetuhiko Ohno, A New Topology for SinglePhase UPS Systems, IEEE Power Conversion Conference,
Aug. 1997, Vol. 2, pp. 913-918
[3] Joan Salaet, et. Al., SVM Based Control of a Single-Phase
Half-Bridge Rectifier Under Power Factor Correction andBalanced Operation, IEEE ISIE 2000, Vol. 1, pp. 130-134.
[4] Maksimovic. D, Jang. Y, R. Erickson, Nonlinear-Carrier
Control for High-Power-Factor Boost Rectifiers, IEEETrans. on power Electronics, Vol. 11, No. 4, July 1996.
[5] S. Chattopadhyay, V. Ramanarayanan and V. Jayashankar, Predictive switching modulator for current mode control of
high power factor boost rectifier, IEEE Trans. On PowerElectron. Vol. 18. No. 1, pp. 114-123, January 2003.
[6] Robert W. Erickson, Fundamentals of Power Electronics,first edition, Chapman and Hall, New York, May 1997.
[7] S. Chattopadhyay, V. Ramanarayanan, A Single-Reset-
Integrator-Based Implementation of Line-Current-ShapingController for High-Power-Factor Operation of Flyback
Rectifier, IEEE Trans. On Industry Applications, Vol. 38,Issue. 2, March-April 2002, pp. 490-499.
Table-I
PARAMETERS AND COMPONENTS OF THE SYSTEM
Po(W)
Vgm(V)
Vo(V)
(Rad/s)
L(mH)
RL
C1, C2F
800 156 220 2**50 10 0.2 2200
S1, S2, S3, S4
IRGT 100 25M12 (25A, 1200V IGBT)
R1 R2 R3 R4 R5 R6
1M 22K 10K 10K 10K 10K
R7 Rs C3 C4 C5
10K 0.01 0.01F 1F 0.01F
Op-amps Comparator Inverter Clock T
TL084 TL084 CD4069 555 2N2222
1312