8/17/2019 ANALISIS QUIMICO GRAVIMETRIA

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Muestra + HCl à  CaCl + H 2 O

2CaCl + (NH 4 )2 C 2 O4 à 2CaC 2 O4 + 2NH 4Cl 

CaC 2 O4 + H 2 O à CaCO3 + CO

DATOS:M crisol: 51.0292M muestra: 0.8107M papel: 1.0137

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CALCULOS 

1 Determinar el porcentaje de calcio en la muestra.

mesa mi(g)

m P.F.

(g)

m crisol 

(g)

M (crisol P.F.

ceni!a)

ceni!a

 papel 

CaCO"

(mp) m Ca # Ca1 0.8039 1.0210 39.3218

2 0.8107 1.0137 51.0292 51.6057 0.5765

3 0.8397 1.0950 41.8947 42.4908 0.5961

4 0.8262 1.0850 50.1832 50.8077 0.6245

Papel ceni!a $ m (crisol P.F. ceni!a) % m (crisol)

Papel ceniza (1) !

Papel ceniza (2) 51.6057 ! 51.0292 0.5765

Papel ceniza (3) 42.4908 ! 41.8947 0.5961

Papel ceniza (4) 50.8077 ! 50.1832 0.6245

Masa de CaCO "

m p  $ ceni!a papel % papel &iltro

mp 1 ! 0.8395 0.1605

mp  1.0717 ! 0.9736 0.0981

mp  1.3608 ! 0.9642 0.3966

mp 1.0104 ! 0.9693 0.0411

mCa = Ca x mp  CaCO3

m"a (40.09# 100.09) $ 0.1605 0.0643

m"a (40.09# 100.09) $ 0.0981 0.0393

m"a (40.09# 100.09) $0.3966 0.1588

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m"a (40.09# 100.09) $0.0411 0.0165

  %Ca = mCa x100  mi

%"a (0.0643 #0.502) $ 100 12.8088 

%"a (0.0393#0.5077) $1 00 7.7408

  %"a (0.1588#0.5011) $ 100 31.6903 %"a (0.0165#0.5025) $ 100 3.2836

FG = 40.09 = 0.4004  100.09

M$ &' mpm$ 0.4004 $ 0.1605 0.0643m$ 0.4004 $ 0.0981 0.0393m$ 0.4004 $ 0.3966 0.1588