amplitude, period, and phase shift section 4-5 2 objectives i can determine amplitude, period, and...
TRANSCRIPT
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Objectives
• I can determine amplitude, period, and phase shifts of trig functions
• I can write trig equations given specific period, phase shift, and amplitude.
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Radian versus Degree
• We will use the following to graph or write equations:– “x” represents radians– “” represents degrees– Example: sin x versus sin
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sin ( )a b x ps d Amplitude
Period:
2π/b Phase Shift:
Left (+)
Right (-)Vertical Shift
Up (+)
Down (-)
Copyright © by Houghton Mifflin Company, Inc. All rights reserved. 6
The graph of y = A sin B(x – C) is obtained by horizontally shifting the graph of y = A sin Bx so that the starting point of the cycle is shifted from x = 0 to x = C. The number C is called the phase shift.
amplitude = | A|
period = 2 /B.
The graph of y = A sin B(x – C) is obtained by horizontally shifting the graph of y = A sin Bx so that the starting point of the cycle is shifted from x = 0 to x = C. The number C is called the phase shift.
amplitude = | A|
period = 2 /B.
x
y
Amplitude: | A|
Period: 2/B
y = A sin Bx
Starting point: x = C
The Graph of y = AsinB(x - C)
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The amplitude of y = a sin x (or y = a cos x) is half the distance between the maximum and minimum values of the function.
amplitude = |a| If |a| > 1, the amplitude stretches the graph vertically.If 0 < |a| > 1, the amplitude shrinks the graph vertically.If a < 0, the graph is reflected in the x-axis.
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y
x
4
2
y = – 4 sin xreflection of y = 4 sin x y = 4 sin x
y = 2 sin x
2
1y = sin x
y = sin x
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y
x
2
sin xy period: 2 2sin y
period:
The period of a function is the x interval needed for the function to complete one cycle.
For b 0, the period of y = a sin bx is .b
2
For b 0, the period of y = a cos bx is also .b
2
If 0 < b < 1, the graph of the function is stretched horizontally.
If b > 1, the graph of the function is shrunk horizontally.y
x 2 3 4
cos xy period: 2
2
1cos xy
period: 4
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y
x
2y = cos (–x)
Use basic trigonometric identities to graph y = f (–x)Example 1: Sketch the graph of y = sin (–x).
Use the identity sin (–x) = – sin x
The graph of y = sin (–x) is the graph of y = sin x reflected in the x-axis.
Example 2: Sketch the graph of y = cos (–x).
Use the identity cos (–x) = cos x
The graph of y = cos (–x) is identical to the graph of y = cos x.
y
x
2y = sin x
y = sin (–x)
y = cos (–x)
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ExampleDetermine the amplitude, period, and phase shift of
y = 2sin (3x - )Solution:First factor out the 3y = 2 sin 3(x - /3)Amplitude = |A| = 2period = 2/B = 2/3phase shift = C/B = /3 right
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Find Amplitude, Period, Phase Shift• Amplitude (the # in front of the trig. Function• Period (360 or 2 divided by B, the #after the trig function
but before the angle)• Phase shift (the horizontal shift after the angle and inside
the parenthesis)• y = 4sin y = 2cos1/2 y = sin (4x - )
Amplitude:
Phase shift:
Period:
4 2 1
NA NA )(4
Right
360 7202
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y
1
123
2
x 32 4
Example: Sketch the graph of y = 3 cos x on the interval [–, 4].
Partition the interval [0, 2] into four equal parts. Find the five key points; graph one cycle; then repeat the cycle over the interval.
maxx-intminx-intmax
30-303y = 3 cos x20x 2
2
3
(0, 3)
2
3( , 0)( , 0)
2
2( , 3)
( , –3)
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Writing Equations• Write an equation for a positive sine curve with an amplitude
of 3, period of 90 and Phase shift of 45 left. • Amplitude goes in front of the trig. function, write the eq.so
far: • y = 3sin • period is 90. use P = • • rewrite the eq. • y = 3 sin4• 45 degrees left means +45
• Answer: y = 3sin4( + 45)
490
360,90
360 Bso
B
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Writing Equations• Write an equation for a positive cosine curve with an
amplitude of 1/2, period of and Phase shift of right . • Amplitude goes in front of the trig. function, write the eq.so
far: • y = 1/2cos x• period is /4. use P = • • rewrite the eq. • y = 1/2cos 8x• right is negative, put this phase shift inside the parenthesis
w/ opposite sign.
• Answer: y = 1/2cos8(x - )
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2,
4
2
BsoB
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