sr. no. chapter no. of mcqs percentage
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RCC STUDY MATERIAL QUESTIONNEET - 2021 PAPER QUESTION RCC TOPIC STUDYWITH P. NO.NEET 2021 PAPER ANALYSIS - [N4 SET]
Sr. No. Chapter No. Of MCQs Percentage1 Mole Concept 1 2
2 Structure of Atom 1 2
3 Periodic Table 1 2
4 Chemical Bonding and Molecular structure 3 6
5 The States of Matter : Gases and Liquids 2 4
6 Thermodynamics 2 4
7 Equilibrium 1 2
8 Redox Reaction 1 2
9 Hydrogen 1 2
10 S-block elements 2 4
11 Some p-block elements - Group 13, 14 0 0
12 GOC 3 6
13 Hydrocarbons 2 4
14 Environmental Chemistry 1 2
15 Solid State 2 4
16 Solution 2 4
17 Electrochemistry 2 4
18 Chemical Kinetics 2 4
19 Surface Chemistry 1 2
20 Metallurgy 2 4
21 p-Block Elements - Group 15, 16, 17, 18 3 6
22 d- and f- Block Elements 2 4
23 Coordination Compounds 2 4
24 Haloalkanes and Haloarenes 2 4
25 Alcohols, Phenols and Ether 2 4
26 Aldehydes, Ketones and Carboxylic Acids 2 4
27 Organic Compounds containing Nitrogen 2 4
28 Biomolecules 1 2
29 Polymers 1 2
30 Chemistry in Everyday Life 1 250 100Total
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Number of Questions
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Sr. No. Chapter No. Of MCQs Percentage
1 Mole Concept 1 2
2 Structure of Atom 1 2
3 Periodic Table 0 0
4 Chemical Bonding and Molecular structure 2 4
5 The States of Matter : Gases and Liquids 1 2
6 Thermodynamics 1 2
7 Equilibrium 1 2
8 Redox Reaction 1 2
9 Hydrogen 1 2
10 S-block elements 2 4
11 Some p-block elements - Group 13, 14 0 0
12 GOC 3 6
13 Hydrocarbons 1 2
14 Environmental Chemistry 0 0
15 Solid State 2 4
16 Solution 1 2
17 Electrochemistry 1 2
18 Chemical Kinetics 1 2
19 Surface Chemistry 1 2
20 Metallurgy 2 4
21 p-Block Elements - Group 15, 16, 17, 18 2 4
22 d- and f- Block Elements 2 4
23 Coordination Compounds 1 2
24 Haloalkanes and Haloarenes 2 4
25 Alcohols, Phenols and Ether 1 2
26 Aldehydes, Ketones and Carboxylic Acids 0 0
27 Organic Compounds containing Nitrogen 1 2
28 Biomolecules 1 2
29 Polymers 1 2
30 Chemistry in Everyday Life 1 235 70
SECTION-A
Total
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Number of Questions
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Sr. No. Chapter No. Of MCQs Percentage
1 Mole Concept 0 0
2 Structure of Atom 0 0
3 Periodic Table 1 2
4 Chemical Bonding and Molecular structure 1 2
5 The States of Matter : Gases and Liquids 1 2
6 Thermodynamics 1 2
7 Equilibrium 0 0
8 Redox Reaction 0 0
9 Hydrogen 0 0
10 S-block elements 0 0
11 Some p-block elements - Group 13, 14 0 0
12 GOC 0 0
13 Hydrocarbons 1 2
14 Environmental Chemistry 1 2
15 Solid State 0 0
16 Solution 1 2
17 Electrochemistry 1 2
18 Chemical Kinetics 1 2
19 Surface Chemistry 0 0
20 Metallurgy 0 0
21 p-Block Elements - Group 15, 16, 17, 18 1 2
22 d- and f- Block Elements 0 0
23 Coordination Compounds 1 2
24 Haloalkanes and Haloarenes 0 0
25 Alcohols, Phenols and Ether 1 2
26 Aldehydes, Ketones and Carboxylic Acids 2 4
27 Organic Compounds containing Nitrogen 1 2
28 Biomolecules 0 0
29 Polymers 0 0
30 Chemistry in Everyday Life 0 015 30
SECTION-B
Total
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Number of Questions
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Chapter Section- A Section - B TotalMole Concept 1 0 1Structure of Atom 1 0 1Periodic Table 0 1 1Chemical Bonding and Molecular structure 2 1 3The States of Matter : Gases and Liquids 1 1 2Thermodynamics 1 1 2Equilibrium 1 0 1Redox Reaction 1 0 1Hydrogen 1 0 1S-block elements 2 0 2Some p-block elements - Group 13, 14 0 0 0GOC 3 0 3Hydrocarbons 1 1 2Environmental Chemistry 0 1 1Total 15 6 21
Chapter Section- A Section - B TotalSolid State 2 0 2Solution 1 1 2Electrochemistry 1 1 2Chemical Kinetics 1 1 2Surface Chemistry 1 0 1Metallurgy 2 0 2p-Block Elements - Group 15, 16, 17, 18 2 1 3d- and f- Block Elements 2 0 2Coordination Compounds 1 1 2Haloalkanes and Haloarenes 2 0 2Alcohols, Phenols and Ether 1 1 2Aldehydes, Ketones and Carboxylic Acids 0 2 2Organic Compounds containing Nitrogen 1 1 2Biomolecules 1 0 1Polymers 1 0 1Chemistry in Everyday Life 1 0 1Total 20 9 29
Class XI
Class XII
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36 %
64 %
Classwise Distribution
Class XIClass XII
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• Difficulty level – Easy to Moderate• Physical Chemistry – 15 Questions
Organic Chemistry – 17 QuestionsInorganic Chemistry – 18 Questions
• All questions based on the NCERT textbook. Statements directly taken from the NECRTtextbooks.
• Straightforward questions & easy to comprehend.• One controversial question with more than one correct answer.• Not lengthy. Students should have completed the Chemistry part within 45 minutes.
Enough time for revision.• Barely a few calculations.• An average student should have been able to attempt approximately 40 questions with
ease.While others could have attempted 44 questions.The Chemistry section was of easy to moderate difficulty level. Organic Chemistryslightly less dominated the subject with 13 questions. 16 questions were asked fromPhysical Chemistry and 16 questions were from Inorganic Chemistry. All the questionswere from the prescribed NEET syllabus and completely based on the NCERT textbooks.In fact, statements were directly picked from the NCERT textbook. Questions werestraightforward and easy to comprehend. There was one controversial question withmore than one correct answer. Overall, the Chemistry section was not lengthy and studentsshould have completed this part in 40-45 minutes. With minimalistic calculations, anaverage student should have been able to attempt approximately 40 questions with ease,while others would have been able to attempt a minimum of 44 questions.
XI XII XI XII XI XII XI XII XI XII XI XIIEasy 1 3 1 1 2 4 0 1 1 3 2 0Medium 4 2 1 1 2 2 0 3 5 2 0 2Difficult 0 1 0 1 0 1 1 1 0 2 0 0
Level Sect-A Sect-BPhysical Chemistry Organic Chemistry Inorganic Chemistry
Sect-A Sect-B Sect-A Sect-B
12th Syllabus TotalChem Total XI Syllabus Total XII Syllabus TotalPhysical Chemistry 16 Physical Chemistry 7 Physical Chemistry 9Organic Chemistry 17 Organic Chemistry 5 Organic Chemistry 12Inorganic Chemistry 17 Inorganic Chemistry 8 Inorganic Chemistry 9Total 50 Total 20 Total 30
No. of Question Class Wise Distributions
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RCC STUDY MATERIAL QUESTIONNEET - 2021 PAPER QUESTION RCC TOPIC STUDYWITH P. NO.
Solid State60. Right option for the number of
tetrahedral and octahedral voids inhexagonal primitive unit cell are1) 6, 12 2) 2, 13) 12, 6 4) 8, 4
114. The number of tetrahedral andoctahedral voids in hexagonalprimitive unit cell are1) 8, 4 2) 2, 1 3) 12, 6 4) 6, 12
RCCSolid State Booklet
Page - 26 Q. 114(Exactly Same
As it is)RCC
Do or Die BookletQ. No. 35 Page - 3(Exactly Same
As it is)
Atomic Structure85. A particular station of All India
Radio, New Delhi, broadcasts on afrequency of 1,368 kHz (kilohertz).The wavelength of theelectromagnetic radiation emittedby the transmitter is [speed of light,c= 3.0 × 108 ms–1]1) 219.2 m 2) 2192 m3) 21.92 cm 4) 219.3 m
16. The vividh bharati station of Allindia Radio, delhi,broadcasts on afrequency of 1,368 kHz (kilo hertz).Calculate the wavelength of theelectromagnetic radiation emittedby transmitter. Which part of theelectromagnetic spectrum does itbelong to?
Sol:
c
where c = velocity of E.M.R in
vaccum= 3 × 108 m sec–1
v = frequency = 1368 kHz = 1368×103 sec–1
=8 1
3 13.00 101368 10
mss
= 219.3m
This is a characteristic radiowavewavelength.
RCCStructure of atom
BookletPage - 63Q. No. 16
Solved Example
(Exactly SameAs It is
Question)
Solution69. The following solutions were
prepared by dissolving 10 g ofglucose (C6H12O6) in 250 ml of water(P1), 10 g of urea (CH4N2O) in 250 mlof water (P2) and 10 g of sucrose(C12H22O11) in 250 ml of water (P3).The right option for the decreasingorder of osmotic pressure of thesesolutions is :1) P1 > P2 > P3 2) P2 > P3 > P13) P3 > P1 > P2 4) P2 > P1 > P3
304. The three solutions containing 10 g. ofglucose. 10 g. of urea and 10 g ofsucrose in equal volumes have osmoticpressure of P1, P2 and P3 respectivelyWhich one of the following is correctin this case1) P2 > P1 > P3 2) P2 > P3 > P13) P1 > P2 > P3 4) P1 > P3 > P2
66. Arrange the following solutions inincreasing order of their osmoticpressures.(i) 34.2 g/litre sucrose(ii) 60 g/litre urea(iii) 90 g/litre glucose(iv) 58.5 g/litre of sodium chloride1) i < iii < ii < iv2) iii < i < iv < ii3) i < iii < iv < ii4) ii < iv < i < iii
RCCSolutionBooklet
Page - 87Q. No. 304
(Exactly SameAs it is)
RCCDo or Die Booklet
Page - 11Q. No. 66
(Exactly Si milarType of
Question)
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Redox Reaction79. Which of the following reactions is
the metal displacement reaction?Choose the right option.
1) Cr2O3 + 2Al Al2O3+2Cr
2) Fe + 2HCl FeCl2+H2 3) 2Pb(NO3)2 2PbO + 4NO2 + O2
2KClO3 2KCl + 3O2
3. Match the reaction in Column I withthieir types in Column IIColumn Ii)
OH4OCrNOCr)NH( 23227224
ii) 2222 OHPbOOHPbO
iii) 2 3 2 3Cr O + 2Al Al O + 2Cr
iv) OHClClOHO2Cl 232
Column IIa) Intermolecular redox reactionb) Disproportionationc) Intermoelcular redoxd) Metal displacement1) (i) - c; (iii) - a; (iii) - a, d; (iv) - b2) (i) - a; (ii) - c; (iii) - d, (iv) - b3) (i) - b; (ii) - a; (iii) - a, d; (iv) - c4) (i) - a, b; (ii) - c; (iii) - a, d; (iv) - b
RCCDo or Die Booklet
Page - 71Q. No. 3
(Exactly SameAs It is
Question)
p-block86. In which one of the following
arrangements the given sequence isnot strictly according to theproperties indicated against is?1) H2O < H2S : Increasing pKa values
< H2Se < H2Te2) NH3 < PH3 < AsH3 : Increasing acidic
< SbH3 character3) CO2 < SiO2 : Increasing oxidizing
< SnO2 < PbO2 power4) HF < HCl : Increasing acidic
< HBr < HI strength
RCCDo or Die Booklet
Page - 67Q. No. 32
(Exactly SameAs It is
Question)
32. In which of the following arrange-ments, the sequence is not strictlyaccording to the property writtenagainst it ?1) CO2 < SiO2 < SnO2 < PbO2: increas-
ing oxidising power2) HF < HCl < HBr < HI : increasing acid
strength3) NH3 < PH3 < AsH3 < SbH3 : increas-
ing basic strength4) B < C < O < N : increasing first ion-ization enthalpy
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Halo Alkanes & Halo Arenes78. The major product formed in
dehydrohalogenation reaction of2-Bromo pentane is Pent-2-ene. Thisproduct formation is based on?1) Hund’s Rule2) Hofmann Rule3) Huckel’s Rule4) Saytzeff’s Rule
RCCHalo Alkanes &
Halo ArenesBooklet
Page - 50Q. No. 1
(Exactly SameAs It is
Question)
&
Page-52Q. No. 25
(Exactly SimilarType of
Question)
1. Elimination reaction of 2-Bromo-pentane to form pent-2-ene is
(A) -elimination reaction(B)Follows Zaitsev rule (Saytzeff Rule)(C) Dehydrohalogenation reaction(D) Dehydration reaction1) (A), (C), (D) 2) (B), (C), (D)3) (A), (B), (D) 4) (A), (B), (C)
25. 2-Bromopentane is heated withpotassium ethoxide in ethanol. Themajor product obtained is1) 2-ethyoxypentane 2) pentene-13) trans-2-pentene 4) cis-pentene-2
Halo Alkanes & Halo Arenes77. The correct sequence of bond
enthalpy of ‘C–X’ bond is1) CH3–F> CH3–Cl>CH3–Br>CH3–I2) CH3–F<CH3–Cl>CH3–Br>CH3–I3) CH3–Cl> CH3–F>CH3–Br>CH3–I4) CH3–F<CH3–Cl<CH3–Br<CH3–I
103. In CH3–X the order of C–X bondstrength is1) CH3F > CH3Cl > CH3Br > CH3I2) CH3Cl > CH3Br > CH3I > CH3F3) CH3Br > CH3 I > CH3 F > CH3Cl4) CH3I > CH3 Br > CH3F > CH3 Cl
40. C – X bond is stronger in1) CH3Cl 2) CH3F3) CH3Br 4) CH3I
55. Which of the following order is correctamong the following.I. C –X Bond length order isH3C –F < H3C – Cl < H3C – Br < CH3 – III. C–X Bond enthalapiesH3C –F > H3C – Cl > H3C – Br > H3C – IIII. C–X Bond dipole moment
H3C–Cl > H3C–F > CH3–Br > CH3-I1) Only I & II2) Only II & III3) Only I & III4) All are correct
RCCHalo Alkanes &
Halo ArenesBooklet
Page - 42Q. No. 103
RCCDo or Die Booklet
i. Page-90Q. No. 40
ii. Page - 91Q. No. 55
(Exactly SameAs It is
Question)
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s-block80. The structures of beryllium chloride
in solid state and vapour phase, are1) Linear in both2) Dimer and Linear, respectively3) Chain in both4) Chain and dimer, respectively
37. An oxide of alkaline earth metals (X)reacts with C and Cl2 to give a compoundY. Y is found in polymeric chainstructure and is electron deficientmolecule. The compound Y is1) BeO 2) BeCl2
3) Be(OH)2 4) BeCO3
46. The following two figures represent
Cl – BeCl
ClBe – Cl
(i)
BeCl
ClBe
Cl
ClBe
Cl
Cl (ii)
1) (i) BeCl2 is a dimer in vapour phase;(ii) BeCl2 is chain structure in solidstate
2) (i) BeCl2 is in solid state; (ii) BeCl2is in vapour phase
3) (i) BeCl2 is monomer in solid state;(ii) BeCl2 is linear polymer invapour phase
4) (i) BeCl2 is linear monomer; (ii)BeCl2 is three dimensional dimer
RCCs-block
Booklet Page - 32 (Exactly Same AsIt is TheoreticalConcept )
s-block81. Among the following alkaline earth
metal halides one which is covalentand soluble in organic solvents is1) Strontium chloride2) Magnesium chloride3) Beryllium chloride4) Calcium chloride
151. Which of the following is more solublein ether or organic solvent?
1) BeCl2 2) CaCl23) SrCl2 4) BaCl2
63. Some of the Group 2 metal halides arecovalent and soluble in organicsolvents. Among the following metalhalides, the one which is soluble inethanol is1) BeCl2 2) MgCl2
3) CaCl2 4) SrCl2
RCCs-block Booklet
Page-42 Q. No. 151(Exactly Same As
It is Question)
RCCDo or Die Booklet
i. Page - 85Q. No. 37
ii. Page-86Q. No. 46
(Exactly SameAs It is
Question)
RCCDo or Die Booklet
i. Page - 87(Exactly Same
As It isQuestion)
BeCl2(s) BeCl2(g) K1200
above BeCl2(g)
(polymeric Chain) (Dimer)
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Hydrocarbon
94. CH3CH2COO–Na+ NaOH,+ ?
Heat
CH3CH3+ Na2CO3
Consider the above reaction andidentify the missing reagent/chemical1) Red Phosphorus 2) CaO3) DIBAL–H 4) B2H6
IV. Decarboxylation of salt ofcarboxylic acid
Sodalime 1 Part3 Part
NaOH CaO
CaO
R–H + Na2CO3
Sod. salt of carboxylic acid Alkane
48. A CaO/NaOH B 32 AlBr/Br C
etherDry/Na
n-butane A and C are1) Methyl bromide, ethyl bromide2) Sodium acetate, methyl bromide3) Methane, methyl bromide4) Sodium propionate, ethyl bromide
14. Action of heat on a mixture of sodiumpropionate and sodalime produces:1) methane 2) ethane3) propane 4) ethylene
RCCHydrocarbon
BookletPage No. 3
(Exactly SameAs It is
TheoreticalConcept )
Page, No 30Q. No. 48
(Exactly SimilarType of Question)
RCCDo or Die Booklet
Page - 118Q. No. 14
(Exactly SimilarType of Question)
d & f block71. Zr(Z=40) and Hf(Z=72) have similar
atomic and ionic radii because of1) diagonal relationship2) lanthanoid contraction3) having similar chemical properties4) belonging to same group
308. The fact that can be explained basedon lanthanide contraction is1) Zr and Y have about the same
radius2) Zr and Nb have similar oxidation
state3) Zr and Hf have about same radius4) Zr and Zn have the same oxidation
state.23. The properties of Zr and Hf are similar
because :1) both belong to d-block2) both belong to same group of the
periodic table3) both have similar radii4) both have same number ofelectrons
RCCd & f block
BookletPage - 62
Q. No. 308(Exactly Similar
Type ofQuestion)
RCCDo or Die Booklet
Page - 75Q. No. 23
(Exactly SimilarType of
Question)
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Solid State70. The correct option for the number
of body centred unit cells in all 14types of Bravias lattice unit cells is1) 5 2) 23) 3 4) 7
RCCSolid State
BookletPage - 4
(Exactly SameAs It is
TheoreticalConcept )
States of Matter51. Choose the correct option for
graphical representation of Boyle’slaw, which shows a graph ofpressure vs. volume of a gas atdifferent temperature :
1) 2)
3) 4)
27. From the graph the correct order oftemperature is1) T1 < T2 < T3
2) T1 = T2 = T3
T1
T2T3
P
V
3) T1 > T2 > T3
4) T1 < T2 > T3
RCCStates of Matter
BookletQ. No. 27/Page - 58
(Exactly SameAs it is)
6. From the graph the correct order oftemperature is1) T1 < T2 < T3
2) T1 = T2 = T3
T1
T2T3
P
V
3) T1 > T2 > T3
4) T1 < T2 > T3
RCCDo or Die Booklet
Q. No. 6Page - 36
(Exactly SameAs it is)
Electrochemistry52. The molar conductance of NaCl, HCl
and CH3COONa at infinite diluteare 126.45, 426.16 and 91.0 S cm2 mol–
1 respectively. The molarconductance of CH3COOH atinfinite dilution is Choose the rightoption for your answer1) 390.71 S cm2 mol–1
2) 698.28 S cm2 mol–1
3) 540.48 S cm2 mol–1
4) 201.28 S cm2 mol–1
173. 03
CH COONa = 224 ohm–1 cm2 gm eq–1,
NaCl = 38.2 ohm–1 cm2 gm eq–1,
HCl = 203 ohm–1 cm2 gm eq–1
What is the value of 3
0CH COOH ?
1) 288.5 ohm–1 cm2 gm eq–1
2) 289.5 ohm–1 cm2 gm eq–1
3) 388.8 ohm–1 cm2 gm eq–1
4) 59.5 ohm–1 cm2 gm eq–1
RCCElectrochemistry
BookletQ. No. 173/
Page - 28(Exactly Same
As it is)
RCCDo or Die Booklet
Q. No. 21Page - 62
(Exactly SameAs it is)
173. 0ClCH COONa2 = 224 ohm–1 cm2 gm eq–1,
NaCl = 38.2 ohm–1 cm2 gm eq–1,
HCl = 203 ohm–1 cm2 gm eq–1
What is the value of 2
0ClCH COOH ?
1) 288.5 ohm–1 cm2 gm eq–1
2) 289.5 ohm–1 cm2 gm eq–1
3) 388.8 ohm–1 cm2 gm eq–1
4) 59.5 ohm–1 cm2 gm eq–1
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Hydrogen58. Tritium, a radioactive isotope of
hydrogen, emits which of thefollowing particles?1) Alpha ()2) Gamma ()3) Neutron (n)4) Beta ()
Isotopes of Hydrogen Isotopes of H are 1
1 H (protium), 21 H
(or) D (deuterium) and 31 H (or) T
(tritium). Deuterium is also known as heavy
hydrogen. One part of tritium is present per 1018
parts of ordinary hydrogen mostly inthe form of HD
Of these isotopes, only tritium is radioactive and emit low energy harmless-particles.
RCCHydrogen
BookletPage - 1
Theory
(Exactly SameAs it is)
p-Block Element82. Statement I :
Acid strength increses in the ordergiven as HF << HCl << HBr <<HI.Statement II : As the size of theelements F, Cl, Br, I increases downthe group, the bond strength of HF,HCl, HBr and HI decreases and sothe acid strength increases.In the light of the above statments,choose the correct answer of fromthe options given below.1) Both Statement I and Statement IIare false.2) Statement I is correct but StatementII is false.3) Statement I is incorrect butStatement II is true.4) Both Statement I and Statement IIare true.
Hydrogen Halides Bond strength, bond length and thermal
stability :• Since size of halogen atom increases
from F to I down the gorup, bond lengthof H–X bond increases down the group.
Reactivity and acidic character .
HF < HCl < HBr < HI• Bond strength is inversely, proportional
to bond length i.e., larger the bondlength, lower the bond strength is
HF > HCl > HBr > HI• Higher the bond dissociation energy,
greater will be thermal stability. Thus,thermal stability follows the order.
HF > HCl > HBr > HI.
RCCp-block
Mission inorganic
Page-12
(Exactly SameAs It is
TheoreticalConcept )
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Co-ordiantion Compound53. Ethylene diaminetetraacetate
(EDTA) ion is1) Unidentate ligand2) Bidentate ligand with two “N”donor atoms3) Tridentate ligand with three “N”donor atoms4) hexadentate ligand with four “O”and two “N” donor atoms
RCCCo-ordiantion
Comp.Booklet
Page - 70
Theory
(Exactly SameAs it is)
GOC - Isomerism61. The compound which shows
metamerism is :1) C3H8O 2) C3H6O3) C4H10O 4) C5H12
13. Minimum number of carbon atoms inether to form metamers is1) 2 2) 33) 4 4) 5
14. The compoundsCH3 – O – C3H7 and C2H5 – O – C2H5exhibit1) metamerism2) optical isomerism3) chain isomerism4) cis-trans isomerism
RCCGOC - Isomerism
BookletPage - 54Q. 13, 14
(Exactly SameAs it is)
GOC- Isomerism67. Dihedral angle of least stable
conformer of ethane is1) 180° 2) 60°3) 0° 4) 120°
I = III (Eclipsed form) in this formdistance between 2C–H bonds isminimum so maximum repulsion orminimum stable.
II = IV (Staggered form) in this formdistance between 2C–H bonds ismaximum so minimum repulsion somaximum stable.
There are infinite conformers betweeneclipsed and staggered forms whichare called as skew forms
Dihedral Angle : Dihedral anglein eclipsed form of ethane is 0°.So it is least stable conformer.
Dihedral angle in staggered form ofethane is 60°.
RCCGOC- Isomerism
BookletPage - 50
(Exactly SimilarTheoreticalConcept )
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RCC STUDY MATERIAL QUESTIONNEET - 2021 PAPER QUESTION RCC TOPIC STUDYWITH P. NO.
Polymer63. Which one of the following
polymers is prepared by additionpolymerisation?1) Nylon-66 2) Novolac3) Dacron 4) Teflon
1) Addn or chain growth polymarisn
Defn : These polymers are formed by addn
of monomers containg =, bond. (ofwithout elimination of smallmolecules like H2O, CH3OH.)
eg – i) LDPE,ii) HDPE ,iii) Teflon (PTFE) ,iv) Orlon (PAN-Polyacrylonitrile)v) PVC,vi) Polypropene
RCCPolymersBooklet
Page - 34
Theory(Exactly Same
As it is)
19. Find out odd from following1) Backelite 2) Melamine3) Nylon 4) Teflon
RCCDo or Die Booklet
Page - 143Q. No. 19
(Exactly SameAs it is)
Biomolecules54. The RBC deficiency is deficiency
disease of1) Vitamin B6 2) Vitamin B1
3) Vitamin B2 4) Vitamin B12
RCCBiomolecule
Do or Die BookletPage - 142Q. No. 57
(ExactlySimilar)
57. Pernicious anaemia is caused bydeficiency of1) vitamin B1 2) vitamin B2
3) vitamin B6 4) vitamin B12
Thermodyanmics68. Which one among the following the
correct option for right relationshipbetween CP and CV for one mole ofideal gas?1) CP–CV=R 2) CP = RCV
3) CV=RCP 4) CP + CV = R
Relation Between Cp and Cv for an Ideal Gas:
CP & CV are heat capacities at constantpressure and volume respectively.
from mayer's relation CP – CV = R
RCCThermodynamics
BookletPage - 37
(Exactly Same Asit is Theoretical
Concept )
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RCC STUDY MATERIAL QUESTIONNEET - 2021 PAPER QUESTION RCC TOPIC STUDYWITH P. NO.
Ionic Equilibrium65. The pKb of dimethylamine and pKa
of acetic acid are 3.27 and 4.77respectively at T(K). The correctoption for the pH ofdimethylammonium acetatesolution is1) 5.50 2) 7.753) 6.25 4) 8.50
37. Calculate the pH of one molarammonium formate Sol. pK a for HCOOH= 3.8; pKb for NH3 = 4.8.
Sol: Hydrolysis of ammonium acetate is givenby the equation as
HCOONH4 + H2O HCOOH + NH4OHpH of the Solof a salt of weak acid andweak base is calculated using
b a w1pH [logK logK logK ]2
a w b1
[pK pK pK ]2
pH of 1M HCOONH41 (3.8 14 4.8) 6.52
.
14. pKa of a weak acid (HA) and pKb of aweak base (BOH) are 3.2 and 3.4respectively. The pH of their salt (AB)solution at 25°C is1) 6.9 2) 7.03) 1.0 4) 7.2
RCCIonic Equilibrium
BookletPage - 63
Q. 37
(Exactly SimilarJust Values are
Change)
RCCDo or Die BookletPage - 56 Q. No. 14
(Exactly SimilarJust Values are
Change)
Chemical Bonding55. BF3 is planar and electron deficient
compound. Hybridization andnumber of electrons around thecentral atom, respectively are :1) sp3 and 6 2) sp2 and 63) sp2 and 8 4) sp3 and 4
IUPAC Name56. The correct structure of 2, 6-
Dimethyl-dec-4-ene is
1) 2)
3) 4)
93. BCl3 is a planar molecule because inthis molecule boron is1) sp3 hybridised2) sp2 hybridised3) sp hybridised4) Unh ybridised
100. The correct IUPAC name of thefollowing compound
is
1) 2, 6–Dimethylhepta–2, 6–diene2) 2, 6–Dimethylhepta–1, 5–diene3) 1, 1, 5–Trimethylhexa–l, 5–dienc4) 2, 6, 6–Trimethylhexa–1, 5–diene
RCCChemical Bonding
BookletPage - 27
Q. 93(ExactlySimilar)
RCCGOC IUPAC
BookletPage - 36
Q. 100(ExactlySimilar)
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Solutions93. The correct option for the value of
vapour pressure of a solution at 45°Cwith benzene to octane in molarratio 3:2 is[At 45° C vapour pressure ofbenzene is 280 mm Hg and that ofoctane is 420 mm Hg. Assume Idealgas]1) 168 mm of Hg 2) 336 mm of Hg3) 350 mm of Hg 4) 160 mm of Hg
175. A solution has 1:4 molar ratio ofpentane and hexane. The vapourpressure of pure hydrocarbons at 20ºCare 440 mm Hg for pentane and 120mm of Hg for hexane. The molefraction of pentane in vapour phasewould be1) 0.200 2) 0.4783) 0.547 4) 0.786
176. The vapour pressure of two liquids ‘P’and ‘Q’ are 80 and 60 torr respectively.Calculate the total vapour pressure ofthe solution obtained by mixing 3moles of P and 2 moles of Q.1) 72 torr 2) 27 torr3) 60 torr 4) 70 torr
25. A solute has 2:3 mass ratio of touleneto benzene, the vapour pressure ofbenzene and toulene at 25°C are 95 and28 bar respectively, the mole fraction ofToulene vapour is1) 0.658 2) 0.3263) 0.548 4) 0.855
RCCSolutions
BookletPage - 73
Q. No. 175, 176(Exactly Similar
Type of Question)(Just Values are
changed)
RCCDo or Die Booklet
Page - 8Q. No. 25
(Exactly SimilarType of Question)
Chemical Kinetics87. The slope of Arrhenius Plot
1ln k v / sT
of first order reaction is
–5 ×10 3K. The value of Ea of thereaction is. Choose the correctoption for your answer.[Given R = 8.314 JK–1 mol–1]1) 83.0 kJ mol–1 2) 166 kJ mol–1
3) – 83 kJ mol–1 4) 41.5 kJ mol–1
36. The temperature dependence of therate constant k is expressed as k = Ae–
Ea/RT. When a plot between log k and1/T is plotted we get the graph asshown. What is the value of slope inthe graph ?
1) aERT
2) aE2.303R
3) aE log A2.303RT
4) aE R2.303 T
RCCChemical Kinetics
BookletPage - 77Q. No. 35
(Exactly SimilarType of
Question)
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RCC STUDY MATERIAL QUESTIONNEET - 2021 PAPER QUESTION RCC TOPIC STUDYWITH P. NO.
Aldehyde ketone Carboxylic acid+ Alcohol Phenol ether91. Match List-I with List-II
List-I List-II
a) 3
CO,HClAnhyd.AlCl /CuCl i) Hell-Volhard-
Zelinskyreaction
b) 3
O||
R C CH + ii) Gattermann-Koch
NaOX reactionc) R–CH2–OH iii) Haloform reaction
+R’COOH’
2 4Conc.H SO
d) R–CH2COOH iv)Esterification
2
2
i)X /RedP
ii) H O
Choose the correct answer from theoptions given below.
1) a -iii, b-ii, c-i, d-iv 2) a-i, b-iv, c-iii, d-ii3) a-ii, b-iii, c-iv, d-i 4) a-iv, b-i, c-ii, d-iii
RCCAldehyde Ketone
& Carboxylicacid
BookletPage - 23, 6
(Exactly SimilarTheoreticalConcept )
IV) Halogenation• Hell–Vohlard–Zelinsky reaction
(-halogenation)HBrCOOHH
XCRCOOHH
HCR
|OH.ii
phosphorusred/X.i
| 2
2
4) By Gatterman-Koch reaction
Benzene
+ CO + HCl anhy AlCl 3CHO
Benzaldehyde
2. Esterification
R’CO OH+H –OR R’COOR + H O2
Ester
H SO (conc.)2 43 2 5 3 2 5 2Heat
Acetic acid Ethyl alcohol Ethyl acetateCH COOH+ HOC H CH COOC H + H O
1. Which of the following correct set ofname reaction:
a.
Cannizzaro reaction
b. CH3–CH2–CHO ΔNaOH
3
2 3
CH|C CH CH CH|CHO
Aldol condensation
c.CH3–CH2–COOH Δ
NaOH CH3–
Cl|
COOHCH
HVZ reaction
d.
Hoffmann’s bromide1) a, b 2) b, c,3) a, b, c 4) All of these
RCCDo or Die Booklet
Page - 112Q. No. 1
(Exactly SimilarType of
Question)
RCCAlcohol Phenol
EthersBooklet
Page - 60,(Exactly Same
TheoreticalConcept )
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d & f block57. The incorrect statement among the
following is :1) Most of the trivalent Lanthanoid
ions are colourless in the solid state.2) Lanthanoids are good conductors of
heat and electricity3) Actinoids are highly reactive metals,
especially when finely divided4) Actinoid contraction is greater for
element to element than Lanthanoidcontraction
RCCd & f block
BookletPage - 42
Theory
(ExactlySimilar)
a) Lanthanides : Defn : These are the element in which last
electron entres in 4f orbital ofantipenultimate shell.
They form Ist inner transition series. General electronic confn 4f1–14, 5d°–1, 6s2. These elements starts from. 58Ce to 71Lu They have similar properties to
Lanthanum so, called as Lanthanides(Lanthanones).
These are 14 elements. Most of the trivalent Lanthanoids
are colour due to the presence ofunpaired electron
Chemical Kinetics59. For a reaction A B, enthalpy of
reaction is – 4.2 kJ mol–1 andenthalpy of activation is 9.6 kJ mol–
1. The correct potential energyprofile for the reaction is shown inoption.
1) 2)
3) 4)
204. Given the energyprofile for the reactionA + B C + D
Pick up the correct statement1. Activation evergy for the reaction
C + D A + B is(x+y)2. H of the reaction
A + B C + D is –y3. Threshold energy of the reaction isx + y + z1) 1 and 2 2) 2 and 33) 1 and 3 4) 1, 2 and 3
RCCChemical Kinetics
BookletPage - 78
Q. 204
(ExactlySimilar)
RCCDo or Die Booklet
Q. No. 7
Page - 31(Exactly Similar)
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RCC STUDY MATERIAL QUESTIONNEET - 2021 PAPER QUESTION RCC TOPIC STUDYWITH P. NO.
Alcohol Phenol Ether62. Which is the IUPAC name of the
organic compound formed in thefollowing chemical reaction?
Acetone (i)C H MgBr, dry Ether2 5+(ii)H O, H2
Product
1) pentan-2-ol2) pentan-3-ol3) 2-methylbutan-2-ol4) 2-methylpropan-2-ol
60. Consider the following sequence ofreactions:
A 2 5C H Mgl X 2H / H O
tert -
amylalcoholThe compound A in the above sequenceof reactions is:1) 2- Butanone 2)Acetaldehyde3) Acetone 4)Propanal
RCCAlcohol Phenol
EtherBooklet
Page - 97Q. 60
(Exactly Similar)
RCCAlcohol Phenol
EtherBooklet
Page - 58Theory
C. Primary of Tertiary Alcohol :CH –C=O + CH –Mg-I3 3
CH 3
Acetone
Methyl Magnesium Iodide
etherdry
3
3
3
Mg-complex
CH|
CH C O Mg - I|CH
H O H2+
CH –C–OH + Mg3
CH3
Tert.-Butyl alcohol
CH3
OH
I
RCCDo or Die Booklet
Q. No. 32Page - 103
(Exactly Similar)
32. (CH3)2CHOH OxidMild X
HOHii.
MgBrCHi. 3 Y Here Y is
1) Isobutyl alcohol 2) tert-Butyl alcohol3) Isobutylene 4) sec-Butyl alcohol
Metallurgy72. Which one of the following
methods can be used to obtainhighly pure metal which is liquidat room temperature?1) Chromatography 2) Distillation3) Zone refining 4) Electrolysis
iii) Distillation : • This is very useful for low boiling
metal like Zn & Hg. The impure metalis evaporated to obtain the pure metalas distillate
RCCMetallury
BookletPage - 10Theory
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Chemical Bonding64. Match List-I with List-II
List-I List-IIa) PCl5 (i) Square pyramidalb) SF6 (ii) Trigonal planarc) BrF5 (iii) Octahedrald) BF3 (iv) Trigonal bipyramidalChoose the correct answer from the
options gien below.1) (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)2) (a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)3) (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)4) (a)-(iv), (b)-(iii), (c)-(i), (d)-(ii)
132. Match the interhalogen compounds ofcolumn-I with the geometry in column -II and assign the correct code.Column I Column IIA. XX’ i. T-shapeB. XX’3 ii. Pentagonal bipyramidalC. XX’5 iii. LinearD. XX’7 iv. Square-pyramidal
v. Tetrahedral1) A-iii, B-i, C-iv, D-ii2) A-v, B-iv, C-iii, D-ii3) A-iv, B-iii, C-ii, D-i4) A-iii, B-iv, C-i, D-ii
6. Match the lists I and II and writethe correct matchingList-I (Species) List-II (Geometry)A. H3O+ 1.PlanarB. H2C = NH 2.AngularC. ClO2 3.TetrahedralD. NH4
+ 4. Trigonal bipyramidalE. PCl5 5.Pyramidal1) A-2, B-1, C-3, D-5, E-42) A-1, B-5, C-2, D-3, E-43) A-5, B-1, C-2, D-3, E-44) A-3, B-1, C-4, D-5, E-2
RCCChemical Bonding
BookletPage - 30
Q. 132
(ExactlySimilar)
RCCDo or Die Booklet
Page - 26Q. No. 6
(Exactly Similar)
Chemistry in Everday life66. Give below are two statements :
Statement I :Aspirin and Paracetamol belong theclass of narcotic anallgesics.Statement II :Morphine and Heroin are non-narcotic analgesics. In the light ofthe above statements, choose thecorrect answer from the optonsgiven below.1) Both statement I and statement II are
false2) Statement I is correct but statement
II is false3) Statement I is incorrect but stateemnt
II is true4) Both statement I and statement II are
true
RCCChemistry ineverday life
BookletPage - 51
(Exactly SimilarTheoreticalConcept )
6
• Act at inflammation • Severe use causes -
toxici ty & -toxicity
• To treat moderate pain, body pain, minor cut, Arthritis, Headache, Gaut.
e.g. Analgin, Ibuprofen , Naproxen, Nimesulide
site Renal
Hepato
Aspirin,
• Act via • Severe use causes
• Used to treat pain. (labour pain, Burn, Fractur, Cancer, Post-operative pain)
e.g.
(diacetyl morphine)
Mo r phi ne , c o d e i n e
CNS
additionsevere
heroin
Non-NarcoticNarcotic
42. Which statement about apsirin is nottrue ?1) Aspirin belongs to narcoticanalgesics2) It is effective in relieving pain3) It has antiblood clotting action4) It is a neurologically active drug
RCCDo or Die Booklet
Page - 148Q. No. 42
(Exactly SimilarTheoreticalConcept )
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Amines73. Identify the comound that will react
with Hinsberg’s reagent to give asolid which dissolves in alkali.
1)
2)
3)
4)
5) Hinsberg’s test : (Distinction test)i) Primary amines :
R – NH2 + C6H5SO2Cl
2 6 5N-alkyl benzenesulphonamide
R NHSO C H + HCl
dissolveKOH
RCCAminesBooklet
Page - 87
(Exactly SameAs It is
TheoreticalConcept )
Hydrocarbon74. The major product of the following
chemical reaction is :
– CH= CH2 + HBr 6 5 2 2(C H CO) O ?
1)CH3
CH3 CH–CH –CH –O–COC H2 2 6 5
2) CH3
CH3
CH–CH–CH3
Br
3)CH3
CH3
CBr–CH –CH2 3
4)CH3
CH3
CH–CH –CH –Br2 2
45. CH3CH2 – CH = CH2 + HBr
ROORMinorMajor[Y][X] ; [X] & [Y]
respectively are
1) BrCH2CH2CH = CH2 & C2H5 –CHBr – CH3
2) C2H5–CH2CH2–Br & Br–CH2CH2–CH=CH2
3) C2H5 – CH2 – CH2Br & C2H5–CHBr – CH3
4) C2H5CHBr – CH3 & C2H5 – CH2 –CH2 Br
43. Observe the following reactions andpredict the nature of A and B.
B2 2
HBrH O
1) A and B both are
2) A and B both are
3) A is & B is
4) A is & B is
RCCHydrocarbon
BookletPage - 39Q. No. 45
(Exactly SimilarType of
Question)
RCCDo or Die Booklet
Page - 120Q. No. 43
(Exactly SimilarType of
Question)
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Surface Chemistry75. The right option for the statement
“Tyndall effect is exhibited by” is1) Glucose solution2) Starch Solution3) Urea Solution4) NaCl solution
p-block76. Noble gases are named because of
their inertness towards reactivity.Identify an incorrect statementabout them.1) Noble gases have very high melting
and boiling points.2) Noble gases have weak dispersion
forces.3) Noble gases have large positive
values of electron gain enthalpy.4) Noble gases are sparingly soluble inwater.
13. Tyndall effect is observed only wheni) the diameter of the dispersedparticles is not much smaller than thewavelength of the light usedii) the refractive indices of dispersedphase and dispersion medium differgreatly in magnitudeiii) the size of the particles is generallybetween 10–11 and 10–9 m in diameteriv) the dispersed phase anddispersion medium can be seenseparated in the system1) (i) and (iii) 2) (i) and (iv)3) (ii) and (iii) 4) (i) and (ii)
RCCSurface ChemistryDo or Die Booklet
Page - 40Q. No. 13
(Similar Typeof Question)
4) Melting point and boiling point :
• They have low M.P. & B.P.• M.P. and B.P. of noble gases increases
from He to Rn.
Atomic mass or size ,polarisability ,London force
Liquification increases because
• He < Ne < Ar < Kr < Xe < Rnmpt. bptMagnitude of London forces increases.
• He < Ne < Ar < Xe < Rn5) Solubility in water :
• Solubility of noble gases in waterincreases from He to Xe
because dipole induced dipoleattraction increases
• They are sparingly soluble inwater
He < Ne < Ar < Xe < Rn
RCCp-block Chart
Page - 7
(Exactly SameAs It is
TheoreticalConcept )
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Mole Concept83. An organic compound contains 78%
(by wt.) carbon and remainingpercentage of hydrogen. The rightoption for the empirical formula ofthis compound is (Atomic wt. of Cis 12, H is 1)1) CH2 2) CH3
3) CH4 4) CH
41. A hydrocarbon has 75% C. Thus,hydrocarbon is1) CH4 2) C2H6
3) C2H4 4) C2H2
RCCMole Concept
BookletPage - 17
(Exactly SimilarType of
Question)
Metallurgy84. The maximum temperature that can
be achieved in blast furnace is1) upto 2200 K 2) upto 1900 K3) upto 5000 K 4) upto 1200 K
146. In the blast furnace during theextraction of iron the temperatureattained in the hearth is nearly1) 4000C 2) 10000C3) 15000C 4) 20000C
Hint : 2000 + 273 = 2273 K
RCCMetallurgy
BookletPage - 28
Q. No. 146
(Exactly SimilarType of
Question)
Environmental Chemistry90. Match List–I with List-II
List-I List-IIa) 2SO2(g) + O2(g) i) Acid rain
2SO3(g)
b) HOCl(g) hv ii) Smog
• •
O H + C lc) CaCO3 + H2SO4 iii) Ozone depletion
CaSO4 + H2O + CO2
d) NO2(g) hv iv) Tropospheric
NO(g) + O(g) pollutionChoose the correct answer from theopitons given below.1) a-ii, b-iii, c-iv, d-i2) a-iv, b-iii, c-i, d-ii3) a-iii, b-ii, c-iv, d-i4) a-i, b-ii, c-iii, d-iv
N2(g) + O2(g) 1483 K 2NO(g)
NO reacts instantly with oxygen to giveNO22NO(g) + O2(g) 2NO2(g)The rate of production of NO2 is highwhen nitric oxide reacts with ozone inthe stratosphere.NO(g) + O3(g) NO2(g) + O2(g)
Formation of photo chemical smog: When fossil fuels are burnt, two
pollutants (NO) are emitted intoatmosphere.
The formation of photo chemical smogare : sun light. oxygen atom.
NO2(g) hv NO(g) + O(g) with the O2
in air to produce O3O(g) + O2(g) O3(g)
Regeneration of NO2.NO(g)+O3(g)NO2(g)+O2(g)
RCCEnvironmental
Chemistry
BookletPage - 83, 84
(Exactly SimilarTheoreticalConcept )
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Chemical Bonding88. Which of the following molecules is
non-polar in nature?1) CH2O 2) SbCl5
3) NO2 4) POCl3
192. Which of the following is non-polar1) H2S 2) NaCl3) Cl2 4) H2SO4
200. In which of the following bonds arepolar but molecule is non-polar
1) HCO3 OCH3
2) Cl I
3) SF6
4) CHCl3
201. Which of the following compounds isplanar and non-polar?1) XeO4 2) SF43) XeF4 4) CF4
RCCChemical Bonding
BookletPage - 33
Q. No. 192(Exactly Similar
Type of Question)
RCCChemical Bonding
BookletPage - 33
Q. No. 192Page - 34
Q. No. 200, 201(Exactly Similar
Type ofQuestion)
126. Match the lists I and II and pick thecorrect matching from the codes givenbelowList -I List -II(complex) (Structure & magnetic mo-ment)
a) [Ag(CN)2]– 1) square planar & 1.73 BMb) [Cu(CN)4]3– 2) Linear and zeroc) [Cu(CN)6]4– 3) Octahedral and zerod) [Cu(NH)3)4]2+ 4) tetrahedral and zeroe) [Fe(CN)6]4– 5) octahedral and 1.73BM1) a-2,b-4,c-5,d-1,e-3 2) a-5,b-4,c-1,d-3,e-23) a-1,b-3,c-4,d-2,e-5 4) a-4,b-5,c-2,d-1,e-3
Co-ordiantion Comp.89. Match List-I with List-II
List-I List-IIa) [Fe(CN)6]3– i) 5.92 BMb) [Fe(H2O)6]3+ ii) 0 BMc) [Fe(CN)6]4– iii) 4.90 BMd) [Fe(H2O)6]2+ iv)1.73 BMChoose the correct answer from theoptions given below.1) a-ii, b-iv, c-iii, d-i2) a-i, b-iii, c-iv, d-ii3) a-iv, b-i, c-ii,d-iii4) a-iv, b-ii, c-i, d-iii
RCCCo-ordination
Comp.Booklet
Page - 93Q. No. 126
(Exactly SimilarType of
Question)RCC
Do or Die BookletPage - 81Q. No. 32
Similar Type
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Thermodynamics92. For irreversible expansion of an
ideal gas under isothermalcondition, the correct option is1) U 0, Stotal 02) U 0, Stotal 03) U 0, Stotal 04) U 0, Stotal 0
10. During isothermal expansion of anideal gas, its internal energy1) Decreases2) Increases3) May increase or decrease4) Remains unchanged
101. For an irreversible process, the valueof[S(system) +S(surroundings)] is1) > 0 2) < 03) 0 4) 2S(surr)
RCCThermodynamics
BookletPage - 43Q. No. 10
&Page-50
Q. No. 101
(Exactly SimilarType of
Question)
Alcohol Phenol Ether95. The product formed in the
following chemical reaction is
CH –C– OCH2 3
CH3
OO
4
2 5
NaBH
C H OH ?
1)CH –CH –OH2 2
CH3
O
2)CH –C–CH2 3
CH3
OH
OH
3)
OCH –C–OCH2 3
CH3
OH
4)
HCH –C–OCH2 3
CH3
OH
OH
RCC
Special NaBH4 reduces only
O||
R C H ,
O||
R C R ,
O||
R C Cl
(No efffect on C = C, N = N, C N , NO2,ester group)
RCCAlcohol Phenol
EtherBooklet
Page No. 58(Exactly Similar
TheoreticalConcept )
41. The product formed in the followingreaction
is
1) 2)
3) 4)
RCCDo or Die Booklet
Page - 104Q. No. 41
(Exactly SimilarType of
Question)
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Electrochemistry96. The molar conductivity of 0.007 M
acetic acid is 20 S cm2 mol–1. What isthe dissociation constant of aceticacid? Choose the correct option.
+
-3
° 2 -1H
° 2 -1CH COO
Λ = 350Scm mol
Λ = 50S cm mol
1) 2.50 × 10–4 mol L–1
2) 1.75 × 10–5 mol L–1
3) 2.50 × 10-5 mol L–1
4) 1.75 × 10–4 mol L–1
9. The equivalent conductance of M32
solution of a weak monobasic acid is 8.0mhos cm2 and at infinite dilution is 400mhos cm2. The dissociation constant ofthis acid is :- [2009]1) 1.25 × 10–6 2) 6.25 × 10–4
3) 1.25 × 10–4 4) 1.25 × 10–5
RCCElectrochemistry
BookletPage - 39
Q. No. 9(Exactly Similar
Type ofQuestion)
States of Matter97. Choose the correct option for the
total pressure (in atm) in a mixtureof 4 g O2 and 2g H2 confined in atotal volume of one litre at 0° C is[Given R = 0.082 L atm mol–1 K–1,T= 273 K]1) 2.602 2) 25.183) 26.02 4) 2.518
26. A two litre flask contain a mixture of16g of oxygen, 7g of nitrogen and 2g ofhydrogen at 20°C. Report the totalpressure and partial pressures.
Sol: Total number of moles of mixture =2 21 1
16gof O 7g of N32g mol 28g mol
2
1
2gof H2gmol
= 1 1 712 4 4
Using ideal gas equation,
RT 7 0.0821 293P nV 4 2
= 21atm
15. The total pressure of a mixture of 8g ofoxygen and 14g of nitrogen contained ina 11.2L vessel at 0ºC is.1) 0.5 atm 2) 1 atm3) 1.5 atm 4) 2 atm
RCCStates of Matter
BookletPage -69Q. No. 26
Solved example(Exactly Similar
Type ofQuestion)
(Just values arechanged)
RCCDo or Die Booklet
Page - 37Q. No. 15
(Exactly SimilarType of
Question)(Just values are
changed)
NEE-2021 Paper Analysis
Prof.Motegaonkar S.R. M.Sc.Chem.Gold Medalist SET/NET-JRF,GATE, DRDO,TIFR qualified 31
RCC STUDY MATERIAL QUESTIONNEET - 2021 PAPER QUESTION RCC TOPIC STUDYWITH P. NO.
Periodic Table98. From the following pairs of ions
which one is not an iso-electronicpair?1) Na+, Mg2+ 2) Mn2+, Fe3+
3) Fe2+, Mn2+ 4) O2–, F–
127. Which of the following groupingrepresents a collection of iso-electionicspecies?1) Ca2+, Cs2+, Br 2) Na+, Ca2+, Mg2+
3) N3–, F–, Na+ 4) Be, Al3+, Cl+
25. The ions O2–, F–, Na+, Mg2+, andAl3+ are isoelectronic. Their ionicradii show -1) an increase from O2– to F– and then
decrease from Na+ to Al3+
2) a decrease from O2– to F– and thenincrease from Na+ to Al3+
3) a singnificant increase from O2– toAl3+
4) a singnificant decrease from O2– toAl3+
RCCPeriodic Table
BookletPage - 20
Q. No. 127(Exactly Similar
Type ofQuestion)
RCCDo or Die Booklet
Page - 66Q. No. 25
(Exactly SimilarType of
Question)
Amines99. The reagent ‘R’ in the given
sequence of chemical reaction is
NH2
Br Br
Br
2NaNO ,HCl0-5°C
N Cl2+ –
Br Br
Br
R
Br Br
Br
1) CH3CH2OH 2) HI3) CuCN/KCN 4) H2O
Ar–N X2+ –
H PO + H O/CuCl3 2 2 ArH + N + H PO + HX2 3 3
RCCAmines Booklet
Page - 89(Exactly Same As It
is TheoreticalConcept )
42. Mark the incorrect pairing
1)6 5 2 3 2 2C H N Cl H PO H O
Cu
C6H6+H3PO3+HPCl + N2
2)(Benzene)
6 5 2 6 6C H N Cl C H NaOH
6 5 6 5(Diphenyl)
C H C H +N2 + NaCl + H2O
3) 6 5 2C H N Cl HBF4
HCl 26 5 4
6 5 3 2(Fluorobenzene)
C H N .BF
C H F BF N
4)6 5 2C H N Cl
+ C2H5OH heat
6 5(Phenol)
C H OH +N2+HCl + CH3CHO
RCCDo or Die Booklet
Page - 134Q. No. 42
(Exactly SimilarType of
Question)
NEE-2021 Paper Analysis
Prof.Motegaonkar S.R. M.Sc.Chem.Gold Medalist SET/NET-JRF,GATE, DRDO,TIFR qualified 32
RCC STUDY MATERIAL QUESTIONNEET - 2021 PAPER QUESTION RCC TOPIC STUDYWITH P. NO.
Aldehyde Ketones100. The intermediate compound ‘X’ in
the following chemical reaction is
CH3
+CrO2Cl2 2CS X +
3H O
C H
O
1)CH(OCOCH )3 2
2)CH
ClCl
3)CH
ClH
4) CH(OCrOHCl )2 2
1) Etard reaction (CrO2Cl2)
CH3
Toulene
2CrO Cl2 2
CS2
2CrO Cl CH
OCrOHCl2
OCrOHCl2H O3
+ CHO+ CrO Cl + 2H2 2 2
Chromium complex Benzaldehyde
RCCAldehyde Ketones
BookletPage - 6
(Exactly Similartype of
Question)
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