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Published by – www.Padasalai.Net. Thanks to Mr. Ravi, B.T.Asst., GHS, Arangaldurgam. k/r]`pfpDtfTk: 2 x 3 + x 2 – 5x + 2. k/r]`pfpDtfTk: 2 x 3 + x 2 – 5x + 2. k/r]`pfpDtfTk: 2 x 3 + x 2 – 5x + 2. k/r]`pfpDtfTk: 2 x 3 + x 2 – 5x + 2. k/r]`pfpDtfTk: 2 x 3 + x 2 – 5x + 2. - PowerPoint PPT Presentation

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Published by – www.Padasalai.Net

Thanks to Mr. Ravi, B.T.Asst., GHS, Arangaldurgam.

k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2

k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2

+ +2 + 1 – 5 + 2

0 + 2 + 3 – 2 (x – 1) oR k/r]`

+ 2 + 3 – 2 0

2x2 + 3x – 2 <p.p. – 4 $. p. + 3

= 2x2 – 1x + 4x – 2 – +

= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)

= X (2X – 1) + 2 (X+2)

= (2X – 1) (X + 2)

k/r]`kqf = (X – 1) (X + 2) (2X – 1)

k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2

+ +2 + 1 – 5 + 2

0 + 2 + 3 – 2 (x – 1) oR k/r]`

+ 2 + 3 – 2 0

2x2 + 3x – 2 <p.p. – 4 $. p. + 3

= 2x2 – 1x + 4x – 2 – +

= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)

= X (2X – 1) + 2 (X+2)

= (2X – 1) (X + 2)

k/r]`kqf = (X – 1) (X + 2) (2X – 1)

k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2

+ 1 +2 + 1 – 5 + 2

0 + 2 + 3 – 2 (x – 1) oR k/r]`

+ 2 + 3 – 2 0

2x2 + 3x – 2 <p.p. – 4 $. p. + 3

= 2x2 – 1x + 4x – 2 – +

= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)

= X (2X – 1) + 2 (X+2)

= (2X – 1) (X + 2)

k/r]`kqf = (X – 1) (X + 2) (2X – 1)

k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2

+ 1 +2 + 1 – 5 + 2

0 + 2 + 3 – 2 (x – 1) oR k/r]`

+ 2 + 3 – 2 0

2x2 + 3x – 2 <p.p. – 4 $. p. + 3

= 2x2 – 1x + 4x – 2 – +

= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)

= X (2X – 1) + 2 (X+2)

= (2X – 1) (X + 2)

k/r]`kqf = (X – 1) (X + 2) (2X – 1)

k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2

+ 1 +2 + 1 – 5 + 2

0 + 2 + 3 – 2 (x – 1) oR k/r]`

+ 2 + 3 – 2 0

2x2 + 3x – 2 <p.p. – 4 $. p. + 3

= 2x2 – 1x + 4x – 2 – +

= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)

= X (2X – 1) + 2 (X+2)

= (2X – 1) (X + 2)

k/r]`kqf = (X – 1) (X + 2) (2X – 1)

k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2

+ 1 +2 + 1 – 5 + 2

0 + 2 + 3 – 2 (x – 1) oR k/r]`

+ 2 + 3 – 2 0

2x2 + 3x – 2 <p.p. – 4 $. p. + 3

= 2x2 – 1x + 4x – 2 – +

= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)

= X (2X – 1) + 2 (X+2)

= (2X – 1) (X + 2)

k/r]`kqf = (X – 1) (X + 2) (2X – 1)

k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2

+ 1 +2 + 1 – 5 + 2

0 + 2 + 3 – 2 (x – 1) oR k/r]`

+ 2 + 3 – 2 0

2x2 + 3x – 2 <p.p. – 4 $. p. + 3

= 2x2 – 1x + 4x – 2 – +

= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)

= X (2X – 1) + 2 (X+2)

= (2X – 1) (X + 2)

k/r]`kqf = (X – 1) (X + 2) (2X – 1)

k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2

+ 1 +2 + 1 – 5 + 2

0 + 2 + 3 – 2 (x – 1) oR k/r]`

+ 2 + 3 – 2 0

2x2 + 3x – 2 <p.p. – 4 $. p. + 3

= 2x2 – 1x + 4x – 2 – +

= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)

= X (2X – 1) + 2 (X+2)

= (2X – 1) (X + 2)

k/r]`kqf = (X – 1) (X + 2) (2X – 1)

k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2

+ 1 +2 + 1 – 5 + 2

0 + 2 + 3 – 2 (x – 1) oR k/r]`

+ 2 + 3 – 2 0

2x2 + 3x – 2 <p.p. – 4 $. p. + 3

= 2x2 – 1x + 4x – 2 – +

= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)

= X (2X – 1) + 2 (X+2)

= (2X – 1) (X + 2)

k/r]`kqf = (X – 1) (X + 2) (2X – 1)

k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2

+ 1 +2 + 1 – 5 + 2

0 + 2 + 3 – 2 (x – 1) oR k/r]`

+ 2 + 3 – 2 0

2x2 + 3x – 2 <p.p. – 4 $. p. + 3

= 2x2 – 1x + 4x – 2 – +

= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)

= X (2X – 1) + 2 (X+2)

= (2X – 1) (X + 2)

k/r]`kqf = (X – 1) (X + 2) (2X – 1)

k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2

+ 1 +2 + 1 – 5 + 2

0 + 2 + 3 – 2 (x – 1) oR k/r]`

+ 2 + 3 – 2 0

2x2 + 3x – 2 <p.p. – 4 $. p. + 3

= 2x2 – 1x + 4x – 2 – +

= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)

= X (2X – 1) + 2 (X+2)

= (2X – 1) (X + 2)

k/r]`kqf = (X – 1) (X + 2) (2X – 1)

k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2

+ 1 +2 + 1 – 5 + 2

0 + 2 + 3 – 2 (x – 1) oR k/r]`

+ 2 + 3 – 2 0

2x2 + 3x – 2 <p.p. – 4 $. p. + 3

= 2x2 – 1x + 4x – 2 – +

= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)

= X (2X – 1) + 2 (X+2)

= (2X – 1) (X + 2)

k/r]`kqf = (X – 1) (X + 2) (2X – 1)

k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2

+ 1 +2 + 1 – 5 + 2

0 + 2 + 3 – 2 (x – 1) oR k/r]`

+ 2 + 3 – 2 0

2x2 + 3x – 2 <p.p. – 4 $. p. + 3

= 2x2 – 1x + 4x – 2 – +

= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)

= X (2X – 1) + 2 (X+2)

= (2X – 1) (X + 2)

k/r]`kqf = (X – 1) (X + 2) (2X – 1)

k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2

+ 1 +2 + 1 – 5 + 2

0 + 2 + 3 – 2 (x – 1) oR k/r]`

+ 2 + 3 – 2 0

2x2 + 3x – 2 <p.p. – 4 $. p. + 3

= 2x2 – 1x + 4x – 2 – +

= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)

= X (2X – 1) + 2 (X+2)

= (2X – 1) (X + 2)

k/r]`kqf = (X – 1) (X + 2) (2X – 1)

k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2

+ 1 +2 + 1 – 5 + 2

0 + 2 + 3 – 2 (x – 1) oR k/r]`

+ 2 + 3 – 2 0

2x2 + 3x – 2 <p.p. – 4 $. p. + 3

= 2x2 – 1x + 4x – 2 – +

= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)

= X (2X – 1) + 2 (X+2)

= (2X – 1) (X + 2)

k/r]`kqf = (X – 1) (X + 2) (2X – 1)

k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2

+ 1 +2 + 1 – 5 + 2

0 + 2 + 3 – 2 (x – 1) oR k/r]`

+ 2 + 3 – 2 0

2x2 + 3x – 2 <p.p. – 4 $. p. + 3

= 2x2 – 1x + 4x – 2 – +

= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)

= X (2X – 1) + 2 (X+2)

= (2X – 1) (X + 2)

k/r]`kqf = (X – 1) (X + 2) (2X – 1)

k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2

+ 1 +2 + 1 – 5 + 2

0 + 2 + 3 – 2 (x – 1) oR k/r]`

+ 2 + 3 – 2 0

2x2 + 3x – 2 <p.p. – 4 $. p. + 3

= 2x2 – 1x + 4x – 2 – +

= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)

= X (2X – 1) + 2 (X+2)

= (2X – 1) (X + 2)

k/r]`kqf = (X – 1) (X + 2) (2X – 1)

k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2

+ 1 +2 + 1 – 5 + 2

0 + 2 + 3 – 2 (x – 1) oR k/r]`

+ 2 + 3 – 2 0

2x2 + 3x – 2 <p.p. – 4 $. p. + 3

= 2x2 – 1x + 4x – 2 – +

= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)

= X (2X – 1) + 2 (X+2)

= (2X – 1) (X + 2)

k/r]`kqf = (X – 1) (X + 2) (2X – 1)

k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2

+ 1 +2 + 1 – 5 + 2

0 + 2 + 3 – 2 (x – 1) oR k/r]`

+ 2 + 3 – 2 0

2x2 + 3x – 2 <p.p. – 4 $. p. + 3

= 2x2 – 1x + 4x – 2 – +

= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)

= X (2X – 1) + 2 (2X – 1)

= (2X – 1) (X + 2)

k/r]`kqf = (X – 1) (X + 2) (2X – 1)

k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2

+ 1 +2 + 1 – 5 + 2

0 + 2 + 3 – 2 (x – 1) oR k/r]`

+ 2 + 3 – 2 0

2x2 + 3x – 2 <p.p. – 4 $. p. + 3

= 2x2 – 1x + 4x – 2 – +

= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)

= X (2X – 1) + 2 (2X – 1)

= (2X – 1) (X + 2)

k/r]`kqf = (X – 1) (X + 2) (2X – 1)

k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2

+ 1 +2 + 1 – 5 + 2

0 + 2 + 3 – 2 (x – 1) oR k/r]`

+ 2 + 3 – 2 0

2x2 + 3x – 2 <p.p. – 4 $. p. + 3

= 2x2 – 1x + 4x – 2 – +

= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)

= X (2X – 1) + 2 (2X – 1)

= (2X – 1) (X + 2)

k/r]`kqf = (X – 1) (X + 2) (2X – 1)

k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2

+ 1 +2 + 1 – 5 + 2

0 + 2 + 3 – 2 (x – 1) oR k/r]`

+ 2 + 3 – 2 0

2x2 + 3x – 2 <p.p. – 4 $. p. + 3

= 2x2 – 1x + 4x – 2 – +

= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)

= X (2X – 1) + 2 (2X – 1)

= (2X – 1) (X + 2)

k/r]`kqf = (X – 1) (X + 2) (2X – 1)

k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2

+ 1 +2 + 1 – 5 + 2

0 + 2 + 3 – 2 (x – 1) oR k/r]`

+ 2 + 3 – 2 0

2x2 + 3x – 2 <p.p. – 4 $. p. + 3

= 2x2 – 1x + 4x – 2 – +

= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)

= X (2X – 1) + 2 (2X – 1)

= (2X – 1) (X + 2)

k/r]`kqf = (X – 1) (X + 2) (2X – 1)

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