published by – padasalai.net
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Published by – www.Padasalai.Net. Thanks to Mr. Ravi, B.T.Asst., GHS, Arangaldurgam. k/r]`pfpDtfTk: 2 x 3 + x 2 – 5x + 2. k/r]`pfpDtfTk: 2 x 3 + x 2 – 5x + 2. k/r]`pfpDtfTk: 2 x 3 + x 2 – 5x + 2. k/r]`pfpDtfTk: 2 x 3 + x 2 – 5x + 2. k/r]`pfpDtfTk: 2 x 3 + x 2 – 5x + 2. - PowerPoint PPT PresentationTRANSCRIPT
Published by – www.Padasalai.Net
Thanks to Mr. Ravi, B.T.Asst., GHS, Arangaldurgam.
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+ +2 + 1 – 5 + 2
0 + 2 + 3 – 2 (x – 1) oR k/r]`
+ 2 + 3 – 2 0
2x2 + 3x – 2 <p.p. – 4 $. p. + 3
= 2x2 – 1x + 4x – 2 – +
= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)
= X (2X – 1) + 2 (X+2)
= (2X – 1) (X + 2)
k/r]`kqf = (X – 1) (X + 2) (2X – 1)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+ +2 + 1 – 5 + 2
0 + 2 + 3 – 2 (x – 1) oR k/r]`
+ 2 + 3 – 2 0
2x2 + 3x – 2 <p.p. – 4 $. p. + 3
= 2x2 – 1x + 4x – 2 – +
= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)
= X (2X – 1) + 2 (X+2)
= (2X – 1) (X + 2)
k/r]`kqf = (X – 1) (X + 2) (2X – 1)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+ 1 +2 + 1 – 5 + 2
0 + 2 + 3 – 2 (x – 1) oR k/r]`
+ 2 + 3 – 2 0
2x2 + 3x – 2 <p.p. – 4 $. p. + 3
= 2x2 – 1x + 4x – 2 – +
= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)
= X (2X – 1) + 2 (X+2)
= (2X – 1) (X + 2)
k/r]`kqf = (X – 1) (X + 2) (2X – 1)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+ 1 +2 + 1 – 5 + 2
0 + 2 + 3 – 2 (x – 1) oR k/r]`
+ 2 + 3 – 2 0
2x2 + 3x – 2 <p.p. – 4 $. p. + 3
= 2x2 – 1x + 4x – 2 – +
= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)
= X (2X – 1) + 2 (X+2)
= (2X – 1) (X + 2)
k/r]`kqf = (X – 1) (X + 2) (2X – 1)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+ 1 +2 + 1 – 5 + 2
0 + 2 + 3 – 2 (x – 1) oR k/r]`
+ 2 + 3 – 2 0
2x2 + 3x – 2 <p.p. – 4 $. p. + 3
= 2x2 – 1x + 4x – 2 – +
= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)
= X (2X – 1) + 2 (X+2)
= (2X – 1) (X + 2)
k/r]`kqf = (X – 1) (X + 2) (2X – 1)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+ 1 +2 + 1 – 5 + 2
0 + 2 + 3 – 2 (x – 1) oR k/r]`
+ 2 + 3 – 2 0
2x2 + 3x – 2 <p.p. – 4 $. p. + 3
= 2x2 – 1x + 4x – 2 – +
= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)
= X (2X – 1) + 2 (X+2)
= (2X – 1) (X + 2)
k/r]`kqf = (X – 1) (X + 2) (2X – 1)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+ 1 +2 + 1 – 5 + 2
0 + 2 + 3 – 2 (x – 1) oR k/r]`
+ 2 + 3 – 2 0
2x2 + 3x – 2 <p.p. – 4 $. p. + 3
= 2x2 – 1x + 4x – 2 – +
= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)
= X (2X – 1) + 2 (X+2)
= (2X – 1) (X + 2)
k/r]`kqf = (X – 1) (X + 2) (2X – 1)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+ 1 +2 + 1 – 5 + 2
0 + 2 + 3 – 2 (x – 1) oR k/r]`
+ 2 + 3 – 2 0
2x2 + 3x – 2 <p.p. – 4 $. p. + 3
= 2x2 – 1x + 4x – 2 – +
= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)
= X (2X – 1) + 2 (X+2)
= (2X – 1) (X + 2)
k/r]`kqf = (X – 1) (X + 2) (2X – 1)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+ 1 +2 + 1 – 5 + 2
0 + 2 + 3 – 2 (x – 1) oR k/r]`
+ 2 + 3 – 2 0
2x2 + 3x – 2 <p.p. – 4 $. p. + 3
= 2x2 – 1x + 4x – 2 – +
= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)
= X (2X – 1) + 2 (X+2)
= (2X – 1) (X + 2)
k/r]`kqf = (X – 1) (X + 2) (2X – 1)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+ 1 +2 + 1 – 5 + 2
0 + 2 + 3 – 2 (x – 1) oR k/r]`
+ 2 + 3 – 2 0
2x2 + 3x – 2 <p.p. – 4 $. p. + 3
= 2x2 – 1x + 4x – 2 – +
= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)
= X (2X – 1) + 2 (X+2)
= (2X – 1) (X + 2)
k/r]`kqf = (X – 1) (X + 2) (2X – 1)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+ 1 +2 + 1 – 5 + 2
0 + 2 + 3 – 2 (x – 1) oR k/r]`
+ 2 + 3 – 2 0
2x2 + 3x – 2 <p.p. – 4 $. p. + 3
= 2x2 – 1x + 4x – 2 – +
= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)
= X (2X – 1) + 2 (X+2)
= (2X – 1) (X + 2)
k/r]`kqf = (X – 1) (X + 2) (2X – 1)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+ 1 +2 + 1 – 5 + 2
0 + 2 + 3 – 2 (x – 1) oR k/r]`
+ 2 + 3 – 2 0
2x2 + 3x – 2 <p.p. – 4 $. p. + 3
= 2x2 – 1x + 4x – 2 – +
= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)
= X (2X – 1) + 2 (X+2)
= (2X – 1) (X + 2)
k/r]`kqf = (X – 1) (X + 2) (2X – 1)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+ 1 +2 + 1 – 5 + 2
0 + 2 + 3 – 2 (x – 1) oR k/r]`
+ 2 + 3 – 2 0
2x2 + 3x – 2 <p.p. – 4 $. p. + 3
= 2x2 – 1x + 4x – 2 – +
= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)
= X (2X – 1) + 2 (X+2)
= (2X – 1) (X + 2)
k/r]`kqf = (X – 1) (X + 2) (2X – 1)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+ 1 +2 + 1 – 5 + 2
0 + 2 + 3 – 2 (x – 1) oR k/r]`
+ 2 + 3 – 2 0
2x2 + 3x – 2 <p.p. – 4 $. p. + 3
= 2x2 – 1x + 4x – 2 – +
= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)
= X (2X – 1) + 2 (X+2)
= (2X – 1) (X + 2)
k/r]`kqf = (X – 1) (X + 2) (2X – 1)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+ 1 +2 + 1 – 5 + 2
0 + 2 + 3 – 2 (x – 1) oR k/r]`
+ 2 + 3 – 2 0
2x2 + 3x – 2 <p.p. – 4 $. p. + 3
= 2x2 – 1x + 4x – 2 – +
= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)
= X (2X – 1) + 2 (X+2)
= (2X – 1) (X + 2)
k/r]`kqf = (X – 1) (X + 2) (2X – 1)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+ 1 +2 + 1 – 5 + 2
0 + 2 + 3 – 2 (x – 1) oR k/r]`
+ 2 + 3 – 2 0
2x2 + 3x – 2 <p.p. – 4 $. p. + 3
= 2x2 – 1x + 4x – 2 – +
= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)
= X (2X – 1) + 2 (X+2)
= (2X – 1) (X + 2)
k/r]`kqf = (X – 1) (X + 2) (2X – 1)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+ 1 +2 + 1 – 5 + 2
0 + 2 + 3 – 2 (x – 1) oR k/r]`
+ 2 + 3 – 2 0
2x2 + 3x – 2 <p.p. – 4 $. p. + 3
= 2x2 – 1x + 4x – 2 – +
= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)
= X (2X – 1) + 2 (X+2)
= (2X – 1) (X + 2)
k/r]`kqf = (X – 1) (X + 2) (2X – 1)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+ 1 +2 + 1 – 5 + 2
0 + 2 + 3 – 2 (x – 1) oR k/r]`
+ 2 + 3 – 2 0
2x2 + 3x – 2 <p.p. – 4 $. p. + 3
= 2x2 – 1x + 4x – 2 – +
= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)
= X (2X – 1) + 2 (X+2)
= (2X – 1) (X + 2)
k/r]`kqf = (X – 1) (X + 2) (2X – 1)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+ 1 +2 + 1 – 5 + 2
0 + 2 + 3 – 2 (x – 1) oR k/r]`
+ 2 + 3 – 2 0
2x2 + 3x – 2 <p.p. – 4 $. p. + 3
= 2x2 – 1x + 4x – 2 – +
= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)
= X (2X – 1) + 2 (2X – 1)
= (2X – 1) (X + 2)
k/r]`kqf = (X – 1) (X + 2) (2X – 1)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+ 1 +2 + 1 – 5 + 2
0 + 2 + 3 – 2 (x – 1) oR k/r]`
+ 2 + 3 – 2 0
2x2 + 3x – 2 <p.p. – 4 $. p. + 3
= 2x2 – 1x + 4x – 2 – +
= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)
= X (2X – 1) + 2 (2X – 1)
= (2X – 1) (X + 2)
k/r]`kqf = (X – 1) (X + 2) (2X – 1)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+ 1 +2 + 1 – 5 + 2
0 + 2 + 3 – 2 (x – 1) oR k/r]`
+ 2 + 3 – 2 0
2x2 + 3x – 2 <p.p. – 4 $. p. + 3
= 2x2 – 1x + 4x – 2 – +
= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)
= X (2X – 1) + 2 (2X – 1)
= (2X – 1) (X + 2)
k/r]`kqf = (X – 1) (X + 2) (2X – 1)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+ 1 +2 + 1 – 5 + 2
0 + 2 + 3 – 2 (x – 1) oR k/r]`
+ 2 + 3 – 2 0
2x2 + 3x – 2 <p.p. – 4 $. p. + 3
= 2x2 – 1x + 4x – 2 – +
= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)
= X (2X – 1) + 2 (2X – 1)
= (2X – 1) (X + 2)
k/r]`kqf = (X – 1) (X + 2) (2X – 1)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+ 1 +2 + 1 – 5 + 2
0 + 2 + 3 – 2 (x – 1) oR k/r]`
+ 2 + 3 – 2 0
2x2 + 3x – 2 <p.p. – 4 $. p. + 3
= 2x2 – 1x + 4x – 2 – +
= (2 x X x X) – (1 x X) + (2x2xX) – (1 x 2) – 1 + 4 (+ 3)
= X (2X – 1) + 2 (2X – 1)
= (2X – 1) (X + 2)
k/r]`kqf = (X – 1) (X + 2) (2X – 1)