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Distributed Online Data Aggregation in Dynamic Graphs

bramas@unistra.fr

Quentin Bramas, Toshimitsu Masuzawa, and Sébastien Tixeuil

NETYS 2019, Marrakech, June, 21st

Data Aggregation Problem 2

3

Data Aggregation Problem

4

Data Aggregation Problem

5

Data Aggregation Problem

6

Data Aggregation Problem

7

Data Aggregation Problem

8

Data Aggregation Problem

9

Data Aggregation Problem

10

Data Aggregation Problem

11

Data Aggregation Problem

12

Data Aggregation Problem

Each node transmits at most once.

The goal: to minimize the duration

13

Data Aggregation Problem

14

Data Aggregation Problem

15

Data Aggregation Problem

16

Data Aggregation Problem

17

Data Aggregation Problem

18

Dynamic Data Aggregation Problem

18

Dynamic Data Aggregation Problem

We consider a dynamic network with pairwise interactions

s

32

15

4

t = 0 1 2 3

18

Dynamic Data Aggregation Problem

We consider a sequence of interactions

We consider a dynamic network with pairwise interactions

s

32

15

4

t = 0 1 2 3

18

Dynamic Data Aggregation Problem

We consider a sequence of interactions

A node can transmit only once

We consider a dynamic network with pairwise interactions

s

32

15

4

t = 0 1 2 3

18

Dynamic Data Aggregation Problem

We consider a sequence of interactions

A node can transmit only once

Nodes may or may not have other information

We consider a dynamic network with pairwise interactions

s

32

15

4

t = 0 1 2 3

18

Dynamic Data Aggregation Problem

We consider a sequence of interactions

A node can transmit only once

Nodes may or may not have other information

The goal is to aggregate all the data with

minimum duration

We consider a dynamic network with pairwise interactions

s

32

15

4

t = 0 1 2 3

Distributed Online Data Aggregation 19

We consider a dynamic network with pairwise interactions

s

32

15

4

t = 0 1 2 3

Distributed Online Data Aggregation 19

We consider a dynamic network with pairwise interactions

s

32

15

4

A Distributed Online Data Aggregation (DODA) Algorithm answers the question: Which node transmits?

t = 0 1 2 3

Distributed Online Data Aggregation 19

We consider a dynamic network with pairwise interactions

s

32

15

4

a

b

A Distributed Online Data Aggregation (DODA) Algorithm answers the question: Which node transmits?

t = 0 1 2 3

Distributed Online Data Aggregation 19

We consider a dynamic network with pairwise interactions

s

32

15

4

a

b

a transmits or b transmits or no one transmits

(a node can transmit only once)

A Distributed Online Data Aggregation (DODA) Algorithm answers the question: Which node transmits?

t = 0 1 2 3

has data 1 2 3 4

has transmitted

Distributed Online Data Aggregation

1

2

20

t = 0 1 2 3 4 5 6

has data 2(1) 3 4

has transmitted 1

Distributed Online Data Aggregation

1

2

20

t = 0 1 2 3 4 5 6

has data 2(1) 3 4

has transmitted 1

Distributed Online Data Aggregation

1

2

3

4

20

t = 0 1 2 3 4 5 6

has data 2(1) 3 4

has transmitted 1

Distributed Online Data Aggregation

1

2

1

3

3

4

20

t = 0 1 2 3 4 5 6

has data 2(1) 3 4

has transmitted 1

Distributed Online Data Aggregation

1

2

1

3

3

4

s

1

20

t = 0 1 2 3 4 5 6

has data 2(1) 3 4

has transmitted 1

Distributed Online Data Aggregation

1

2

1

3

2

3

3

4

s

1

20

t = 0 1 2 3 4 5 6

has data 2(1,3) 4

has transmitted 1 3

Distributed Online Data Aggregation

1

2

1

3

2

3

3

4

s

1

20

t = 0 1 2 3 4 5 6

has data 2(1,3) 4

has transmitted 1 3

Distributed Online Data Aggregation

1

2

1

3

2

3

2

4

3

4

s

1

20

t = 0 1 2 3 4 5 6

has data 2(1,3,4)

has transmitted 1 3 4

Distributed Online Data Aggregation

1

2

1

3

2

3

2

4

3

4

s

1

20

t = 0 1 2 3 4 5 6

has data 2(1,3,4)

has transmitted 1 3 4

Distributed Online Data Aggregation

1

2

1

3

2

3

2

4

3

4

s

1

s

2

20

t = 0 1 2 3 4 5 6

has data

has transmitted 1 2 3 4

Distributed Online Data Aggregation

1

2

1

3

2

3

2

4

3

4

s

1

s

2

20

t = 0 1 2 3 4 5 6

How to evaluate the performance of a DODA? 21

Is the duration of the aggregation is significant ?

How to evaluate the performance of a DODA? 21

Is the duration of the aggregation is significant ? No

How to evaluate the performance of a DODA? 21

Is the duration of the aggregation is significant ?

Even the offline optimal algorithm will struggle in the sequence:

1

2

1

2

1

2

1

2

1

2

1

2

1

2

1

2

No

How to evaluate the performance of a DODA? 22

Is the duration of the aggregation significant ? No

Is the ratio between the duration of the aggregation and the duration of the offline optimal algorithm significant ?

How to evaluate the performance of a DODA? 22

Is the duration of the aggregation significant ? No

Is the ratio between the duration of the aggregation and the duration of the offline optimal algorithm significant ?

No

How to evaluate the performance of a DODA? 22

Is the duration of the aggregation significant ? No

Is the ratio between the duration of the aggregation and the duration of the offline optimal algorithm significant ?

No

Each algorithm is either optimal or does not terminates in the sequence:

1

2

1

2

1

2

1

2

1

2

1

2

1

2

1

2

s

1

optimal duration = a convergecast

}

23

How to evaluate the performance of a DODA?

Definition of costI(A), for an algorithm A in a sequence I :

23

How to evaluate the performance of a DODA?

Definition of costI(A), for an algorithm A in a sequence I :

}

convergecast

23

How to evaluate the performance of a DODA?

Definition of costI(A), for an algorithm A in a sequence I :

}

convergecast

}

convergecast (starting after the previous one)

23

How to evaluate the performance of a DODA?

Definition of costI(A), for an algorithm A in a sequence I :

}

convergecast

}

convergecast (starting after the previous one)

}convergecast

}convergecast

}

convergecast

23

How to evaluate the performance of a DODA?

Definition of costI(A), for an algorithm A in a sequence I :

}

convergecast

}

convergecast (starting after the previous one)

}convergecast

}convergecast

}

convergecast

execution of A

23

How to evaluate the performance of a DODA?

Definition of costI(A), for an algorithm A in a sequence I :

}

convergecast

}

convergecast (starting after the previous one)

}convergecast

}convergecast

}

convergecast

execution of A

costI(A) = 4

24

How to evaluate the performance of a DODA?

Definition of the costI(A) function, for an algorithm A in a sequence I :

} } }convergecast

A does not terminate

costI(A) = 4

no more convergecast convergecast convergecast

25

How to evaluate the performance of a DODA?

Definition of the costI(A) function, for an algorithm A in a sequence I :

} } }convergecast

A does not terminate

costI(A) =∞

infinitely many convergecasts

convergecast convergecast }

convergecast

26

Distributed Online Data Aggregation

s

32

15

4

t = 0 1 2 3

26

Distributed Online Data Aggregation

s

32

15

4

Who generates the sequence?

t = 0 1 2 3

26

Distributed Online Data Aggregation

An adversary

s

32

15

4

Who generates the sequence?

t = 0 1 2 3

26

Distributed Online Data Aggregation

An adversary

Three adversaries:

s

32

15

4

Who generates the sequence?

t = 0 1 2 3

26

Distributed Online Data Aggregation

An adversary

Three adversaries:

s

32

15

4

Who generates the sequence?

t = 0 1 2 3

- Online Adaptive: generates the next interaction based on what happened in the past

26

Distributed Online Data Aggregation

An adversary

Three adversaries:

s

32

15

4

Who generates the sequence?

t = 0 1 2 3

- Online Adaptive: generates the next interaction based on what happened in the past

- Oblivious: generates the sequence before the execution of the algorithm

26

Distributed Online Data Aggregation

An adversary

Three adversaries:

s

32

15

4

Who generates the sequence?

t = 0 1 2 3

- Online Adaptive: generates the next interaction based on what happened in the past

- Oblivious: generates the sequence before the execution of the algorithm

- Randomized: each interaction is chosen uniformly at random.

Impossibility Results - Online Adaptive Adversary 27

- Online Adaptive: generates the next interaction based on what the algorithm decides in the current interaction

Let A be a DODA

Impossibility Results - Online Adaptive Adversary 27

- Online Adaptive: generates the next interaction based on what the algorithm decides in the current interaction

s

1

Let A be a DODA

Impossibility Results - Online Adaptive Adversary 27

- Online Adaptive: generates the next interaction based on what the algorithm decides in the current interaction

s

1

1 transmitsLet A be a DODA

Impossibility Results - Online Adaptive Adversary 27

- Online Adaptive: generates the next interaction based on what the algorithm decides in the current interaction

s

1

1 transmits 1

2

s

1

Let A be a DODA

Impossibility Results - Online Adaptive Adversary 27

- Online Adaptive: generates the next interaction based on what the algorithm decides in the current interaction

s

1

1 transmits 1

2

s

1s

2

Let A be a DODA

Impossibility Results - Online Adaptive Adversary 27

- Online Adaptive: generates the next interaction based on what the algorithm decides in the current interaction

s

1

1 transmits 1

2

s

1s

2

2 transmits

Let A be a DODA

Impossibility Results - Online Adaptive Adversary 27

- Online Adaptive: generates the next interaction based on what the algorithm decides in the current interaction

s

1

1 transmits 1

2

s

1s

2

2 transmits2

1

s

2

Let A be a DODA

Impossibility Results - Online Adaptive Adversary 27

- Online Adaptive: generates the next interaction based on what the algorithm decides in the current interaction

s

1

1 transmits 1

2

s

1s

2

2 transmits2

1

s

2otherwise

Let A be a DODA

Impossibility Results - Online Adaptive Adversary 27

- Online Adaptive: generates the next interaction based on what the algorithm decides in the current interaction

s

1

1 transmits 1

2

s

1s

2

2 transmits2

1

s

2otherwise

Let A be a DODA

A never terminates

Impossibility Results - Online Adaptive Adversary 27

- Online Adaptive: generates the next interaction based on what the algorithm decides in the current interaction

s

1

1 transmits 1

2

s

1s

2

2 transmits2

1

s

2otherwise

Starting from any time t, the aggregation is always possible, so:

Let A be a DODA

A never terminates

Impossibility Results - Online Adaptive Adversary 27

- Online Adaptive: generates the next interaction based on what the algorithm decides in the current interaction

s

1

1 transmits 1

2

s

1s

2

2 transmits2

1

s

2otherwise

Starting from any time t, the aggregation is always possible, so:

cost(A) = ∞

Let A be a DODA

A never terminates

Impossibility Results - Online Adaptive Adversary 28

Impossibility Results - Online Adaptive Adversary 28

Theorem: If k transmissions are allowed per node, there exists an online adaptive adversary that generates for every DODA A a sequence I such that costI(A)=∞

Impossibility Results - Online Adaptive Adversary 28

Theorem: If k transmissions are allowed per node, there exists an online adaptive adversary that generates for every DODA A a sequence I such that costI(A)=∞

Corollary: If k transmissions are allowed per node, there exists an oblivious adversary that generates for every deterministic DODA A a sequence I such that costI(A)=∞

Impossibility Results - Online Adaptive Adversary 28

Theorem: If k transmissions are allowed per node, there exists an online adaptive adversary that generates for every DODA A a sequence I such that costI(A)=∞

Corollary: If k transmissions are allowed per node, there exists an oblivious adversary that generates for every deterministic DODA A a sequence I such that costI(A)=∞

What about randomized DODA algorithms against an oblivious adversary?

Impossibility Results - Oblivious Adversary 29

Theorem: If k transmissions are allowed per node, there exists an oblivious adversary that generates for every oblivious DODA A a sequence I such that costI(A)=∞ with high probability

What about randomized DODA algorithms against an oblivious adversary?

Impossibility Results - Oblivious Adversary 29

Theorem: If k transmissions are allowed per node, there exists an oblivious adversary that generates for every oblivious DODA A a sequence I such that costI(A)=∞ with high probability

proof: not trivial

What about randomized DODA algorithms against an oblivious adversary?

Impossibility Results - Oblivious Adversary 30

sketch of proof, for k=1

Impossibility Results - Oblivious Adversary 30

s

1

s

2

s

n

sketch of proof, for k=1

Impossibility Results - Oblivious Adversary 30

s

1

s

2

s

n

s

1

s

2

s

n

sketch of proof, for k=1

Impossibility Results - Oblivious Adversary 30

s

1

s

2

s

n

s

1

s

2

s

n

sketch of proof, for k=1

Pt = probability that no node transmits before time t

Impossibility Results - Oblivious Adversary 30

s

1

s

2

s

n

s

1

s

2

s

n

sketch of proof, for k=1

Pt = probability that no node transmits before time tlemma: if Pt > 1/n then there exists a node u that has not transmitted w.h.p.

Impossibility Results - Oblivious Adversary 30

s

1

s

2

s

n

s

1

s

2

s

n

sketch of proof, for k=1

Pt = probability that no node transmits before time tlemma: if Pt > 1/n then there exists a node u that has not transmitted w.h.p.

if Pt > 1/n for all t, then it’s over

Impossibility Results - Oblivious Adversary 30

s

1

s

2

s

n

s

1

s

2

s

n

sketch of proof, for k=1

Pt = probability that no node transmits before time tlemma: if Pt > 1/n then there exists a node u that has not transmitted w.h.p.

if Pt > 1/n for all t, then it’s over , otherwise there is a time t0 such that:

Impossibility Results - Oblivious Adversary 30

s

1

s

2

s

n

s

1

s

2

s

n

sketch of proof, for k=1

Pt = probability that no node transmits before time tlemma: if Pt > 1/n then there exists a node u that has not transmitted w.h.p.

if Pt > 1/n for all t, then it’s over , otherwise there is a time t0 such that:• Pt0 -1 > 1/n • Pt0 ≤1/n

Impossibility Results - Oblivious Adversary 30

s

1

s

2

s

n

s

1

s

2

s

n

sketch of proof, for k=1

Pt = probability that no node transmits before time tlemma: if Pt > 1/n then there exists a node u that has not transmitted w.h.p.

if Pt > 1/n for all t, then it’s over

t0

s

1

s

2

s

n

s

1

s

2

s

n

… …

, otherwise there is a time t0 such that:• Pt0 -1 > 1/n • Pt0 ≤1/n

Impossibility Results - Oblivious Adversary 30

s

1

s

2

s

n

s

1

s

2

s

n

sketch of proof, for k=1

Pt = probability that no node transmits before time tlemma: if Pt > 1/n then there exists a node u that has not transmitted w.h.p.

if Pt > 1/n for all t, then it’s over

t0

s

1

s

2

s

n

s

1

s

2

s

n

… …

, otherwise there is a time t0 such that: : one node u has not transmitted w.h.p.• Pt0 -1 > 1/n

• Pt0 ≤1/n

Impossibility Results - Oblivious Adversary 30

s

1

s

2

s

n

s

1

s

2

s

n

sketch of proof, for k=1

Pt = probability that no node transmits before time tlemma: if Pt > 1/n then there exists a node u that has not transmitted w.h.p.

if Pt > 1/n for all t, then it’s over

t0

s

1

s

2

s

n

s

1

s

2

s

n

… …

, otherwise there is a time t0 such that: : one node u has not transmitted w.h.p.• Pt0 -1 > 1/n

• Pt0 ≤1/n : one node has transmitted w.h.p.

Impossibility Results - Oblivious Adversary 30

s

1

s

2

s

n

s

1

s

2

s

n

sketch of proof, for k=1

Pt = probability that no node transmits before time tlemma: if Pt > 1/n then there exists a node u that has not transmitted w.h.p.

if Pt > 1/n for all t, then it’s over

t0

s

1

s

2

s

n

s

1

s

2

s

n

… …

n

u

n-1

n

s

1

, otherwise there is a time t0 such that: : one node u has not transmitted w.h.p.• Pt0 -1 > 1/n

• Pt0 ≤1/n : one node has transmitted w.h.p.

Impossibility Results - Oblivious Adversary 30

s

1

s

2

s

n

s

1

s

2

s

n

sketch of proof, for k=1

Pt = probability that no node transmits before time tlemma: if Pt > 1/n then there exists a node u that has not transmitted w.h.p.

if Pt > 1/n for all t, then it’s over

t0

s

1

s

2

s

n

s

1

s

2

s

n

… …

n

u

n-1

n

s

1

n

u

n-1

n

s

1

, otherwise there is a time t0 such that: : one node u has not transmitted w.h.p.• Pt0 -1 > 1/n

• Pt0 ≤1/n : one node has transmitted w.h.p.

Impossibility Results - Oblivious Adversary 31

sketch of proof, for k>1

require nk nodes

Ik-1

Ik-1

Ik-1

Each group of nodes acts like a node that can transmit only once

Impossibility Results - Oblivious Adversary 32

What about randomized DODA algorithms against oblivious adversary?

Theorem: If k transmissions are allowed per node, there exists an oblivious adversary that generate for every oblivious DODA A a sequence I such that costI(A)=∞ with high probability

Impossibility Results - Oblivious Adversary 32

What about randomized DODA algorithms against oblivious adversary?

Theorem: If k transmissions are allowed per node, there exists an oblivious adversary that generate for every oblivious DODA A a sequence I such that costI(A)=∞ with high probability

What about non-oblivious randomized DODA algorithms against oblivious adversary?

Impossibility Results - Oblivious Adversary 32

What about randomized DODA algorithms against oblivious adversary?

Theorem: If k transmissions are allowed per node, there exists an oblivious adversary that generate for every oblivious DODA A a sequence I such that costI(A)=∞ with high probability

What about non-oblivious randomized DODA algorithms against oblivious adversary?

open question

DODA against randomized adversary

34

DODA against randomized adversary

If you have no information about the future, always transmit is optimal. It takes O(n2) interactions in average.

If you know everything about the future, it takes O(nlog(n)) interactions in average.

35

DODA against randomized adversary

35

DODA against randomized adversary

The meetTime information: each node knows when will be its next interaction with the sink

35

DODA against randomized adversary

The meetTime information: each node knows when will be its next interaction with the sink

1

meetTime = 3

2

meetTime = 6

36

DODA against randomized adversary

Greedy Algorithm: if I meet the sink after the other node, then I transmit my data

36

DODA against randomized adversary

Greedy Algorithm: if I meet the sink after the other node, then I transmit my data

1

meetTime = 3

2

meetTime = 5

36

DODA against randomized adversary

Greedy Algorithm: if I meet the sink after the other node, then I transmit my data

1

meetTime = 3

2

meetTime = 5

37

DODA against randomized adversary

-Waiting Greedy Algorithm: if at least one of the nodes has meetTime > , then we apply Greedy Algorithm

37

DODA against randomized adversary

-Waiting Greedy Algorithm: if at least one of the nodes has meetTime > , then we apply Greedy Algorithm

1

meetTime = 3

2

meetTime = 5=10

37

DODA against randomized adversary

-Waiting Greedy Algorithm: if at least one of the nodes has meetTime > , then we apply Greedy Algorithm

1

meetTime = 3

2

meetTime = 5

1

meetTime = 3

2

meetTime = 15

=10

37

DODA against randomized adversary

-Waiting Greedy Algorithm: if at least one of the nodes has meetTime > , then we apply Greedy Algorithm

1

meetTime = 3

2

meetTime = 5

1

meetTime = 3

2

meetTime = 15

=10

37

DODA against randomized adversary

-Waiting Greedy Algorithm: if at least one of the nodes has meetTime > , then we apply Greedy Algorithm

1

meetTime = 3

2

meetTime = 5

1

meetTime = 3

2

meetTime = 15

=10

1

meetTime = 13

2

meetTime = 15

37

DODA against randomized adversary

-Waiting Greedy Algorithm: if at least one of the nodes has meetTime > , then we apply Greedy Algorithm

1

meetTime = 3

2

meetTime = 5

1

meetTime = 3

2

meetTime = 15

=10

1

meetTime = 13

2

meetTime = 15

37

DODA against randomized adversary

-Waiting Greedy Algorithm: if at least one of the nodes has meetTime > , then we apply Greedy Algorithm

1

meetTime = 3

2

meetTime = 5

1

meetTime = 3

2

meetTime = 15

=10

1

meetTime = 13

2

meetTime = 15

1

meetTime = 7

s

38

DODA against randomized adversary

n√n log(n)-Waiting Greedy Algorithm is optimal

-Waiting Greedy Algorithm: if at least one of the nodes has meetTime > , then we apply Greedy Algorithm

38

DODA against randomized adversary

n√n log(n)-Waiting Greedy Algorithm is optimal

Without knowledge: 𝞗(n2) interactions in average

-Waiting Greedy Algorithm: if at least one of the nodes has meetTime > , then we apply Greedy Algorithm

38

DODA against randomized adversary

n√n log(n)-Waiting Greedy Algorithm is optimal

Without knowledge: 𝞗(n2) interactions in average

With full knowledge: 𝞗(n log(n)) interactions w.h.p.

-Waiting Greedy Algorithm: if at least one of the nodes has meetTime > , then we apply Greedy Algorithm

38

DODA against randomized adversary

n√n log(n)-Waiting Greedy Algorithm is optimal

Without knowledge: 𝞗(n2) interactions in average

With full knowledge: 𝞗(n log(n)) interactions w.h.p.

meetTime information: 𝞗(n√n log(n)) interactions w.h.p.

-Waiting Greedy Algorithm: if at least one of the nodes has meetTime > , then we apply Greedy Algorithm

Conclusion 39

Conclusion 39

Online Data Aggregation: - hard in general - optimal algorithms exist in randomized networks

Conclusion 39

Perspective

Online Data Aggregation: - hard in general - optimal algorithms exist in randomized networks

Conclusion 39

Perspective

Online Data Aggregation: - hard in general - optimal algorithms exist in randomized networks

More realistic networks?

Conclusion 40

Perspective

Online Data Aggregation: - hard in general - optimal algorithms exist in randomized networks

More realistic networks?

Thank you for your attention!

quentin.bramas@lip6.fr

Impossibility Results - Online Adaptive Adversary 41

What if nodes are allowed to transmit more than once?

s

1

1

2

1 transmits s

1s

2

2 transmits2

1

s

2otherwise

Starting from any time t, the aggregation is always possible, so:

cost(A) = ∞

Let A be a DODA

Impossibility Results - Online Adaptive Adversary 42

What if nodes are allowed to transmit more than once?

s

1

1

2

s

1

s

2

1

2

s

1

Impossibility Results - Online Adaptive Adversary 43

What if nodes are allowed to transmit more than once?

s’

1

1

2

s’

1

s’

2

1

2

s’

1

Impossibility Results - Online Adaptive Adversary 43

What if nodes are allowed to transmit more than once?

s’

1

1

2

s’

1

s’

2

1

2

s’

1

s’

s

Impossibility Results - Online Adaptive Adversary 43

What if nodes are allowed to transmit more than once?

s’

1

1

2

s’

1

s’

2

1

2

s’

1

s’

s

s’

s

Impossibility Results - Online Adaptive Adversary 43

What if nodes are allowed to transmit more than once?

s’

1

1

2

s’

1

s’

2

1

2

s’

1

s’

s

s’

s

s’

s

Impossibility Results - Online Adaptive Adversary 43

What if nodes are allowed to transmit more than once?

s’

1

1

2

s’

1

s’

2

1

2

s’

1

s’

s

s’

s

s’

s

s’

s

Impossibility Results - Online Adaptive Adversary 43

What if nodes are allowed to transmit more than once?

s’

1

1

2

s’

1

s’

2

1

2

s’

1

s’

s

s’

s

s’

s

s’

s

s’

s

Impossibility Results - Online Adaptive Adversary 43

What if nodes are allowed to transmit more than once?

s’

1

1

2

s’

1

s’

2

1

2

s’

1

s’

s

s’

s

s’

s

s’

s

s’

s

s’

s

Impossibility Results - Online Adaptive Adversary 43

What if nodes are allowed to transmit more than once?

s’

1

1

2

s’

1

s’

2

1

2

s’

1

s’

s

s’

s

s’

s

s’

s

s’

s

s’

s

if s’ owns all the data:

Impossibility Results - Online Adaptive Adversary 43

What if nodes are allowed to transmit more than once?

s’

1

1

2

s’

1

s’

2

1

2

s’

1

s’

s

s’

s

s’

s

s’

s

s’

s

s’

s

if s’ owns all the data:

then, a node has transmitted twice

Impossibility Results - Online Adaptive Adversary 43

What if nodes are allowed to transmit more than once?

s’

1

1

2

s’

1

s’

2

1

2

s’

1

s’

s

s’

s

s’

s

s’

s

s’

s

s’

s

if s’ owns all the data:

then, a node has transmitted twice

and s does not own all the data

Impossibility Results - Online Adaptive Adversary 44

What if nodes are allowed to transmit more than once?

s’

1

1

2

s’

1

s’

2

s’

s

s’

s

s’

s

if s’ owns all the data:

then, a node has transmitted twice

and s does not own all the data

Impossibility Results - Online Adaptive Adversary 44

What if nodes are allowed to transmit more than once?

s’

1

1

2

s’

1

s’

2

s’

s

s’

s

s’

s

if s’ owns all the data:

then, a node has transmitted twice

1

2

1

s

1

s’

and s does not own all the data

Impossibility Results - Online Adaptive Adversary 44

What if nodes are allowed to transmit more than once?

s’

1

1

2

s’

1

s’

2

s’

s

s’

s

s’

s

if s’ owns all the data:

then, a node has transmitted twice

1

2

1

s

1

s’

and s will never own all the data

Impossibility Results - Online Adaptive Adversary 44

What if nodes are allowed to transmit more than once?

s’

1

1

2

s’

1

s’

2

s’

s

s’

s

s’

s

if s’ owns all the data:

then, a node has transmitted twice

1

2

1

s

1

s’

and s will never own all the data

yet a convergecast is always possible

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