antidifferentiation: the indefinite intergral chapter five
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Antidifferentiation: The Indefinite Intergral
Chapter Five
§5.1 Antidifferetiation
§5.1 General Antiderivative of a Function
§5.1 General Antiderivative of a Function
§5.1 Rules for Integrating Common Function
The Constant Rule
§5.1 Rules for Integrating Common Function
Example:
Solution:
§5.1 Applied Initial Value Problems
An initial Value problems is a problem that involves solving a differential equation subject to a specified initial condition. For instance, we were required to find y=f(x) so that
A Differential equation is an equation that involves differentials or derivatives.
We solved this initial problem by finding the antiderivative
And using the initial condition to evaluate C.
The population p(t) of a bacterial colony t hours after observation begins is found to be change at the rate
If the population was 2000,000 bacteria when observations began, what will be population 12 hours later?
Example:
Solution:
§5.2 Integration by Substitution
How to do the following integral?
§5.2 Integration by Substitution
Think of u=u(x) as a change of variable whose differential is
Then
Example:
Solution:
Find
Example:
Solution:
Example:
Solution:
To be continued
Example:
Solution:
Example:
Solution:
§5.3 The Definite Integral and the Fundamental Theorem of Calculus
All rectangles have same width.
• n subintervals:
• Subinterval width
•Formula for xi:
• Choice of n evaluation points
Right-endpoint approximation
left-endpoint approximation
Midpoint Approximation
Example:
=0.285
To be continued
=0.3325
=0.385
Example:
left-endpoint approximation
Midpoint Approximation
Right-endpoint approximation
00=1.098608585 =1.098611363
Area Under a Curve Let f(x) be continuous and satisfy f(x)≥0on the interval a≤x≤b. Then the region under the curve y=f(x)over the interval a≤x≤b has area
1 21
lim lim[ ( ) ( ) ... ( )] lim ( )n
n n jn n n
j
A S f x f x f x x f x x
Where xj is the point chosen from the jth subinterval if the Interval a≤x≤b is divided into n equal parts, each of length
b ax
n
§5.3 The Definite Integral
Riemann sum Let f(x) be a function that is continuous onthe interval a≤x≤b. Subdivide the interval a≤x≤b into n equal
parts, each of width ,and choose a number xk from the
kth subinterval for k=1, 2, …, . Form the sum
b ax
n
Called a Riemann sum.
Note: f(x)≥0 is not required
§5.3 The Definite Integral
The Definite Integral the definite integral of f on the interval
a≤x≤b, denoted by , is the limit of the Riemann sum asn→+∞; that is
b
af(x)dx
The function f(x) is called the integrand, and the numbers a and b are called the lower and upper limits of integration, respectively. The process of finding a definite integral is called definite integration.
Note: if f(x) is continuous on a≤x≤b, the limit used to define integral exist and is same regardless of how the subinterval representatives xk are chosen.
b
af(x)dx
§5.3 Area as Definite Integral
If f(x) is continuous and f(x)≥0 for all x in [a,b],then
( ) 0b
af x dx
and equals the area of the region bounded by the graph f and the x-axis between x=a and x=b
If f(x) is continuous and f(x)≤0 for all x in [a,b],then
( ) 0b
af x dx
And equals the area of the region bounded by the graph f and the x-axis between x=a and x=b
( )b
af x dx
§5.3 Area as Definite Integral
equals the difference between the area under the graph
of f above the x-axis and the area above the graph of f below the x-axis between x=a and x=b
This is the net area of the region bounded by the graph of f and the x-axis between x=a and x=b
( )b
af x dx
§5.3 The Fundamental Theorem of Calculus
The Fundamental Theorem of Calculus If the function f(x) is continuous on the interval a≤x≤b, then
( ) ( ) ( )b
af x dx F b F a
Where F(x) is any antiderivative of f(x) on a≤x≤b
Another notation:
( ) ( ) | ( ) ( )b b
aaf x dx F x F b F a
§5.3 The Fundamental Theorem of Calculus (Area justification )
In the case of f(X)≥0, represents the area the curve y=f(x) over the interval [a,b]. For fixed x between a and b let A(x) denote the area under y=f(x) over the interval [a,x].
( )b f x dxa
By the definition of the derivative,
Differentiation
Indefinite Integration
Definite integration
Example
§5.3 Integration Rule
Subdivision Rule
§5.3 Subdivision Rule
Example
Solution:
Example
Solution:
To be continued
§5.3 Substituting in a definite integral
23
3
222 3
300
1 1 2 21
3 3 31
2 41
3 31
xdx du u x
ux
xdx x
x
2.
§5.3 Substituting in a definite integral
Example
Solution:
Example
Solution:
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