4 map and compass and compass...rotate entire compass until orienteering lines in the compass...

Map and Compass

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Bearing:anangleindegreesmeasuredclockwisefromanorthreferencelinetoyourdestinationline.

Bearingof90°shownbelow.

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Bearingofappr.315°shownbelow.

Final Exam and Practice Map -provided in class -

Taking Map Bearing in - 3 Steps

• Whatisthebearingfromcenterof“C”inLakeCtocenterof“D”inLakeD?

Step 1 - Intersect two points with side edge of compass with direction of travel arrow pointing towards destination

Step 2 - Rotate compass housing until orienting lines align N-S, with north end of line pointing north. Ignore the magnetic needle!

Step 3 - read the bearing at index line (in line with direction of travel arrow).

• Whatisthebearingfromcenterof“D”inLakeDtocenterof“F”inLakeF?

Step 1 - Intersect two points with side edge of compass with direction of travel arrow pointing towards destination

Step 2 - Rotate compass housing until orienting lines align N-S, with north end of line pointing north. Ignore the magnetic needle!

Step 3 - read the bearing at index line (in line with direction of travel arrow).

index line

Depiction of 340° bearing (always measure clockwise from N).

• Bearingfromcenterof“F”inLakeFtosummitofPeak2= 266°

• BearingfromthesummitofPeak2tocampsite“Z”= 135°

• WhatistheelevationofPeak2? 5700’

• WhatistheelevationofCampsiteX? 3900’

• WhatistheelevationofLakeD? 4700’

• WhatisthenetelevationdifferencebetweenCampsitesYandZ?

CampsiteY=5100’ CampsiteZ=4700’ Netelevationdifference=400’

How many feet of elevation will you gain hiking SE along the trail from campsite Y to the top of Peak 4? How many feet will you lose?

A

Uphill from B to C

B

Downhill along trail from A to B

C

- +

4 8

- 4 x 200 = -800

+ 8 x 200= +1600

Net elevation diff = +800

Elevation of Y = 5100’

Elevation of 4 = 5900’

Net elev. difference = 800

What is the length of trail between Peak 5

and Peak 4?

What is the trail distance between Campsites Y and x?

2.8 miles

• Bearingfromcenterof“C”inLakeCtocenterof“D”inLakeD=62°TRUENORTHBEARING.

• WhatistheMNbearingifdeclinationis15°E?

x

x

62°

15°

47°

MN bearing = 47°

Bearingfromcenterof“D”inLakeDtocenterof“F”inLakeF=342°TN

Declination=15°E

x342°TN

15°

MN bearing = 327°

• WhenPLOTTINGABEARINGthemissingpieceofinformationisthedestinationpoint.

• Weknowourlocationandthebearingvalue.Here’sanexampleplottingproblem:

WhatfeatureliesataTNbearingof70°and1.65milesFROMcampsitex?

Plotting A Bearing

• Acompletedmapandcompassproblemconsistsof3piecesofinformation:

• startingpoint

• destinationpoint• bearing

• WhenTAKINGABEARINGweknowourstartingpointandthedestinationpoint.

• Wecalculatethebearingvalue.Forexample:

Whatisthebearingfromcenterof“C”inLakeCtocenterof“D”inLakeD?

Plotting A Bearing

WhatfeatureliesataTNbearingof70°and1.65milesFROMcampsitex? Step1?

Rotatecompasshousinguntil70°isatthe“readbearingheremarker”.

Intersectsideedgeofcompasswithpointx.SincebearingisFROMxtothefeature,placexnearbackendofcompass

Step2?

Step3RotateENTIRECOMPASSuntilorienteeringlinesinthecompasshousingareparalleltoN-Slinesonthemap.Makesurethattheorienteeringarrowpointsnorth,ANDtheedgeofthecompassintersectspointx.

Step4Usingthescalediagram,measure1.65linearmilesalongtheedgeofapieceofpaper.

Step5Placepieceofpaperwithdistancemarkersalongthesideedge.Thefeaturethatlies1.65milesatabearingof70°frompointxisPeak4.

• Whatfeatureliesatabearingof242°and1.92milesfromthesummitofPeak3?

Peak2

• Whatfeatureliesatabearingof63°and1.68milesfromthe“C”inLakeC?

Peak4

• Whatfeatureliesatabearingof302°and1.61milesfromtheCampsiteX?

Peak2

• Whatfeatureliesatabearingof150°and4.5milesfromtheCampsiteY?

CampsiteZ