air pollution control – part a cyclone – basic principles
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Air Pollution Control – Part A Cyclone – Basic Principles. Yaacov Mamane Visiting Scientist, CNR Rome, Italy. What is a Cyclone ?. Cyclone Performance for various Application. Standard Cyclone Dimensions. General guidelines: - PowerPoint PPT PresentationTRANSCRIPT
04/19/23
Air Pollution Control – Part A
Cyclone – Basic Principles
Yaacov MamaneVisiting Scientist, CNR
Rome, Italy
04/19/23
What is a CycloneWhat is a Cyclone?
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Cyclone Performance for various Application
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Standard Standard Cyclone Cyclone Dimensions Dimensions
General guidelines: H < S W < (D-De)/2 Lb+Lc > 3D Cone angle = 7o ~ 8o De/D = 0.4~0.5, (Lb+Lc)/De = 8, S/De = 1
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Conventional Cyclone
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Stokes Law Gravitational forces are balanced by
drag and buoyancy forces. This will lead to stokes law - settling
velocity of particles.
v
m p
d 3 = F
gd 6
= g
d
3p
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18 d g = v p2
t
WhereWhereg – gravity accelerationg – gravity accelerationd – particle diameterd – particle diameterrrpp – particle density – particle density
m - air viscositym - air viscosity
For example VFor example Vtt (1 (1 m) = 0.006 cm/sm) = 0.006 cm/s
When Fd = Fg the When Fd = Fg the settling velocity is settling velocity is given: as follows. given: as follows.
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r
v= w c
For a particle moving at high speed Vc in a circle, the centrifugal
acceleration is given by Vc*Vc/r. The centrifugal force is similar to the
gravity forces
mg = F , r
v m = F g
2c
c
But Fc >> Fg
The equivalent “settling velocity” of the
centrifugal forces is taken from Stokes
Law and is given by the following
Equation:
r
v g
2c
18 d
r
v v p2
2c
t
Vc
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18
kg/m 2000 m 10
m 3.0m/s 18.3
= v326-
2
t
= 1.8 10 kg
m s-5
vt = 0.68 cm/s
While Vt stokes is only 0.006 cm/s!!!
ExampleFor a particle of 1 m moving in a 0.3 diameter circle at 18.3 m/s:
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Settling ChamberSettling Chamber
Particle is entering a chamber at height h an horizontal speed V and settling velocity Vt, may fall inside the chamber. Time (Tl) to cross the chamber is L / V . Time (Th) to fall inside the chamber is h / Vt, thus we could define a collection efficiency = Tl / Th = L Vt / H V
H
L
W
hVt
v
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= L Vt / H V = L Vt / H V oror
= = L g dL g d2 2 pp / H V 18 / H V 18
ButBut V = Q / WH where V = Q / WH where QQ is the flow through the is the flow through the settling chamber, and thussettling chamber, and thus
= L g d= L g d22 pp / H V 18 / H V 18 = = L W g dL W g d22 pp / Q 18 / Q 18
= = L W g d L W g d22 pp / Q 18 / Q 18
This collection efficiency may be applied to a Cyclone This collection efficiency may be applied to a Cyclone wherewhereH and L of the chamberH and L of the chamber are equivalent to are equivalent to W and NW and NDD00 of a cyclone of a cyclone
The Collection Efficiency of a settling chamber used to collect large particles is given by the simple expression:
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18 v W
d g DN = p
2o
c
c
toc v
v
W
DN =
4W = Do = 2r
r 18
d v = v p
22c
t
Since a cyclone is an elongated settling chamber
2r 9 v W
d v2r N =
c
p22
c
= L V= L Vtt / H V for a cyclone may be written as: / H V for a cyclone may be written as:
For centrifugal forces
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W9
d v N = p
2c
lam
turb = 1 - exp - lam
Example:Example:
Calculate efficiency for a cyclone to collect 1 mm particles of density 1. Calculate efficiency for a cyclone to collect 1 mm particles of density 1.
Cyclone width – 15 cm, Vc – 18.3 m/s and N – 5.Cyclone width – 15 cm, Vc – 18.3 m/s and N – 5.
The efficiency is h = 0.023The efficiency is h = 0.023
And for a particle of 10 mm diameter h is larger than 1.And for a particle of 10 mm diameter h is larger than 1.
After rearranging the parameters the equation is now given by:
And for a turbulent flow it is then expressed by the general term:
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pccut Nv 2
W 9 = d
Where
Dcut - cut diameter in mm
- is viscosity
N - number of rotations
Vc - tangential velocity
p - particle density
W - entrance width of the cyclone
Let define a parameter of importance in particulate control, d cut , used to
describe the properties of the cyclone,
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Pressure Drop
Number of gas inlet velocity head
2e
v D
HWKH
Static pressure drop
vig HVP 2
2
1
Power requirement
PQw f K = 16 for normal tangential inlet = 7.5 for one with an inlet vane
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Number of effective turns
2
1 cbe
LL
HN
Gas residence time
ie VDNt /
Terminal velocity
D
VdtWV igpp
t
9
/
22
Smallest collected diameter
gpiep VN
Wd
9
Lapple Theory (laminar flow)
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50% cut size
gpiepc VN
Wd
2
9
The collection efficiency of any size dpj
2/1
1
pjpc
jdd
Overall efficiency
jj f
Penetration
1P Particle size ratio dp/dpc
(%)
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Licht Theory (turbulent flow)
1
1
exp1 npAd
1693.0
n
pc Ad
)1(2
1
318
)1(2
np
D
nKQA
1
1
693.0exp1n
pc
pjj d
d
3.0
14.0
28367.011
TDn (D in )
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Arrangement
Series
Parallel/Battery
Air Pollution Control Equipment, Theodore & Buonicore, CRC Press, 1988
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Discharge
Handbook of Air Pollution Control Engineering & Technology,Mycock, McKenna and Theodore, Lewis Publishers, 1995.
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Advantages & Disadvantages
Advantages: Low capital cost Ability to operate at high
temperatures Low maintenance
requirements because there are no moving parts
Disadvantages: Low efficiencies for fine
particles High operating costs (due to
pressure drop) Cyclones used for removing wood dust