aim: integrate inverse trig functions course: calculus do now: aim: how do we integrate inverse trig...
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Aim: Integrate Inverse Trig Functions Course: Calculus
Do Now:
Aim: How do we integrate Inverse Trig functions?
Complete the square, express as the sum of
two squares:
x2 + 4x + 7
Aim: Integrate Inverse Trig Functions Course: Calculus
Differentiation Pairs & Integration
2
'arccos
1
d uu
dx u
2
'arctan
1
d uu
dx u
2
'arccot
1
d uu
dx u
2
'arcsec
1
d uu
dx u u
2
'arccsc
1
d uu
dx u u
2
'arcsin
1
d uu
dx u
Integration will only require one formula for each pair.
Aim: Integrate Inverse Trig Functions Course: Calculus
Integrals of Inverse Trig Functions
2 2
2 2
2 2
Let be a differentiable function of , and let > 0
1. arcsin
12. arctan
13. arcsec
u x a
du uC
aa udu u
Ca u a a
uduC
a au u a
24
dx
x arcsin2
xC
Aim: Integrate Inverse Trig Functions Course: Calculus
Model Problems
41
xdx
x
u = x2 1a
2
1
2 1
du
u
2 2arcsin
du uC
aa u
2du x dx 1
2du x dx
1arcsin
2u C 1 21
sin2
x C
Aim: Integrate Inverse Trig Functions Course: Calculus
Model Problems
22 9
dx
x u = 3x
2a 2 2
1arctan
du uC
a u a a
2 2
1 3
3 2 3
dx
x
1 1 3arctan
3 2 2
xC
24 9
dx
x x
u = 2x
3a 2 2
1 2
2 2 2 3
dx
x x
21 1arcsec
2 3 3
xC
2 2
1arcsec
uduC
a au u a
du = 2dx
du = 3dx
Aim: Integrate Inverse Trig Functions Course: Calculus
Model Problem – Not Quite
2 1x
dx
e 2 2
2 2
2 2
1. arcsin
12. arctan
13. arcsec
du uC
aa udu u
Ca u a a
uduC
a au u a
u = ex
du = exdxdx = du/ex
21x
dx
e
2
/
1
du u
u
2 1
du
u u arcsec arcsec1
xuC e C
arcsin xe C
rewrite
substitute
= du/u
substitute/rewrite and back-substitute
Aim: Integrate Inverse Trig Functions Course: Calculus
Model Problem
2
2
4
xdx
x
2 2
2 2
2 2
1. arcsin
12. arctan
13. arcsec
du uC
aa udu u
Ca u a a
uduC
a au u a
Denominator is 1 term: split integrand
2 2
2
4 4
xdx dx
x x
1 22
2
1 12 4 2
2 4x x dx dx
x
1 2241
2arcsin2 1 2 2
x xC
24 2arcsin2
xx C
Aim: Integrate Inverse Trig Functions Course: Calculus
Completing the Square
sometimes: when quad functions in integrand
2 4 7
dxdx
x x
2 2
22 2
4 7 ( 4 4) 4 7
2 3 2 3
x x x x
x x
u2 + a2
2 2
dxdx
u a
2 2
1arctan
du uC
a u a a
22 4 7 2 3
dx dxdx dx
x x x
1 2arctan
3 3
xC
Aim: Integrate Inverse Trig Functions Course: Calculus
Model Problem
2
Find the area of the region bounded by
1the graph of ( ) the -axis
33 9
and the lines = and = .2 4
f x xx x
x x
9 4
23 2
1
3dx
x x
2 2
2 2
2 2
3 33 3
2 2
3 3
2 2
x x x x
x
2 2arcsin
du uC
aa u
a = 3/2
u = x - 3/2
Complete the square
Aim: Integrate Inverse Trig Functions Course: Calculus
Model Problem
2
Find the area of the region bounded by the graph of
1 3 9 ( ) the -axis and the lines = and = .
2 43f x x x x
x x
9 4
23 2
1
3dx
x x
a = 3/2; u = x - 3/22 2
arcsindu u
Caa u
9 4
23 2 2
1
3 2 3 2x
9 4
3 2
3 2 1arcsin arcsin arcsin0
3 2 2
0.5246
x