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  • 7/30/2019 AeroL40

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    SELF-EXCITED VIBRATION

    The force acting on a vibrating object is usually external to the

    system and independent of the motion. However, there aresystems in which the exciting force is a function of the motionvariables (displacement, velocity or acceleration) and thus varies

    with the motion it produces (called coupling). Friction-induced

    vibration (in vehicle clutches and brakes, vehicle-bridge

    interaction) and flow-induced vibration (circular wood saws, CDs,

    DVDs, in machining, fluid-conveying pipelines) are examples of

    self-excited vibration

    Example 1: a mass supported by a spring is carried by a moving

    belt through friction.

    The friction coefficient at the mass and belt interface is a function

    of the relative velocity between the mass and the belt as

    The equation of motion of the mass is

    m

    x

    v0

    v

    gradiant (>0)

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    xmgmgvmgvxmgkxxm 00000 )1()](1[ ++===+

    ormgvkxxmgxm )1( 000 +=+

    negative damping causing (initially) divergent vibration

    As vibration grows, velocity x and hence relative velocity 0vx .This causes the friction coefficient to decrease (see m v curve)and then vibration decreases. This cycle of increasing and

    decreasing vibration repeats itself forever (unless there is

    structural damping). The moving belt can sustain vibration self-excited vibration.

    Example 2: a solid oscillating in a fluid can interact with the fluidand produce interesting behaviour. The relative airflow against the

    oscillating solid modifies the velocity vectorand thus the lift and

    drag force acting on the solid.

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    k

    x

    V d

    Consider a long cylinder of length l

    supported by a spring kand a damperc.

    The equation of vertical motion of the

    c linder in the flow is

    )(tfkxxcxm =++

    The lift forcefis

    L

    2

    2

    1)( dlCVtf =

    Which term varies with time on the right ?

    http://www.algor.com/products/analysis_replays/turbulent_flow/default.asp?sQuery=vortex%20shedding

    Due to vibration of the cylinder, the lift coefficient is no longer a

    constant because of shedding of vortices. It may be expressed as

    Karman Vortices

    shedding occurs in Re=[60, 5000]

    http://www.algor.com/products/analysis_replays/turbulent_flow/default.asp?sQuery=vortex%20sheddinghttp://www.algor.com/products/analysis_replays/turbulent_flow/default.asp?sQuery=vortex%20sheddinghttp://www.algor.com/products/analysis_replays/turbulent_flow/default.asp?sQuery=vortex%20sheddinghttp://www.algor.com/products/analysis_replays/turbulent_flow/default.asp?sQuery=vortex%20sheddinghttp://www.algor.com/products/analysis_replays/turbulent_flow/default.asp?sQuery=vortex%20shedding
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    tCC sinL0L

    = ( 1L0 C for cylinder)

    and

    d

    Vks2=

    where sk is the Strouhal number. For 1000Re >= Vd

    , 21.0s k .

    So when

    s

    n

    s 22 k

    d

    m

    k

    k

    dV

    ==

    the cylinder vibrates violently (in resonance) in the flow. Whenflow velocity becomes high enough, the flow becomes turbulent,

    and the lift force becomes random.

    Flutter is a phenomenon of self-excited vibration.

    OV

    G

    A rigid wing attached to a rigid support through a spring

    M

    x

    D

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    V

    L

    Vertical motion: sincos DLkxxm =+

    where

    +=

    +=+=

    D22L22

    L

    22)(

    2)(

    2)(

    2

    ClcxVD

    ClcxVlcCxVL

    and

    )arctan(0

    V

    x==

    Assume small displacement so that222

    1costan VxVV

    x+=

    then

    ])d

    d

    d

    d(

    d

    d[

    2

    ]sin)(d

    dcos)(

    d

    d[

    2

    0

    DL

    0

    L2

    0

    D

    0

    L2

    CCClcV

    CClcVkxxm

    +=

    =+

    finally

    0

    L2

    0

    DL

    d

    d

    2)

    d

    d

    d

    d(

    2

    ClcVkxx

    CCVlcxm =+++

    Torsional vibration (assuming centre of gravity and aerodynamic centre

    coincide):

    MLeKIme +=++ )(2

    where the pitching moment

    O

    V

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    )(d

    d

    22

    )(d

    d

    22

    0

    M22

    M

    22

    0

    L2

    M

    22

    +==

    +==

    ClcVClcVM

    ClcVClcVL

    The above equation becomes

    0

    ML2ML22 )]d

    d

    d

    d(

    2)]

    d

    d

    d

    d(

    2[)(

    c

    Ce

    ClcVc

    Ce

    ClcVKIme +=+++

    The static divergence speed is

    )d

    d

    d

    d(

    2

    ML

    div

    cC

    eC

    lc

    KV

    +

    =

    for a symmetric aerofoil

    eC

    lc

    KV

    d

    d

    2

    L

    div=

    The high the divV , the greater speed capacity the aircraft has.