ac-140 peltier-thermoelectric air cooler · 2019. 2. 6. · -20-10 0 10 20 30 40 50 60 70 0 40 80...

• Ideal for telecommunications equipment and electronic enclosures where the cooler’s

power supply is located inside the enclosure.

• Can be used with a wide variety of TE Technology temperature controllers.

• Anodized heat sink and environmentally sealed external fan.

• Maintains enclosure at NEMA 4 rating.

• High coefficient of performance at low temperature differences.

• Input wires are routed on the cold side of the cooler, making it easy to power via

wiring from inside the enclosure.

• Can easily be customized for production sized orders to meet your exact

requirements.

• CE marked, RoHS compliant.

AC-140 Peltier-Thermoelectric Air Cooler

NOTE: All specifications are subject to change without notice. © 2018 TE Technology, Inc.

https://tetech.com/ • [email protected] • 231-929-3966 • 1590 Keane Drive • Traverse City, MI 49696

TETECHNOLOGY, INC.® Expert Engineering, Precision Manufacturing:

Quality Thermal Solutions Delivered

AC-140 6-FEB-2019 of 8

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mailto:[email protected]

Thermoelectric (TE) Power (typical)1,3 : 24 VDC at 4.7 A

Thermoelectric (TE) Power (maximum)2,3 : 24 VDC at 6.9 A

External (ambient) Fan Power: 24 VDC at 0.65 A

Internal (enclosure) Fan Power: 24 VDC at 0.22 A

Weight (kg): 7.8

NEMA Rating: 4

AC-140Specifications

Performance is based on unrestricted air flow to fans and

from air-flow outlets. Do not operate if the ambient,

enclosure air, heat sink, or cold sink temperatures exceed

70 °C. Do not operate fan at air temperatures below -20 °C

or above 70 °C.

External (ambient) Fan Noise: 55 dBA

Internal (enclosure) Fan Noise: 39 dBA

1Current is rated at +25 °C ambient, +25 °C internal, maximum heat removal. At -5.7 °C internal, the typical current is 4.2 A.

2Current, at steady-state operation under-worst case conditions, is rated at -20 °C ambient, +70 °C internal, maximum heat removal.

3Total current consumption is sum of TE current and Fan current.

Ext Fan Rating: IP68

215.9

246.4

21.6

6.4

259.1

161

175.8

7.44X Ø6.35 THRU

6431

135.4 20.2

80.3

137.6

INTERNAL

(ENCLOSURE)-SIDE

AIR FLOW INLET

INTERNAL

(ENCLOSURE)-SIDE

AIR FLOW OUTLET

EXTERNAL

(AMBIENT)-SIDE

AIR FLOW OUTLET

EXTERNAL

(AMBIENT)-SIDE

AIR FLOW INLET

EXTERNAL

(AMBIENT)-SIDE

AIR FLOW OUTLET

INTERNAL

(ENCLOSURE)-SIDE

AIR FLOW OUTLET

13.8

77

120.6

25 DEEP HOLE with

M3 x 0.5 THREADING TAPPED 9.7 DEEP

for SENSOR MOUNTING

RoHS Compliant

Directive 2011/65/EU

A 3D PDF, .stp, and .sldprt solid models

are also available from the website. Contact

TE Technology for 3D solid models in other

formats.

All dimensions in millimeters.

Internal (enclosure) side shown in blue;

External (ambient) side shown in red.

Please review the Thermoelectric Cooling Assembly

(TCA) Instruction Manual (or manual in other languages),

ordering information, and FAQ’s for related technical

information before purchasing or using this product.





AC-140 6-FEB-2019 of 8

https://tetech.com/files/TCA_Manual_English.pdf

https://tetech.com/downloads/

https://tetech.com/files/ordering-information.pdf

https://tetech.com/faqs/

https://tetech.com/


-20

-10

0

10

20

30

40

50

60

70

0 40 80 120 160 200 240 280 320 360

50 °C ambient

35 °C ambient

25 °C ambient

AC-140 Cooling Performance Graph

(removing heat from enclosure)In

tern

al A

ir T

em

pe

ratu

re o

f E

nc

los

ure

(°C

)

How to use the Performance Graph:

Heat Removed from Enclosure (watts)

Example: You need to maintain the enclosure at 15 °C while in a 25 °C ambient. The cooler can remove a maximum of

approximately 95 W of heat from the enclosure. If the heat load (internally generated heat plus the heat gain through

insulation, solar, vapor condensation, etc.) in the enclosure exceeds this, you would need more coolers and/or a larger

cooler.

3. Determine Cooling Capacity

The maximum amount of heat

that the cooler can remove from

the enclosure is determined by

the intersection point (determined

in the previous step). The cooler

will be able to maintain the

desired enclosure temperature if

the cooling capacity exceeds the

heat load. If the heat load

exceeds the cooling capacity then

a higher capacity cooler will be

needed.

1. Select Performance Line

The diagonal lines represent cooling

performance at the indicated ambient

air temperature (intake temperature

on the ambient-side fan). If the cooler

is to operate at a different ambient,

then you must sketch in a new

performance line. This can be drawn

parallel to one of the existing lines,

using the distance between the

existing lines as a scale to properly

locate the new line.

2. Select Enclosure Temperature

Draw a horizontal line on the graph

corresponding to the desired internal

air temperature of the enclosure.

Make the line intersect with the

performance line corresponding to

the ambient temperature at which

the cooler is to operate.





AC-140 6-FEB-2019 of 8

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-20

-10

0

10

20

30

40

50

60

70

0 40 80 120 160 200 240 280 320 360 400 440 480

25 °C ambient

0 °C ambient

-20 °C ambient

Example: You need to maintain the enclosure at 10 °C while in a 0 °C ambient. The cooler can add a maximum of

approximately 193 W of heat to the enclosure. If the heat dissipation from the enclosure exceeds this (plus anything

else generating heat), you would need more coolers and/or a larger cooler.

Inte

rna

l A

ir T

em

pe

ratu

re o

f E

nc

los

ure

(°C

)

How to use the Performance Graph:

AC-140 Heating Performance Graph

(adding heat to enclosure)

Heat Added to Enclosure (watts)

1. Select Performance Line

The diagonal lines represent heating

performance at the indicated ambient

air temperature (intake temperature

on the ambient-side fan). If the cooler

is to operate at a different ambient,

then you must sketch in a new

performance line. This can be drawn

parallel to one of the existing lines,

using the distance between the

existing lines as a scale to properly

locate the new line.

2. Select Enclosure Temperature

Draw a horizontal line on the graph

corresponding to the desired

internal air temperature of the

enclosure. Make the line intersect

with the performance line

corresponding to the ambient

temperature at which the cooler is

to operate.

3. Determine Heating Capacity

The maximum amount of heat that

the cooler can add to the enclosure

is determined by the intersection

point (determined in previous step).

If the heat added to the enclosure

(including heat generated by

equipment inside) is greater than the

enclosure’s heat loss, then the

cooler will be able to heat to the

desired temperature. A higher

capacity cooler will be needed if the

total heat added is less than the

enclosure’s heat loss.





AC-140 6-FEB-2019 of 8

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Terminal Block Configuration for Continuous Operation at Full Power

As-Shipped Configuration 1 of 2

1

2

REMOVE TERMINAL

BLOCK COVER

FOUR ELECTRICAL

JUMPERS INSTALLED

(ORIGINAL

CONFIGURATION)

LOOSEN TWO SCREWS

KEEP JUMPERS INSTALLED





AC-140 6-FEB-2019 of 8

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Power supply (-) Black Wire

to POSITION 1

Power supply (+) Red Wire

to POSITION 6

3

Terminal Block Configuration for Continuous Operation at Full Power

2 of 2

4INSTALL WIRES,

TIGHTEN SCREWS

TO 1.0 N-M, AND

REPLACE COVER





AC-140 6-FEB-2019 of 8

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1

REMOVE TERMINAL

BLOCK COVER

FOUR ELECTRICAL

JUMPERS INSTALLED

(ORIGINAL CONFIGURATION)

LOOSEN SIX SCREWS

REMOVE TWO

ELECTRICAL JUMPERS

FROM 2-3 AND 4-5

2

Terminal Block Configuration for Operation with Temperature Controller

1 of 2





AC-140 6-FEB-2019 of 8

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Power supply (-) Black Wire

to POSITION 1

Power supply (+) Red Wire

to POSITION 6

Temperature Controller (-) Black Wire

To POSITION 3

Temperature Controller (+) Red Wire

to POSITION 4

3

4

Terminal Block Configuration for Operation with Temperature Controller

2 of 2

INSTALL WIRES,

TIGHTEN SCREWS

TO 1.0 N-M, AND

REPLACE COVER





AC-140 6-FEB-2019 of 8

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ac-140 peltier-thermoelectric air cooler · 2019. 2. 6. · -20-10 0 10 20 30 40 50 60 70 0 40 80...

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