abnormal pressure
TRANSCRIPT
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7. Abnormal Pressure 661. Drilling Engineering Slide 1
PETE 661Drilling Engineering
Lesson 7
Abnormal Pressure
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7. Abnormal Pressure 661. Drilling Engineering Slide 4
Abnormal
Pressure
Gradients
Normal Pressure Gradients
West Texas: 0.433 psi/ft
Gulf Coast: 0.465 psi/ft
Normal and Abnormal Pore Pressure
Pore Pressure, psig
Depth,
ft
10,000??
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7. Abnormal Pressure 661. Drilling Engineering Slide 5
Pore Pressure vs. Depth
8 9 10 11 12 13 14 15 16
Pore Pressure Equivalent, lb/gal
0
5,000
10,000
15,000
20,000
{ Density of mud required to control this pore pressure }
Normal
Abormal
0.433 psi/ft 8.33 lb/gal0.465 psi/ft 9.0 lb/gal
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7. Abnormal Pressure 661. Drilling Engineering Slide 6
Pore Pressure
Gradient
Fracture Gradient
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* Pore
Pressure
Gradients
* Fracture
Gradients
* Casing
Setting
Depths
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Some Causes of Abnormal Pressure
1. Incomplete compaction of sediments
Fluids in sediments have not
escaped and are still helping to
support the overburden.
2.Tectonic movements
Uplift
Faulting
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Some Causes of Abnormal Pressure
3. Aquifers in Mountainous Regions
Aquifer recharge is at higher
elevation than drilling rig location.
4. Charged shallow reservoirs due to
nearby underground blowout.
5. Large structures...
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7. Abnormal Pressure 661. Drilling Engineering Slide 10
HIGH PRESSURE
NORMAL PRESSURE
Thick, impermeable layers of shale (or salt) restrict the movement
of water. Below such layers abnormal pressure may be found.
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7. Abnormal Pressure 661. Drilling Engineering Slide 11
HIGH PRESSURE
NORMAL PRESSURE
Hydrostatic pressure gradient is lower in gas or oil than in water.
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7. Abnormal Pressure 661. Drilling Engineering Slide 12
When crossing faults it is possible to go from normal
pressure to abnormally high pressure in a short interval.
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7. Abnormal Pressure 661. Drilling Engineering Slide 13
Well A found only Normal Pressure ...
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7. Abnormal Pressure 661. Drilling Engineering Slide 14
sOB = p + sZ
sob
p sz
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7. Abnormal Pressure 661. Drilling Engineering Slide 15
?
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7. Abnormal Pressure 661. Drilling Engineering Slide 16
Indications of Abnormal Pore Pressures
Methods:
1. Seismic data
2. Drilling rate
3. Sloughing shale
4. Gas units in mud
5. Shale density
6. Chloride content
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7. Abnormal Pressure 661. Drilling Engineering Slide 17
Indications of Abnormal Pore Pressures
Methods, contd:
7. Change in Mud properties
8. Temperature of Mud Returns
9. Bentonite content in shale
10. Paleo information
11. Wire-line logs
12. MWD-LWD
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7. Abnormal Pressure 661. Drilling Engineering Slide 18
Prediction and Detection of Abnormal
Pressure Zones
1. Before drilling
Shallow seismic surveys
Deep seismic surveys
Comparison with nearby wells
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7. Abnormal Pressure 661. Drilling Engineering Slide 19
Prediction and Detection of Abnormal
Pressure Zones
2. While drilling
Drilling rate, gas in mud, etc. etc.
D- Exponent
DC - Exponent
MWD - LWD
Density of shale (cuttings)
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7. Abnormal Pressure 661. Drilling Engineering Slide 20
Prediction and Detection of Abnormal
Pressure Zones
3. After drilling
Resistivity log
Conductivity log
Sonic log
Density log
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7. Abnormal Pressure 661. Drilling Engineering Slide 21
.
.SD000085.0
e41.0
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7. Abnormal Pressure 661. Drilling Engineering Slide 22
Decreasing ROP
What is d-
exponent?
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7. Abnormal Pressure 661. Drilling Engineering Slide 23
D - Exponent
Thedrilling rate
equation:
WhereR = drilling rate, ft/hr
K = drillability constant
N = rotary speed, RPME = rotary speed expon.
W = bit weight, lbs
DB = bit diameter, in
D = bit wt. Exponent
or D - exponent
D
B
E
D
WNKR
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7. Abnormal Pressure 661. Drilling Engineering Slide 24
D - Exponent
If we assume that K = 1
and E = 1
Then
D
B
E
D
WNKR
BD
Wlog
N
Rlog
D
D
BDW
NR
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7. Abnormal Pressure 661. Drilling Engineering Slide 25
D - Exponent
A modified version of this equation
follows:
B
6 D10W12log
N60
Rlog
d
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7. Abnormal Pressure 661. Drilling Engineering Slide 26
Example
Calculate the value of the d - exponent ifthe drilling rate is 35 ft/hr, the rotary RPM is
100, and the weight on the 12 1/4 bit is
60,000 lbs.
B
6 D10W12log
N60
Rlog
d
2308.1
2341.2
25.1210000,60*12log
100*60
35log
6
d = 1.82
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7. Abnormal Pressure 661. Drilling Engineering Slide 27
Example
What happens to d if R doubles to 70 ft/hr?
Note that an increase in Rresulted in a decrease in d.
Doubling R decreased d from 1.82 to 1.57
57123081
93311
251210
0006012
10060
70
6
..
.
.
,*log
*logd
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7. Abnormal Pressure 661. Drilling Engineering Slide 28
Example
d may be Corrected for mud densityas follows:
)ppg(useinweightmudactual
)ppg(gradientnormalforweightmudddc
37.112
9*82.1
12
9dd.,g.e c
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7. Abnormal Pressure 661. Drilling Engineering Slide 29
Procedure for Determining Pore
Pressure From dc - Exponent
Calculate dc over10-30 ft intervals
Plot dc vs depth (use only date from
Cleanshale sections) Determine the normal line for the
dc vs. depth plot.
Establish where dc deviates from thenormal line to determine abnormal
pressure zone
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7. Abnormal Pressure 661. Drilling Engineering Slide 30
Procedure for Determining Pore
Pressure From dc - Exponent
dc - Exponent
Depth Normal
Abnormal
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7. Abnormal Pressure 661. Drilling Engineering Slide 31
Procedure for Determining Pore
Pressure From dc - Exponent
If possible, quantify the magnitude of the
abnormal pore pressure using
overlays, orBen Eatons Method
Pore
Pressure
Grad.Overburden
Stress Grad.
Normal Pore
Pressure Grad.
2.1
c
c
nnormald
calculatedd
D
P
D
S
D
S
D
P
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7. Abnormal Pressure 661. Drilling Engineering Slide 32
In normally pressured
shales, shale
compaction increaseswith depth
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7. Abnormal Pressure 661. Drilling Engineering Slide 33
Shale Density - Mud Cup Method
1. Fill mud cup with shale until the weight is 8.33.2. Fill to top with water, and record the reading Wtot.
Note: Dry sample carefully with towel.
Do not apply heat.
totW66.16
33.8Gravity.Spec
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7. Abnormal Pressure 661. Drilling Engineering Slide 34
Alternate Method: Use variable density column.
See p. 270 in text
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7. Abnormal Pressure 661. Drilling Engineering Slide 35
Pore Pressure from
Resistivity
Shale resistivity plots
may be developed
from (i) logs or
(ii) cuttings
What is the pore
pressure at the point
indicated on the plot?
[Assume Gulf Coast].
Depth=10,000 ft0.2 0.5 1 2 3
10,000
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7. Abnormal Pressure 661. Drilling Engineering Slide 36
From plot, Rn = 1.55 ohms
Robs = 0.80 ohms
From Eaton:
EATON
2.1
n
obs
nR
R
D
P
D
S
D
S
D
P
2.1
55.1
80.0465.095.095.0
D
P
= 0.7307 psi/ft = 14.05 lb/gal
P = 0.7307 * 10,000 = 7,307 psi0.2 0.5 1 2 3
10,000
Dep
th
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7. Abnormal Pressure 661. Drilling Engineering Slide 37
Prediction of
Abnormal Pore Pressure
Resistivity of Shale
Temperature in the Return Mud
Drilling Rate Increase
dc - Exponent
Sonic Travel Time
Conductivity of Shale
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7. Abnormal Pressure 661. Drilling Engineering Slide 38
EXAMPLE
Shale Resistivityvs. Depth
1. Establish normal
trend line
2. Look for
deviations
(semi-log)
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7. Abnormal Pressure 661. Drilling Engineering Slide 39
Shale Resistivity
vs. Depth
1. Establish normal
trend line
2. Look for
deviations
3. Use OVERLAYto quantify
pore pressure(use with caution)
Pore Pressure
(lb/gal equivalent)
16 14 12 10
9 ppg(normal)
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7. Abnormal Pressure 661. Drilling Engineering Slide 40
Example
8.2 X
Why?
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7. Abnormal Pressure 661. Drilling Engineering Slide 41
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7. Abnormal Pressure 661. Drilling Engineering Slide 42
DP = (P2 - P1)1,000
Effect of Differential Pressure
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7. Abnormal Pressure 661. Drilling Engineering Slide 43
Typical Drilling Rate Profiles - Shale
The drilling rate in a normallypressured, solid shale
section will generally
generate a very steady and
smooth drilling rate curve.
The penetration rate will be
steady and not erratic(normally pressured, clean
shale).
Shale
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7. Abnormal Pressure 661. Drilling Engineering Slide 44
Typical Drilling Rate Profiles
Note:
If you are drilling overbalancedin a transition it
will be very difficult to pick up the
transition zone initially. This will allow you to move well into the
transition zone before detecting the problem.
Any deviation from the expected decrease inddilling rate with depth, when you are drilling in a
clean shale, might indicate a transition zone.
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7. Abnormal Pressure 661. Drilling Engineering Slide 46
Determination of Abnormal Pore
Pressure Using the dc - exponent
From Ben Eaton:
2.1
cn
c
n d
d
D
P
D
S
D
S
D
P
21
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7. Abnormal Pressure 661. Drilling Engineering Slide 47
Where
trendnormalthefromonentexpdd
plotfromentexpondactuald
psi/ftgradient,stressoverburden
D
S
psi/ft0.465,or0.433e.g.,
areaingradientwaternormalD
P
psi/ftgradient,pressureformationD
P
ccn
cc
n
2.1
cn
c
n d
d
D
P
D
S
D
S
D
P
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7. Abnormal Pressure 661. Drilling Engineering Slide 48
Example
Calculate the porepressure at depth X using
the data in this graph.
Assume:
West Texas location with
normal overburden of
1.0 psi/ft.X = 12,000 ft.
X
1.2 1.5
dc
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7. Abnormal Pressure 661. Drilling Engineering Slide 49
Example
From Ben Eaton:
psi/ft5662.0D
P
5.1
2.1]433.00.1[0.1
d
d
D
P
D
S
D
S
D
P
2.1
2.1
cn
c
n
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7. Abnormal Pressure 661. Drilling Engineering Slide 50
Example
lbm/gal9.1012,000x0.052
6794EMW
psi6794000,12x5662.0P
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E S P b k
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7. Abnormal Pressure 661. Drilling Engineering Slide 52
E.S. Pennebaker
Any departure from this trend is an
indication of possible abnormal
pressures.
Pennebaker used overlays to estimate
abnormal pore pressures from the
difference between normal and actualtravel times.
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7. Abnormal Pressure 661. Drilling Engineering Slide 53
Interval Travel Time, msec per ft
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B E t
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7. Abnormal Pressure 661. Drilling Engineering Slide 55
Ben Eaton
From Ben Eaton,
psi/ft0.6904
12,000
10,0000.465]-[1.0-1.0
t
t
D
P
D
S
D
S
D
P
3
0.3
n
n
D
D
( Dt a 1/v )
B E t
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7. Abnormal Pressure 661. Drilling Engineering Slide 56
Ben Eaton
From Ben Eaton
Note: Exponent is 3.0 this time,NOT 1.2!
r = (0.6904 / 0.052) = 13.28 lb/gal
p = 0.6904 * 13,500 = 9,320 psig
Equations for Pore Pressure Determination
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7. Abnormal Pressure 661. Drilling Engineering Slide 57
Equations for Pore Pressure Determination
2.1
c
c
n
normald
calculatedd
D
P
D
S
D
S
D
P
2.1
n
obs
n R
R
D
P
D
S
D
S
D
P
rr
ACTUALNORMAL
B6
C *
D10
W12log
N60
Rlog
d
2.1
o
n
nC
C
D
P
D
S
D
S
D
P
0.3
o
n
nt
t
D
P
D
S
D
S
D
P
D
D
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7. Abnormal Pressure 661. Drilling Engineering Slide 58
Pore Pressure Determination
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7. Abnormal Pressure 661. Drilling Engineering Slide 59
EXAMPLE 3 - An Application...
Mud Weight = 10 lb/gal. (0.52 psi/ft)Surface csg. Set at 2,500 ft.
Fracture gradient below surf. Csg = 0.73 psi/ft
Drilling at 10,000 ft in pressure transition zone* Mud weight may be less than pore pressure!
DETERMINE Maximum safe underbalance
between mud weight and pore pressure if well
kicks from formation at 10,000 ft.
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7. Abnormal Pressure 661. Drilling Engineering Slide 60
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7. Abnormal Pressure 661. Drilling Engineering Slide 62
Wellbore Pressure, psi
Dep
th,
ft
DP
Casing Seat at 2,500 ft
Kick at 10,000 ft
Before Kick
After Kick and
Stabilization
525
525
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7. Abnormal Pressure 661. Drilling Engineering Slide 63
At 2,500 ftInitial mud pressure = 0.52 psi/ft * 2,500 ft = 1,300 psi
Fracture pressure = 0.73 psi/ft * 2,500 ft = 1,825 psi
Maximum allowable increase in pressure = 525 psi
At 10,000 ftMaximum allowable increase in pressure = 525 psi
(since the pressure increases uniformly everywhere).
This corresponds to an increase in mud weight of525 / (0.052 * 10,000) = 1.01 lb/gal
= maximum increase in EMW
= kick tolarance for a small kick size.
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7. Abnormal Pressure 661. Drilling Engineering Slide 64
Wellbore Pressure, psi
Depth,
ft
DP
Casing Seat at 2,500 ft
Kick at 10,000 ft
1,300 psi
1,825 psi
5,725 psi
5,200 psi
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Wellbore Pressure, psi
Dep
th,
ft
DP
Casing Seat at 2,500 ft
Kick at 10,000 ft
Before Kick
After Small Kick
and Stabilization
After Large Kick and Stabilization