• We need to find out the surface area of the Earth (SE) and the area of the widest part of the soccer ball (WAS).

• We’re not finding out the surface area of the soccer ball because we’re not going to be able to stretch it apart to cover the earth.

• We use WAS times the Avogadro's number and use that to divide the SE. Then we use that number and times it by the diameter of the soccer to find out to what depth would it cover.

Diameter: 22.2 cmSurface Area of the widest part: A = πr2

A = 3.14 x (22.2 cm / 2)2

A = 386.88 cm 2

Surface Area: 5.1 x 108 km2

or5.1 x 1018 cm2

ProcessArea of a mole of soccer ball = SA of Ball x 1 mole =386.88cm2 x 6.022 x 1023 = 2.3 x 1026 cm 2Number of times covering the Earth = SA of 1 mole of soccer ball ÷ SA of Earth

=2.3 x 10 26 ÷ 5.1 x 1018

= 4.51 x 10 7Depth it would cover to = # of times it would cover the Earth x Soccer ball’s Diameter

= 4.51 x 10 7 x 22.2 cm = 1.001 x 10 9 cm

Area of a Circle: πr2

Km 2 to cm 2 = 10 x 10 9

A mole of soccer balls would cover the surface of the Earth to a depth of 1.001 x

10 9 cm or 10012 km