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Ni(CO) 4 + P-P (PP)Ni(CO) 2 + 2 CO. BITIOP. DPPB R=H. (DPPB)Ni(CO) 2. (BITIOP)Ni(CO) 2. R,R. Pd(PhCN) 2 Cl 2. Ni(CO) 4. b '. a. b. a '. Cs. -38.98 ppm. -1.75 ppm. b. a. H 2. H 2. H 2. e.d.% = 43% e.e.% = 70% Conf = R/R. Conv % = 100% (55h) - PowerPoint PPT PresentationTRANSCRIPT
Structural variations on chiral ligands: new chelanting diphosphines from optical active (1,4)-(Z)-2-Structural variations on chiral ligands: new chelanting diphosphines from optical active (1,4)-(Z)-2-
butenes.butenes.
E. Cesarotti, I. Rimoldi, P. Spalluto
Università degli Studi di Milano, Facoltà di Farmacia, Dipartimento di Chimica Inorganica, Metallorganica e Analitica.
HO
H3C CH3
OH
HO
H3C CH3
OH
H3COCO
H3C CH3
OCOCH3
OH OH
H3C CH3
OTs OTs
H3C CH3
P
Pd
P
Cl
Cl
Cl2
Cl1Pd
C11
C41C4C1
C2C3
C111
C121
C211
C221
'
'
Cs
PPh2 PPh2
H3C CH3
-1.75 ppm
-38.98 ppm
P
Ni
P
CO
CO
PPh2
PPh2RhB(Ph)4
NH
OTBS
O
NH
CHO
OTBS
O
NH
OTBS CHO
O
NH
OTBS
O
CHO
linconv (%) = 100%
α+β/l = 60/40
α/β = 67/33
H2O
O O
O
OH O
PAr2
PAr2Ru
I
+
H2
Conv % = 100% (55h)e.e. % = 66% (Ar = C6H5) e.e. % = 64% (Ar = C8H9)Conf = R
An essential feature: the conformational rigidity of the
ligand
versus Another essential feature:the modulation of the ligand steric
properties by the modification of the substituents
on the stereogenic atoms
Is it possible to prepare a ligand gathering the conformational rigidity of an atropisomeric ligand with the possibility to modulate steric properties by the modification of the substituents
on the stereogenic atoms?
enzymatic resolution by
LAKVinyl acetate
e.e.% > 98%S,S
Commercial available mixture
R,R meso
H3COCO
H3C CH3
OH
TsCl
NaOH
Ni(CO)4 + P-P
(PP)Ni(CO)2 + 2 CO
-20 -20 -10 -10 0 0 10 10 20 20 30 30 40 40 50 50 60 60 70 70 80 80 90 90 100 100 110 110 120 120 130 130
-40-40-30-30-20-20-10-1000101020203030404050506060707080809090100100110110120120130130
PPh2
PPh2
S
S
BITIOP
(BITIOP)Ni(CO)2
-50-50-40-40-30-30-20-20-10-10001010202030304040505060607070
DPPBR=H PPh2
PPh2
R
R
(DPPB)Ni(CO)2
Ar2PLi-78°C
Work in progress:
PAr2 PAr2
R RR=(CH3)2CH-, C6H11-, C6H5-
PPh2
PPh2Ru
I
+O O
O
NHCO
OH O
O
NHCONH
OTBS
O
e.d.% = 43%e.e.% = 70%Conf = R/R
H2
S,S S,S
Pd(PhCN)2Cl2 Ni(CO)4
PAr2 PAr2
H3C CH3
R,R