8.8: factoring by grouping:

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8.8: FACTORING BY GROUPING: Higher Degree Polynomials: Polynomials with a degree higher than 2.

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Higher Degree Polynomials : Polynomials with a degree higher than 2 . 8.8: FACTORING BY GROUPING:. Procedure:. 1) Always look for the GCF of all the terms. FACTORING ax 2 + bx + c . - PowerPoint PPT Presentation

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Page 1: 8.8:  FACTORING  BY GROUPING:

8.8: FACTORING BY GROUPING:

Higher Degree Polynomials: Polynomials with a degree higher than 2.

Page 2: 8.8:  FACTORING  BY GROUPING:

FACTORING ax2 + bx + c Procedure:

1) Always look for the GCF of all the terms2) Factor the remaining terms – pay close attention to the value of coefficient a and follow the proper steps.

3) Re-write the original polynomial as a product of the polynomials that cannot be factored any further.

Page 3: 8.8:  FACTORING  BY GROUPING:

GOAL:

Page 4: 8.8:  FACTORING  BY GROUPING:

FACTORING: By Grouping

Ex: What is the FACTORED form of:

3n3-12n2+2n-8?

Page 5: 8.8:  FACTORING  BY GROUPING:

SOLUTION: To factor a polynomial by grouping we group terms that have a GCF:

Look at GCF of each: 3n3-12n2

Now take the GCF of the two:

Factored form : (n-4)(3n2+2)

3n3-12n2+2n-8 3n3-12n2+2n-8

3n2(n-4) 2n-8 2(n-4)

3n2 (n-4) +2 (n-4)

Page 6: 8.8:  FACTORING  BY GROUPING:

YOU TRY IT:

Ex: What is the FACTORED form of:

8t3+20t+14t2+35?

Page 7: 8.8:  FACTORING  BY GROUPING:

SOLUTION: To factor a polynomial by grouping we group terms that have a GCF:

Look at GCF of each: 8t3+14t2

Now take the GCF of the two:

Factored form : (4t+7)(2t2+5)

8t3+14t2+20t+35 8t3+14t2+20t+35

2t2(4t+7) 20t+35 5(4t+7)

2t2 (4t+7) +5(4t+7)

Page 8: 8.8:  FACTORING  BY GROUPING:

YOU TRY IT:

Ex: What is the FACTORED form of:

4q4-8q3+12q2-24q?

Page 9: 8.8:  FACTORING  BY GROUPING:

SOLUTION: Before we group, we must again go back to the first step of factoring:

1) Factor what is in common? 4q4-8q3+12q2-24q?

4q(q3-2q2+3q-6)

Page 10: 8.8:  FACTORING  BY GROUPING:

SOLUTION: To factor a polynomial by grouping we group terms that have a GCF:

Look at GCF of each: q3-2q2

Now take the GCF of the two:

Factored form : 4q (q-2) (q2+3)

4q(q3-2q2+3q-6) 4q(q3-2q2+3q-6)

q2(q-2) 3q-6 3(q-2)

q2 (q-2) +3(q-2)

Page 11: 8.8:  FACTORING  BY GROUPING:

REAL-WORLD:

The area of a square rug is given by 4x2-100.What are the possible dimensions of the rug?

Page 12: 8.8:  FACTORING  BY GROUPING:

SOLUTION: To factor a difference of two squares with a coefficient ≠ 1 we still follow the factoring procedure:

4x2-100ax2+c a= +1 c =-25 Look at the factors of a and c:

a : (1)(1) c: (-5)(5)We now see that the factored form is:

4(x-5)(x+5)

4(x2-25)

Page 13: 8.8:  FACTORING  BY GROUPING:

NOW SOLVE THIS:

Page 16: 8.8:  FACTORING  BY GROUPING:

CLASSWORK:

Page 514-516:

Problems: 1, 2, 3, 9, 13, 16, 22, 27, 30, 32, 37, 45.