8-2 electric current

12
Warm-up Which particles move freely through metals? a. Atoms c. Protons b. Electrons d. Molecules What is the charge on the following particles: c. Proton - d. Electron - e. Neutron - negative positive neutral

Upload: guested7952

Post on 24-Dec-2014

360 views

Category:

Education


0 download

DESCRIPTION

 

TRANSCRIPT

Page 1: 8-2 Electric Current

Warm-up

Which particles move freely through metals?

a. Atoms c. Protons

b. Electrons d. Molecules

What is the charge on the following particles:

c. Proton -

d. Electron -

e. Neutron - negative

positive

neutral

Page 2: 8-2 Electric Current

8-2 Current Electricity

Describe electric current.

Identify the two types of current.

Explain how voltage produces electric current.

Calculate voltage, current, and resistance using Ohm’s Law

Page 3: 8-2 Electric Current

Electric Current

A steady flow of electrons through a conductor.

Measured in amperes or amps (A).

Variable is “I”

Page 4: 8-2 Electric Current

Direct Current (DC)Charge flows in one direction.– battery operated devices– Electrons flow from the negative to the

positive.– Opposite to direction of the current.

Page 5: 8-2 Electric Current

Alternating Current (AC)

A flow of electrical charge that regularly reverses the flow of charge.– American electricity changes directions 60

times a second.– Household current is alternating current.

Page 6: 8-2 Electric Current

Potential Difference

Also known as Voltage.

The “push” that causes electrons to flow through a circuit.

Measured in volts (V).

Variable is “V”

Page 7: 8-2 Electric Current

Resistance

Anything that slows the flow of electrons through a conductor.

Measured in ohms (W ).

Variable is “R”

Page 8: 8-2 Electric Current

Ohm’s Law

The mathematical equation that shows the relationship between current, potential difference and resistance.

V = IR

Where: I = current in amps (A)

V = potential difference in volts (V)

R = resistance in ohms (W)

Page 9: 8-2 Electric Current

Sample Problem

How many 1.5V batteries would be needed to supply 0.83A of current if the appliance offers 5.4W of resistance?

I = 0.83A

R = 5.4W V = IR

V = 0.83A(5.4 )W

V = 4.482V4.482V / 1.5V per battery = 2.988 or 3 batteries

Page 10: 8-2 Electric Current

Sample Problem

If a lamp bulb requires 5.5amps of current supplied at 110volts, how much resistance does it offer?I = 5.5ampsV = 110volts

R = V / I

R = 110V / 5.5a

R = 20W

Page 11: 8-2 Electric Current

Sample Problem

If an electrical appliance offers 24 W of resistance, and is connected to a 9.0V battery, how much current will flow?

R = 24WV = 9.0V I = V / R

I = 9.0V / 24W

I = 0.375a

Page 12: 8-2 Electric Current

Conclusion

What is the relationship between current, voltage, and resistance?