5. thin airfoil
DESCRIPTION
Thin AirfoilTRANSCRIPT
CAIRO UNIVERSITY
FACULTY OF ENGINEERING
AEROSPACE DEPARTMENT
THIRD YEAR STUDENTS
FIRST TERM
Course Title: AERODYNAMICS (A)
Course Code: AER 301 A
PROF. Dr. MOHAMED MADBOULI ABDELRAHMAN
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Thin Airfoil
Theory
Assume steady, 2-D, non viscous, irrotational, incompressible flow The solution of the airfoil problem may be obtained as
the superposition of the solutions of the following two simple problems:
Thin Airfoil Theory
1) Cambered airfoil with angle of attack
2) Symmetric airfoil at zero angle of attack y
y(x)
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Assume steady, 2-D, non viscous, irrotational, incompressible flow The solution of the airfoil problem may be obtained as
the superposition of the solutions of the following two simple problems:
Thin Airfoil Theory
1) Cambered airfoil with angle of attack
2) Symmetric airfoil at zero angle of attack y
y(x)
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The flow field may be represented by a distribution of vortices γ(x) along the x-axis on the chord line
The γ(x) distribution can be determine by applying the boundary condition (velocity must be tangent to the camber)
For small angle of attack and small camber the boundary condition can be written as “dy/dx ≈ α + v/V∞” where “v” is the velocity component in y-direction
Thin Airfoil Theory (Cambered airfoil with angle of attack)
c
0
1
1
dx)xx
(V2
1
dx
dy
y y
y(x) 5
Thin Airfoil Theory
c
0
1
1
dx)xx
(V2
1
dx
dy
To solve this integral-differential equation
Change the variables x and x1 to θ and θ1 with
Assume γ can be written in the following series form as
After substitution, the governing equation will be
)cos1(2
cx
)]nsin(Asin
)cos1(A[V2 1n
11
10
0
1
1
11n
0
1
1
10 dcoscos
sin)nsin(A1d)
coscos
)cos1(A1
dx
dy
0
1
1
11 )ncos(dcoscos
sin)nsin(
0
1
1
1
sin
)nsin(d
coscos
)ncos(
Using the following identities
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Thin Airfoil Theory we can prove that
)nsin(AAdx
dyn
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To calculate the coefficients A0 and An for n = 1 to ∞
we integrate this equation as
0
n1
0
0
d)nsin(AAddx
dy
0
n1
0
0
d)mcos()nsin(AAd)mcos(dx
dy
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Thin Airfoil Theory
0
)mn(when0d)mcos()ncos(
and using the following identities
0
)mn(when)2
(d)mcos()ncos(
we can prove that
0
0 ddx
dy)
1(A
0
n d)ncos(dx
dy)
2(A&
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Thin Airfoil Theory As a conclusion, if we have the camber line equation of an airfoil section given by “y = f(x)” then we can calculate the distribution of vortices γ(x) along the x-axis by
where
0
0 ddx
dy)
1(A
0
n d)ncos(dx
dy)
2(A&
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)]nsin(Asin
)cos1(A[V2 n
10
with A0 and An are calculated by )cos1(2
cx
Thin Airfoil Theory
The lift force
c
0
dxVVL
where
)(2)2/AA(2C 010L
0
0 d)cos1)(dx
dy()
1(
)]nsin(Asin
)cos1(A[V2 n
10
)cos1(2
cx and
We can
prove that
Then
10
1cCV2
1
2
AAcVL L
210
2
where
Thin Airfoil Theory
The pitching moment about the leading edge point
c
0
LE xdxVM
)2/AAA)(2/(C 210MLE then
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where
)]nsin(Asin
)cos1(A[V2 n
10
)cos1(2
cx and
We can prove that
c1cCV2
1
2
AAAcV
4M
LEM
2210
22
LE
Thin Airfoil Theory The pitching moment about any arbitrary reference point
c
xCCC LMM LEx
Neglecting the moment contribution due to drag, the pitching moment about any arbitrary reference point can be related by the pitching moment about the leading edge point by the following equation
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Thin Airfoil Theory Determination of the center of pressure point
The center of pressure point is defined as that point about which the pitching moment is zero. Neglecting the moment contribution due to drag, it can be seen that
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)AA(
LCC
C
c
cpx
L
M LE
2144
1
0
c
xCCC
cp
LMM LEcp
then
Thin Airfoil Theory Determination of the aerodynamic center point
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c
xCCC ac
LMM LEac
A very important reference point on an airfoil is the aerodynamic center. The aerodynamic center is defined as that point about which the variation of the pitching moment with angle of attack is zero. Neglecting the moment contribution due to drag, it can be seen that
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1
LC
C
c
acx
LEM
Then
0
c
xCCC acLMMac LE
Thin Airfoil Theory
Determination of the aerodynamic center point
c
xxCCC ac
LMM xac
The aerodynamic center (point about which the pitching moment is independent on the angle of attack) can be calculated using any arbitrary reference point as
0c
xxCCC acLMMac x
LC
C
c
x
c
acx
xM
&
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Then
Using experimental data of CM versus CL it is possible to compute the location of the aerodynamic center xac. For low subsonic flow it is found that the aerodynamic center is at the quarter chord point.
Thin Airfoil Theory The pitching moment coefficients and center of pressure
)2/AAA)(2/(C 210MLE
and )AA)(4/(C 21M 4/c
)2
A1
A(
LC44
1
c
cpx
and 16
Thin Airfoil Theory Using the small perturbation for thin airfoil the
velocity on the airfoil surface can be approximated by
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uVVanduVV lu
V
u
V
u
V
u
V
Vu 21
21
22
V
u
V
u
V
u
V
Vl 21
21
22
then
2
ll
22
uu V2
1pV
2
1pV
2
1p
If
and
using B.E.
then VuVpp ul 2
u2and
Thin Airfoil Theory
The velocity distribution over thin airfoil
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The velocity distribution over the upper and lower surface of a thin airfoil can be calculated by
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VVandVV lowerupper
where )]nsin(Asin
)cos1(A[V2 n
10
)cos1(2
cx and
Thin Airfoil Theory
The pressure coefficient can be calculated using
Bernoulli equation
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The pressure distribution over the upper and lower surface of a thin airfoil can be calculated by
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2
1
2
1
2
1lluu VpVpVp
where
)]nsin(Asin
)cos1(A[V2 n
10
)cos1(2
cx
and
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VVandVV lu
with
22
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V
VCand
V
VC l
pu
p luor
Thin Airfoil Theory
The chord-wise velocity distribution
2VV l,u
where )]nsin(Asin
)cos1(A[V2 n
10
)cos1(2
cx and
The chord-wise pressure distribution
V)VV(Vpp luul
)V/2()CC(Cullu ppp
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Thin Airfoil Theory For symmetric airfoil (dy/dx=0), the vortex strength is
21 )V/2()CC(Cul ppp
where
then
and
where
Thin Airfoil Theory
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)]nsin(Asin
)cos1(A[V2 n
10
)ncos(AAdx
dyn
10
)cos1(2
cx
Thin Airfoil Theory
By applying the boundary condition (velocity tangent to the camber line)
with x = 0 at the L.E. point and x = c at the T.E. point.
where
For a zero thickness cambered airfoil "y(x)" placed in a free stream velocity "V" with an angle of attack "α" the flow-field may be presented by a the following distribution of vortices "(x)" along the chord line "c" as
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)ncos(AAdx
dyn
10
Thin Airfoil Theory
to1nforI2
Aand)I
(A nn
00
to1nford)ncos()dx
dy(Iandd)
dx
dy(I
0
n
0
0
The coefficients A0 & An for n = 1, 2, 3, …. are given by
where
The aerodynamic characteristics for this airfoil can be determined by:
]AA[4
)C(
]2
AAA[
2)C(
]2
AA[2C
214/cM
210LEM
10L
4
1)
c
x(
)C4(
)AA(
4
1)
c
x(
]2
AA[
ac
L
21cp
100
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)ncos(AAdx
dyn
10
Thin Airfoil Theory
&
]II[2
1)C(
]II2I[2
1)C(
]II[2C
214/cM
210LEM
10L
4
1)
c
x(
)II(4
)II(
4
1)
c
x(
)II(
ac
10
21cp
100
V)VV(Vpp&2
VV&2
VV luullu
The aerodynamic characteristics for this airfoil can be determined in terms of “Io“ & ”In ” by:
where
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Thin Airfoil Theory
mc
x
c
xa
c
xa
c
xaa
c
y )(0)()()( 3
3
2
2101
1)()()()( 3
3
2
2102
c
xm
c
xb
c
xb
c
xbb
c
y
])[2
)2sin((])[(sin])[(][ 221221112010200 tttttttI m
mm
]][6
)3sin([]][
4
)2sin([]
22)[(sin])[
2()
2( 22122111
221220102111211 tttt
tttttttI mm
mm
]][8
)4sin([]][
6
)3sin([]][
2
)2sin([])[
2
sin(])[
2(])[
2( 22122111201021112212222 tttttttttttI mmmmm
3123211321108
3
2
3
8
921cos ataataaatmm
3223221321208
3
2
3
8
9btbbtbbbt
For camber line airfoil given by the following 2 equations:-
The integrations I0, I1 and I2 can be calculated by
with
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For a flat plate wing section airfoil where the mean camber line equation is
(y/c) = 0 for 0 =< (x/c) =< 1
Using thin airfoil theory we can calculate the following
the zero lift angle of attack αo = 0 rad = 0o,
the pitching moment coefficient at the aerodynamic center (Cm)ac = 0,
When the angle of attack is “α=8o ”,
the lift coefficient CL = 0.8773,
the pitching moment coefficient at the leading edge (Cm)LE = −0.2193
the center of pressure (xc.p/c) = 0.25
the aerodynamic center (xac/c) = 0.25
Thin Airfoil Theory
Flat plate
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The NACA 25012 wing section airfoil has a mean camber line given by
(y/c) = 0.5383 (x/c)3 - 0.6315 (x/c)2 + 0.2147 (x/c) for 0 =< (x/c) =< 0.391
(y/c) = 0.0322 (1 - x/c ) for 0.391 =< (x/c) =< 1
Using thin airfoil theory we can calculate the following
the zero lift angle of attack αo = − 0.0259 rad = −1.483o,
the pitching moment coefficient at the aerodynamic center (Cm)ac = −0.0244,
When the angle of attack is “α=10o ”,
the lift coefficient CL = 1.26,
the pitching moment coefficient at the leading edge (Cm)LE = −0.339
the pitching moment coefficient at the half chord point (Cm)C/2= 0.29
the center of pressure (xc.p/c) = 0.27
the aerodynamic center (xac/c) = 0.25
Thin Airfoil Theory
NACA 25012
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Thin Airfoil Theory
Flat plate with a trailing edge flap
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Consider a flat plate airfoil with a trailing edge flap
as shown in figure, the flap chord to total chord
are "λ= cf/c" and the flap deflection angle are δ.
The expressions for the lift coefficient CL, the
pitching moment coefficient about the leading
edge point CM(LE), the pitching moment coefficient
about the aerodynamic center Cm(ac), the zero lift
angle of attack αo as functions of λ, δ, and the
angle of attack "α" using the thin airfoil theory can
be written as
Thin Airfoil Theory
Flat plate with a trailing edge flap
λ, δ
V∞, α After deflection
V∞, α c
Before deflection
cf
ffL
L
LLL
sin2C
and2Cwith
CCC
2
2sinsin2
2
1C
and2
Cwith
CCC
fff)LE(M
)LE(M
)LE(M)LE(MM )LE(
)12(cos 1
f
where
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Thin Airfoil Theory
Flat plate with a trailing edge flap (cont.)
λ, δ
V∞, α After deflection
V∞, α c
Before deflection
cf
)sin(
)cos1(sin
44
1
c
x
ff
ffcp
)12(cos 1
f where
2
2sinsin
2
1C
and0Cwith
CCC
ff)ac(M
)ac(M
)ac(M)ac(MM )ac(
ff
0
sin)1(
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Thin Airfoil Theory
Flat plate with a trailing edge flap (cont.)
λ, δ
V∞, α After deflection V∞, α c
Before deflection
cf
)12(cos 1
f where
fff
2
ff2)H(M
ffff2)H(M
)H(M)H(MM
sin)(4cos21)(2)2cos(1(4
1C
and)2sin(sin4)1cos2)((24
1Cwith
CCC)H(
H
The hinge moment coefficient due to flap deflection
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Thin Airfoil Theory
Flat plate with a trailing edge flap (cont.) If the flap chord to total chord “ λ = cf /c = 1/4”, the flap
deflection angle ” δ = 4o ”, and the angle of attack
“ α = 8o “. Using thin airfoil theory :-
Before deflection
the lift coefficient
“ CL = 0.877 ”
the pitching moment
coefficient about the
leading edge point
“ CM(LE) = - 0.219 ”
the center of pressure
point “ xcp/c = 0.25 ”
After deflection
the lift coefficient
“ CL = 1.144 ”
the pitching moment
coefficient about the
leading edge point
“ CM(LE) = - 0.331 ”
the center of pressure
point “ xcp/c = 0.29 ”
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Thin Airfoil Theory
Flat plate with a trailing edge flap (cont.) If the flap chord to total chord “ λ = cf /c = 0.2 ”, the flap
deflection angle ” δ = 6o ”, and the angle of attack
“ α = 12o “. Using thin airfoil theory :-
Before deflection
the lift coefficient
“ CL = 1.316 ”
the pitching moment
coefficient about the
leading edge point
“ CM(LE) = - 0.329 ”
the center of pressure
point “ xcp/c = 0.25 ”
After deflection
the lift coefficient
“ CL = 1.678 ”
the pitching moment
coefficient about the
leading edge point
“ CM(LE) = - 0.486 ”
the center of pressure
point “ xcp/c = 0.29 ”
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Thin Airfoil Theory
Flat plate with a trailing edge flap (cont.)
If the flap chord to total chord “ λ = cf /c = 0.2 ”, the flap
deflection angle ” δ = 6o ”, and the angle of attack
“ α = 12o “. Using thin airfoil theory :-
After deflection
the hinge moment coefficient “ CM(H) = - 0.201 ”
923.0Cand5.0Cwith
CCC
)H(M)H(M
)H(M)H(MM )H(
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λ1,δ1
λ2,δ2 Voo, α c
Voo, α Before deflection After deflection
Problem Consider a flat plate airfoil with double trailing edge flap as shown in
figure, the flap chord to total chord are "λ1= cf1/c" and "λ2= cf2/c". The flap
deflection angles are δ1 and δ2, respectively.
•Derive the lift coefficient CL as function of λ1, λ2, δ1, δ2 and the angle of attack
"α" using the thin airfoil theory.
•What is the change in the lift coefficient due to flap deflections δ1=5o and δ2 =
5o for λ1 = 0.2 and λ2 = 0.2 when α = 10o.
Thin Airfoil Theory Problem Consider the NACA 6412 wing section airfoil with a mean camber line
given by
(y/c) = 0.3 (x/c) - 0.375 (x/c)2 for 0 =< (x/c) =< 0.4
(y/c) = 0.0333 + 0.1332 (x/c) – 0.1665 (x/c) 2 for 0.4 =< (x/c) =< 1.0
Using thin airfoil theory calculate the zero lift angle of attack “αo” and the
pitching moment coefficient at the aerodynamic center (Cm)ac . When the angle
of attack is “α=10o ”, find the lift coefficient CL, the pitching moment coefficient
at the leading edge (Cm)LE, the pitching moment coefficient at the half chord
point (Cm)C/2, and the center of pressure (Xc.p/c).
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END OF THIN AIRFOIL THEORY
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