40 mph v'= 25 mph if the observed horizontal speed of the b a volley on board is v'=25mph...
TRANSCRIPT
40mph
v'=25 mph
If the observed horizontal speed of the BA volley on board is v'=25mphthen stationary observers on the train platform, see it travel with a speed
(1) -25 mph (3) 15 mph (5) 40 mph(2) -15 mph (4) 25 mph (6) 65 mph
40mph
v'=25 mph
If the horizontal speed of the return (AB) volley is v'=25mphthen stationary observers on the train platform see the ball’s speed as
(1) -25 mph (3) 15 mph (5) 40 mph(2) -15 mph (4) 25 mph (6) 65 mph
40mph
v'=40 mph
What if v'=40mph?
5m/sec
Frame
Frame
v2B=3 m/sec
1 kg1 kg
v1B=0
u
Frame
Frame
am
d
Within Frame B a mass, m, is accelerated from rest by a force F through a distance d.
ConcepTestConcepTest
In Galilean or Newtonian Relativity, which of the quantities below change when you change your reference frame?
1) velocity
2) distance
3) mass
4) acceleration
5) all of the above
6) 1 and 2 only
ConcepTestConcepTest
1) time
2) mass
3) force
4) all of the above
5) none of these
In Galilean or Newtonian Relativity, which of the quantities below change when you change your reference frame?
How do you tell when you are completely stopped?
horizontal speed of the BA volley
(6) 65 mph
horizontal speed of the AB volley
(3) 15 mph
The common sense rule you apply is
Though according to spectators on board the train volleys are simplyleft-right-left-right-left-right-left…the ground-based observers actuallysee the ball always traveling left, but:fast-slow-fast-slow-fast-slow-fast…
oArelativeBtframeBframeA vvv
(6) 1 and 2 only Sure mass doesn’t seem to be something affected by being in a moving compartment. But if velocity is, why wouldn’t acceleration be?Recall the definition: a=v/t =(vfinal-vinitial)/t. Since vA
final= vBfinal+ Vrel and vA
initial= vBinitial+ Vrel then vA= vB !
5) none of these We call such absolute quantities invariant.